$0 doesn't work when I source a bash script - bash

I have a simple script test.sh
#!/bin/bash
echo $0
When I run the following from csh terminal:
bash -c 'test.sh'
Then the output is test.sh
But when I run:
bash -c 'source test.sh'
The output is bash
Does anybody know how to print the script name in this case?

#!/bin/bash
declare -r SCRIPT_NAME=$(readlink -f ${BASH_SOURCE[0]})

Use $BASH_SOURCE. From the man-page:
BASH_SOURCE
An array variable whose members are the source filenames where
the corresponding shell function names in the FUNCNAME array
variable are defined. The shell function ${FUNCNAME[$i]} is
defined in the file ${BASH_SOURCE[$i]} and called from
${BASH_SOURCE[$i+1]}.
You can simply refer to $BASH_SOURCE instead of ${BASH_SOURCE[0]} since dereferencing an array variable in bash without an index will give you the first element.
This is a common pattern in my scripts to allow different behavior for sourcing versus executing a script:
foo() {
some cool function
}
if [[ "$BASH_SOURCE" == "$0" ]]; then
# actually run it
foo "$#"
fi

When a script is run using source it runs within the existing shell, any variables created or modified by the script will remain available after the script completes. In contrast if the script is run just as filename, then a separate subshell (with a completely separate set of variables) would be spawned to run the script.
Also you want to modify the shell scripts
This can not work for the same reason that you can not use a child shell to modify the enviroment of the parent shell. The environment of the child process is private and cannot affect the environment of its parent.
The only way to accomplish what you are attempting might be to have make compose a standard output stream that contains a list of shell variable assignments. The standard output could then be used as the input to the parent 'source' or '.' command. Using a 'noisy' program such as make to do this will be significantly challenging.

If, from csh, youre trying to reach session variables defined in a bash shell script, you must call the bash script prior to starting up the csh.
A session gets inherited into subprocesses, like so, where the csh.SESSION and csh.SESSION_INHERITED are merged once the csh 'boots':
bash/
├── csh
│   ├── SESSION
│   └── SESSION_INHERITED
└── SESSION
The bash.SESSION is NOT accessible from within csh shell as this would expose the init runlevel to any subprocesses.. Its is a fork, which during spawn duplicates the environment.
So, you can run from bash: source test.sh; csh. This will expose the exports from test.sh to csh - but its a static export which cannot be modified programatically in the csh.
Haven't 100% understood your question since its very abstract.. But this hopefully helps :)

when you use source or . , you run the script in this Shell. Your script share variables with the Shell, including the $0. When you run the Shell, you typed in 'bash', so the $0 is bash, and the script use it. That's why it shows bashstrong text.
If you want a new $0, use './script_name.sh' instead!

Related

Access variable declared inside Makefile command

I'm trying to access a variable declared by previous command (inside a Makefile).
Here's the Makefile:
all:
./script1.sh
./script2.sh
Here's the script declaring the variable I want to access,script1.sh:
#!/usr/bin/env bash
myVar=1234
Here's the script trying to access the variable previously defined, script2.sh:
#!/usr/bin/env bash
echo $myVar
Unfortunately when I run make, myVar isn't accessible. Is there an other way around? Thanks.
Make will run each shell command in its own shell. And when the shell exits, its environment is lost.
If you want variables from one script to be available in the next, there are constructs which will do this. For example:
all:
( . ./script1.sh; ./script2.sh )
This causes Make to launch a single shell to handle both scripts.
Note also that you will need to export the variable in order for it to be visible in the second script; unexported variables are available only to the local script, and not to subshells that it launches.
UPDATE (per Kusalananda's comment):
If you want your shell commands to populate MAKE variables instead of merely environment variables, you may have options that depend on the version of Make that you are running. For example, in BSD make and GNU make, you can use "variable assignment modifiers" including (from the BSD make man page):
!= Expand the value and pass it to the shell for execution and
assign the result to the variable. Any newlines in the result
are replaced with spaces.
Thus, with BSD make and GNU make, you could do this:
$ cat Makefile
foo!= . ./script1.sh; ./script2.sh
all:
#echo "foo=${foo}"
$
$ cat script1.sh
export test=bar
$
$ cat script2.sh
#!/usr/bin/env bash
echo "$test"
$
$ make
foo=bar
$
Note that script1.sh does not include any shebang because it's being sourced, and is therefore running in the calling shell, whatever that is. That makes the shebang line merely a comment. If you're on a system where the default shell is POSIX but not bash (like Ubuntu, Solaris, FreeBSD, etc), this should still work because POSIX shells should all understand the concept of exporting variables.
The two separate invocations of the scripts create two separate environments. The first script sets a variable in its environment and exits (the environment is lost). The second script does not have that variable in its environment, so it outputs an empty string.
You can not have environment variables pass between environments other than between the environments of a parent shell to its child shell (not the other way around). The variables passed over into the child shell are only those that the parent shell has export-ed. So, if the first script invoked the second script, the value would be outputted (if it was export-ed in the first script).
In a shell, you would source the first file to set the variables therein in the current environment (and then export them!). However, in Makefiles it's a bit trickier since there's no convenient source command.
Instead you may want to read this StackOverflow question.
EDIT in light of #ghoti's answer: #ghoti has a good solution, but I'll leave my answer in here as it explains a bit more verbosely about environment variables and what we can do and not do with them with regards to passing them between environments.

