Basically, I am attempting to apply the d3 fisheye distortion algorithm to a radial tree. I believe the issues I am encountering revolve around the fact that the coords being fed to the fisheye distortion are the coords computed by the d3.layout.tree. But the actual coords have been adjusted by the g transform. So, the coords resulting from the fisheye distortion need to be adjusted back to the g transform.
For example:
// re-setting the projection according to fisheye coords
diagonal.projection(function(d) { d.fisheye = fisheye(d); return [d.fisheye.y, d.fisheye.x / 180 * Math.PI]; })
I have been attempting this...here is the fiddle.
I am somewhat close...help is appreciated.
Following the direction I'd suggested in the comments, this is the result:
https://jsfiddle.net/xdk5ehcr/
Instead of using rotations and translations to position the nodes, I created two trigonometry-based functions to calculate horizontal and vertical position from the data (x,y) values, which are treated as polar coordinates.
Then I had to set the fisheye function to use my positioning functions as "accessor" functions instead of reading d.x and d.y directly. Unfortunately, the basic plug-in you were using for the fisheye didn't include a way to get and set x/y accessor functions, so I had to modify that too. I was surprised it wasn't already in the code; it's a standard functionality on most d3 layout objects.
(When I get github set up, I will have to make a pull request to add it in. I'll need to figure out how the fisheye scale/zoom function works, though -- I took that out of this example since you weren't using it.)
The positioning functions were as follows:
function getHPosition(d){
//calculate the transformed (Cartesian) position (H, V)
//(without fisheye effect)
//from the polar coordinates (x,y) where
//x is the angle
//y is the distance from (radius,radius)
//See http://www.engineeringtoolbox.com/converting-cartesian-polar-coordinates-d_1347.html
return (d.y)*Math.cos(d.x);
}
function getVPosition(d){
return (d.y)*Math.sin(d.x);
};
The functions are used to set the original position of the nodes and links, and then once the fisheye kicks in it uses these functions internally, returning the results (with distortion if appropriate) as d.fisheye.x and d.fisheye.y.
For example, for links that means the projection setting the d3.svg.diagonal function like this for initialization:
var diagonal = d3.svg.diagonal()
.projection(function(d) {
return [getHPosition(d), getVPosition(d)];
});
But like this for update:
diagonal.projection(function(d) {
d.fisheye = fisheye(d);
return [d.fisheye.x, d.fisheye.y];
});
There are a couple other little changes:
I simplified the dimensions of the plotting area a bit.
I added a background rectangle with pointer-events:all; so that the fisheye doesn't turn on and off as the mouse moves between nodes and empty background.
I didn't bother rotating the text (since the node groups are no longer rotating, it doesn't happen by default), but you could easily add in a rotate transformation on the individual text elements.
Finally, and this one stumped me for longer than I'd like to admit, the angles have to be in radians for the Javascript trig functions. Couldn't figure out why my layouts were so ugly, with overlapping lines. I thought it was something to do with switching between d3.svg.diagonal() and d3.svg.diagonal.radial() and spent a lot of time trying to do inverse-trig and all sorts of things...
Related
In Three.js there seems to be quite a few ways of rotation which i personally do not find very intuitive. See e.g. the example
http://cloud.engineering-bear.com/apps/robot/robot.html
I get very strange unexpected effects when I apply rotation to multiple objects. E.g. when I rotate objects that have been added to each other and start rotating the parent the individual objects will all over sudden by placed differently in respect to each other then they originally where. I am now experimenting with grouping and would like to avoid the same effect.
See http://pi-q-robot.bitplan.com/example/robot?robot=/models/thing3088064.json for the current state of affairs and https://github.com/BITPlan/PI-Q-Robot for the source code.
So i searched for proper examples following the different API options:
rotation
function renderScene() {
stats.update();
//side1.rotation.z += 0.02;
pivot.rotation.z += 0.02;
https://jsfiddle.net/of1vfhzz/1/
https://github.com/mrdoob/three.js/issues/1958
rotateOnAxis
three.js rotate Object3d around Y axis at it center
How to rotate a 3D object on axis three.js?
