After a couple of conversations on here i'm finally getting somewhere but after the pagintion now works when i got to search?page=2 i get a json array of the logged in user and not page 2 of the results.
Here's my controller:
public function search()
{
$q = Input::get('term');
if($q && $q != ''){
$searchTerms = explode(' ', $q);
$query = DB::table('wc_program');
if(!empty($searchTerms)){
foreach($searchTerms as $term) {
$query->where('JobRef', 'LIKE', '%'. $term .'%');
$query->orwhere('Road', 'LIKE', '%'. $term .'%');
}
}
$results = $query->paginate(10);
return View::make('layouts.results', compact('results'));
}
}
Route:
Route::get('/search', 'HomeController#search');
So how can i work around this?
You need to append query string to the pagination.
in your controller, pass the query string to the view.
return View::make('layouts.results', compact('results', 'q'));
In your view (results.blade.php):
append the query string to the pagination otherwise in page 2 you will not get any result.
<?php echo $results->appends(array('term' => $q))->links(); ?>
Related
Im working on product filtering using AJAX. Is there any possible way to produce same output as picture shown below using query builder?
I have tried union but it’s not working.
I hope this example gives idea , Try this one
use multiple if statement and get data into DB using joins .
function datatables($request) {
$data = $this->leftJoin('blog_category', 'blog_category.blog_category_uuid', '=', 'blog_detail.blog_category_uuid')
->where('blog_detail.blog_detail_is_deleted', 'NO');
if ($request->search['value'] != null && $request->search['value'] != '') {
$keyword = $request->search['value'];
$data = $data->where(function($query) use ($keyword) {
// $query->orWhere('activity_type.activity_type_name', 'LIKE', '%' . $keyword . '%');
$query->orWhere('blog_detail.blog_detail_title', 'LIKE', '%' . $keyword . '%');
});
}
if (isset($request->order[0]['dir'])) {
$data = $data->orderBy('blog_detail.blog_detail_id', $request->order[0]['dir']);
} else {
$data = $data->orderBy('blog_detail.blog_detail_created_date');
}
$datacount = $data->count();
$dataArray = $data->select('blog_detail.*', 'blog_category.blog_category_name' , DB::raw('DATE_FORMAT(blog_detail.blog_detail_created_date,"%Y-%m-%d") as blog_detail_date'));
if ($request->length == -1) {
$dataArray = $dataArray->get();
} else {
$dataArray = $dataArray->skip($request->start)->take($request->length)->get();
}
return [$datacount, $dataArray];
}
In laravel you can create a model for product say Product. Then the query will be like
$products = Product::where('product_status', '1');
if ($request->input('minimum_price') && $request->input('maximum_prize')) {
$products = $products->whereBetween('product_prize', array($request->input('minimum_price'), $request->input('maximum_prize')));
}
if ($request->input('brand')){
$brand_filter = implode("','", $request->input('brand'));
$products = $products->whereIn('product_brand', $brand_filter);
}
$products = $products->get();
after the execution $products contains the products after query.
I have a GET form with three filters.
make
Year
country
I need to get all posts from db. But filter the results based on these three filters.
If a country is selected, get posts for that country only or all countries.
if a make is selected, get posts for that make only or all makes
if a year is selected, get posts for that year only or all years
how to write one query that filters all these three options. What I have done is used if and else statements and written different queries for each scenario. That's 9 queries to get one information. Can we make it dynamic and just have one query?
My Example query:
public function search(Request $request)
{
$search=$request->input('search');
if($request->input('country') == "all")
{
$posts = Post::where('status','Published')->orderBy('status_change','DESC')
->where('status','Published')
->where(function($query) use ($search){
$query->where('title','LIKE','%'.$search.'%');
$query->orWhere('model','LIKE','%'.$search.'%');
$query->orWhere('notes','LIKE','%'.$search.'%');
$query->orWhere('description','LIKE','%'.$search.'%');
})
->paginate(25);
}
else
{
$posts = Country::where('country_name', $request->input('country'))->first()->posts()->orderBy('status_change','DESC')
->where('status','Published')
->where(function($query) use ($search){
$query->where('title','LIKE','%'.$search.'%');
$query->orWhere('model','LIKE','%'.$search.'%');
$query->orWhere('notes','LIKE','%'.$search.'%');
$query->orWhere('description','LIKE','%'.$search.'%');
})
->paginate(25);
}
return view('welcome')
->with('published_posts',$posts)
;
}
I think something like this would work:
/**
* #param Request $request
*/
function search(Request $request)
{
$postsQuery = Post::where('status', 'Published');
if ($request->has('country')) {
$country = $request->country;
// assuming relationships are setup correclty
$postsQuery->whereHas('country', function ($query) use ($country) {
$query->where('country_name', 'LIKE', $country);
});
}
if ($request->has('search')) {
$postsQuery->where(function ($query) use ($search) {
$query->where('title', 'LIKE', '%' . $request->search . '%');
$query->orWhere('model', 'LIKE', '%' . $request->search . '%');
$query->orWhere('notes', 'LIKE', '%' . $request->search . '%');
$query->orWhere('description', 'LIKE', '%' . $request->search . '%');
});
}
$postsQuery->orderBy('status_change', 'DESC')->paginate(25);
return view('welcome')->with('published_posts', $result);
}
I used 'when' method.
