We have to load two controller from an another controller class.
The source is like this:
public function index()
{
/** Laodning the Twitter Controller for the Twitter Feed **/
$this->load->controller('twitter', 'twitter_controller');
$data['twitter_feed'] = $this->twitter_controller->fetchAll();
echo '<pre>';
print_r($data['twitter_feed']);
echo '</pre>';
/** Loading the News Controller to get the Latest News **/
$this->load->controller('news', 'news_controller');
$data['news'] = $this->news_controller->get_latest_news();
The twitter controller is getting loaded but not able to load the news controller.
you can use redirect function instead, try
redirect("controller_name/function_name","refresh");//this code is using header function of php, it simple get the base_url+1st parameter.
hope this will help you
Related
Okay, so i have pages controller and user_authenticator controller.
pages controller is like a terminal to my views whilst the user_authenticator controller does the functions that relates to users like registration/logging in.
Whenever i'm done with a function in user_authenticator say for example logging in, how do i load the views via pages controller?
Login->user_auth(controller)->acc_model(model)->user_auth(controller)->view.
to
Login->user_auth->acc_model->pages(controller)->view.
It would be a boon for me if you guys can tell me if what i'm doing is impractical and a better way to do things. Or maybe i should just stick to loading views on the controller i used previously.
EDIT: so i may have forgotten the purpose of my pages controller but i remembered due to a moment of clarity from my foggy and tired mind.
I made a pages controller solely to load views, i guess in a sense, pages won't be loading ALL view but atleast most of the views, for example, if i had links in my views to other views, i would link them via the pages.
For specific functions that need specific controllers i guess i can let them handle loading some views.
Then again, if someone could tell me what i'm doing is a waste of time and should just delete pages controller please tell me so, i'd like to know why.
also if you have any suggestions for further uses of my pages controller thatd be great!
Also regarding session. I have a base controller.
<?php
class MY_Controller extends CI_Controller {
public function __construct()
{
parent::__construct();
}
public function is_logged_in($data){
$session = $this->session->userdata();
if($session['isloggedin']['username'] == ''){
return isset($session);
}else{
return FALSE;}
}
}
?>
How do i make it so that it automatically runs and checks for every controller i load if there are any session set?
Do i have to put it into a constructor? or do i have to call the base controller method from all controllers?
Here is the best solution for you.
You can use Hooks
Step1:
application/config/config.php
$config['enable_hooks'] = TRUE;//enable hook
Step2:
application/config/hooks.php
$is_logged_in= array();
$is_logged_in['class'] = '';
$is_logged_in['function'] = 'is_logged_in';//which function will be executed
$is_logged_in['filename'] = 'is_logged_in.php';//hook file name
$is_logged_in['filepath'] = 'hooks';//path.. default
$is_logged_in['params'] = array();
$hook['post_controller_constructor'][] = $is_logged_in;//here we decare a hook .
//the hook will be executed after CI_Controller construct.
//(also u can execute it at other time , see the CI document)
Step3:
application/hooks/is_logged_in.php //what u decared
<?php
//this function will be called after CI controller construct!
function is_logged_in(){
$ci =& get_instance();//here we get the CI super object
$session = $ci->session->userdata();//get session
if($session['isloggedin']){ //if is logged in = true
$ci->username = 'mike';//do what you want just like in controller.
//but use $ci instead of $this**
}else{
//if not loggedin .do anything you want
redirect('login');//go to login page.
}
}
Step4:application/controller/pages.php
<?php
class pages extends CI_Controller{
function construct ........
function index(){
echo $this->username;//it will output 'Mike', what u declared in hook
}
}
Hope it will help u.
I'm trying to generate ajax specific responses from my controllers by using the Request::ajax() method, which is working just fine. The only problem is that the way I have it set up right now isn't really a nice looking solution.
My controller:
class HomeController extends BaseController {
protected $layout = 'layouts/main';
public function __construct()
{
$this->beforeFilter('auth');
}
public function getIndex()
{
$view = View::make('content.home.index');
if(Request::ajax()) return $view; //For ajax calls we only want to return the content to be placed inside our container, without the layout
$this->layout->menu = 'content.menu';
$this->layout->content = $view;
}
}
So right now, for every method I define within my controllers I need to add the code snippet that checks for an AJAX request and returns a single view if the statement returns true.
This leads to my question that is probably more PHP related than it is to the framework;
Is there a way of executing my AJAX check on every method call, without actually placing it inside the method? Or is there some other solution to keep my code DRY?
Thanks in advance!
PS: This is my first post on stackoverflow, so feel free to correct me if I made any mistakes
Create a new barebone layout named 'layouts/ajax' (or any name you like).
<?php echo $content ?>
In your Base controller, override this setupLayout() function.
protected function setupLayout()
{
if ( ! is_null($this->layout))
{
$layout = Request::ajax() ? 'layouts/ajax' : $this->layout;
$this->layout = View::make($layout);
}
}
Change your getIndex() function to this.
public function getIndex()
{
$view = View::make('content.home.index');
$this->layout->menu = 'content.menu';
$this->layout->content = $view;
}
Now non-ajax requests will be rendered using layout set in the controller, where as ajax requests will receive whatever set to $this->layout->content.
