Update batch codeigniter - codeigniter

I'm trying to update the database by editing a form with multiple valuse based on 1 id.
I'm trying to use $this->db->update_batch('table', $data, 'id');
But i think i'm not getting the correct parse to insert the data in batch mode to the database.
My question is if this way is the correct:
<input type="text" name="item_id[]" value="">
<input type="text" name="rep_id[]" value="">
<input type="text" name="ean[]" value="">
$update_item_id = $this->input->post('item_id');
$update_rep_id = $this->input->post('rep_id');
$update_ean = $this->input->post('ean');
$update_items = array(
'id' => $update_item_id,
'rep_id' => $update_rep_id,
'ean' => $update_ean
);
if($this->form_validation->run() == true && $this->model_m->editbatch($rep_id, $update_items)){
this->session->set_flashdata('message', "All is ok");
redirect("controller", 'refresh');
}
Model:
public function editbatch($id, $update_items)
{
$this->db->update('table', $update_items, 'id');
}
Any help is appreciated.

you don't use correctly the update, try like this:
$this->db->where('id', $id);
$this->db->update('mytable', $data);

Use update_batch instead of update
public function editbatch($id, $update_items)
{
$this->db->update_batch('table', $update_items, 'id');
}

Related

send some variable to the blade view laravel in an addColumn () function of datatable

Its possibility of sending a variable to the blade view through the addColumn() function of datatable jquery?
I want to pass another variable to compare values ​​of the result of the query.
this is the code:
if ($request->ajax()) {
$products = Product::with('categories', 'featureds')->orderBy('name', 'ASC');
$selecteds = [];
$products_selecteds = Product::all();
foreach($products_selecteds as $products_selected){
foreach($products_selected->featureds as $featured){
array_push($selecteds, $products_selected->id);
}
}
return Datatables::of($products)->addColumn('format_price', function($product) {
return $product->format_price;
})->addColumn('checkbox', function ($product, $selecteds) {
return view('pages.products.components.table.checkbox', ['product' => $product, 'selecteds' => $selecteds]);
});
}
the array $selecteds its i want to pass to the view checkbox:
<td>
<label>
<input type="checkbox" class="checkbox-item" {{ in_array($product->id, $selecteds) ? 'checked' : "" }} value=""/>
<span></span>
</label>
</td>
Yes, it's possible to render view on additional columns. But to achieve that, you have to make the column as a Raw Column like this:
Datatable::of($products)
->addColumn('selected', function($product) use($selecteds) {
return view('product.selected', compact('product', 'selecteds'));
})
->rawColumns(['selected'])
note:
you also need to declare use keyword since $selecteds is outside the closure

How to redirect back to preivous template with both input and collections of Eloquent in Laravel?

I need to pass both input and collections, that this controller produce, to the previous template. I try to use:
return redirect()->back->withInput()->with('userdata',$userdata);
but get undefined variable when access $userdata in template. This is controller:
public function inquireUpdateProcess(){
$input = request()->all();
$userdata = AuthorityKind::where('authority', $input['authority'])->first();
return redirect()->back->withInput()->with('userdata',$userdata);
}
And this is template of view:
<label for="text-authority-change">name of authority:</label>
<input type="text" name="authority_name_change" class="form-control"
value="{{$userdata->authority_name}}" />
I use the following instead then it works. But the outcome is couldn't pass the input data and collection in the same time, I know there must be a way to use return redirect()->back()... and get both previous input and the collection in template.
$userdata = AuthorityKind::where('authority', $input['authority'])->first();
$binding = [
'title' => 'Authority management',
'userdata' => $userdata,
];
return view('authority.authView', $binding);
I found out the data put into with() can only get it by session in template of blade like this :
<input type="text" id="text-authority-change" name="authority_name_change" class="form-control"
value="{{session()->get('userdata')['authority_name']}}"
/>
Even the collections of Eloquent are the the same way to access.

