I am attempting to create a report in SSRS with an Oracle data source. The solution to this issue can be in SSRS but it would be preferable to be in Oracle. I do not have access to modify the tables or to create anything in the database.
Given the following table layout (Note that these tables are simplifications via sub queries of the tables that are actually being queried.):
Table 1 (Bills)
AccountID Period Tax
--------------------------
123 13/10 21.12
123 13/11 6.46
123 13/12 5.28
Table 2 (Adjustments)
AccountID Period Tax
--------------------------
123 13/11 -16.66
123 14/01 5.00
I am looking for results similar to this:
AccountID Period Tax
--------------------------
123 13/10 21.12
123 13/11 -10.20
123 13/12 5.28
123 14/01 5.00
As you can see, there can be records in the Adjustments table for a period and not have a corresponding record in the Bills table for the same period (and vice versa). I am having difficulty wrapping my head around how to modify my query to make this work. The below query is a pseudocode version of the current query I am using.
SELECT A.AccountID, NVL(B.Period, C.Period) "Period", NVL(A.Tax, 0) + NVL(B.Tax, 0) "Tax"
FROM Account A
LEFT JOIN (SELECT AccountID, Period, SUM(Tax) "Tax"
FROM Bills
GROUP BY AccountID, Period) B ON A.AccountID = B.AccountID
LEFT JOIN (SELECT AccountID, Period, SUM(Tax) "Tax"
FROM Adjustments
GROUP BY AccountID, Period) C ON A.AccountID = C.AccountID
WHERE NVL(A.Tax, 0) + NVL(B.Tax, 0) <> 0
Hopefully this is enough information. Please let me know if any more information is required.
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE Bills ( AccountID , Period, Tax )
AS
SELECT 123, '13/10', 21.12 FROM DUAL
UNION ALL SELECT 123, '13/11', 6.46 FROM DUAL
UNION ALL SELECT 123, '13/12', 5.28 FROM DUAL;
CREATE TABLE Adjustments ( AccountID , Period, Tax )
AS
SELECT 123, '13/11', -16.66 FROM DUAL
UNION ALL SELECT 123, '14/01', 5.00 FROM DUAL;
Query 1:
SELECT AccountID, Period, SUM( Tax ) AS Tax
FROM ( SELECT * FROM Bills
UNION ALL
SELECT * FROM Adjustments )
GROUP BY AccountID, Period
ORDER BY AccountID, Period
Results:
| ACCOUNTID | PERIOD | TAX |
|-----------|--------|-------|
| 123 | 13/10 | 21.12 |
| 123 | 13/11 | -10.2 |
| 123 | 13/12 | 5.28 |
| 123 | 14/01 | 5 |
Related
I have data with overlapping data ranges. Example below
Customer_ID
FAC_NUM
Start_Date
End_Date
New_Monies
12345
ABC1234
26/NOV/2014
26/MAY/2015
100000
12345
ABC1234
12/DEC/2014
12/JUN/2015
200000
12345
ABC1234
15/JUN/2015
15/DEC/2015
500000
12345
ABC1234
20/DEC/2015
20/JUN/2016
600000
I want to convert this table into data with non overlapping ranges such that for each overlapping period, the New_Monies column is summed together and shown as a new row. For the example above, I want the output to be as follows
Customer_ID
FAC_NUM
Start_Date
End_Date
New_Monies
12345
ABC1234
26/NOV/2014
11/DEC/2014
100000
12345
ABC1234
12/DEC/2014
26/MAY/2015
300000
12345
ABC1234
27/MAY/2015
12/JUN/2015
200000
12345
ABC1234
15/JUN/2015
15/DEC/2015
500000
12345
ABC1234
20/DEC/2015
20/JUN/2016
600000
Row 2 above being the overlapping period of 12 Dec 2014 to 26 May 2015 showing the total New_Monies as 300000 (100000+200000)
What would be the best way to do this in Oracle?
Thanks in advance for your support.
