Phalcon validation scenario - validation

I used to use Yii framework. I would like to make project using Phalcon. I could not find validation scenario on Phalcon. What is the best way to correctly implement it on Phalcon?
Thanks in advance.

Any data validation:
<?php
use Phalcon\Validation\Validator\PresenceOf,
Phalcon\Validation\Validator\Email;
$validation = new Phalcon\Validation();
$validation->add('name', new PresenceOf(array(
'message' => 'The name is required'
)));
$validation->add('email', new PresenceOf(array(
'message' => 'The e-mail is required'
)));
$validation->add('email', new Email(array(
'message' => 'The e-mail is not valid'
)));
$messages = $validation->validate($_POST);
if (count($messages)) {
foreach ($messages as $message) {
echo $message, '<br>';
}
}
http://docs.phalconphp.com/en/1.2.6/reference/validation.html
If you are working with models:
<?php
use Phalcon\Mvc\Model\Validator\InclusionIn,
Phalcon\Mvc\Model\Validator\Uniqueness;
class Robots extends \Phalcon\Mvc\Model
{
public function validation()
{
$this->validate(new InclusionIn(
array(
"field" => "type",
"domain" => array("Mechanical", "Virtual")
)
));
$this->validate(new Uniqueness(
array(
"field" => "name",
"message" => "The robot name must be unique"
)
));
return $this->validationHasFailed() != true;
}
}
http://docs.phalconphp.com/en/1.2.6/reference/models.html#validating-data-integrity
models also have events, so you can add any logic you need in these functions:
http://docs.phalconphp.com/en/1.2.6/reference/models.html#events-and-events-manager

I would like to use forms for CRUD as they are very dynamic and reusable.
You can achieve that in forms using options.
You can pass additional options to form and act like a scenario.
You can check Form constructor here
https://docs.phalconphp.com/en/latest/api/Phalcon_Forms_Form.html
In your controller you can pass $options
<?php
use Phalcon\Mvc\Controller;
class PostsController extends Controller
{
public function insertAction()
{
$options = array();
$options['scenario'] = 'insert';
$myForm = new MyForm(null, $options);
if($this->request->hasPost('insert')) {
// this will be our model
$profile = new Profile();
// we will bind model to form to copy all valid data and check validations of forms
if($myForm->isValid($_POST, $profile)) {
$profile->save();
}
else {
echo "<pre/>";print_r($myForm->getMessages());exit();
}
}
}
public function updateAction()
{
$options = array();
$options['scenario'] = 'update';
$myForm = new MyForm(null, $options);
}
}
And your form should look like something this
<?php
// elements
use Phalcon\Forms\Form;
use Phalcon\Forms\Element\Text;
// validators
use Phalcon\Validation\Validator\PresenceOf;
class MyForm extends Form {
public function initialize($entity = null, $options = null) {
$name = new Text('first_name');
$this->add($name);
if($options['scenario'] == 'insert') {
// at the insertion time name is required
$name->addValidator(new PresenceOf(array('message' => 'Name is required.')));
}
else {
// at the update time name is not required
// as well you can add more additional validations
}
}
}
now you can add multiple scenarios and act based on scenarios.

Related

CodeIgniter 3 code does not add data to database into 2 different tables (user_info & phone_info)

The problem is when I entered a new name no data is added. A similar thing happen when I entered an already existing name. Still, no data is added to the database. I am still new to CodeIgniter and not entirely sure my query builder inside the model is correct or not.
In the Model, I check if the name already exists insert data only into the phone_info table. IF name does not exist I insert data into user_info and phone_info.
Controller:
public function addData()
{
$name = $this->input->post('name');
$contact_num = $this->input->post('contact_num');
if($name == '') {
$result['message'] = "Please enter contact name";
} elseif($contact_num == '') {
$result['message'] = "Please enter contact number";
} else {
$result['message'] = "";
$data = array(
'name' => $name,
'contact_num' => $contact_num
);
$this->m->addData($data);
}
echo json_encode($result);
}
Model:
public function addData($data)
{
if(mysqli_num_rows($data['name']) > 0) {
$user = $this->db->get_where('user_info', array('name' => $data['name']))->result_array();
$user_id = $user['id'];
$phone_info = array(
'contact_num' => $data['contact_num'],
'user_id' => $user_id
);
$this->db->insert('phone_info',$phone_info);
} else {
$user_info = array(
'name' => $data['name']
);
$this->db->insert('user_info', $user_info);
$user = $this->db->get_where('user_info', array('name' => $data['name']))->result_array();
$user_id = $user['id'];
$phone_info = array(
'contact_num' => $data['contact_num'],
'user_id' => $user_id
);
$this->db->insert('phone_info', $phone_info);
}
}
DB-Table user_info:
DB-Table phone_info:
Extend and change your model to this:
public function findByTitle($name)
{
$this->db->where('name', $name);
return $this->result();
}
public function addData($data)
{
if(count($this->findByTitle($data['name'])) > 0) {
//.. your code
} else {
//.. your code
}
}
Explanation:
This:
if(mysqli_num_rows($data['name']) > 0)
..is not working to find database entries by name. To do this you can use codeigniters built in model functions and benefit from the MVC Pattern features, that CodeIgniter comes with.
I wrapped the actual findByName in a function so you can adapt this to other logic and use it elswehere later on. This function uses the query() method.
Read more about CodeIgniters Model Queries in the documentation.
Sidenote: mysqli_num_rows is used to iterate find results recieved by mysqli_query. This is very basic sql querying and you do not need that in a MVC-Framework like CodeIgniter. If you every appear to need write a manual sql-query, even then you should use CodeIgniters RawQuery methods.

