Using separate folders in powershell command - image

Question

I'm using Powershell and imagemagick to create a simple code to append images. I need to Powershell to be run from one folder, the input images to be take from a sub-folder, and the output images to be taken from a subfolder of that folder.
For example, the folder structure goes:
\image-converter\Append-images\Appended
So Powershell will be run from the "image-converter" folder, and will open with the directory:
PS
C:\Users\name\Downloads\image-converter>
The input images to be appended will be stored in the folder "Append-images", and the output images will be saved to the folder "Appended".
An example of the command I will be using is:
convert +append input.png input.png output.png
So I would need to modify the command to take the input images from \Append-images and save the output images to \Append-images\Appended.
P.S. I can't use the full "C:\..." path as this will be used by different people and the image-convert folder will be saved in different places. So I need the command to build on the "PS C:\...\image-converter>" path that Powershell will be run from.

Answer 1

How about this.
$scriptPath = split-path -parent $MyInvocation.MyCommand.Definition
Get-Content -path "$scriptPath\Append-images\"
That should give you the location you need to browse the subsequent files.

Answer 2

Use environment variables to get the userprofile, and then your subdirectorys:
$env:userprofile
Will give you your C:\Users\User1
If you want to make the folders, do the following:
mkdir $env:userprofile\images
mkdir $env:userprofile\images\AppendImages
mkdir $env:userprofile\images\Output
And then work with those.