Regards,
Ani
with
prep (customer_id, fac_num, dt, amount) as (
select t.customer_id, t.fac_num,
case h.col when 's' then t.start_date else t.end_date + 1 end as dt,
case h.col when 's' then t.new_monies else - t.new_monies end as amount
from sample_data t
cross join
(select 's' as col from dual union all select 'e' from dual) h
)
, cumul_sums (customer_id, fac_num, dt, amount) as (
select distinct
customer_id, fac_num, dt,
sum(amount) over (partition by customer_id, fac_num order by dt)
from prep
)
, with_intervals (customer_id, fac_num, start_date, end_date, amount) as (
select customer_id, fac_num, dt,
lead(dt) over (partition by customer_id, fac_num order by dt) - 1,
amount
from cumul_sums
)
select customer_id, fac_num, start_date, end_date, amount
from with_intervals
where end_date is not null
order by customer_id, fac_num, start_date
;
The prep subquery unpivots the inputs, while at the same time changing the "end date" to the "start date" of the following interval and assigning a positive amount to the "start date" and the negative of the same amount to the following "start date". cumul_sums computes the cumulative sums; note that if two or more intervals begin on the same date (so the same date from prep appears multiple times for a customer and fac_num), the analytic sum will include the amounts from ALL the rows up to that date - the default windowing clause is range between...... After the cumulative sums are computed, this subquery also de-duplicates the output rows (to handle precisely that complication, of multiple intervals starting on the same date). with_intervals recovers the "start date" - "end date" intervals, and the final step simply removes the last interval ("to infinity") which would have an "amount" of zero.
EDIT This solution answers the OP's original question. After posting the solution, the OP changed the question. The solution can be changed easily to address the new formulation. I'm not going to chase shadows though; the solution will remain as is.
Here is an way to do this.
with all_data
as (select Customer_ID,FAC_NUM,start_date as dt,new_monies as calc_monies
from t
union all
select Customer_ID,FAC_NUM,end_date as dt,new_monies*-1 as calc_monies
from t
)
select x.customer_id
,x.fac_num
,x.start_date
,case when row_number() over(order by end_date desc)=1 then
x.end_date + 1
else x.end_date
end as new_end_date
from (
select t.customer_id
,t.fac_num
,t.dt as start_date
,lead(dt) over(order by dt)-1 as end_date
,sum(calc_monies) over(order by dt) as new_monies
from all_data t
)x
where end_date is not null
order by 3
db fiddle link
https://dbfiddle.uk/?rdbms=oracle_11.2&fiddle=856c9ac0954e45429994f4ac45699e6f
+-------------+---------+------------+--------------+------------+
| CUSTOMER_ID | FAC_NUM | START_DATE | NEW_END_DATE | NEW_MONIES |
+-------------+---------+------------+--------------+------------+
| 12345 | ABC1234 | 26-NOV-14 | 11-DEC-14 | 100000 |
| 12345 | ABC1234 | 12-DEC-14 | 25-MAY-15 | 300000 |
| 12345 | ABC1234 | 26-MAY-15 | 12-JUN-15 | 200000 |
+-------------+---------+------------+--------------+------------+
Suppose I have a table with the following data:
+----------+-----+--------+
| CLASS_ID | Day | Period |
+----------+-----+--------+
| 1 | A | CCR |
+----------+-----+--------+
| 1 | B | CCR |
+----------+-----+--------+
| 2 | A | 1 |
+----------+-----+--------+
| 2 | A | 2 |
+----------+-----+--------+
| 3 | A | 3 |
+----------+-----+--------+
| 3 | B | 4 |
+----------+-----+--------+
| 4 | A | 5 |
+----------+-----+--------+
As you could probably guess from the nature of the data, I'm working on an Oracle SQL query that pulls class schedule data from a Student Information System. I'm trying to pull a class's "period expression", a calculated value that contains the Day and Period fields into a single field. Let's get my expectation out of the way first:
If the Periods match, Period should be the GROUP BY field, and Day should be the aggregated field (via a LISTAGG function), so the calculated field would be CCR (A-B)
If the Days match, Day should be the GROUP BY field, and Period should be the aggregated field, so the calculated field would be 1-2 (A)
I'm only aware of how to do each GROUP BY individually, something like for where Days match:
SELECT
day,
LISTAGG(period, '-') WITHIN GROUP (ORDER BY period)
FROM schedule
GROUP BY day
and vice versa for matching Periods, but I'm not seeing how I could do that dynamically for Period and Day in the same query.
