Can sed be used with find to print Fields and Folder Name - bash

Question

This small script :
touch ilFldsN9LS.txt
ls -l | grep "^d" > /home/userB/PLAY/LibTESTxOutputFiles/ilFldsN9LS_testTEST.txt
produces file content of this format:
drwxr-xr-x 2 userB userB 4096 Mar 23 22:40 BASH_Collection_FolderNESTY
drwxr-xr-x 2 userB userB 4096 Mar 24 17:33 BASH_Collection_Functionality
What I wish to achieve is to get output very much like the above, but using find.
Turning to the use of find, this script: (which unlike the one previous, is recursive)
find . -type d \( ! -iname ".*" \) -exec ls -ld {} \; | grep "^d" |\
| tee -a /home/UserB/PLAY/LibTESTxOutputFiles/ilFldsR9FB.txt
produces file content of this format:
drwxr-xr-x 2 UserB UserB 4096 Mar 24 17:33 ./BASH_Collection_Functionality
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 ./LibTESTxOutputFiles/AdditionalTESTresults
adding some AWK to the script, like so:
find . -type d \( ! -iname ".*" \) -exec ls -ld {} \; | grep "^d" | awk '{ sub(/\.\//, " ");print}'\
| tee -a /home/innocentxlii/PLAY/LibTESTxOutputFiles/ilFldsR9FB.txt
produces output with the ** ./ * stripped from the front of the path
and pads the gap with an extra space to ease reading:
drwxr-xr-x 2 UserB UserB 4096 Mar 24 17:33 BASH_Collection_Functionality
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 LibTESTxOutputFiles/AdditionalTESTresults
Where I have gotten stuck, is I have been trying to use sed to keep the Fields, but to
have only the last Folder in the path, listed. For example the last item above would be:
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 AdditionalTESTresults
Ideas? I tried literally dozens of sed variants but have realized something must be
wrong with this approach.

Answer 1

How about this: sed -r 's/(.* )(.*)\/(.*)$/\1\3/g'
Check my test runs below:
$ echo "drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir1/dir2/dir3/dir4" | sed -r 's/(.* )(.*)\/(.*)$/\1\3/g'
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir4
$ echo "drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir1/dir2/dir3" | sed -r 's/(.* )(.*)\/(.*)$/\1\3/g'
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir3
$ echo "drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir1/dir2" | sed -r 's/(.* )(.*)\/(.*)$/\1\3/g'
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir2
$ echo "drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir1" | sed -r 's/(.* )(.*)\/(.*)$/\1\3/g'
drwxr-xr-x 2 UserB UserB 4096 Mar 25 16:04 dir1
NOTE: Please note that there is a space After the 1st asterisks in the sed command

Answer 2

You don't need sed, you can do it all with awk
find . -type d \( ! -iname ".*" \) -exec ls -ld {} \; |
awk '{n=split($NF,a,"/"); sub($NF, " "a[n])}1'
grep "^d" is redundant since you are already finding directories with find . -type d
awk Explanation:
n=split($NF,a,"/") splits the last field (denoted by $NF) by / and assigns it to array a
n gives the length of the array
a[n] will therefore return the string following the last / (i.e. the inner most directory)
sub($NF, " "a[n]) replaces the last field (denoted by $NF) with a space for padding (as per example) + inner most directory (denoted by a[n])
awk '{...}1' the 1 outside the awk is the same as print
EDIT: RE: for cases where directory contain spaces in name
find . -type d \( ! -iname ".*" \) -exec ls -ld {} \; |
awk -F '[0-9]+:[0-9]+ ' '{n=split($NF,a,"/"); sub($NF, " "a[n])}1'
specifying the input separator with -F '[0-9]+:[0-9]+ ' (for modification time) will ensure the last field ($NF) is the file name -- regardless whether or not it contain spaces in the directory name

Answer 3

what about
sed 's|\./||'
that remove the first ./, so in your line
find . -type d \( ! -iname ".*" \) -exec ls -ld {} \; | sed 's|\./||'