ThreeJS - rotation around object's own axis
rotateAroundWorldAxis
object.rotateAroundWorldAxis(p, ax, r * Math.PI * 2 / frames);
How to rotate a object on axis world three.js?
https://stackoverflow.com/a/32038265/1497139
https://jsfiddle.net/b4wqxkjn/7/
THREE.js Update rotation property of object after rotateOnWorldAxis
rotateOnWorldAxis
object.rotateOnWorldAxis( axis, angle );
Rotate around World Axis
rotateAboutPoint
Three JS Pivot point
Rotation anchor point in Three.js
setRotationFromAxisAngle
https://threejs.org/docs/#api/en/core/Object3D.setRotationFromAxisAngle
setEulerFromQuaternion
quaternion = new THREE.Quaternion().setFromAxisAngle( axisOfRotation, angleOfRotation );
object.rotation.setEulerFromQuaternion( quaternion );
Three.js - Rotating a sphere around a certain axis
applyMatrix
this.mesh.updateMatrixWorld(); // important !
childPart.mesh.applyMatrix(new THREE.Matrix4().getInverse(this.mesh.matrixWorld))
Applying a matrix in Three.js does not what I expect
I like the jsFiddle for https://stackoverflow.com/a/56427636/1497139
var pivot = new THREE.Object3D();
pivot.add( cube );
scene.add( pivot );
I also found the following discussions
pivot issue in discourcee.three.js.org
https://discourse.threejs.org/t/rotate-group-around-pivot/3656
https://discourse.threejs.org/t/how-to-rotate-an-object-around-a-pivot-point/6838
https://discourse.threejs.org/t/set-dynamically-generated-groups-pivot-position-to-the-center-of-its-children-objects-position/6349
https://discourse.threejs.org/t/my-3d-model-is-not-rotating-around-its-origin/3339/3
https://jsfiddle.net/blackstrings/c0o3Lm45/
https://discourse.threejs.org/t/rotate-object-at-end-point/2190
https://jsfiddle.net/f2Lommf5/3594/
Questions
None of the above information is clear enough to get to the point of the problem to be solved. The graphics above are much clearer stating the problem than the proposals are stating a solution.
a)
I'd like to use the cylinder as the axis even when the cylinder is moved.I'd expect the easiest way to go would be to use rotateAroundWorldAxis - is that available in the latest revision from three.js or do i have to add it from e.g. https://stackoverflow.com/a/32038265/1497139?
b) I'd like to get a chain of objects to be rotated to later apply inverse kinematics as in
https://github.com/jsantell/THREE.IK
https://jsantell.github.io/THREE.IK/
Although i looked at the source code of that solutions I can't really find the place where the parent-child positioning and rotating is happening. What are the relevant lines of code / API functions that would make proper rotation around a chain of joints happen?
I already looked in the Bone/Skeleton API of Three.js but had the same problem there - lots of lines of code but no clear point where the rotation/positioning between child and parent happens.
Question a)
Basically it works as expected:
cylinder.position.set( options.x, 15, options.z );
pivot.position.x=options.x;
pivot.position.z=options.z;
see
https://jsfiddle.net/wf_bitplan_com/4f6ebs90/13/
Question b)
see
https://codepen.io/seppl2019/pen/zgJVKM
The key is to set the positions correctly. Instead of the proposal at https://stackoverflow.com/a/43837053/1497139 the size is computed in this case.
// create the pivot to rotate around/about
this.pivot = new THREE.Group();
this.pivot.add(this.mesh);
// shift the pivot position to fit my size + the size of the joint
this.pivot.position.set(
x,
y + this.size.y / 2 + this.pivotr,
z + this.size.z / 2
);
// reposition the mesh accordingly
this.mesh.position.set(0, this.size.y / 2, 0);
i want get some points from path after rotating it
i use below code to rotate path
let path= svg.append("path")
.attr("class","offset control")
.attr("d", lineFunction(offsetLineData))
.style("stroke-width", 0.5)
.style("stroke", "red")
.style("fill", "none")
.attr("transform","rotate(90,"+p.x+","+p.y+")")
.attr('transform-origin',"center")
then i want get end point and start point of path
path.node().getPointAtLength(0)
but it return coordination where it don't rotated
how can i get x and y of point after rotation
Think of a SVG as a tree of nested coordinate systems. Every element has its own coordinates, and is fitted into its parent with a rule how to re-calculate them. These rules can be explicit transform attributes, but also implicit combinations of width, height and viewBox ("fit box A in size B").
A transform attribute is considered to be the link to the parent element. That means, if you ask for a geometric property of an element, most of the times you get the value before the transform is applied. After it is applied would be asking for geometric values in the coordinate system of the parent.