Is there a good way to preload or include a script prior to executing another script?

I am looking to execute a script but have it include another script before it executes. The problem is, the included script would be generated and the executed script would be unmodifiable. One solution I came up with, was to actually reverse the include, by having the include script as a wrapper, calling set to set the arguments for the executed script and then dotting/sourcing it. E.g.
#!/bin/bash
# Generated wrapper or include script.
: Performing some setup...
target_script=$1 ; shift
set -- "$#"
. "$target_script"
Where target_script is the script I actually want to run, importing settings from the wrapper.
However, the potential problem I face is that callers of the target script or even the target script itself may be expecting $0 to be set to the path of it's location on the file system. But because this wrapper approach overrides $0, the value of $0 may be unexpected and could produce undefined behaviour.
Is there another way to perform what is in effect, an LD_PRELOAD but in the scripted form, through bash without interfering with its runtime parameters?
I have looked at --init-file or --rcfile, but these only seem to be included for interactive shells.
Forcing interactive mode does seem to allow me to specify --rcfile:
$ bash --rcfile /tmp/x-include.sh -i /tmp/xx.sh
include_script: $0=bash, $BASH_SOURCE=/tmp/x-include.sh
target_script: $0=/tmp/xx.sh, $BASH_SOURCE=/tmp/xx.sh
Content of the x-include.sh script:
#!/bin/bash
echo "include_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
Content of the xx.sh script:
#!/bin/bash
echo "target_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
From the bash documentation:
When bash is started non-interactively, to run a shell script, for example, it looks for the variable BASH_ENV in
the environment, expands its value if it appears there, and uses the expanded value as the name of a file to read
and execute. Bash behaves as if the following command were executed:
if [ -n "$BASH_ENV" ]; then . "$BASH_ENV"; fi
but the value of the PATH variable is not used to search for the file name.
So that settles it then:
BASH_ENV=/tmp/x-include.sh /bin/bash /tmp/xx.sh

Defining common variables across multiple scripts?

