I am new to spring and creating simple two page web app that will go to specified link from index page. here is my web.xml.
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<filter>
<filter-name>indexFilter</filter-name>
<filter-class>filter.indexFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>indexFilter</filter-name>
<url-pattern>/index.htm</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<listener>
<listener-class>listener.listenerDB</listener-class>
</listener>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
And here is the index.jsp
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Welcome to Spring Web MVC project</title>
</head>
<body>
<form action="home.htm" method="get">
<input type="submit" value="Submit"/>
</form>
</body>
</html>
Code for dispatcher-servlet is like:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<bean class="org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter" />
<bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping" />
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />
<context:component-scan base-package="controller"/>
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
<prop key="login.htm">loginController</prop>
<prop key="home.htm">homeController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
<bean name="loginController" class="org.springframework.web.servlet.mvc.ParameterizableViewController" p:viewName="login" />
<bean name="homeController" class="org.springframework.web.servlet.mvc.ParameterizableViewController" p:viewName="home" />
</beans>
My controller class is myController.java that looks like:
package controller;
import java.io.IOException;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.List;
import java.util.logging.Logger;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.jboss.weld.logging.LoggerFactory;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.portlet.ModelAndView;
/**
*
* #author rajkumar
*/
#Controller
#RequestMapping("/home")
public class homeController {
#RequestMapping(method=RequestMethod.GET)
public void homeManage(HttpServletRequest req,HttpServletResponse res) throws SQLException, ServletException, IOException{
System.out.println("Raj");
}
}
Finally home.jsp is:
<%# taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%# taglib prefix="f" uri="http://java.sun.com/jsp/jstl/core"%>
<%#page contentType="text/html" pageEncoding="UTF-8" %>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
Hiii
<f:forEach var="element" items="${deptInfo}" varStatus="i">
<c:out value="${element['dept_id']}" />
</f:forEach>
</body>
</html>
When I run this web app as per my knowledge it should print "Raj" to the console but it doesn't print it. I have also tried to debug the app but still it is not going to the controller class.
Is there any mistake for mapping controller?
change your controller to:
*all other imports
import org.springframework.web.servlet.ModelAndView;
#Controller
public class homeController {
#RequestMapping("/home")
public ModelAndView homeManage(HttpServletRequest req,HttpServletResponse res) throws SQLException, ServletException, IOException{
System.out.println("Raj");
return new ModelAndView("home");
}
}
Related
My flow is not forwarded to my controller..And I am getting a warning like:
org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/Spectrum_Inverntory/hello] in DispatcherServlet with name 'dispatcher'
-This is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID"
version="2.5">
<display-name>Spectrum_Inventory</display-name>
<welcome-file-list>
<welcome-file>welcome.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-
class>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
-And this is dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<mvc:annotation-driven/>
<context:component-scan base-package="com.spectrum" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass">
<value>org.springframework.web.servlet.view.JstlView</value>
</property>
<property name="prefix"><value>/</value></property>
<property name="suffix"><value>.jsp</value></property>
</bean>
<bean id="properties"
class="org.springframework.beans.factory.config.
PropertyPlaceholderConfigurer">
<property name="location">
<value>WEB-INF/mysql.properties</value>
</property>
</bean>
</beans>
**
- InventoryController.java
**
package com.spectrum.controller;
import javax.servlet.http.HttpServletRequest;
import org.springframework.context.annotation.Scope;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
#RequestMapping(value = "/Spectrum_Inverntory")
public class InventoryController {
#RequestMapping(value="/hello")
public String viewProducts(Model model,HttpServletRequest request){
return "index";
}
}
welcome.jsp
<%# page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>index here</title>
</head>
<body>
hiiiii
<jsp:forward page="hello"></jsp:forward>
</body>
</html>
It is going upto
but not hitting my controller... Please help
I am unable to know the exact reason for it.
My flow is not going in my controller..And I am getting a warning like :
org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/Spectrum_Inverntory/hello] in DispatcherServlet with name 'dispatcher'
My security xml is ::
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<security:http auto-config="true">
<security:intercept-url method="POST" pattern="/admin**" access="ROLE_USER" />
<security:http-basic />
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="user" password="pass" authorities="ROLE_USER" />
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>
I am using spring-security 3.2.xsd. In this application it should prompt for login while accessing the /admin pages. But it is directly going to the /admin pages without the authentication.
Please specify me where i am wrong.
