I have the following code:
module A
def self.included(base)
base.extend(ClassMethods)
end
def foo
a = bar
puts a
end
def bar(str="qwe")
str
end
module ClassMethods
end
end
class B
include A
def bar(str="rty")
str
end
end
B.new.foo #=> "rty"
I wish class B to look like this:
class B
include A
bar "rty"
end
B.new.foo #=> rty
or
class B
include A
HelperOptions.bar "rty" # HelperOptions class should be in module A
end
B.new.foo #=> rty
I tried using define_method, class_eval, and initialize. How can be implemented syntax bar 'rty' or HelperOptions.bar 'rty' and what shall be done in module A?
If I got your question properly you want to define a class method A.bar that defines an instance method B#bar that returns it's argument, you can do it like this:
module A
def self.included(base)
base.extend(ClassMethods)
end
def foo
puts bar
end
module ClassMethods
def bar(str)
define_method(:bar) { str }
end
end
end
class B
include A
bar 'rty'
end
B.new.bar
# => "rty"
B.new.foo
# Output: rty
Related
I'm having some issues with the access rules of ruby. At one point I thought that something like this worked:
module Foo
def bar(x)
puts "#{x}"
end
class Baz
def initialize(x)
bar(x)
end
end
end
Foo::Baz.new(3)
but somehow it no longer does. I've tried to declare bar using self.bar and Foo.bar, but neither work. What am I missing?
The inclusion of the module methods isn't "automatic", I think because it can lead to unexpected behavior.
You can try making them a class method as you mentioned, or including the module and getting access to the methods there:
module Foo
class << self
def bar(x)
puts "#{s}" % x
end
def s
"s1"
end
end
def bar(x)
puts "#{s}" % x
end
def s
"s2"
end
class Baz
include Foo
def initialize(x)
bar(x)
Foo.bar(x)
end
end
end
Foo::Baz.new(3)
# s2
# s1
Two modules Foo and Baa respectively define a method with the same name name, and I did include Foo and include Baa in a particular context.
When I call name, how can I disambiguate whether to call the name method of Foo or Baa?
Only the order of modules inclusion decides which one will get called. Can't have both with the same name - the latter will override the former.
Of course, you can do any tricks, just from the top of my head:
module A
def foo
:foo_from_A
end
end
module B
def foo
:foo_from_B
end
end
class C
def initialize(from)
#from = from
end
def foo
from.instance_method(__method__).bind(self).call
end
private
attr_reader :from
end
C.new(A).foo #=> :a_from_A
C.new(B).foo #=> :a_from_B
But that's no good for real life use cases :)
Technically, there is no name collision because the method foo is redefined.
In the following exemple, A.foo is redefined and is never called
module A
def foo
raise "I'm never called"
end
end
module B
def foo
puts :foo_from_B
end
end
class C
include A
include B
end
C.new.foo
# =>
# foo_from_B
If you write A and B module, you can use super to call previous definition of foo. As if it where an inherited method.
module A
def foo
puts :foo_from_A
end
end
module B
def foo
super
puts :foo_from_B
end
end
class C
include A
include B
end
C.new.foo
# =>
# foo_from_A
# foo_from_B
There are side effects and I would not use this but this is doing the trick :
module A
def foo
puts :foo_from_A
end
end
module B
def foo
puts :foo_from_B
end
end
class C
def self.include_with_suffix(m, suffix)
m.instance_methods.each do |method_name|
define_method("#{method_name}#{suffix}", m.instance_method(method_name))
end
end
include_with_suffix A, "_from_A"
include_with_suffix B, "_from_B"
end
c= C.new
c.foo_from_A
c.foo_from_B
begin
c.foo
rescue NoMethodError
puts "foo is not defined"
end
# =>
# foo_from_A
# foo_from_B
# foo is not defined
Provided none of the methods of Foo or Baa call name (which seems a reasonable assumption), one can simply create aliases.
module Foo
def name; "Foo#name"; end
end
module Baa
def name; "Baa#name"; end
end
class C
include Foo
alias :foo_name :name
include Baa
alias :baa_name :name
undef_method :name
end
c = C.new
c.foo_name
#=> "Foo#name"
c.baa_name
#=> "Baa#name"
C.instance_methods & [:foo_name, :baa_name, :name]
#=> [:foo_name, :baa_name]
The keyword alias is documented here. One may alternatively use the method #alias_method. See this blog for a comparison of the two.