Get specific row from database with codeigniter

I'm new to this so i have this silly question.I want to make a login form and when the user logs in i want to show all his information in the screen(username attack defence...).The thing is i don't know how to call the specific function i've made because in my controller calls function index() by default and not the function guser().
login view
<h2>Login</h2>
<?php if($error==1){ ?>
<p>Your Username/password did not match </p>
<?php } ?>
<form action="<?=base_url()?>index.php/Users/login" method="post">
<p>Username: <input name="user" type="text" /> </p>
<p>Password: <input name="password" type="password" /> </p>
<p><input type="submit" value="Login" /></p>
</form>
users controller
<?php
class Users Extends CI_Controller{
function __construct(){
parent::__construct();
$this->load->model('User');
}
function index(){
$data['users']=$this->User->get_users();//sto model post tha kalesei tin sinartisi get_posts
$this->load->view('Post_index',$data);
}
function guser($id){
$data['user']=$this->User->get_user($id);
$this->load->view('Post_index',$data);
}
function login(){
$data['error'] = 0; // simenei oti den exei errors
if($_POST){
$user=$this->input->post('user',true);//pairnei to username p edose o xristis(einai idio me to $_POST)
$password=$this->input->post('password',true);//pairnei to password p edose o xristis
//$type=$this->input->post('charact',true);
$user1=$this->User->login($user,$password);//,$type);
if(!$user1){
$data['error']=1;
}else{
$this->session->set_userdata('id',$user1['id']);
$this->session->set_userdata('user',$user1['user']);
$this->session->set_userdata('name',$user1['name']);
$this->session->set_userdata('money',$user1['money']);
$this->session->set_userdata('attack',$user1['attack']);
$this->session->set_userdata('defence',$user1['defence']);
$this->session->set_userdata('level',$user1['level']);
$this->session->set_userdata('xp',$user1['xp']);
redirect(base_url().'index.php/Users');
}
}
$this->load->view('Login',$data);
}
function registerSam(){
if($_POST){
$data=array(
'user'=>$_POST['user'],
'name'=>$_POST['name'],
'password'=>$_POST['password'],
'charact'=>"Samurai",
'money'=>400,
'attack'=>10,
'defence'=>5,
'level'=>0,
'xp'=>0
);
$userid=$this->User->create_user($data);
}
}
function registerKnight(){
if($_POST){
$data=array(
'user'=>$_POST['user'],
'name'=>$_POST['name'],
'password'=>$_POST['password'],
'charact'=>"Knight",
'money'=>400,
'attack'=>5,
'defence'=>10,
'level'=>0,
'xp'=>0
);
$userid=$this->User->create_user($data);
}
}
}
?>
user model
<?php
class User Extends CI_Model{
function create_user($data){
$this->db->insert('unityusers',$data);
}
function login($user,$password){
$where=array(
'user'=>$user,
'password'=>$password,
);
$this->db->select()->from('unityusers')->where($where);
$query=$this->db->get();
return $query->first_row('array');
}
function get_user($id){
$this->db->select()->from('unityusers')->where(array('id'=>$id));
$query=$this->db->get();
return $query->first_row('array');
}
function get_users($num=20,$start=0){// tha paroume 20 posts k tha arxisoume apo to proto
$this->db->select()->from('unityusers')->limit($num,$start);
$query=$this->db->get();
return $query->result_array();
}
}
?>
Although you have accepted the answer I like to point out some basic functionality for you to more improved code.
Different technique to load the data to view from controller:
function index(){
$users = $this->User->get_users();
$this->load->view('Post_index',['users' => $users, 'any_other_data' => $any_other_data ... and so on]);
}
When you get post data in the controller then you should check for a validation first inside your login function. And in login functionality it will be more useful. setting-validation-rules
$this->form_validation->set_rules('username', 'Username', 'required');
$this->form_validation->set_rules('password', 'Password', 'required',
Loading a model and it's function. You don't need to use uppercase in this as give below.
$this->load->model('user');
$this->user->get_users();
Your registration Function registerSam you don't need to create an array of post data Codeigniter will provide the functionality to get all your post data at once. To remove unnecessary data from that array use unset.
$your_post_array = $this->input->post();
To call a specific function made, you can access it via a browser using the link
BASE_URL/index.php/ControllerName/MethodName
So, in your case to call the guser method, the url would be
BASE_URL/index.php/users/guser
Hope that helps.
You have an error in guser function on the controller. You don't need to passs any argument to the function. You can get ID of user from the session, which was actually added in session once the user has entered correct credentials.
Also after login, you need to redirect user to guser function instead of users. Because as per your controller users function dosen't exist.
Change From
redirect(base_url().'index.php/Users');
To
redirect(base_url().'index.php/guser');
Please check below for solution.
function guser(){
$data['user']=$this->User->get_user($this->session->userdata('id'));
$this->load->view('Post_index',$data);
}
Let me know if it not works.