You'll also notice that the last row in the example data set doesn't span multiple days or periods, so I also need to account for classes that don't need a GROUP BY at all.
Edit
The end result should be:
+------------+
| Expression |
+------------+
| CCR(A-B) |
+------------+
| 1-2(A) |
+------------+
| 3-4(A-B) |
+------------+
| 5(A) |
+------------+
It is really not clear to me WHY you want output in that way. It doesn't provide any useful information (I don't think) - you can't tell, for example for class_id = 3, which combinations of day and period are actually used. There are four possible combinations (according to the output), but only two are actually in the class schedule.
Anyway - you may have your reasons. Here is how you can do it. You seem to want to LISTAGG both the day and the period (both grouped by class_id, they are not grouped by each other). The difficulty is that you want distinct values in the aggregate lists only - no duplicates. So you will need to select distinct, separately for period and for day, then to the list aggregations, and then concatenate the results in an inner join.
Something like this:
with
test_data ( class_id, day, period ) as (
select 1, 'A', 'CCR' from dual union all
select 1, 'B', 'CCR' from dual union all
select 2, 'A', '1' from dual union all
select 2, 'A', '2' from dual union all
select 3, 'A', '3' from dual union all
select 3, 'B', '4' from dual union all
select 4, 'A', '5' from dual
)
-- end of test data; the actual solution (SQL query) begins below this line
select a.class_id, a.list_per || '(' || b.list_day || ')' as expression
from ( select class_id,
listagg(period, '-') within group (order by period) as list_per
from ( select distinct class_id, period from test_data )
group by class_id
) a
inner join
( select class_id,
listagg(day, '-') within group (order by day) as list_day
from ( select distinct class_id, day from test_data )
group by class_id
) b
on a.class_id = b.class_id
;
CLASS_ID EXPRESSION
-------- ----------
1 CCR(A-B)
2 1-2(A)
3 3-4(A-B)
4 5(A)
How about union with having count(*) = 1?
select LISTAGG(period, '-') list WITHIN GROUP (ORDER BY period)
from schedule
group by CLASS_ID, day
having count(*) = 1
union all
select LISTAGG(day, '-') list WITHIN GROUP (ORDER BY day)
from schedule
group by CLASS_ID, period
having count(*) = 1
I have a table in an Oracle 11g database that looks like this:
ownerid | propertyid | name
--------------------------------------
1 | 1000001 | SMITH MARY
2 | 1000001 | SMITH JOHN
3 | 1000002 | HUGHES JANE
4 | 1000003 | CHEN ALICE
5 | 1000003 | MCCOY ELLIS
I'm trying to group the table on propertyid and pivot the rows to columns so that it looks like this:
propertyid | owner1 | owner2
---------------------------------------------
10001 | SMITH MARY | SMITH JOHN
10002 | HUGHES JANE | <null>
10003 | CHEN ALICE | MCCOY ELLIS
Each property can have between 1 and 3 owners, but I'm only interested in the first two as they appear when ordered on ownerid.
My best solution was to create two subqueries: one of "first" owners and another "second" owners. I used the nth_value function as follows:
-- first owners
select
propertyid,
nth_value(name, 1) over (partition by propertyid order by ownerid) as owner_1
from owners
But this gives me duplicate (although correct) pairs of properties and owners if the total number of owners is greater than 1. In general I feel like there must be a better way of doing this. Does anyone have any ideas?
with
inputs ( ownerid, propertyid, name ) as (
select 1, 1000001, 'SMITH MARY' from dual union all
select 2, 1000001, 'SMITH JOHN' from dual union all
select 3, 1000002, 'HUGHES JANE' from dual union all
select 4, 1000003, 'CHEN ALICE' from dual union all
select 5, 1000003, 'MCCOY ELLIS' from dual
),
prep ( propertyid, name, rn ) as (
select propertyid, name,
row_number() over (partition by propertyid order by ownerid)
from inputs
)
select *
from prep
pivot (max(name) for rn in (1 as owner1, 2 as owner2))
order by propertyid
;
PROPERTYID OWNER1 OWNER2
---------- ----------- -----------
1000001 SMITH MARY SMITH JOHN
1000002 HUGHES JANE
1000003 CHEN ALICE MCCOY ELLIS
3 rows selected.