My dispatcher servlet :::
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.suva.*" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
My web.xml is::::
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring MVC Application</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<!-- Loads Spring Security config file -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name >
<url-pattern>/**</url-pattern>
</filter-mapping>
</web-app>
My controller class ::
*
package com.suva.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class HelloController {
#RequestMapping(value = { "/", "/welcome**" }, method = RequestMethod.GET)
public ModelAndView welcomePage() {
ModelAndView model = new ModelAndView();
model.addObject("title", "Spring Security Hello World");
model.addObject("message", "This is welcome page!");
model.setViewName("hello");
return model;
}
#RequestMapping(value = "/admin**", method = RequestMethod.GET)
public ModelAndView adminPage() {
ModelAndView model = new ModelAndView();
model.addObject("title", "Spring Security Hello World");
model.addObject("message", "This is protected page!");
model.setViewName("admin");
return model;
}
}
The JSP files::
hello.jsp ::
*
<%# page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%#page session="false"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<h1>Title : ${title}</h1>
<h1>Message : ${message}</h1>
</body>
</html>
*
admin.jsp
<%#taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<%#page session="true"%>
<html>
<body>
<h1>Title : ${title}</h1>
<h1>Message : ${message}</h1>
<c:if test="${pageContext.request.userPrincipal.name != null}">
<h2>Welcome : ${pageContext.request.userPrincipal.name}
<a href="<c:url value="/j_spring_security_logout" />" > Logout</a></h2>
</c:if>
</body>
</html>
Thats it nothing else.. please help me find out where i am wrong
The problem can be solved simply by changing the following in your web.xml
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name >
<url-pattern>/*</url-pattern>
</filter-mapping>
I have created a Spring application using netbeans, I did not change any of configuration. In index.jsp I have a link to another page but it does not get to the second page and shows "The requested resource () is not available."
in the server console it shows the following warning
"WARNING: No mapping found for HTTP request with URI [/Myapp/emp.htm] in DispatcherServlet with name 'dispatcher'"
my emp.jsp file is in jsp folder.
index.jsp
<%#page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Welcome to Spring Web MVC project</title>
</head>
<body>
emp
</body>
</html>
dispatcher-servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
<bean name="/emp.htm" class="controller.Employee"/> <<I changed this to "/Myapp/emp.htm" as well but does not work
</beans>
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
</web-app>
Employee.java
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package controller;
import org.springframework.web.servlet.mvc.Controller;
import org.springframework.web.servlet.ModelAndView;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import java.io.IOException;
public class Employee implements Controller {
protected final Log logger = LogFactory.getLog(getClass());
#Override
public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
logger.info("Returning hello view");
return new ModelAndView("emp.jsp");
}
}
Change the <a href> to get the actual url like this
<a href="<c:url value="/emp"/>" />
Also make sure that the Dispatcher servlet is mapped in your web.xml
<servlet>
<servlet-name>DispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>DispatcherServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
More about Spring MVC implementation can be found here
I've solved it by adding
<prop key="emp.htm">empController</prop>
and
<bean name="empController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="emp" />
#Daniel
Yes, I can see that emp.jsp is a simple message jsp. The thing is this is how MVC pattern works(no thing to do with Spring). MVC is all about having a dispatcher sitting in front of all request and route the request to proper resources(e.g. controller,servlet, etc)
If the message in the jsp is dynamic generated, I reckon the request should go through a controller and forwarded to emp.jsp. If the whole point of emp.jsp is just some kinda of static page, you can put emp.js under webapp/static/emp.jsp and in your spring servlet configuration file indicate that everything under /static should by pass Spring ServletDispatcher.
The configuration file will look like this
<mvc:resources mapping="/static/**" location="/static/" />
By doing so, the request /static/emp.jsp will work and do not go through Spring DispatcherServlet.
In the following program, if I replace "/home.htm" with "/home.jsp" in dispatcher-servlet.xml and index.jsp, then the server is not able to find home.jsp. Are strings ending with ".jsp" invalid as bean name?
dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task-3.0.xsd">
<bean id="handlerMapping" class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/>
<bean name="/home.htm" class="com.sample.HomePageController" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
index.jsp
<%# page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>Dynamic Tiles</title>
</head>
<body>
<form action="/home.htm" method="post">
Please enter your name:
<input type="text" name="visitorName" />
<input type="submit" value="Go"/>
</form>
</body>
</html>
HomePageController.java
package com.sample;
import org.apache.log4j.Logger;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractController;
public class HomePageController extends AbstractController {
private static Logger logger = Logger.getLogger(HomePageController.class);
HomePageController () {
logger.info("Constructing HomePageController object");
};
public ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception {
logger.info("Handling request for home.jsp");
return new ModelAndView("home", "visitorName", request.getParameter("visitorName"));
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
</web-app>
There are several pieces of your application that need to be modified for it to work as intended. The first piece is the Dispatcher Servlet mapping in web.xml. In Spring the dispatcher is used to route particular requests from the client to Spring controllers within the application. What requests are routed via the dispatcher is determined by the url-pattern specified in the web.xml file for the servlet: org.springframework.web.servlet.DispatcherServlet.
In your case we want to set the url-pattern to something that does not conflict with accessing your jsp files. Since you have specified a viewResolver in your Spring configuration that prefixes generic names with /WEB-INF/jsp/ and suffixes them with .jsp, we must use a url-pattern other than .jsp.
