counting the total numbers of files and directories in a provided folder including subdirectories and their files - shell

Question

I want to count all the files and directories from a provided folder including files and directories in a subdirectory. I have written a script which will count accurately the number of files and directory but it does not handle the subdirectories any ideas ???
I want to do it without using FIND command
#!/bin/bash
givendir=$1
cd "$givendir" || exit
file=0
directories=0
for d in *;
do
if [ -d "$d" ]; then
directories=$((directories+1))
else
file=$((file+1))
fi
done
echo "Number of directories :" $directories
echo "Number of file Files :" $file

Answer 1

Use find:
echo "Number of directories: $(find "$1" -type d | wc -l)"
echo "Number of files/symlinks/sockets: $(find "$1" ! -type d | wc -l)"
Using plain shell and recursion:
#!/bin/bash
countdir() {
cd "$1"
dirs=1
files=0
for f in *
do
if [[ -d $f ]]
then
read subdirs subfiles <<< "$(countdir "$f")"
(( dirs += subdirs, files += subfiles ))
else
(( files++ ))
fi
done
echo "$dirs $files"
}
shopt -s dotglob nullglob
read dirs files <<< "$(countdir "$1")"
echo "There are $dirs dirs and $files files"

Answer 2

find "$1" -type f | wc -l will give you the files, find "$1" -type d | wc -l the directories
My quick-and-dirty shellscript would read
#!/bin/bash
test -d "$1" || exit
files=0
# Start with 1 to count the starting dir (as find does), else with 0
directories=1
function docount () {
for d in $1/*; do
if [ -d "$d" ]; then
directories=$((directories+1))
docount "$d";
else
files=$((files+1))
fi
done
}
docount "$1"
echo "Number of directories :" $directories
echo "Number of file Files :" $files
but mind it: On my build folder for a project, there were quite some differences:
find: 6430 dirs, 74377 non-dirs
my script: 6032 dirs, 71564 non-dirs
#thatotherguy's script: 6794 dirs, 76862 non-dirs
I assume that has to do with the legions of links, hidden files etc., but I am too lazy to investigate: find is the tool of choice.

Answer 3

Here are some one-line commands that work without find:
Number of directories: ls -Rl ./ | grep ":$" | wc -l
Number of files: ls -Rl ./ | grep "[0-9]:[0-9]" | wc -l
Explanation:
ls -Rl lists all files and directories recursively, one line each.
grep ":$" finds just the results whose last character is ':'. These are all of the directory names.
grep "[0-9]:[0-9]" matches on the HH:MM part of the timestamp. The timestamp only shows up on file, not directories. If your timestamp format is different then you will need to pick a different grep.
wc -l counts the number of lines that matched from the grep.