Note : Controller will neglect the layout setup in setupLayout(), if the called method returns truthy value. So this method will not work for functions like below.
public function getIndex()
{
return View::make('content.home.index');
}
You could just change the layout property, in the constructor, if it's an ajax request:
public function __construct()
{
$this->beforeFilter('auth');
if(Request::ajax()) {
$this->layout = '';
}
}
If it doesn't work try setting it to NULL instead.
Why would you return a VIEW via ajax? Are you using it to create a SPA? If so there are better ways. I'm generally against returning HTML via AJAX.
The route I'd go in your position is probably opposite of how you're doing it. Render the view no matter what, if the request is ajax, pass the extra data back and have JS render the data on the page. That's essentially how most Javascript MVC frameworks function.
Sorry if I am totally missing the point here, just going on an assumption of your end goal with the info you provided.
Till now i am using the form post method like this::
controller ::
public function loading_view()
{
.
.
.
.
$this->load->view('abc');
}
view abc:
">
when this form posted it will redirected to
public function method_of_controller()
{
.
//perform query
.
// here i am havin 2 way to call
//1.
$this ->load->view('abc');
//and 2.
load->loading_view();
}
//bu url remain same after the post method like ....index.php/loading_view
and but on reloading the page again the query runs fr 2nd method of loading view
so which way you will suggest me to use best
1- If you are not passing data to your view and your view is just contains html and javascript
than first method is beter.
2- if you are passing data to our abc view page than second is beter.
3- beter way is to make another view for this part for portability
because in some point you will reach you make changes so it is beter to each should be
separate.
yes you can post data to save view, without changing url redirection, in following way
controller
class PostTest extends CI_Controller{
public function loading_view()
{
$this->form_validation->rules('name','Name','required');
if(!$this->form_validation->run()){
$this->load->view('abc');
}
else{
$name = $this->input->post('name');
}
}
}
now here is most interesting part is view in form action you need to use uri_string() method like this
view
<? echo form_open(uri_string())
.form_input('name').br()
.form_error('name')
.form_submit('submit','Post data');
?>
I have an ajax method which sends data to one of my controller but the method inside of my controller is not getting fired. Everytime the first method is getting executed on call. The controller looks as it follows
class TieraerzteControllerUploader extends JController
{
/**
* display task
*
* #return void
*/
function display($cachable = false)
{
require_once JPATH_COMPONENT_ADMINISTRATOR.'/helpers/upload.php';
$upload_handler = new UploadHandler();
//this one is going to be outputed
die();
}
public function locator(){
// I wait here for a dump, but is not happening
var_dump('test');
die();
echo '{"text":"John Smith","id":"433"},{"text":"Paul Sparks","id":"434"}';
}
}
I call the controller with the following url
/administrator/index.php?option=com_tieraerzte&task=uploader.locator&tmpl=component&q=search
even if I call the above url the result is the same
I think you are using wrong formated joomla url.
Try this url formate,u may call the controller
index.php?option=com_tieraerzte&view=uploader&tmpl=component&q=search
watch the difference between your url and my url.
I have a table of data from a database that I want to display on various pages of my website. Ideally, i would like to just have an include or something that will go off and get the data, and return the html table. The html and data will be identical everytime I need to use this.
I wanted to know the best way of doing this
Thanks
EDIT
If this helps, something similar to a Django "inclusion" custom tag...for any django developers reading
you need to pass the variable $data to the view method.
This is your code:
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view');
}
Please change it to this in order to load the $data into the view:
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view',$data);
}
You should use a function in a model to fetch the data you need. Your controller calls the model function and sends the returned information to a view. You don't need to use traditional php includes with Codeigniter. I recommend a review of the user guide. It's very good and will tell you all the basic stuff you need to know to develop with CI. But to get you started, you watn to use Models, Views, and Controllers. Your url will tell CI what controller and function inside that controller to run. If your url is
http://www.example.com/my_controller/load_my_view
Then CI will do what is inside the load_my_view function in the my_controller controller. function load_my_view in turn instantiates a model "my_table" and runs a database query, returns information that the controller sends to the view. A basic example follows:
Your model
class my_table extends CI_Model{
function my_data(){
$this->db->select('column_1,column_2,column_3');
$this->db->from('my_table');
$query = $this->db->get();
if($query->num_rows()>0){
$result = $query->result();
}
else{
$result = false;
}
return $result;
}
}
Your controller
class my_controller extends CI_Controller{
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view');
}
}
Your View
<ul id = "my_db_results">
<?php foreach($my_results as $result):?>
<li><?php echo $result->column_1." : ".$result->column_2." ( ".$result->column_3." )";?></li>
<?php endforeach;?>
</ul>
It looks like a good oportunity to use cache: http://codeigniter.com/user_guide/libraries/caching.html
Ok, so here is one thing that worked for me, but its definitely not perfect.
I created a view in which made a call to the model getting the data then put the data into a table. This way, I only have to include this view to put the table anywhere.
I understand this completely ruins the point of having a MVC framework, but hopefully it demonstrates what I want to do...and it works