PL/SQL checking if number is Integer - oracle

Question

I want to check my employee table if there is any employee who works as an
employee for exactly one year or two years, or three years, ...
The Problem for me now is that i dont know how i can check if a number is
an integer or not.
CREATE OR REPLACE PROCEDURE jubilar
IS
v_cur_date DATE := TO_DATE('03-JAN-2012');
v_cur_year NUMBER;
v_first_name employees.first_name%TYPE;
v_last_name employees.last_name%TYPE;
v_hire_date employees.hire_date%TYPE;
CURSOR c_emp_cursor IS
SELECT first_name, last_name, hire_date FROM employees;
BEGIN
OPEN c_emp_cursor;
LOOP
FETCH c_emp_cursor INTO v_first_name, v_last_name, v_hire_date;
EXIT WHEN c_emp_cursor%NOTFOUND;
v_cur_year := round((v_cur_date - v_hire_date) / 365, 1);
IF v_cur_year ???
DBMS_OUTPUT.PUT_LINE(v_first_name || ' ' || v_last_name || ' ist heute ' || v_cur_year || ' Jahre im Unternehmen tätig.');
END IF;
END LOOP;
CLOSE c_emp_cursor;
END jubilar;
/
At this line
IF v_cur_year ??
I need to check if v_cur_year is an integer or not. Because if it is the employee
works for exactly X year as an employee. And i need to know that.
EDIT:
I tried this:
CREATE OR REPLACE PROCEDURE jubilar
IS
v_cur_date DATE := TO_DATE('03/01/12', 'dd/mm/yy');
v_cur_year NUMBER;
v_cur_year_temp VARCHAR2(100);
v_first_name employees.first_name%TYPE;
v_last_name employees.last_name%TYPE;
v_hire_date employees.hire_date%TYPE;
CURSOR c_emp_cursor IS SELECT first_name, last_name, hire_date FROM employees;
BEGIN
OPEN c_emp_cursor;
LOOP
FETCH c_emp_cursor INTO v_first_name, v_last_name, v_hire_date;
EXIT WHEN c_emp_cursor%NOTFOUND;
v_cur_year := round((v_cur_date - v_hire_date) / 365, 1);
v_cur_year_temp := TO_CHAR(v_cur_year);
IF REGEXP_COUNT(v_cur_year_temp, ',') = 0 THEN
DBMS_OUTPUT.PUT_LINE(v_first_name || ' ' || v_last_name || ' ist heute ' || v_cur_year || ' Jahre im Unternehmen tätig.' || TO_CHAR(v_hire_date));
END IF;
END LOOP;
CLOSE c_emp_cursor;
END jubilar;
/
But it gives me wrong persons with hire_date for example 17/01/2005
I also tried this:
CREATE OR REPLACE PROCEDURE jubilar
IS
v_cur_date DATE := TO_DATE('03/01/12', 'dd/mm/yy');
v_cur_year NUMBER;
v_first_name employees.first_name%TYPE;
v_last_name employees.last_name%TYPE;
v_hire_date employees.hire_date%TYPE;
CURSOR c_emp_cursor IS SELECT first_name, last_name, hire_date FROM employees;
BEGIN
OPEN c_emp_cursor;
LOOP
FETCH c_emp_cursor INTO v_first_name, v_last_name, v_hire_date;
EXIT WHEN c_emp_cursor%NOTFOUND;
v_cur_year := round((v_cur_date - v_hire_date) / 365, 1);
IF trunc(v_cur_year) = v_cur_year THEN
DBMS_OUTPUT.PUT_LINE(v_first_name || ' ' || v_last_name || ' ist heute ' || v_cur_year || ' Jahre im Unternehmen tätig.' || TO_CHAR(v_hire_date));
END IF;
END LOOP;
CLOSE c_emp_cursor;
END jubilar;
/
But it gives me wrong persons with hire_date for example 17/01/2005

Answer 1

This may help you ..
DECLARE
d1 DATE := TO_DATE ('01/12/12', 'mm/dd/yy');
d2 DATE := SYSDATE;
n1 NUMBER;
chk VARCHAR2 (100);
BEGIN
n1 := ROUND ( (d2 - d1) / 365, 1);
DBMS_OUTPUT.put_line (n1);
chk := TO_CHAR (n1);
DBMS_OUTPUT.put_line (chk);
IF REGEXP_COUNT (chk, '.') != 0
THEN
---YOUR LOGIC
END IF;
END;

Answer 2

To check for employees who are employed exactly two years at e.g. January 14th, you can use this:
select *
from employees
where months_between(DATE '2014-01-14', trunc(hire_date)) / 12 = 2;
(I prefer using ANSI date literals over the to_date() function. Works on multiple DBMS and is less typing)
months_between(...) / 12 will result in a fractional value if it's not exactly one year and therefore the comparison with a non-fractional value will fail.
Just change the comparison date (DATE '2014-01-14') and the condition ( =2) to accommodate for other dates or durations.
SQLFiddle example: http://sqlfiddle.com/#!4/27c3d/4

Answer 3

I would do it like this:
with y as
(select trunc(ADD_MONTHS(SYSDATE, -12 * LEVEL)) as the_date, LEVEL as anniversary
from dual
connect by LEVEL <= 6)
select first_name, last_name, hire_date, anniversary, the_date
join y on the_date = hire_date