I am trying to:
Create a cursor that gets all the current prices of items in a store.
I bulk collect the cursor and loop upserting by using MERGE statement into STORE_INVENTORY table.
Now I want to NULL out the PRICE column in the STORE_INVENTORY table that are not in the cursor.
How can step 3 be done? I can do step 1 and 2 already as I have already updated or inserted the items that are pulled from the cursor.
Here is some example data:
There are three source tables where it is updated by an external party. My objective is to take these three sources of data and merge it into a singular table.
SOURCE TABLES
ITEM_TYPES
DESC_ID | TYPE
A | Kitchen
B | Bath
ITEM_MANIFEST
LOC_ID | ORIGIN
U | USA
C | CHINA
ITEM_PRICE
ITEM_ID | PRICE | DESC_ID | LOC_ID | DATE
0 | 3.99 | A | U | 9/11/2015
1 | 2.99 | B | C | 9/11/2015
2 | 1.99 | A | U | 9/05/2015
DESTINATION TABLE
STORE_INVENTORY
ITEM_ID | TYPE | ORIGIN | PRICE
0 | Kitchen | CHINA | 3.99
8 | Bath | USA | 2.99
So after I execute the SQL Procedure that has a date as a parameter. It will only pull from ITEM_PRICE if it's after the given date.
If execute the procedure with the passed in date 9/10/2015
Expected Output
STORE_INVENTORY
0 | Kitchen | USA | 3.99
1 | Bath | China | 2.99
8 | Bath | USA | NULL
So, something like this, then?
drop table item_description;
drop table item_manifest;
drop table item_price;
drop table store_inventory;
create table item_description
as
select 'A' desc_id, 'Kitchen' type from dual union all
select 'B' desc_id, 'Bath' type from dual;
create table item_manifest
as
select 'U' loc_id, 'USA' origin from dual union all
select 'C' loc_id, 'CHINA' origin from dual;
create table item_price
as
select 0 item_id, 3.99 price, 'A' desc_id, 'U' loc_id, to_date('11/09/2015', 'dd/mm/yyyy') dt from dual union all
select 1 item_id, 2.99 price, 'B' desc_id, 'C' loc_id, to_date('11/09/2015', 'dd/mm/yyyy') dt from dual union all
select 2 item_id, 1.99 price, 'A' desc_id, 'U' loc_id, to_date('05/09/2015', 'dd/mm/yyyy') dt from dual;
create table store_inventory
as
select 0 item_id, 'Kitchen' type, 'CHINA' origin, 3.99 price from dual union all
select 8 item_id, 'Bath' type, 'USA' origin, 2.99 price from dual;
select * from store_inventory;
ITEM_ID TYPE ORIGIN PRICE
---------- ------- ------ ----------
0 Kitchen CHINA 3.99
8 Bath USA 2.99
select coalesce(ip.item_id, si.item_id) item_id,
coalesce(id.type, si.type) type,
coalesce(im.origin, si.origin) origin,
ip.price
from item_description id
inner join item_price ip on (id.desc_id = ip.desc_id and ip.dt > to_date('10/09/2015', 'dd/mm/yyyy')) -- use a parameter for the date here
inner join item_manifest im on (ip.loc_id = im.loc_id)
full outer join store_inventory si on (si.item_id = ip.item_id);
ITEM_ID TYPE ORIGIN PRICE
---------- ------- ------ ----------
0 Kitchen USA 3.99
8 Bath USA
1 Bath CHINA 2.99
merge into store_inventory tgt
using (select coalesce(ip.item_id, si.item_id) item_id,
coalesce(id.type, si.type) type,
coalesce(im.origin, si.origin) origin,
ip.price
from item_description id
inner join item_price ip on (id.desc_id = ip.desc_id and ip.dt > to_date('10/09/2015', 'dd/mm/yyyy')) -- use a parameter for the date here
inner join item_manifest im on (ip.loc_id = im.loc_id)
full outer join store_inventory si on (si.item_id = ip.item_id)) src
on (src.item_id = tgt.item_id)
when matched then
update set tgt.type = src.type,
tgt.origin = src.origin,
tgt.price = src.price
when not matched then
insert (tgt.item_id, tgt.type, tgt.origin, tgt.price)
values (src.item_id, src.type, src.origin, src.price);
commit;
select * from store_inventory;
ITEM_ID TYPE ORIGIN PRICE
---------- ------- ------ ----------
0 Kitchen USA 3.99
8 Bath USA
1 Bath CHINA 2.99
Obviously, your procedure would have an input parameter of DATE datatype to pass into the query, and your query would use the parameter, rather than a hardcoded date like I did in my example. E.g. ip.dt > p_cutoff_date
I can do step 1 and 2 already as I have already updated or inserted
the items that are pulled from the cursor.