I have a number of Bash and Perl scripts which are unrelated in functionality, but are related in that they work within the same project.
The fact that they work in the same project means that I commonly specify the same directories, the same project specific commands, the same keywords at the top of every script.
Currently, this has not bitten me, but I understand that it would be easier to have all of these values in one place, then if something changes I can change a value once and have the various scripts pick up on those changes.
The question is - how is best to declare these values? A single Perl script that is 'required' in each script would require less changes to the Perl scripts, though doesn't provide a solution to the Bash script. A configuration file using a "key=value" format would perhaps be more universal, but requires each script to parse the configuration and has the potential to introduce issues. Is there a better alternative? Using environmental variables? Or a Bash specific way that Perl can easily execute and interpret?
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. So when you declare a variable as key=value its scope is limited to the sub-shell context. You want to source the script by doing:
. ./myscript.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell environment and return the exit status of the last command executed from filename.
If filename does not contain a slash, file names in PATH are used to find the directory containing filename.
Also you can use the export command to create a global environment variable. export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./myscript2.sh
then $BAR will be available in the environment of myscript2.sh, but $FOO will not.
Define environments variables :
user level : in your ~/.profile or ~/.bash_profile or ~/.bash_login or ~/.bashrc
system level : in /etc/profile or /etc/bash.bashrc or /etc/environment
For example add tow lines foreach variable :
FOO=myvalue
export FOO
To read this variable in bash script :
#! /bin/bash
echo $FOO
in perl script :
#! /bin/perl
print $ENV{'FOO'};
You could also source another file, so you do not create extra env variables, that may lead to unexpected behaviours.
source_of_truth.sh:
FOO="bar"
scritp1.sh
#!/usr/bin/env bash
source source_of_truth.sh
echo ${FOO}
# ... doing something
scritp2.sh
#!/usr/bin/env bash
source source_of_truth.sh
echo ${FOO}
# ... doing something else

Unable to use cd within a bash script as intended

Consider this script I wrote, which should go into parent directory, when no argument is given (the if ... part).
#/bin/bash
if (($# == 0))
then
cd ..
else
for basename
do
cd ${PWD%$basename*}$basename
done
fi
The problem is, that if I execute it like this
./up.sh
the cd is executed in a subshell, rendering it useless.
If I execute the script using source, it works, but I don't want to call it that way (I makes calling the script to complicated, also you would expect to call it directly if found in the PATH).
An arbitrary program (such as your bash program) cannot change the working directory of the parent process, as that would pretty much break all existing processes that spawn children.
You should define a bash alias or function instead. As you have discovered, typing source ./up.sh (or shorter: . ./up.sh) works too.
I suggest using a function instead of a script
function myscript()
{
// use $1, $2, "$#" as usual in scripts
local v1="bla" # can use globals
export PATH="$PATH" # but global shell env too
somedirectory=..
cd $somedirectory
}
Alternatively, alias would work (but it doesn't support redirection, argument passing, flow control etc well, and you cannot nest them in $() IIRC).
Lastly source the existing script in the current shell like so:
source ./script.sh
ksh and bash have shorthands for that:
. ./script.sh
Beware of scripts with 'exit' statements though: they will exit the parent shell!

Can a shell script set environment variables of the calling shell? [duplicate]