If the .jsp url-pattern were used, a request would first be processed by the dispatcher servlet and routed to any mapped controller. If the controller attempts to use a view name to navigate to another page, for example, home, the view name is prefixed/suffixed resulting in a url: /WEB-INF/jsp/home.jsp. This constructed URL matches the .jsp url-pattern specified for the dispatcher and an attempt to route /WEB-INF/jsp/home.jsp is made, most likely failing because no mapping is found.
To remedy this problem we setup your web.xml as follows:
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
</web-app>
As you can see, we map the dispatcher to the url-pattern *.do. This allows the dispatcher to be used to route requests without interference with common file prefixes.
Changing the url-pattern to *.do requires us to change the action on your form. I modified your form to the following:
Index.jsp
<%# page contentType="text/html;charset=UTF-8" language="java"%>
<html>
<head>
<title>Dynamic Tiles</title>
</head>
<body>
<form action="home.do" method="post">
Please enter your name: <input type="text" name="visitorName" />
<input type="submit" value="Go" />
</form>
</body>
</html>
I also assumed that all of your .jsp files are located within the WEB-INF directory. This requires us to use a controller to access each of these .jsp files. Mappings to the controllers must be created in your Spring configuration file for the dispatcher and the appropriate controller for index.jsp must be created. Notice that I am using the .do suffix for the mappings.
dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="handlerMapping"
class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping" />
<bean name="/home.do" class="com.sample.HomePageController" />
<bean name="/index.do" class="com.sample.IndexPageController" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
IndexPageController.java
package com.sample;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractController;
public class IndexPageController extends AbstractController {
#Override
protected ModelAndView handleRequestInternal(HttpServletRequest arg0,
HttpServletResponse arg1) throws Exception {
return new ModelAndView("index");
}
}
Just to be thorough, I created a home.jsp file to test the application since one was not provided. Here is my home.jsp file:
Home.jsp
<%# taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%# page session="false" %>
<html>
<head>
<title>Home</title>
</head>
<body>
<h1>
Hello, ${visitorName}
</h1>
<P> The time on the server is ${serverTime}. </P>
</body>
</html>
You decided that dispatcher would only handle .htm-ended urls but then you want it to handle .jsp-ended url. For the latter to work just change url-pattern element's content in web.xml to, for example, something like this:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.jsp</url-pattern>
</servlet-mapping>
I'm trying to build an application using Spring MVC and Maven 3.0 within Eclipse using the webapp. I'm not able to get to the initial page, or navigate to any other pages from there w/out getting a 404 error. Please let me know if there's something I'm missing. Thanks!
mvc-dispatcher.xml
<?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:jdbc="http://www.springframework.org/schema/jdbc" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/jdbc
http://www.springframework.org/schema/jdbc/spring-jdbc-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<context:component-scan base-package="se.guards.controller" />
<mvc:resources mapping="/resources/**" location="/resources/" />
<mvc:annotation-driven />
<context:annotation-config />
<!-- show pictures -->
<mvc:default-servlet-handler />
<!-- also add the following beans to get rid of some exceptions -->
<bean
class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />
<bean
class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping">
</bean>
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/views/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="messageSource"
class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basenames">
<list>
<value>mymessages</value>
</list>
</property>
</bean>
web.xml
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring MVC Application</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.js.resource.ResourceServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/mvc-dispatcher-servlet.xml,
/WEB-INF/spring-database.xml,
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
database.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/test" />
<property name="username" value="root" />
<property name="password" value="password" />
</bean>
userController.java
package se.guards.controller;
import java.util.ArrayList;
import java.util.Collection;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import se.datalayer.guards.service.UserService;
import se.guard.User;
#Controller
#RequestMapping(value="/")
public class UserController
{
#SuppressWarnings("unused")
#Autowired
private UserService userService;
#RequestMapping(value = "/", method = RequestMethod.GET)
public String findAllUsers(Model model){
Collection<User> userList= new ArrayList<User>();
model.addAttribute("users", userList);
return "showallusers";
}
}
showallusers.jsp
<%# page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%# taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<%# taglib uri="http://java.sun.com/jsp/jstl/fmt" prefix="fmt"%>
<%# taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4 /loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>found users</title>
</head>
<body>
<table>
<c:forEach var="allusers" items="${users}">
<tr>
<td>${allusers.firstname}</td>
<td>${allusers.lastname}</td>
</tr>
</c:forEach>
</table>
</body>
</html>
Answer to the questions:
This is the code I'm using.
The #Controller annotation must be there.
As I said before I get :
HTTP Status 404 - /guard_weblayer/ type Status report message /guard_weblayer/
description The requested resource (/guard_weblayer/) is not available.
Apache Tomcat/7.0.25
I use a restfule design, a domainlayer, datalayer and weblayer. Can it effecting the weblayer?
You might want to start over and use an example from springbyexample. It contains everything you need in a understandable fashion (and its in maven as well.)
Most likely that's easier than debugging the current code.