Error in Echo of awk command piped to wc -l - bash

Question

I have hundreds of files containing lines similar to this:
>34764998 Halalkalicoccus_jeotgali_B3 -132.6938 Halalkalicoccus 0.528 Halobacteriaceae 0.638 Halobacteriales 0.648 Halobacteria 0.706 Euryarchaeota 0.850
I am interested in counting the number of items in column 5 that is less than 0.1, ...0.95. I have written a bash script that calls an AWK command to look evaluate the column value then pipe it into wc -l (see below). However, I don't quite have my $, ', and brackets arranged correctly. Can anyone advise me as to what I did incorrectly? This is probably not the most efficient way so I welcome suggestions, but I do want to know what I did wrong with the code I listed.
for fileName in 4440319.3_genus.txt 4440372.3_genus.txt 4440373.3_genus.txt 4440378.3_genus.txt 4440379.3_genus.txt 4440380.3_genus.txt 4440381.3_genus.txt
do
echo $fileName
for number in 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.95
do
#NUM={awk '$5 < '$number' {print $5}' $filename | wc -l}
NUM={awk '$5 < $number {print $5}' $filename | wc -l}
#NUM=${awk '$5 < '$number' {print $5}' $filename | wc -l}
#NUM=${awk '$5 < $number {print $5}' $filename | wc -l}
echo $NUM
done
done
exit 0
All variations yield invalid option errors depending on which line is un-commented.
Thank you very much.

Answer 1

you don't need the wc -l pipe, even don't need the for loop of filename, try this:
awk -v n=0.95 '$5<n{a++}END{print a}' *_genus.txt

Answer 2

Assuming that you're using sh or bash, here's what I'd do:
NUM=`awk -v x=$number '$5 < x {print $5}' $fileName | wc -l`
Some explanation why this works and your attempts do not work:
You need to execute the pipe and store its output in variable NUM. That's why you need the backquotes around the pipe.
Your $number is a shell variable. Shell variable expansion does not take place inside single quotes, so your $number in the awk script has no chance of being substituted with the numbers that you want. To deal with this, you can either use double quotes to embed the number in the right place (this will cause some trouble because of the other dollar signs in the awk script that you don't want to be shell expanded), or you can use an awk variable that is externally initialized. That's what the -v argument does.
Last but not least, you need to fix the lowercase 'N' in filename.

Answer 3

Here I give the full script:
for fileName in 4440319.3_genus.txt 4440372.3_genus.txt 4440373.3_genus.txt 4440378.3_genus.txt 4440379.3_genus.txt 4440380.3_genus.txt 4440381.3_genus.txt
do
echo $fileName
for number in 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.95
do
NUM={awk -v n=$number '$5<n{a++}END{print a}'}
echo "$NUM records is less than $number"
done
done
exit 0