Webform validation message is not displaying - validation

I'm new in drupal 7, and I have to work on an existing project
i want to display a validation message of a webform.
In my custom node.tpl i have a webform with a unique validation on the email, but it's don't show any error message.
I think it was stored in "$messages", but nope.
How can i do this ?
Thanks.

Wow that was easy, but so hard to fine ...
so here is my solution :
<ul style="color:red;">
<?php
foreach (form_get_errors() as $key => $value) {
?>
<li>
<?= $value ?>
</li>
<?php
}
?>
</ul>
<?php

Related

Laravel paginator an all pages

I have an paginator that I use for my forum.
The problem is, when I include this, it displays on every page, including the pages that doesn't need to have the pagination jet.
How Can I fix this?
Now I have this to display my pagination:
{{ $comments->links() }}
I guess that you changed the default view for a paginator to your own - because Laravel hides pagination when it isn't needed.
This is how Laravel handles this:
<?php
$presenter = new Illuminate\Pagination\BootstrapPresenter($paginator);
?>
<?php if ($paginator->getLastPage() > 1): ?>
<ul class="pagination">
<?php echo $presenter->render(); ?>
</ul>
<?php endif; ?>
you can find it in:
vendor/laravel/framework/src/Illuminate/Pagination/views/slider-3.php

not working login form to display error in model window after server side validation in yii

I have a login form in modules which uses a chtml textfield which using jQuery does client side validation but if the user does not exist and enters both fields it redirect to the login url and does not display the error in a modal popup.
I am calling modules login via ajax in main layout. It can be in any page and calls the login perfectly.
but the only thing not WORKING is server side validations if login credentials are wrong. It redirects to the user/login page and not display the server side validation error in the modal window.
<?php echo CHtml::beginForm(); ?>
<div class="row1">
<?php echo CHtml::activeTextField($model,'username',array('placeholder'=>'Username or Email','class'=>'pclas')) ?>
</div>
<div class="row1">
<?php echo CHtml::activePasswordField($model,'password',array('placeholder'=>'Password','class'=>'pclas')) ?>
</div>
<div class="remsub">
<div class="rememberMe1">
<?php echo CHtml::activeCheckBox($model,'rememberMe',array('class'=>"btn1"));echo CHtml::activeLabelEx($model,'rememberMe',array('class'=>"btn1")); ?>
<?php ?>
</div>
<div class="submit1">
<?php echo CHtml::submitButton(UserModule::t("Login"),array('class'=>"btn")); ?>
</div>
<div class="regpwd">
<?php echo CHtml::link(UserModule::t("Register"),Yii::app()->getModule('user')->registrationUrl,array('class'=>'pclas1')); ?> | <?php echo CHtml::link(UserModule::t("Lost Password?"),Yii::app()->getModule('user')->recoveryUrl,array('class'=>'pclas1')); ?>
< /div>
</div>
<?php echo CHtml::endForm(); ?>
<?php
$form = new CForm(array(
'elements'=>array(
'username'=>array(
'type'=>'text',
'maxlength'=>32,
),
'password'=>array(
'type'=>'password',
'maxlength'=>32,
),
'rememberMe'=>array(
'type'=>'checkbox',
)
),
'buttons'=>array(
'login'=>array(
'type'=>'submit',
'label'=>'Login',
),
),
), $model);
?>
and its a LOGIN FORM AND NOT A SIGN UP FORM is what my need is possible or any ohter solutions would be appreciated
Yes, please add your code so that we know what you're up to.
Some things that could help:
Perhaps users who are using the form are not allowed to access the controller/action that does the validation? That would cause Yii to redirect him/her to login page. Try looking at the permissions for the controller/action that does the validation.
Make sure your forms have enabled ajax validation:
<?php $form = $this->beginWidget('CActiveForm', array(
'id'=>'user-form',
'enableAjaxValidation'=>true, <----------
'enableClientValidation'=>true,
'focus'=>array($model,'firstName'),
)); ?>