Laravel - How to update Input Array without deleting Sales Detail

In my Laravel-8 project, I have this controller for Input Field Array Update.
Controller:
public function update(UpdateSaleRequest $request, $id)
{
try {
$sale = Sale::find($id);
$data = $request->all();
$update['date'] = date('Y-m-d', strtotime($data['date']));
$update['company_id'] = $data['company_id'];
$update['name'] = $data['name'];
$update['remarks'] = $data['remarks'];
$sale->update($update);
SaleDetail::where('sale_id', $sale->id)->delete();
foreach ($data['invoiceItems'] as $item) {
$details = [
'sale_id' => $sale->id,
'item_id' => $item['item_id'],
'employee_id' => $item['employee_id'],
'quantity' => $item['qty'],
'price' => $item['cost'],
'total_price' => $item['cost'] * $item['qty'],
'sale_type_id'=>$item['sale_type_id']
];
$saleDetail = new SaleDetail($details );
$saleDetail->save();
}
} catch (JWTException $e) {
throw new HttpException(500);
}
return response()->json($sale);
}
In the form, the user can add more Sales Detail or remove.
Some of the SaleDetail fields are being used somewhere else.
Is there a way to update the input field array without deleting the SaleDetail as shown in what I did here:
SaleDetail::where('sale_id', $sale->id)->delete();
Thanks
I've tried to restructure your code so that's easier to edit. I've left some comments. I can really recommend refactoring.guru. There you will find many ways to improve your code so that it is more extensible, maintainable and testable. If you have any questions, please feel free to ask.
class Sale extends Model
{
// Use a relationship instead of building your own query
public function details() {
return $this->hasMany(SaleDetail::class);
}
}
class SaleDetail extends Model
{
// Use a computed property instead of manually calculating total price
// You can access it with $saleDetail->totalPrice
public function getTotalPriceAttribute() {
return $this->price * $this->quantity;
}
}
class UpdateSaleRequest extends Request
{
public function authorize() {
return true;
}
protected function prepareForValidation() {
$this->merge([
// Create a Carbon instance by string
'date' => Carbon::make($this->date)
]);
}
public function rules() {
// Your validation rules
// Please also validate your invoice items!
// See https://laravel.com/docs/8.x/validation#validating-arrays
}
}
// We let Laravel solve the sale by dependency injection
// You have to rename the variable name in ihr web.php
public function update(UpdateSaleRequest $request, Sale $sale)
{
// At this point, all inputs are validated!
// See https://laravel.com/docs/8.x/validation#creating-form-requests
$sale->update($request->validated());
// Please ensure, that all properties have the same name
// In your current implementation you have price = cost, be consistent!
foreach($request->input('invoiceItems') as $invoiceItem) {
// How we can consider that a detail is already created?
// I assume that each item_id will only occur once, otherwise you'll
// place the id of each detail in your update form (e.g. in a hidden input)
$candidate = $sale->details()
->where('item_id', $properties['item_id'])
->first();
if($candidate) {
$candidate->update($properties);
} else {
$sale->details()->create($properties);
}
}
// A JWT-Exception should not be necessary, since your authentication
// will be handled by a middleware.
return response()->json($sale);
}
I have not tested the code, few adjustments may be needed.
Laravel has a method called updateOrCreate as follow
/**
* Create or update a record matching the attributes, and fill it with values.
*
* #param array $attributes
* #param array $values
* #return \Illuminate\Database\Eloquent\Model|static
*/
public function updateOrCreate(array $attributes, array $values = [])
{
return tap($this->firstOrNew($attributes), function ($instance) use ($values) {
$instance->fill($values)->save();
});
}
That means you could do some thing like
public function update(UpdateSaleRequest $request, $id)
{
try {
$sale = Sale::find($id);
$data = $request->all();
$update['date'] = date('Y-m-d', strtotime($data['date']));
$update['company_id'] = $data['company_id'];
$update['name'] = $data['name'];
$update['remarks'] = $data['remarks'];
$sale->update($update);
foreach ($data['invoiceItems'] as $item) {
$details = [
'item_id' => $item['item_id'],
'employee_id' => $item['employee_id'],
'quantity' => $item['qty'],
'price' => $item['cost'],
'total_price' => $item['cost'] * $item['qty'],
'sale_type_id'=>$item['sale_type_id']
];
$sale->saleDetail()->updateOrCreate([
'sale_id' => $sale->id
], $details);
}
} catch (JWTException $e) {
throw new HttpException(500);
}
return response()->json($sale);
}
I would encourage you to refactor and clean up your code.You can also read more about it here https://laravel.com/docs/8.x/eloquent#upserts