Because of this complexity there are several SVG API functions to find out how these coordinate systems fit together. getPointAtLength() gets you coordinates before applying the transform attribute.
var localPoint = path.node().getPointAtLength(0)
First, you have to find out what the transform attribute does. This looks a bit complicated, partly because the attribute can be animated and can contain a list of functions, partly because the API is...well...:
// construct a neutral matrix
var localMatrix = path.node().viewportElement.createSVGMatrix()
var localTransformList = path.node().transform.baseVal
// is there at least one entry?
if (localTransformList.length) {
// consolidate multiple entries into one
localMatrix = localTransformList.consolidate().matrix
}
You can then apply the found transformation to the point with
var transformedPoint = localPoint.matrixTransform(localMatrix)
There are several functions hat will return a SVGMatrix to transform data from the coordinate system after application of the transform attribute (i. e. after the step above):
to ask for the transformation to the nearest viewport (in most cases the nearest parent <svg>) element: element.getCTM()
to ask for the transformation to screen pixels: element.getScreenCTM()
to ask for the transformation to an arbitrary element: element.getTransformToElement(...)
My understanding of D3's projection functions are that they do the same thing as the scale functions. They map GPS coordinates to pixel coordinates. This is the projection I'm currently using. (I don't understand all the variables in detail but I fiddled around with them until the map showed up)
var projection = d3.geo.albers()
.center([-122.436269,37.798107])
.rotate([0, 0, 0])
.parallels([36, 38])
.scale(300000);
This draws the map fine:
.attr("d", d3.geo.path().projection(projection))
When I try to plot points though the numbers are crazy.
.attr("cx",function(d) {
return projection([d._lon,d._lat])[0];
})
.attr("cy",function(d) {
return projection([d._lon,d._lat])[1];
});
How do I properly do this?
Here are some examples of the points I'm getting through the projection function:
[5175.3799972560955, 1808.5108650794136]
[5158.315547249338, 1823.564395627589]
[5143.958532762888, 1831.9879789081751]
On a 1280x800 screen these are way off. Even if I scale them by dividing by 100, they'll still mostly just stack on top of each other. I have a 700*700 svg positioned using twitter bootstrap. Not sure how those are taken into account. I just assumed that if the map if fine, then the same projection should work for the points.
I would like to draw a d3 voronoi diagram and clip it like d3 hull borders do bound a collection of nodes or any similar clipping.
The red line in this Screenshot shows what i would like to achieve.
How can it be done ?
The d3.geom.hull function will find a polygon that contains all your nodes tightly, with no extra spacing. That of course would cancel out much of the purpose of the Voronoi regions, which are intended to add some active space around the nodes. So what you need to calculate is a polygon that is a certain padding distance larger than the convex hull polygon on all sides.
My recommended algorithm:
Use d3.geom.hull(nodes) to calculate the array of vertices that define the tight boundary of your nodes.
Use those vertices to create a d3 polygon object.
Calculate the center of that polygon with .centroid().
For each vertex in your convex hull, calculate a point that is padding distance farther away from the center of the polygon.
Use this expanded polygon to clip all the polygons in the array returned by Voronoi function.
Sample code:
var hullFunction = d3.geom.hull()
.x(/*x accessor function*/)
.y(/*y accessor function*/);
var tightHull = hullFunction(nodes); //returns an array of vertices
var centerPoint = d3.geom.polygon(tightHullArray).centroid();
var expandedHull = tightHullArray.map( function(vertex) {
//Create a new array of vertices, each of which is the result
//of running this function on the corresponding vertex of the
//original hull.
//Each vertex is of the form [x,y]
var vector = [vertex[0] - centerPoint[0],
vertex[1] - centerPoint[1] ];
//the vector representing the line from center to this point
var vectorLength = Math.sqrt(vector[0]*vector[0]
+ vector[1]*vector[1]);
//Pythagorus' theorem to get the length of the line
var normalizedVector = [vector[0] / vectorLength,
vector[1] / vectorLength];
//the vector scaled down to length 1, but with the same angle
//as the original vector
return [vertex[0] + normalizedVector[0]*padding,
vertex[1] + normalizedVector[1]*padding ];
//use the normalized vector to adjust the vertex point away from
//the center point by a distance of `padding`
});
var clippedVoronoi = voronoiPolygons.map(function(voronoi) {
//voronoiPolygons would be the array returned by the voronoi function
return expandedHull.clip(voronoi);
//I think this is correct; if you get weird results, try
// return voronoi.clip(expandedHull);
});
I recently made an example to illustrate to myself how polygon clipping works:
http://tributary.io/inlet/8263747
You can see the clipping code in the update function, and the rendering code in the process function. drag the points around to see how the clipping will be affected.