This question already has answers here:
Can I export a variable to the environment from a Bash script without sourcing it?
(13 answers)
Closed 3 years ago.
The community reviewed whether to reopen this question last year and left it closed:
Original close reason(s) were not resolved
I'm trying to write a shell script that, when run, will set some environment variables that will stay set in the caller's shell.
setenv FOO foo
in csh/tcsh, or
export FOO=foo
in sh/bash only set it during the script's execution.
I already know that
source myscript
will run the commands of the script rather than launching a new shell, and that can result in setting the "caller's" environment.
But here's the rub:
I want this script to be callable from either bash or csh. In other words, I want users of either shell to be able to run my script and have their shell's environment changed. So 'source' won't work for me, since a user running csh can't source a bash script, and a user running bash can't source a csh script.
Is there any reasonable solution that doesn't involve having to write and maintain TWO versions on the script?
Use the "dot space script" calling syntax. For example, here's how to do it using the full path to a script:
. /path/to/set_env_vars.sh
And here's how to do it if you're in the same directory as the script:
. set_env_vars.sh
These execute the script under the current shell instead of loading another one (which is what would happen if you did ./set_env_vars.sh). Because it runs in the same shell, the environmental variables you set will be available when it exits.
This is the same thing as calling source set_env_vars.sh, but it's shorter to type and might work in some places where source doesn't.
Your shell process has a copy of the parent's environment and no access to the parent process's environment whatsoever. When your shell process terminates any changes you've made to its environment are lost. Sourcing a script file is the most commonly used method for configuring a shell environment, you may just want to bite the bullet and maintain one for each of the two flavors of shell.
You're not going to be able to modify the caller's shell because it's in a different process context. When child processes inherit your shell's variables, they're
inheriting copies themselves.
One thing you can do is to write a script that emits the correct commands for tcsh
or sh based how it's invoked. If you're script is "setit" then do:
ln -s setit setit-sh
and
ln -s setit setit-csh
Now either directly or in an alias, you do this from sh
eval `setit-sh`
or this from csh
eval `setit-csh`
setit uses $0 to determine its output style.
This is reminescent of how people use to get the TERM environment variable set.
The advantage here is that setit is just written in whichever shell you like as in:
#!/bin/bash
arg0=$0
arg0=${arg0##*/}
for nv in \
NAME1=VALUE1 \
NAME2=VALUE2
do
if [ x$arg0 = xsetit-sh ]; then
echo 'export '$nv' ;'
elif [ x$arg0 = xsetit-csh ]; then
echo 'setenv '${nv%%=*}' '${nv##*=}' ;'
fi
done
with the symbolic links given above, and the eval of the backquoted expression, this has the desired result.
To simplify invocation for csh, tcsh, or similar shells:
alias dosetit 'eval `setit-csh`'
or for sh, bash, and the like:
alias dosetit='eval `setit-sh`'
One nice thing about this is that you only have to maintain the list in one place.
In theory you could even stick the list in a file and put cat nvpairfilename between "in" and "do".
This is pretty much how login shell terminal settings used to be done: a script would output statments to be executed in the login shell. An alias would generally be used to make invocation simple, as in "tset vt100". As mentioned in another answer, there is also similar functionality in the INN UseNet news server.
In my .bash_profile I have :
# No Proxy
function noproxy
{
/usr/local/sbin/noproxy #turn off proxy server
unset http_proxy HTTP_PROXY https_proxy HTTPs_PROXY
}
# Proxy
function setproxy
{
sh /usr/local/sbin/proxyon #turn on proxy server
http_proxy=http://127.0.0.1:8118/
HTTP_PROXY=$http_proxy
https_proxy=$http_proxy
HTTPS_PROXY=$https_proxy
export http_proxy https_proxy HTTP_PROXY HTTPS_PROXY
}
So when I want to disable the proxy,
the function(s) run in the login shell and sets the variables
as expected and wanted.
It's "kind of" possible through using gdb and setenv(3), although I have a hard time recommending actually doing this. (Additionally, i.e. the most recent ubuntu won't actually let you do this without telling the kernel to be more permissive about ptrace, and the same may go for other distros as well).
$ cat setfoo
#! /bin/bash
gdb /proc/${PPID}/exe ${PPID} <<END >/dev/null
call setenv("foo", "bar", 0)
END
$ echo $foo
$ ./setfoo
$ echo $foo
bar
This works — it isn't what I'd use, but it 'works'. Let's create a script teredo to set the environment variable TEREDO_WORMS:
#!/bin/ksh
export TEREDO_WORMS=ukelele
exec $SHELL -i
It will be interpreted by the Korn shell, exports the environment variable, and then replaces itself with a new interactive shell.
