Remove Vowels from more than first word - c++11

Question

Program compiles, runs, and works.
Big issue:
It only works for the first word of a sentence.
EXAMPLE:
"Welcome to the jungle" results in "wlcm" rather than "wlcm t th jngl".
Small Issue:
There's a "1" appearing between input and output when it runs. How can I get rid of that? I think it's from this, but I'm not positive:
{
withVowel.erase(i, 1);
length = int(withVowel.length());
}
WHOLE CODE:
#include <iostream>
#include <string>
using namespace std;
void removeVowel(string&); // Removes vowels from input string.
string withVowel; // Will be used to read user input.
int main ()
{
const string SENTINEL = "0"; // Sentinel value.
// Request input string unless SENTINEL is entered.
cout << "Enter a word or series of words." << '\n';
cout << "Or, enter " << SENTINEL << " to quit." << '\n' << endl;
cin >> withVowel;
// In case of SENTINEL:
while (withVowel == SENTINEL)
{
cout << '\n' << "***" << endl;
return 0;
}
// Run loop.
removeVowel(withVowel);
// Display the string without vowels.
cout << "The word(s) entered reflecting only consonants: " << withVowel << endl;
return 0;
}
void removeVowel(string& withVowel)
{
int i = 0;
int length = int(withVowel.length());
while (i < length)
{
if (withVowel.at(i) == 'a' ||
withVowel.at(i) == 'A' ||
withVowel.at(i) == 'e' ||
withVowel.at(i) == 'E' ||
withVowel.at(i) == 'i' ||
withVowel.at(i) == 'I' ||
withVowel.at(i) == 'o' ||
withVowel.at(i) == 'O' ||
withVowel.at(i) == 'u' ||
withVowel.at(i) == 'U')
{
withVowel.erase(i, 1);
length = int(withVowel.length());
}
else i++;
}
// Display the string without vowels.
cout << removeVowel << endl;
}

Answer 1

Use getline(cin, withVowel); instead of cin >> withVowel;
Also replace while with if in main().
And don't forget to upvote and accept answers=)

Answer 2

The problem with only getting the first word is being you're using cin >> withVowel;, which will stop reading input as soon as it encounters white space. Try using std::getine(cin, withVowel); instead.
If at all possible, I would avoid manipulating the string in place, and just copy things to the output if they're not vowels.
std::remove_copy_if(withVowel.begin(), withVowel.end(),
[](char c) { return c == 'a' || c == 'A' ||
c == 'e' || c == 'E' ||
c == 'i' ...;});