Can I somehow make use of a static class inside sass to style child elements based on a color variable defined?
Let's say I have a class named red, and I want to define a variable called $color: classname; or $color: #ff0000; based on that class.
If class is red then define an existing variable with a custom color so I can reuse that variable everywhere inside my scss files based on what class I have on the container.
Note that I have a limited number of colors that I need, and can define them inside sass.
Is this what you're looking for?
$colors : (red, blue, green); // array of colors
#each $color in $colors {
.#{$color} {
color: $color;
}
}
The output of the above SASS is
.red {
color: red;
}
.blue {
color: blue;
}
.green {
color: green;
}
If I understand correct your problem You could use a class red and extend this class when you need it.
$red: #FF0000;
.red {
color: $red;
}
.div {
#extend .red;
}
I believe what you are trying to do is:
In an example file called "base.scss":
$red: red;/*this could be a HEX, RGB, whatever*/
#import "other"
In the example file called "other.scss":
div
{
color: $red
}
Related
I’m wondering if I can add a ‘counter’ with Sass when using the #each function. I have a list of backgrounds colors and I want to use the #each function to output a class name and a number behind it.
Is there a way with Sass to automatically count and add that into the class name?
$colors: blue, red, green;
#each $color in $colors {
.class- {
background: $color;
}
}
So the output would be:
.class-1 {
background: red
}
.class-2 {
background: blue
}
Etc…
This did the trick for me:
#for $i from 1 through length($colors) {
.class-#{$i} {
background: '#{nth($colors, $i)}';
}
}
Is it possible to manipulate with #content magic variable in SASS?
I would like to replace some stuff in here before output.
Or maybe can I fill some variable with it?
The conclusion is that, I want to make an mixin #important that create both versions. Important, and no-important.
Input
.test {
#include important {
color: red;
text-align: left;
}
}
Expected output
.test {
color: red;
text-align: left;
}
.test-i {
color: red !important;
text-align: left !important;
}
No, you can't. But I quickly wrote you a mixin to make it work. It doesn't accepts multiple properties (yet).
First Note: I changed the mixin it now does accept multiple properties. Here is the Codepen.
Second Note: I updated the mixin adding multiple properties does no longer compile to different classes for each property, instead you get two versions, one without the !important suffix and one with.
This is the mixin:
#function return($state) {
#return if($state == '', '', '-i');
}
#mixin loop($name, $items...) {
#each $item in $items / 2 {
#each $state in ('', '!important') {
$suffix: return($state);
.#{$name}#{$suffix} {
#for $i from 1 through (length($items) / 2) {
#{nth($items, ($i * 2) - 1)}: #{nth($items, ($i * 2))} #{$state};
}
}
}
}
}
This is how you include it:
// #include loop([classname], [property], [value]);
#include loop(whateverClassname, color, red);
This is what it compiles to:
.whateverClassname {
color: red ;
}
.whateverClassname-i {
color: red !important;
}
This is what it now compiles to, when you use multiple properties at once:
#include loop(whateverClassname, color, red, background-color, green, display, flex);
.whateverClassname {
color: red ;
background-color: green ;
display: flex ;
}
.whateverClassname-i {
color: red !important;
background-color: green !important;
display: flex !important;
}
Conclusion: it works as expected and does no longer bloat your CSS.
Hope I could help you at least a little ;-)
I'm trying to create a little overview for all the colors we use in our corporate identity. All our colors have been defined in _settings-colors.scss, and the only reason I need this bit of css is for the library, where the colors need to be listed.
What I have now is as follows:
$colors-brand: color-brand, color-brand-40, color-brand-60, color-brand-70;
.prfx-color {
display: block;
height: 5rem;
width: 100%;
#each $color in $colors-brand {
&--#{$color} {
background-color: #{'$'+$color};
&::after {
content: '$'+$color;
}
}
}
}
These color-brand variables are set in another file which I'm including in this scss file.
The code above outputs this:
.prfx-color {
display: block;
height: 5rem;
width: 100%;
}
.prfx-color--color-brand {
background: $color-brand;
}
.prfx-color--color-brand::after {
content: "$color-brand";
} [...etc]
What I'm after however, is this:
.prfx-color--color-brand {
background: #00ff11; // don't worry, brand is not actually this color
}
The problem I'm having is that the $color-brand variable isn't interpreted as a sass variable anymore, but is a literal value. I need the #hheexx that this variable refers to!
All the solutions I've found so far consist of using two lists, or a key-value pair. In my situation these variables have already been set once, and I want a solution where I don't want to have to manually edit the library if the colors change.
Is this at all possibe, or am I too greedy here?
And I realized I overcomplicated it. You don't need any extra functions because the #each is designed to work with maps and iterating over multiple values.