laravel 5.3 old input values always empty

see docs here about old input
Route::post('/search/all/', function (Request $request) {
//...
$products = $query->paginate(15);
$data = ['products' => $products,
'oldinput' => $request->all()];
return view('inventory.search_products', $data);
});
in the view:
this works:
<input type="text" id="search_all" name="search_all" value="{{ $oldinput['search_all'] }}">
this is always empty:
<input type="text" id="search_all" name="search_all" value="{{ old('search_all') }}">
Just call flush in your controller then you can use old() helper function in your blade.
public function YourController(Request $request){
$request->flash();
return view('yourblade');
}
In blade file:-
<input id="lng" name="lng" value="{{old('lng')}}" type="hidden">
docs says you should flash() then call old() method.
flashing stores the previous request in the session. so it makes sense that old(search_all) doesn't work
I will suggest the following solution:
return view('inventory.search_products', $data)->withInput(\Input::all());
And in blade you can call as well \Input::old('search_all');.

CodeIgniter update page - Simple CRUD website assistance required

After looking through the forums and starting to try to create a basic CRUD website I am currently struggling to have a page that updates the articles as follows. If someone could kindly tell me where I am going wrong, I will be most greatful. I am getting a 404 error at 'news/input'
model (at news_model.php)
public function update($id, $data)
{
$this->db->where('id', $id);
$this->db->update('news', $data);
}
controller (news.php)
public function update($id){
$data = array(
'title' => $this->input->post('title'),
'slug' => $this->input->post('slug'),
'text' => $this->input->post('text'));
if($this->news_model->exists($id)) {
$this->news_model->update($id, $data);
}
else {
$this->news_model->insert($data);
}
}
html (views/news/input.php)
<h2>Update a news item</h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/update') ?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="slug">Slug</label>
<input type="input" name="slug" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Update an item" />
You get a 404 because your news controller seems to have no method 'input'. Try adding something like this:
public function input(){
// load the form
$this->load->view('/news/input');
}
Note that for updating data you will need to fetch and pass it into the view first, then render the (filled out) form using set_val() and other CI functions.
Currently you're "hardcoding" the HTML form which makes populating and maintaining state (when validation fails) difficult. I suggest you play through the forms tutorial on the CI website.
Edit:
To create a update/insert (upsert) controller change as follows:
Controller:
function upsert($id = false){
$data['id'] = $id; // create a data array so that you can pass the ID into the view.
// you need to differntiate the bevaviour depending on 1st load (insert) or re-load (update):
if(isset($_POST('title'))){ // or any other means by which you can determine if data's been posted. I generally look for the value of my submit buttons
if($id){
$this->news_model->update($id, $this->input->post()); // there's post data AND an id -> it's an update
} else {
$this->news_model->insert($id, $this->input->post()); // there's post data but NO id -> it's an insert
}
} else { // nothing's been posted -> it's an initial load. If the id is set, it's an update, so we need data to populate the form, if not it's an insert and we can pass an empty array (or an array of default values)
if($id){
$data['news'] = $this->news_model->getOne($id); // this should return an array of the news item. You need to iterate through this array in the view and create the appropriate, populated HTML input fields.
} else {
$data['news'] = $this->news_model->getDefaults(); // ( or just array();) no id -> it's an insert
}
}
$this->load->view('/news/input',$data);
}
And amend the $id to the action-url in your view:
<?php echo form_open('news/upsert/'.$id) ?>

Resources