how to give link to each attributes of a manufacturer

I have added 4 to 5 attributes in manufacture and shown in right column of front end.Now i want to link the each attributes of manufacture. if i will click an attribute of a manufacturer, it will show all the products which contain that arribute/brand.
if anyone knows this, please help me out.
thanks!
I have shown the attribute name in front end by the below code
<?php
$attribute = Mage::getSingleton('eav/config')->getAttribute('catalog_product', 'Manufacturer');
if ($attribute->usesSource()) {
$options = $attribute->getSource()->getAllOptions(false);
if(count( $options)>0){
?>
<div class="title_box">Manufacturers</div>
<?php $i=1;?>
<ul class="left_menu">
<?php
foreach($options as $eachval){
?>
<?php if($i%2==0){ ?>
<li class="even"><?php echo $eachval['label']?></li>
<?php } else { ?>
<li class="odd"><?php echo $eachval['label']?></li>
<?php } $i++; ?>
<?php } ?>
</ul>
<?php } } ?>
I have made one page manu.phtml in catalog/product page and put the following above code now how to give link to that arribute...........please describe briefly
in href link,what i have to write so that when i will click on any attribute it will show all products associated to that attribute/brand.
There is always the option of creating a new module with a custom controller that would list the products from a specified brand, but that is a painful process even if it's the clean way.
Here is a simple version if you don't mind the ugly urls.
The main idea is to link your brand names to the advanced search page with a specific brand filled in.
You can get the url like this:
$url = Mage::getUrl('catalogsearch/advanced/result', array('_query'=>'brand='.$value->getId()))
You just need now to get the id of the specific brand ($value->getId()), but if you can get the name you can get the id also.
And don't forget to specify that the brand attribute is used in advanced search. You can do that by editing the attribute in the backend.
[EDIT]
Make your ul element look like this:
<ul class="left_menu">
<?php
foreach($options as $eachval){
$url = Mage::getUrl('catalogsearch/advanced/result', array('_query'=>'Manufacturer='.$eachval['value']));
?>
<?php if($i%2==0){ ?>
<li class="even"><?php echo $eachval['label']?></li>
<?php } else { ?>
<li class="odd"><?php echo $eachval['label']?></li>
<?php } $i++; ?>
<?php } ?>
</ul>
Small tip off topic. You can avoid duplication of the li elements in your code like this
<ul class="left_menu">
<?php
foreach($options as $eachval){
$url = Mage::getUrl('catalogsearch/advanced/result', array('_query'=>'Manufacturer='.$eachval['value']));
?>
<li class="<?php echo ($i%2 == 0) ? 'even':'odd';?>"><?php echo $eachval['label']?></li>
<?php } $i++; ?>
<?php } ?>
</ul>

yii ajax validation errors show up

I have the following form:
$form = $this->beginWidget('bootstrap.widgets.TbActiveForm', array(
'id'=>'new-agenda-entry',
'enableAjaxValidation'=>true,
'action'=>'')); ?>
<div class="four columns">
<div class="right top5 sufix10">
<?php echo $form->labelEx($model,'eventTime'); ?>
<?php $this->widget('zii.widgets.jui.CJuiDatePicker', array(
'name'=>'UserAgenda[eventTime]',
'model'=>$model,
'options'=>array(
'dateFormat'=>'yy-mm-dd',
'minDate'=>'new Date()',
) // jquery plugin options
));?>
<?php echo $form->error($model, 'eventTime'); ?>
</div>
<div class="right top5 sufix10">
<?php echo CHtml::dropdownList('eventTime_hour', false, $this->getHourArray()); ?>
<?php echo CHtml::dropdownList('eventTime_min', false, array('00'=>'00', '30'=>'30')); ?>
</div>
<?php echo $form->labelEx($model,'note'); ?>
<?php echo $form->textField($model, 'note');?>
<?php echo $form->error($model, 'note'); ?>
The model is successfully validated on the server as I can see the response in Firebug:
{"UserAgenda_eventTime":["Event time cannot be blank."],"UserAgenda_note":["Note cannot be blank."]}
The message seems fine, so does the html but the hidden inputs generated by yii remain hidden and empty.
in the action maybe (create or update) you have to uncomment // $this->performAjaxValidation($model); like this you have an ajax validation, if the problem persist I think posting it to yiibootstrap discussion in yii forums i better, I see that you use yiibootstrap, try it with default yii form widget.

Magento: display multi-selection as a list with unique ID' s so list item can be changed to an image using CSS

I figured out how to display my custom multiselection attributie as a list but havent been able to figure out how to add an ID or class to every list item. This would allow me to display an image using CSS instead of text.
Hope you guys can help me. By the way, this is the code I use to display my custom attribute "rating" as a list:
<?php if($_product->getResource()->getAttribute('rating')->getFrontend()->getValue($_product)): ?>
<ul><li><?php
$_comma = ",";
$_list = "</li><li>";
echo str_replace($_comma,$_list,$_product->getResource()->getAttribute('rating')->getFrontend()->getValue($_product)) ?>
</li></ul>
<?php endif; ?>
</div>
Without knowing the exact format of the return of your function, I can't be 100% sure, but I think this would do the trick:
<div>
<?php if($_product->getResource()->getAttribute('rating')->getFrontend()->getValue($_product)):?>
<ul>
<?php $i=0?>
<?php foreach(explode(',', $_product->getResource()->getAttribute('rating')->getFrontend()->getValue($_product)) as $value) : ?>
<li id="value_<?php echo $i?>"><?php echo $value ?></li>
<?php $i++ ?>
<?php endforeach ?>
</ul>
<?php endif; ?>
</div>
It would probably be a little easier to just modify your return to give you back an array, but if the return is a comma separated list and not easy to change, then explode should do the trick.

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