Before running this script, we have SHELL set in the environment to the C shell, and the environment variable TEREDO_WORMS is not set:
% env | grep SHELL
SHELL=/bin/csh
% env | grep TEREDO
%
When the script is run, you are in a new shell, another interactive C shell, but the environment variable is set:
% teredo
% env | grep TEREDO
TEREDO_WORMS=ukelele
%
When you exit from this shell, the original shell takes over:
% exit
% env | grep TEREDO
%
The environment variable is not set in the original shell's environment. If you use exec teredo to run the command, then the original interactive shell is replaced by the Korn shell that sets the environment, and then that in turn is replaced by a new interactive C shell:
% exec teredo
% env | grep TEREDO
TEREDO_WORMS=ukelele
%
If you type exit (or Control-D), then your shell exits, probably logging you out of that window, or taking you back to the previous level of shell from where the experiments started.
The same mechanism works for Bash or Korn shell. You may find that the prompt after the exit commands appears in funny places.
Note the discussion in the comments. This is not a solution I would recommend, but it does achieve the stated purpose of a single script to set the environment that works with all shells (that accept the -i option to make an interactive shell). You could also add "$#" after the option to relay any other arguments, which might then make the shell usable as a general 'set environment and execute command' tool. You might want to omit the -i if there are other arguments, leading to:
#!/bin/ksh
export TEREDO_WORMS=ukelele
exec $SHELL "${#-'-i'}"
The "${#-'-i'}" bit means 'if the argument list contains at least one argument, use the original argument list; otherwise, substitute -i for the non-existent arguments'.
You should use modules, see http://modules.sourceforge.net/
EDIT: The modules package has not been updated since 2012 but still works ok for the basics. All the new features, bells and whistles happen in lmod this day (which I like it more): https://www.tacc.utexas.edu/research-development/tacc-projects/lmod
Another workaround that I don't see mentioned is to write the variable value to a file.
I ran into a very similar issue where I wanted to be able to run the last set test (instead of all my tests). My first plan was to write one command for setting the env variable TESTCASE, and then have another command that would use this to run the test. Needless to say that I had the same exact issue as you did.
But then I came up with this simple hack:
First command ( testset ):
#!/bin/bash
if [ $# -eq 1 ]
then
echo $1 > ~/.TESTCASE
echo "TESTCASE has been set to: $1"
else
echo "Come again?"
fi
Second command (testrun ):
#!/bin/bash
TESTCASE=$(cat ~/.TESTCASE)
drush test-run $TESTCASE
You can instruct the child process to print its environment variables (by calling "env"), then loop over the printed environment variables in the parent process and call "export" on those variables.
The following code is based on Capturing output of find . -print0 into a bash array
If the parent shell is the bash, you can use
while IFS= read -r -d $'\0' line; do
export "$line"
done < <(bash -s <<< 'export VARNAME=something; env -0')
echo $VARNAME
If the parent shell is the dash, then read does not provide the -d flag and the code gets more complicated
TMPDIR=$(mktemp -d)
mkfifo $TMPDIR/fifo
(bash -s << "EOF"
export VARNAME=something
while IFS= read -r -d $'\0' line; do
echo $(printf '%q' "$line")
done < <(env -0)
EOF
) > $TMPDIR/fifo &
while read -r line; do export "$(eval echo $line)"; done < $TMPDIR/fifo
rm -r $TMPDIR
echo $VARNAME
Under OS X bash you can do the following:
Create the bash script file to unset the variable
#!/bin/bash
unset http_proxy
Make the file executable
sudo chmod 744 unsetvar
Create alias
alias unsetvar='source /your/path/to/the/script/unsetvar'
It should be ready to use so long you have the folder containing your script file appended to the path.
It's not what I would call outstanding, but this also works if you need to call the script from the shell anyway. It's not a good solution, but for a single static environment variable, it works well enough.
1.) Create a script with a condition that exits either 0 (Successful) or 1 (Not successful)
if [[ $foo == "True" ]]; then
exit 0
else
exit 1
2.) Create an alias that is dependent on the exit code.
alias='myscript.sh && export MyVariable'
You call the alias, which calls the script, which evaluates the condition, which is required to exit zero via the '&&' in order to set the environment variable in the parent shell.
This is flotsam, but it can be useful in a pinch.
You can invoke another one Bash with the different bash_profile.
Also, you can create special bash_profile for using in multi-bashprofile environment.
Remember that you can use functions inside of bashprofile, and that functions will be avialable globally.
for example, "function user { export USER_NAME $1 }" can set variable in runtime, for example: user olegchir && env | grep olegchir
