valence desire 2 learn profile image upload error 404 - image

Question

I'm trying to upload an image profile using the api but I'm getting a Unknown: NOT_FOUND 404 error. the call I am using is POST /d2l/api/lp/1.3/profile/(profileId)/image, I am passing the content type, length and filename (profileImage). I'm passing the image as a dataStream. I've reduced the size of the image as well. Any ideas?
public static void UploadFilesToRemoteUrl(string file, string logpath, NameValueCollection nvc, ID2LUserContext userContext, string accion)
{
var uri = userContext.CreateAuthenticatedUri(accion, "POST");
string boundary = "bde472ff1f1a46539e54e655857c27c1";
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
request.ContentType = "multipart/form-data; boundary=" +
boundary;
request.Headers.Add("Accept-Encoding", "gzip, deflate, compress");
request.Method = "POST";
request.KeepAlive = true;
request.Proxy.Credentials = new NetworkCredential(Constantes.UsuarioProxy, Constantes.PasswordProxy, Constantes.DominioProxy);
Stream memStream = new System.IO.MemoryStream();
byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +
boundary + "\r\n");
string formdataTemplate = "\r\n--" + boundary +
"\r\nContent-Disposition: form-data; name=\"profileImage\"; filename=\"profileImage.png\" \r\nContent-Type: image/png\r\n";
byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formdataTemplate);
memStream.Write(formitembytes, 0, formitembytes.Length);
// Read image File *************************************************************
FileStream fileStream = new FileStream(file, FileMode.Open,FileAccess.Read);
byte[] buffer = new byte[1024];
int bytesRead = 0;
while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
{
memStream.Write(buffer, 0, bytesRead);
}
fileStream.Close();
//*****************************************************************************
//*********** End Read image file *********************************************
memStream.Write(boundarybytes, 0, boundarybytes.Length);
request.ContentLength = memStream.Length;
Stream requestStream = request.GetRequestStream();
memStream.Position = 0;
byte[] tempBuffer = new byte[memStream.Length];
memStream.Read(tempBuffer, 0, tempBuffer.Length);
memStream.Close();
requestStream.Write(tempBuffer, 0, tempBuffer.Length);
requestStream.Close();
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
StreamReader reader = new StreamReader(response.GetResponseStream(), Encoding.UTF8);
string responseValence = reader.ReadToEnd();
}

Answer 1

It seems most likely that the 404 is coming either from
The API route you're providing (and the back-end service cannot match your API route to a handler method): this could be because of an incorrect profileId value, or a mis-typed route, or an incorrect API version number in the route, and so forth.
That for some reason the back-end service is accepting your profile image data but then unable to assign it to the user's profile.
Here's a capture of some request/response details of what an uploaded profile image packet looks like. When uploading a profile image to "my profile", I use an HTTP header that gets built from these values:
{'Content-Length': '75143',
'User-Agent': 'python-requests/2.2.1 CPython/3.3.3 Darwin/12.5.0',
'Content-Type': 'multipart/form-data; boundary=bde472ff1f1a46539e54e655857c27c1',
'Accept': '*/*',
'Accept-Encoding': 'gzip, deflate, compress'}
Note that this is a multipart/form-data content body, with a boundary marker around a single body part. The body content for the request looks like this:
--bde472ff1f1a46539e54e655857c27c1
Content-Disposition: form-data; name="profileImage"; filename="profile_img-225x225.png"
[actual PNG bytes here]
--bde472ff1f1a46539e54e655857c27c1--
The name property in the Content-Disposition header must be profileImage, and the filename property should be named after the local filename you're using to provide the content (so, as far as the back-end service is concerned, it's value is not particularly relevant).
Finally, there are particular role permissions at play that permit a user to edit someone else's profile image, so you should ensure that your calling user context for the API call has permission to edit someone else's image.

Answer 2

Fixed. This code works correctly:
public static void UploadFilesToRemoteUrl(byte[] profileImage, ID2LUserContext userContext, string accion)
{
//Reference:
//action = "/d2l/api/lp/1.3/profile/" + profileIdentifier + "/image";
//profileImage = the profileImage of user read from disk:
/*
FileStream fileStream = new FileStream(pictureLocalPath, FileMode.Open, FileAccess.Read);
Byte[] img = new Byte[fileStream.Length];
fileStream.Read(img, 0, Convert.ToInt32(img.Length));
fileStream.Close();
*/
var uri = userContext.CreateAuthenticatedUri(accion, "POST");
string boundary = "bde472ff1f1a46539e54e655857c27c1";
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
request.ContentType = "multipart/form-data; boundary=" +
boundary;
request.Headers.Add("Accept-Encoding", "gzip, deflate, compress");
request.Method = "POST";
request.KeepAlive = true;
request.Proxy.Credentials = new NetworkCredential(Constantes.UsuarioProxy, Constantes.PasswordProxy, Constantes.DominioProxy);
Stream memStream = new System.IO.MemoryStream();
byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +
boundary + "\r\n");
string formdataTemplate = "\r\n--" + boundary +
"\r\nContent-Disposition: form-data; name=\"profileImage\"; filename=\"profileImage.jpg\"\r\nContent-Type: image/jpeg;\r\n\r\n";
byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formdataTemplate);
memStream.Write(formitembytes, 0, formitembytes.Length);
//escribo el array de byte de la imagen
memStream.Write(profileImage, 0, profileImage.Length);
byte[] boundaryClose = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--");
memStream.Write(boundaryClose, 0, boundarybytes.Length);
StreamReader readerReq = new StreamReader(memStream);
string stringReq = readerReq.ReadToEnd();
request.ContentLength = memStream.Length;
Stream requestStream = request.GetRequestStream();
memStream.Position = 0;
byte[] tempBuffer = new byte[memStream.Length];
memStream.Read(tempBuffer, 0, tempBuffer.Length);
memStream.Close();
requestStream.Write(tempBuffer, 0, tempBuffer.Length);
requestStream.Close();
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
StreamReader reader = new StreamReader(response.GetResponseStream(), Encoding.UTF8);
string responseValence = reader.ReadToEnd();
response.Close();
}
}