Check if file exists [BASH] - bash

Question

How do I check if file exists in bash?
When I try to do it like this:
FILE1="${#:$OPTIND:1}"
if [ ! -e "$FILE1" ]
then
echo "requested file doesn't exist" >&2
exit 1
elif
<more code follows>
I always get following output:
requested file doesn't exist
The program is used like this:
script.sh [-g] [-p] [-r FUNCTION_ID|-d FUNCTION_ID] FILE
Any ideas please?
I will be glad for any help.
P.S. I wish I could show the entire file without the risk of being fired from school for having a duplicate. If there is a private method of communication I will happily oblige.
My mistake. Fas forcing a binary file into a wrong place. Thanks for everyone's help.

Answer 1

Little trick to debugging problems like this. Add these lines to the top of your script:
export PS4="\$LINENO: "
set -xv
The set -xv will print out each line before it is executed, and then the line once the shell interpolates variables, etc. The $PS4 is the prompt used by set -xv. This will print the line number of the shell script as it executes. You'll be able to follow what is going on and where you may have problems.
Here's an example of a test script:
#! /bin/bash
export PS4="\$LINENO: "
set -xv
FILE1="${#:$OPTIND:1}" # Line 6
if [ ! -e "$FILE1" ] # Line 7
then
echo "requested file doesn't exist" >&2
exit 1
else
echo "Found File $FILE1" # Line 12
fi
And here's what I get when I run it:
$ ./test.sh .profile
FILE1="${#:$OPTIND:1}"
6: FILE1=.profile
if [ ! -e "$FILE1" ]
then
echo "requested file doesn't exist" >&2
exit 1
else
echo "Found File $FILE1"
fi
7: [ ! -e .profile ]
12: echo 'Found File .profile'
Found File .profile
Here, I can see that I set $FILE1 to .profile, and that my script understood that ${#:$OPTIND:1}. The best thing about this is that it works on all shells down to the original Bourne shell. That means if you aren't running Bash as you think you might be, you'll see where your script is failing, and maybe fix the issue.
I suspect you might not be running your script in Bash. Did you put #! /bin/bash on the top?
script.sh [-g] [-p] [-r FUNCTION_ID|-d FUNCTION_ID] FILE
You may want to use getopts to parse your parameters:
#! /bin/bash
USAGE=" Usage:
script.sh [-g] [-p] [-r FUNCTION_ID|-d FUNCTION_ID] FILE
"
while getopts gpr:d: option
do
case $option in
g) g_opt=1;;
p) p_opt=1;;
r) rfunction_id="$OPTARG";;
d) dfunction_id="$OPTARG";;
[?])
echo "Invalid Usage" 1>&2
echo "$USAGE" 1>&2
exit 2
;;
esac
done
if [[ -n $rfunction_id && -n $dfunction_id ]]
then
echo "Invalid Usage: You can't specify both -r and -d" 1>&2
echo "$USAGE" >2&
exit 2
fi
shift $(($OPTIND - 1))
[[ -n $g_opt ]] && echo "-g was set"
[[ -n $p_opt ]] && echo "-p was set"
[[ -n $rfunction_id ]] && echo "-r was set to $rfunction_id"
[[ -n $dfunction_id ]] && echo "-d was set to $dfunction_id"
[[ -n $1 ]] && echo "File is $1"

Answer 2

To (recap) and add to #DavidW.'s excellent answer:
Check the shebang line (first line) of your script to ensure that it's executed by bash: is it #!/bin/bash or #!/usr/bin/env bash?
Inspect your script file for hidden control characters (such as \r) that can result in unexpected behavior; run cat -v scriptFile | fgrep ^ - it should produce NO output; if the file does contain \r chars., they would show as ^M.
To remove the \r instances (more accurately, to convert Windows-style \r\n newline sequences to Unix \n-only sequences), you can use dos2unix file to convert in place; if you don't have this utility, you can use sed 's/'$'\r''$//' file > outfile (CAVEAT: use a DIFFERENT output file, otherwise you'll destroy your input file); to remove all \r instances (even if not followed by \n), use tr -d '\r' < file > outfile (CAVEAT: use a DIFFERENT output file, otherwise you'll destroy your input file).
In addition to #DavidW.'s great debugging technique, you can add the following to visually inspect all arguments passed to your script:
i=0; for a; do echo "\$$((i+=1))=[$a]"; done
(The purpose of enclosing the value in [...] (for example), is to see the exact boundaries of the values.)
This will yield something like:
$1=[-g]
$2=[input.txt]
...
Note, though, that nothing at all is printed if no arguments were passed.

Answer 3

Try to print FILE1 to see if it has the value you want, if it is not the problem, here is a simple script (site below):
#!/bin/bash
file="${#:$OPTIND:1}"
if [ -f "$file" ]
then
echo "$file found."
else
echo "$file not found."
fi
http://www.cyberciti.biz/faq/unix-linux-test-existence-of-file-in-bash/

Answer 4

Instead of plucking an item out of "$#" in a tricky way, why don't you shift off the args you've processed with getopts:
while getopts ...
done
shift $(( OPTIND - 1 ))
FILE1=$1