Another option is to use "Environment Modules" (http://modules.sourceforge.net/). This unfortunately introduces a third language into the mix. You define the environment with the language of Tcl, but there are a few handy commands for typical modifications (prepend vs. append vs set). You will also need to have environment modules installed. You can then use module load *XXX* to name the environment you want. The module command is basically a fancy alias for the eval mechanism described above by Thomas Kammeyer. The main advantage here is that you can maintain the environment in one language and rely on "Environment Modules" to translate it to sh, ksh, bash, csh, tcsh, zsh, python (?!?!!), etc.
I created a solution using pipes, eval and signal.
parent() {
if [ -z "$G_EVAL_FD" ]; then
die 1 "Rode primeiro parent_setup no processo pai"
fi
if [ $(ppid) = "$$" ]; then
"$#"
else
kill -SIGUSR1 $$
echo "$#">&$G_EVAL_FD
fi
}
parent_setup() {
G_EVAL_FD=99
tempfile=$(mktemp -u)
mkfifo "$tempfile"
eval "exec $G_EVAL_FD<>'$tempfile'"
rm -f "$tempfile"
trap "read CMD <&$G_EVAL_FD; eval \"\$CMD\"" USR1
}
parent_setup #on parent shell context
( A=1 ); echo $A # prints nothing
( parent A=1 ); echo $A # prints 1
It might work with any command.
I don't see any answer documenting how to work around this problem with cooperating processes. A common pattern with things like ssh-agent is to have the child process print an expression which the parent can eval.
bash$ eval $(shh-agent)
For example, ssh-agent has options to select Csh or Bourne-compatible output syntax.
bash$ ssh-agent
SSH2_AUTH_SOCK=/tmp/ssh-era/ssh2-10690-agent; export SSH2_AUTH_SOCK;
SSH2_AGENT_PID=10691; export SSH2_AGENT_PID;
echo Agent pid 10691;
(This causes the agent to start running, but doesn't allow you to actually use it, unless you now copy-paste this output to your shell prompt.) Compare:
bash$ ssh-agent -c
setenv SSH2_AUTH_SOCK /tmp/ssh-era/ssh2-10751-agent;
setenv SSH2_AGENT_PID 10752;
echo Agent pid 10752;
(As you can see, csh and tcsh uses setenv to set varibles.)
Your own program can do this, too.
bash$ foo=$(makefoo)
Your makefoo script would simply calculate and print the value, and let the caller do whatever they want with it -- assigning it to a variable is a common use case, but probably not something you want to hard-code into the tool which produces the value.
Technically, that is correct -- only 'eval' doesn't fork another shell. However, from the point of view of the application you're trying to run in the modified environment, the difference is nil: the child inherits the environment of its parent, so the (modified) environment is conveyed to all descending processes.
Ipso facto, the changed environment variable 'sticks' -- as long as you are running under the parent program/shell.
If it is absolutely necessary for the environment variable to remain after the parent (Perl or shell) has exited, it is necessary for the parent shell to do the heavy lifting. One method I've seen in the documentation is for the current script to spawn an executable file with the necessary 'export' language, and then trick the parent shell into executing it -- always being cognizant of the fact that you need to preface the command with 'source' if you're trying to leave a non-volatile version of the modified environment behind. A Kluge at best.
The second method is to modify the script that initiates the shell environment (.bashrc or whatever) to contain the modified parameter. This can be dangerous -- if you hose up the initialization script it may make your shell unavailable the next time it tries to launch. There are plenty of tools for modifying the current shell; by affixing the necessary tweaks to the 'launcher' you effectively push those changes forward as well.
Generally not a good idea; if you only need the environment changes for a particular application suite, you'll have to go back and return the shell launch script to its pristine state (using vi or whatever) afterwards.
In short, there are no good (and easy) methods. Presumably this was made difficult to ensure the security of the system was not irrevocably compromised.
The short answer is no, you cannot alter the environment of the parent process, but it seems like what you want is an environment with custom environment variables and the shell that the user has chosen.
So why not simply something like
#!/usr/bin/env bash
FOO=foo $SHELL
Then when you are done with the environment, just exit.
You could always use aliases
alias your_env='source ~/scripts/your_env.sh'
I did this many years ago. If I rememeber correctly, I included an alias in each of .bashrc and .cshrc, with parameters, aliasing the respective forms of setting the environment to a common form.
Then the script that you will source in any of the two shells has a command with that last form, that is suitable aliased in each shell.
If I find the concrete aliases, I will post them.
Other than writings conditionals depending on what $SHELL/$TERM is set to, no. What's wrong with using Perl? It's pretty ubiquitous (I can't think of a single UNIX variant that doesn't have it), and it'll spare you the trouble.

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