Module#undef_method is not strictly necessary. It's just to ensure that an exception is raised if name is called.
You should definetely read about method lookups.
Anyway, I would do it this way:
module Foo
def name
:foo
end
end
module Bar
def name
:bar
end
end
class MyClass
include Foo
include Bar
def foo_name
Foo.instance_method(:name).bind(self).call
end
def bar_name
Bar.instance_method(:name).bind(self).call
end
#
# or even like this: obj.name(Foo)
#
def name(mod)
mod.instance_method(:name).bind(self).call
end
end
BTW if you are using Module#instance_method and UnboundMethod#bind you don't really need to include specific module. This code works:
Foo.instance_method(:name).bind('any object (e.g. string)').call
I'm trying to modify existing ruby code, and ruby is not my first languange. Part of the code is like below:
#someFile1.rb
module A
module B
def somefunction()
end
end
end
class X::Y
include A::B
end
#someFile2.rb
module A
module C
def anotherfunction()
#somefunction() <-- error
end
end
end
class X::Y
include A::C
end
Somehow I can't access method somefunction() in anotherfunction.
How to access method defined in module B in method inside module C? Why it's not working?
Instance methods in modules aren't generally accessible until you mix them into a class and create an object of that class.
module A
module B
def some_method
"foo"
end
end
end
module A
module C
def another_method
some_method
end
end
end
class X
include A::B
include A::C
end
X.new.another_method
# => "foo"
But I'd say it isn't very elegant to have a module that depends upon the fact that some other module has also been mixed into the same object
Class methods in modules, on the other hand, are accessible like this:
module A
module B
def self.somefunction
"foo"
end
end
end
module A
module C
def self.another_function
A::B.somefunction
end
end
end
A::C.another_function
# => "foo"
Assuming you want to call the module functions themselves, you would first need to make them module functions (think static in Java or namespace in C++). Then you can use the :: (namespace resolution) operator. See foo and bar.
If you want to import them into classes, just import both, and both will be visible. See baz and qux.
module A
module B
def self.foo
puts "foo"
end
def baz
puts "baz"
end
end
end
module A
module C
def self.bar
puts "bar"
A::B::foo
end
def qux
puts "qux"
baz
end
end
end
class X
include A::B
include A::C
end
A::C::bar
x = X.new
x.qux
Output:
bar
foo
baz
qux
I am trying to define some classes in Ruby that have an inheritance hierarchy, but I want to use one of the methods in the base class in the derived class. The twist is that I don't want to call the exact method I'm in, I want to call a different one. The following doesn't work, but it's what I want to do (basically).
class A
def foo
puts 'A::foo'
end
end
class B < A
def foo
puts 'B::foo'
end
def bar
super.foo
end
end
Probably, this is what you want?
class A
def foo
puts 'A::foo'
end
end
class B < A
alias bar :foo
def foo
puts 'B::foo'
end
end
B.new.foo # => B::foo
B.new.bar # => A::foo
A more general solution.
class A
def foo
puts "A::foo"
end
end
class B < A
def foo
puts "B::foo"
end
def bar
# slightly oddly ancestors includes the class itself
puts self.class.ancestors[1].instance_method(:foo).bind(self).call
end
end
B.new.foo # => B::foo
B.new.bar # => A::foo
In class Foo I'd like to include method Bar under certain conditions:
module Bar
def some_method
"orly"
end
end
class Foo
def initialize(some_condition)
if !some_condition
"bar"
else
class << self; include Bar; end
end
end
end
Is there any cleaner (and clearer) way to achieve the include in the method without having to do it inside the singleton class?
extend is the equivalent of include in a singleton class:
module Bar
def some_method
puts "orly"
end
end
class Foo
def initialize(some_condition)
extend(Bar) if some_condition
end
end
Foo.new(true).some_method # => "orly"
Foo.new(false).some_method # raises NoMethodError