I am trying to design a loop that implements a lot of single elements I have seen before and the combination is throwing me off. Basically I have a structure like this:
/bin/script.sh
/conf/patches/1.zip
/conf/patches/2.zip
/conf/patches/3.zip
/sharedir
I want a loop that will go through however many patches I have in /conf/patches, unzip each patch into a separate directory in /sharedir. Each directory should be named the name of the file.
What I was trying so far was:
for file in '../conf/patches/*.zip'
do
unzip "${file%%.zip}" -d /sharedir/$file
done
As you can see...there is definitely something I am missing in this combination.
Try this:
for file in /conf/patches/*.zip
do
f="${file##*/}"
mkdir -p "/sharedir/${f%.zip}"
unzip -d "/sharedir/${f%.zip}" "${file}"
done
Remove quotes from glob pattern otherwise it is not expanded:
for file in ../conf/patches/*.zip
do
unzip "${file%%.zip}" -d /sharedir/
done
EDIT: You can try
for f in ../conf/patches/*.zip; do
echo g="${f%%/*}"
unzip -d "sharedir/${g%*.zip}" "$f"
done
Related
I'm running wget to get data from an FTP server like this:
wget -r -nH -N --no-parent ftp://username:password#example.com/ -P /home/data/
All of the files are in a format similar to this:
2016_07_10_bob-randomtext.csv.gz
2016_07_11_joe-importantinfo.csv.gz
Right now it's putting all of these files into /home/data/.
What I want to do is get the time from the filename and put it into their own folders based on the date. For example:
/home/data/2016_07_10/2016_07_10_bob-randomtext.csv.gz
/home/data/2016_07_11/2016_07_11_joe-importantinfo.csv.gz
Based off the answers here, it is possible to get the date from a file name. However, I'm not really sure how to turn that into a folder automatically...
Sorry if this is a bit confusing. Any help or advice would be appreciated.
Keeping the download of all the files into one directory, /home/files
destination=/home/data
for filename in /home/files/*; do
if [[ -f "$filename" ]]; then # ignore it if it's a directory (not a file)
name=$(basename "$filename")
datedir=$destination/${name:0:10} # first 10 characters of the filename
mkdir -p "$datedir" # create the directory if it doesn't exist
mv "$filename" "$datedir"
fi
done
I have been using an image optimizer for my websites and when I do this, it gives me files with -compressor at the end of it.
input: filename.jpg
output: filename-compressor.jpg
I need help in creating a batch file or a command script that I can just place these files into a folder and it will loop through all of these and change the names of these for me so that I don't have to go through them one by one.
mkdir -p compressors
mv *-compressor.jpg compressors/
cd compressors
for i in *-compressor.jpg; do j=${i%%\-compressor.jpg}.jpg; mv "$i" "$j"; done
Here is the condition:
I have a file with all packages installed.
I have a folder with all kinds of other packages, but they include all of the ones in the list, plus more.
I need a bash script that will read the file and check a folder for packages that don't exist in the list then remove them, they are not needed, but keep the packages that are on the list in that folder.
Or perhaps the bash should read folder then if packages in the folder aren't on the list them rm -f that or those packages.
I am familiar with writing if then conditional statements, I just don't know how to do if making the items in the list a variable or variables (in a loop).
thanks!
I would move the packages on the list to a new folder, delete the original folder, and move the temporary folder back:
DIR=directory-name
mkdir "$DIR-tmp"
while read pkgname; do
if [[ -f "$DIR/$pkgname" ]]; then
mv "$DIR/$pkgname" "$DIR-tmp"
fi
done < package-list.txt
# Confirm $DIR-tmp has the files you want first!
rm -rf "$DIR"
mv "$DIR-tmp" "$DIR"
I think you want something like this:
for file in $(ls folder) ; do
grep -E "$file" install-list-file >/dev/null || \
echo $file
done > rm-list
vi rm-list # view file to ensure correct
rm $(<rm_list)
There are ways to make this faster (using parameter substitution to avoid fork/exec's), but I recommend avoiding fancy shell stuff [${file##*/}] until you've got the basics down. Also, this script basically translates the description into a script and is not intended to be much more than a guide on how to approach the problem.
I have many tar.bz2 files in a directory, and would like to extract them to another directory.
Here is my bash script:
for i in *.tar.bz2 do;
sudo tar -xvjf $i.tar.bz2 -C ~/myfiles/
done
It doesn't work. How can I make it work? Thanks!
Your variable $i contains the entire file name (as you have applied the regex *.tar.bz2). So inside your for loop you don't need to attach the extension.
Try:
for i in *.tar.bz2; do
sudo tar -xvjf "$i" -C ~/myfiles/
done
You also have ; misplaced.
I am trying to rename some zip files in bash with an _orig but I seem to be missing something. Any suggestions??
My goal:
move files to an orig directory
rename original files with a "_orig" in the name
The code Ive tried to write:
mv -v $PICKUP/*.zip $ORIGINALS
for origfile in $(ls $ORIGINALS/*.zip);do
echo "Adding _orig to zip file"
echo
added=$(basename $origfile '_orig').zip
mv -v $ORIGINALS/$origfile.zip $ORIGINALS/$added.zip
done
Sorry still kinda new at this.
Using (p)rename :
cd <ZIP DIR>
mkdir -p orig
rename 's#(.*?)\.zip#orig/$1_orig.zip#' *.zip
rename is http://search.cpan.org/~pederst/rename/ (default on many distros)
Thanks to never use
for i in $(ls $ORIGINALS/*.zip);do
but use globs instead :
for i in $ORIGINALS/*.zip;do
See http://porkmail.org/era/unix/award.html#ls.
I know you've got a solution already, but just for posterity, this simplified version of your own shell script should also work for the case you seem to be describing:
mkdir -p "$ORIGINALS"
for file in "$PICKUP"/*.zip; do
mv -v "$file" "$ORIGINALS/${file%.zip}_orig.zip"
done
This makes use of "Parameter Expansion" in bash (you can look that up in bash's man page). The initial mkdir -p simply insures that the target directory exists. The quotes around $PICKUP and $ORIGINALS are intended to make it safe to include special characters like spaces and newlines in the directory names.
While prename is a powerful solution to many problems, it's certainly not the only hammer in the toolbox.