$make = null;
$year = null;
$country = null;
if($request->filled('make')){
$make = $request->query('make');
}
if($request->filled('year')){
$year = $request->query('year');
}
if($request->filled('country')){
$country = $request->query('country');
}
$posts = DB::table('posts')
->when($make, function($query, $make){
return $query->where("make", "=", $make);
})
->when($year, function($query, $year){
return $query->whereYear("year", "=", $year);
})
->when($country, function($query, $country){
return $query->where('country', "like", $country);
})
->get();
Check out the Laravel Docs:
Check out an article here
I have saved all of my where clause in a variable and i'm trying to join that variable inside laravel query but its not working. Here is mine code
$where .= "";
$where .= '->where("product_details.title", '.$request->title.')';
$where .= '->where("product_details.id", '.$request->id.')';
$results = DB::table('product_details').'$where'.->get();
How to use variable inside query?
you can used like that by using if condition statement for dynamic query
$results = DB::table('product_details')
if($request->title) {
$results->where("product_details.title", $request->title);
}
if($request->id) {
$results->where("product_details.id", $request->id);
}
$result->get();
I am not sure why you want to do this. The following should just work.
DB::table('product_details')
->where([
'product_details.title' => $request->title
'product_details.id' => $request->id
])
->get();
Now, let's say that you may not always have a title or id from the request, you could also do this
DB::table('product_details')
->when($request->title, function ($query, $title) {
return $query->where('product_details.title', $title);
})
->when($request->id, function ($query, $id) {
return $query->where('product_details.id', $id);
})
->get();
this will not work because you are saving text in string and output will be on string you need to convert it to eval Try This.
$results = DB::table('product_details') . eval ($where) .->get();
I have a search button and pagination system. They are working perfectly. But when i searched something and page was paginated with numbers. After clicking next page. Search query is gone. After that all values are coming into page2. Not searched values.
My search button changing url like this /en/news?q=foo
My pagination is changing url like this(default btw) /en/news?page=2
How can i add this side by side. Or how can i solve the problem. I am open any solution.
I am using scope for search.
public function scopeSearch($query, $search) {
return $query->where('title', 'LIKE', '%' .$search. '%')
->orWhere('sub_body', 'like', '%' .$search. '%')
->orWhere('body', 'like', '%' .$search. '%');
}
Also this is my controller:
public function index (Request $request){
$localeCode = LaravelLocalization::getCurrentLocale();
$updates = Update::latest()->take(3)->get();
$query = $request->get('q');
if ($query){
$new = $query ? News::search($query)->orderBy('id', 'desc')->paginate(10):News::all();
return view('frontend.news', compact('localeCode', 'updates', 'new', 'query'));
}
else
{
$new = News::orderBy('id', 'desc')->paginate(10);
return view('frontend.news', compact('localeCode', 'updates', 'new', 'query'));
}
}
I hope i can express my own.
{{ $users->appends($_GET)->links() }}
that append all your filter value in one line
It is explained in the documentation for displaying pagination results:
Appending To Pagination Links
You may append to the query string of pagination links using the appends method. For example, to append sort=votes to each pagination link, you should make the following call to appends:
{{ $users->appends(['sort' => 'votes'])->links() }}
I find your current code quite confusing. I think you can rewrite it like this
public function index (Request $request){
$localeCode = LaravelLocalization::getCurrentLocale();
$updates = Update::latest()->take(3)->get();
$query = $request->get('q');
$new = $request->filled('q') ? News::search($query) : News::query();
$new = $new->orderBy('id', 'desc')->paginate(10);
return view('frontend.news', compact('localeCode', 'updates', 'new', 'query'));
}
and in the view you'll have to use
{{ $new->appends(['q' => $query])->links() }}
Try to use {{ $collection->appends(request()->all())->links() }}
After some help in a previous post Laravel - Search Facility on site using Eloquent I now need to some help on paginating the result using the built in laravel pagination class.
public function search() //no parameter now
{
$q = Input::get('term');
if($q && $q != ''){
$searchTerms = explode(' ', $q);
$query = DB::table('wc_program'); // it's DB::table(), not DB::tables
if(!empty($searchTerms)){
foreach($searchTerms as $term) {
$query->where('JobRef', 'LIKE', '%'. $term .'%');
}
}
$results = $query->get();
dd($results); // for debugging purpose. Use a View here
}
}
Simply change get to paginate and provide number of items per page.
$results = $query->paginate(10);