Hmm. These steps seem unnecessary - why not do them as part of the MERGE statement? What does the store_inventory table look like before you do your insert/update from the cursor? Also, what is the cursor you're using to do this?
couldn't you do a date-limited subselect of ITEM_PRICE.PRICE, after pulling in the TYPE and ORIGIN via the main join to ITEM_PRICE, without limiting on date?
i.e. something like.
select ITEM_ID, TYPE, ORIGIN
/* not selecting PRICE in the main join */
,(select PRICE from ITEM_PRICE where your join conditions
and DATE >= your param)
from ITEM_TYPES, ITEM_MANIFEST, ITEM_PRICE
where your join conditions, but no criteria on DATE
Sorry, would be clearer and easier to type up if you had provided your existing query.
From re-reading your question, I am unsure if you are inserting only 2 rows but want to get 3. Or if you have 3 rows, but you want to NULL out the missing price.
If the target table already has the 3 rows, then, instead of doing a CURSOR based approach (which can be slow on high volumes and is fussy to write), why not do an UPDATE instead, with DATE as a criteria? The NULL will be assigned to price if there is no match, that's how UPDATEs work.
UPDATE STORE_INVENTORY set PRICE
= (select PRICE from ITEM_PRICE where your join conditions
and DATE >= your param)
I have a problem with a query, see I have two tables, let say:
table a:
progid | name | type
12 | john | b
12 | anna | c
13 | sara | b
13 | ben | c
14 | alan | b
15 | george| b
table b:
progid | name | type
12 | john | b
12 | anna | c
13 | sara | b
14 | alan | b
15 | george| b
table a gets count
progid | count(*)
12 | 2
13 | 2
14 | 1
15 | 1
table b gets
progid | count(*)
12 | 2
**13 | 1**<-this is what I want to find different count
14 | 1
15 | 1
What I want is to find which progid in table b aren't in table a by count, (because as you can see the prog id is there but they should be there the same times! So ben is gone but the progid 13 is there)
So I want to get progid where count varies in the tables, I tried:
select a.progid from
(select progid ,count(*) total from tablea group by progid) a,
(select progid ,count(*) total from tableb group by progid) b
where
a.progid=b.progid and a.total<>b.total;
I get b.total invalid identifier
if I use a.count(progid)<>b.count(progid)
Error says can't use group functions there, any ideas? I'm desperate!
ok i've checked your answers and here's the original one
select a.beneficiarioid from
(select beneficiarioid,count(*) total from lmml_ejercicio_2012_3 where programaid=61 group by beneficiarioid order by beneficiarioid) a,
(select beneficiarioid,count(*) total from ejercicio_2012_3 where programaid=61 group by beneficiarioid order by beneficiarioid) where
a.beneficiarioid=b.beneficiarioid and a.total<>b.total;
anyway, i'll try your querys and let you know!! thank you very much!!
btw it's Oracle 11g
You should be able to use a subquery to get each count and then join them using a FULL OUTER JOIN:
select coalesce(a.progId, b.progId) progid,
coalesce(a.atotal, 0) atotal,
coalesce(b.btotal, 0) btotal
from
(
select progid, count(*) aTotal
from tablea
group by progId
) a
full outer join
(
select progid, count(*) bTotal
from tableb
group by progId
) b
on a.progid = b.progid
where coalesce(a.atotal, 0) <> coalesce(b.btotal, 0);
See SQL Fiddle with Demo. I used a FULL OUTER JOIN in the event you have rows in one table that do not exist in the other table.
Even though your query works fine on my database, I would prefer set operation:
(select progid ,count(*) total from tablea group by progid)
minus
(select progid ,count(*) total from tableb group by progid)