$cool: blue;
$mad: red;
$colors: (
cool: $cool,
mad: $mad
);
.prfx-color {
#each $key, $val in $colors {
&--#{$key} {
background-color: $val;
&::after { content: "$#{$key}"; }
}
}
}
You could use a map.
Here's a sassmeister playground for you.
$cool: blue;
$mad: red;
$colors: (
cool: $cool,
mad: $mad
);
.prfx-color {
#each $color in map-keys($colors) {
&--#{$color} {
background-color: map-get($colors, $color);
&::after { content: "$#{$color}"; }
}
}
}
I'm trying to make a mixin that will let me create adapted blocks of code depending on what variable name you up in.
$foo: #00A9EC;
#mixin menu-color($color) {
.color-#{$color} a.level2,
.color-#{$color} a.level2:visited {
color: $color;
&:hover {
color: adjust-lightness($color, 10); }
&:active {
color: adjust-lightness($color, -10); } } }
#include menu-color($foo);
outputs:
.color-foo a.level2,
.color-foo a.level2:visited {
color: #00A9EC; }
.color-foo a.level2:hover,
.color-foo a.level2:visited:hover {
color: #20C0FF; }
.color-foo a.level2:active,
.color-foo a.level2:visited:active {
color: #0084B9; }
In sass you can do this using map, you just pass the variable name instead of the variable itself:
$colors: (
-black: #000,
-blue: #088DC6
);
#mixin generateBgColor($colorName) {
.bg-color#{$colorName} {
background-color: map-get($colors, $colorName);
}
}
#include generateBgColor("-blue");
This will generate class:
.bg-color-blue {
background-color: #088DC6;
}
You achieve this also in less with standard variables, just by using curly brackets and double at character:
#blue: #088DC6;
.generate-bg-color(#color) {
.bg-color-#{color} {
background-color: ##color;
}
}
.generate-bg-color(~"blue");
You should not name CSS classes after specific colors. You would regret that. Just think, if you want to make the color red later on, you would need to go back over all your html and change the classes.
The reason we have CSS is so that you don't have to embed style information in the markup.
Use a semantic class the describes the data, not how it is displayed:
$foo: #00A9EC;
#mixin menu-color($name, $color) {
.custom-#{$name} a.level2,
.custom-#{$name} a.level2:visited {
color: $color;
&:hover {
color: adjust-lightness($color, 10); }
&:active {
color: adjust-lightness($color, -10); } } }
#include menu-color(profile, $foo);
And then in your HTML <div class="custom-profile">.
That way, two years from now when you want to make it black, and underlined (or whatever), you don't have to dig through your html and add a new '.underlined-and-black-color` class to all of those elements. You just change your SCSS in one place.
I'm trying to make a SCSS stylesheet easily configurable by defining a set of constants that will be used in a number of mixins and with the Compass library. Ideally, I'd like to be able to do the following:
$item-bgs: linear-gradient(white, black), #ccc;
#mixin some-mixin() {
#include background-with-css2-fallback($item-bgs*);
}
The background-with-css2-fallback is a Compass mixin that accepts up to 10 params. I'm assuming that SASS does not currently support passing a list parameter as the argument list, otherwise Compass would probably use it, but I'm wondering if I can get the $item-bgs list to be the first 2 arguments to the background-with-css2-fallback mixin. Is there a way to do this currently, or is it even planned for SASS in the future?
It may not be supported by SASS natively, but Compass does support passing a list as the first argument to the background-with-css2-fallback mixin. If you look at the source for the mixin, you'll see that it uses a compact function that handles the logic for collapsing the arguments into a single list, whether passed individually or in a single list parameter.
For example, this works fine for me:
#import "compass";
$item-bgs: (linear-gradient(white, black), #ccc);
.test {
#include background-with-css2-fallback($item-bgs);
}
Examples of useing maps as arguments:
Example 1 (list)
#mixin transition($property...){
#if $property {
transition-property: $property;
}
#else {
transition-property: all;
}
transition-timing-function: ease-in-out;
transition-duration: .3s;
transition-delay: 0;
}
.btn {
color: black;
border: 1px solid black;
#include transition(color, border-color);
&:hover {
color: red;
border-color: red;
}
}
Example 2 (Custom params)
#use 'sass:meta';
#mixin example2($args...) {
#each $key, $value in meta.keywords($args) {
#{$key}: #{$value};
}
}
.shape {
#include example2($width:200px, $height:100px);
}
Example 3 (map)
#mixin colors($args:()) {
#if length($colors) > 0 {
#each $key, $val in $args{
.txt-#{$key} {
color: #{$value};
}
.bg-#{$key} {
background-color: #{$value};
}
}
}
}
$colors_map: (
primary: blue,
secondary: green,
accent: red,
light: white,
dark: black
);
#include colors($colors_map);