I have a list of FAQ links on my home page in a static block in the footer. Each link however just opens up the FAQ page.
My code sample
What is Individually Quick Frozen?</li>
What I want is that when a user clicks a particular link in the list on the homepage footer under FAQs (as above), the user should be directly be taken to the answer of that question on the FAQ page i.e. the page should scroll down to where the questions is answered.
My Code sample
<p><strong><a id="1">What is Individually Quick Frozen?</a></strong></p>
But no joy! what am I doing wrong?
Make your link look like this:
What is Individually Quick Frozen?</li>
or better yet
What is Individually Quick Frozen?</li>
Note: For Cms pages urls use direct_url as a parameter for the {{store}} directive. It avoids having a / at the end of the URL. Useful if your pages end with .html. It's not your case but it may be useful in the future.
Now your code in the cms page should looks like this:
<p><strong><a id="_1">What is Individually Quick Frozen?</a></strong></p>
Avoid using numerical ids for elements. It's not standard
Worked perfectly, be sure to update
<a href="{{store url="faqs"}}#_1">
"faqs" to what ever page you want your tag to land on though.
Related
I have a site with an "About us" page which is divided into multiple sections.
About Us
+Overview
+The Company
+Our services
+Future plans
(etc)
I want to have a floated block on the right hand side of each of these pages which contains links to every other page.
Ideally, what I would like is to create a page titled AboutUsSidebar, and then be able to include this page in all of the about sections through some kind of tag, ie..
{include('Sidebar')}
Is there anything like this in PyroCMS? Or perhaps a better way to do it?
You should use view partials.
Create your sidebar with it's HTML and save it into addons/shared_addons/themes/yourtheme/views/partials/sidebar.html and then you can include it in your layouts as so:
{{ theme:partial name="sidebar" }}
It looks like page types are the way to go, I didn't see the page types button at the top of the page before.
In the end what I was able to achieve the desired result by using a page type.
I have a page type called "About" which contains the sidebar html, then I use pages on top of that page type for each of the sections.
Worked very nicely.
I have a MediaWiki page set up in my company's intranet.
I would like to get the content of a section in a specific page using MediaWiki API (through AJAX).
I would like to refer to the section by its title like 'General' and refer to the page by its title as well, like 'Licenses'.
Is it possible somehow?
The only thing I could achieve is referring to the page by its title and refer to the section by a number like this:
http://mywiki.local/wiki/api.php?format=xml&action=parse&prop=text&page=Licenses§ion=1
But let's say I create a new section before 'General' I would have to update all my AJAX URLs that queries this page. So this isn't good enough.
I couldn't find any working solution for this. Any ideas?
You can do this by first retrieving prop=sections to get the list of sections and their numbers:
http://en.wikipedia.org/w/api.php?format=xml&action=parse&prop=sections&page=License
Then make your original request, with the section number you figured out based on the previous request.
Keep in mind that two different sections can have the same name.
I am setting my blog up using the fantastic Jekyll. Question is my markdown files are being shown in full on the homepage. How do i make them look more like this? So that only a little bit comes up with the title?
Thanks.
http://daverupert.com/
EDIT: As of Jekyll 1.0, this is not longer necessary (Answer is outdated).
Jekyll 1.0 exports a post.excerpt variable that contains the first paragraph of a post by default.
/Edit
So, you want to show an excerpt of the post, instead of the full post?
Theres three ways to do that:
Render the full post but use CSS to hide everything that is not needed
Use filters. You can access post.content, use the truncate filter to truncate it and the markdownify filter to render it.
Specify the excerpt in YAML Front Matter and render it using {{post.excerpt | markdownify}} (that is what i do on my blog)
Each of those blocks between horizontal lines are links to the actual blog post. Any time I have a question about how someone did something on their webpage I always view-source.
The source for that page is -
view-source:http://daverupert.com/
To find out how to do something in markdown I like this site -
http://daringfireball.net/projects/markdown/basics
So I have a website that has just two pages. On the home page, there are some things going on, but are not important. There are some links, however, that will need to link to a specific piece of content on the second page.
On the second page, I have content on there and it's all encased in the jcycle plugin.
What I need to do is if someone is on the homepage and they click on a link, it needs to load up the second page and show the correct "slide" that corresponds to what the homepage link is.
If you need any more clarification, please let me know.
In the cycle options reference, I see that there is a startingSlide option. You could set that dynamically. You could either do it with server-side code, e.g. /foo?slide=3 or you could check which anchor reference was used on the incoming link, e.g. /foo#slide3. Or, you could use DHTML to build the slideshow on the homepage when they click the given link.
Also note that there is a slideExpr option that you could use to filter the slides to a smaller set, depending on what they selected.
I have a page that shows the main product for that page, next to it though are "related products" which when you click on them you go to their page, and they have their own related products as well. The problem is that the related products are getting indexed by Google so when you search for product-A you may get the product-B page where product-A is a related item, instead of just getting the product-A page. I am trying to prevent this. Any ideas?
Thanks!
You can add rel="nofollow" in any links you don't want a bot to crawl. In this case, you can apply that tag to all your links and google won't follow them off your main page.
http://en.wikipedia.org/wiki/Nofollow
EDIT for clarification:
Page "A" is for widgets. You want this page to be returned for searches regarding widgets; on this page is a "related searches" section which links to Other Widgets. On all the anchor tags on page "A" which link to pages "B" and "C" (the related searches for Other Widgets), you'll put a rel="nofollow" tag. This will prevent Google from hitting page A and then following your "related searches" links off to pages "B" and "C".
This will NOT prevent pages "B" and "C" from being indexed on their own, it just prevents them from getting pulled in from page "A".
EDIT#2:
rel="nofollow" tells bots you don't want them to follow the link to the second page. Regardless of the anchor text on a link from A->B, if you've nofollowed it the bot won't "flow" pagerank to the linked-to page and should not follow the link to page "B" to index it due to that tag on the anchor. Note that this is not foolproof: Yahoo and other SE's may not treat nofollow like Google....so your best bet is to make sure that each page is strongly on-page-SEO'd such that it gets included in the index for the term you want it to be included for. Hope this helps...but like much of the SEO world there are few hard-and-fast rules which apply universally.
yes... put them at the bottom of the page for content,
if you want that to appear visually at the top of the page, use a css layout to re-arrange the page elements
also, as darksquid already said, add rel="nofollow" to links you don't want considered
another tip (pertaining to your comment on darksquid's post):
You could load the content via ajax, which would keep most search engine spiders from seeing it at all (since they don't generally execute javascript)
Use Google Applicance - googleoff / googleon Tags:
http://www.geekzilla.co.uk/ViewC8614968-56ED-4729-9C12-F01677DAC412.htm