A couple things to watch out for:
the order of the points in the "hull" (or clipping path in my example) matters. Your polygon has to be counter-clockwise as well as convex (no caves). If these conditions aren't met there is no error, you just get back an empty array.
the polygon operations manipulate your point arrays in place, if you don't want your geometry itself clipped, but want a copy you need to make a copy first.
I've created nycMap, a project that uses angularJS (MVC), yeoman (build), d3 (mapping) and geoJSON (geo data).
Everything works very nicely, but I did have to spend quite some time getting the right scale and translation. I was wondering how I can automatically figure out at what scale the map will show its best and what x and y values go into the translation?
'use strict';
japanAndCo2App.controller('MainCtrl', function($scope) {
function makeJapanAll(){
var path, vis, xy;
xy = d3.geo.mercator().scale(16000).translate([-5600,2200]);
path = d3.geo.path().projection(xy);
vis = d3.select("#japanAll").append("svg:svg").attr("width", 1024).attr("height", 700);
d3.json("data/JPN_geo4.json", function(json) {
return vis.append("svg:g")
.attr("class", "tracts")
.selectAll("path")
.data(json.features).enter()
.append("svg:path")
.attr("d", path)
.attr("fill",function(d,i){ return d.properties.color || "transparent"});
});
}
makeJapanAll();
});
(If you are interested in the code, it's all on github. The code for the map is in scripts/controllers/main.js which is the same as shown above.)
I've had the same problems. But it is very easy to do when you have a bounding box, which can be determined from the GeoJSON (like meetamit said), or while creating the GeoJson. And the width of the wanted SVG.
I'll start with the variables lattop, lonleft, lonright, width and height for the bounding box of the geojson and the dimensions of the image. I haven't yet occupied myself with calculating a good height from the difference in latutude. So the height is just estimated to be big enough to fit the image. The rest should be clear from the code:
var xym = d3.geo.mercator();
// Coordinates of Flanders
var lattop = 51.6;
var lonleft = 2.4;
var lonright = 7.7;
var width = 1500;
var height =1000;
// make the scale so that the difference of longitude is
// exactly the width of the image
var scale = 360*width/(lonright-lonleft);
xym.scale(scale);
// translate the origin of the map to [0,0] as a start,
// not to the now meaningless default of [480,250]
xym.translate([0,0]);
// check where your top left coordinate is projected
var trans = xym([lonleft,lattop]);
// translate your map in the negative direction of that result
xym.translate([-1*trans[0],-1*trans[1]]);
var path = d3.geo.path().projection(xym);
var svg = d3.select("body").append("svg").attr("width",width).attr("height",height);
Note, if you go over the date line (180 degrees), you will have to take the overflow into account.
Given this:
xy = d3.geo.mercator().scale(someScale).translate([0, 0]);
someScale is the pixel width of the entire world when projected using the mercator projection. So, if your json data had outlines for the whole world – spanning from lat/lng -180,90 to latLng 180,-90 – and if someScale was 1024, then the world would be drawn such that it exactly fits within a 1024x1024-pixel square. That's what you see on in this Google Maps view (well... sort of... not quite... read on...).
That's not enough though. When the world is drawn at 1024px, without any translation, lat/lng 0,0 (i.e. the "middle" of the world) will sit at the 0,0 pixel of the projected map (i.e. the top left). Under these conditions, the whole northern hemisphere and western hemisphere have negative x or y values, and therefore fall outside the drawn region. Also, under these conditions, the bottom right of the world (i.e. lat/lng -90, 180) would sit at the exact middle of the 1024x1024 square (i.e. at pixel 512,512).
So, in order to center the world in the square described here, you need to translate the map by half its width in the X and Y directions. I.e. you need
xy = d3.geo.mercator().scale(1024).translate([512, 512]);
That'll give you exactly the Google Map view I linked to.
If your json data only has part of the world (like, nyc or NY state) drawing it with this xy projection will render the outlines in the correct geographic position relative to the entire 1024x1024 world-spanning region. So it would appear rather small, with lots of whitespace.
The challenge is how to scale and translate the projection such that the area in question fills up the 1024x1024 square. And... so far I haven't answered this question, but I hope that this explanation points you in the right direction towards figuring out this math. I'll also try to continue the answer later, when I have more time. :/
There's an example here that gets the bounds of countries from geojson and then scales and translates the map to that country. The code is a bit ugly; there're however efforts to make this easier in the future (see this and this issue).