Awk Bash If-Else Issue - bash

Question

I have a problem of being unable to printout a error message if 0 records are found.
this is what I have as of now.
function search_title
{
awk -F':' -v search="$Title" '$2 ~ search { i++;} END { printf "%d records found\n", i }' test.txt
awk -F':' -v search="$Title" '$2 ~ search { i++; printf "%s, %s,%s,%s,%s\n", $1, $2, $3, $4, $5 } END {}' test.txt
}
function search_author
{
awk -F':' -v search="$Author" '$2 ~ search { i++;} END { printf "%d records found\n", i }' test.txt
awk -F':' -v search="$Author" '$2 ~ search { i++; printf "%s, %s,%s,%s,%s\n", $1, $2, $3, $4, $5 } END {}' test.txt
}
function search_both
{
awk -F':' -v search="$Title" -v search1="$Author" '$1 ~ search && $2 ~ search1 { i++;} END { printf "%d records found\n", i }' test.txt
awk -F':' -v search="$Title" -v search1="$Author" '$1 ~ search && $2 ~ search1 { i++; printf "%s, %s,%s,%s,%s\n", $1, $2, $3, $4, $5 } END {}' test.txt
}
read -p $'Title: ' Title
read -p $'Author: ' Author
if [ "$Title" == "" ];
then
search_author
elif [ "$Author" == "" ];
then
search_title
else
search_both
fi
I need a if else statement to check if the counter is 0 in awk print out "Error! Book does not exist"
For example,
Title input as DAFT
Author input as Linken
(Both value not in test.txt)
"Error! Book does not exist"
instead of the printf now which is "0 Record Found"

Answer 1

You don't need 2 awk command in each function:
You can combine both awk in one command:
awk -F':' -v search="$Title" -v search1="$Author" '$1 ~ search && $2 ~ search1 {
i++;
printf "%s, %s,%s,%s,%s\n", $1, $2, $3, $4, $5;
}
END {
if (!i)
print "Error! Book does not exists!";
else
printf "%d records found\n", i;
}' test.txt