Put other function on FormRequest in Laravel

I'm building a Laravel 6 application, and I am concerned about "best practices." I have one controller named CustomerController. In my controller, I want to update the Customer model, so I will have a function like the following.
public function update(UpdateCustomer $request, Customer $customer){
//
}
UpdateCustomer is my form request and where I will do the validation. In my update() method, I have classic validation.
public function rules()
{
$validationArray = [];
$validationArray['customer.name'] = 'string|required';
$validationArray['customer.vat'] = 'string|required';
$validationArray['customer.email'] = 'email|required';
return $validationArray;
}
Now I have to do some particular validation other the classic.
Let's assume that I have more data in my model, and I don't want these values to be changed.
For example, I have the following: address, cap, locality. I have a second method on the UpdateCustomer request that I can validate.
public function validateForDataCantChange()
{
$data = $this->input("customer");
$customer = $this->route("customerID");
$validator = Validator::make([], []); // Empty data and rules fields
$arrayDataThatCantChange = [
'address' => $data['address'] ?? NULL,
'cap' => $data['cap'] ?? NULL,
'locality' => $data['locality'] ?? NULL
];
foreach ($arrayDataThatCantChange as $key => $v) {
if ($customer->{$key} !== $v) {
$validator->errors()->add($key, __("messages.the field :field can't be changed", ['field' => $key]));
}
}
if ($validator->errors()->any()) {
throw new ValidationException($validator);
}
}
And then in my controller, I've added the following.
public function update(UpdateCustomer $request, Customer $customer){
$request->validateForDataCantChange();
}
Is this a bad practice? Should I create a new FormRequest? How, in this case (two form requests), can I use two different requests for a single controller?
For the little effort required, I'd personally create a new form request.
If you wish to use the same form request you can do the following:
public function rules()
{
$rules = [
'title' => 'required:unique:posts'
];
// when editing i.e. /posts/2/edit
if ($id = $this->segment(2)) {
$rules['title'] .= ",$id";
}
return $rules;
}
However, I always use a separate class for each action.

How to ajaxify Zend_Form validation

I have a Zend_Form subclass. Some elements are set to belong to arrays.
class My_Form extends Zend_Form {
public function __construct() {
$elem = $this->createElement('text','PROJECT_NAME',
array(
'required' => true
));
$elem->setBelongsTo('project');
$this->addElement($elem);
$elem = $this->createElement(
'text','PLANNED_END_DATE',
array(
'required' => true
)
);
$elem->setBelongsTo('project');
$elem->addValidator(new Zend_Validate_Date(array('format'=>'yyyy-MM-dd')));
$this->addElement($elem);
//and so on
}
}
I have a universal validation controller which does create the form and checks for errors, and returns them in json format:
class ValidateController extends Zend_Controller_Action
{
public function formAction()
{
$params = $this->_getAllParams();
if (isset($params['_frm'])) {
$formName = detect_the_form_class($params['_frm']);
if (class_exists($formName)) {
$form = new $formName();
if ($form instanceof Zend_Form) {
$result = $form->isValidPartial($params);
$messages = $form->getMessages();
$this->getResponse()
->setHeader('Content-Type', 'application/json')
->setBody(json_encode(array(
'result' => $result,
'messages' => $messages
)));
} else {
$this->getResponse()->setHttpResponseCode(500);
}
}
}
}
}
This controller works great for non-array forms, but the form I now need to validate hase arrays, eg elements with name 'project[PROJECT_NAME]'.
But the $form->getMessages() returns messages indexed with base name of elements, without array prefix.
The actual result is:
{ result: false,
messages: {
PROJECT_NAME: {isEmpty: "Value is required"},
PROJECT_END_DATE: {isEmpty: "Value is required"}
}
}
The result I need is:
{ result: false,
messages: {
"project[PROJECT_NAME]": {isEmpty: "Value is required"},
"project[PROJECT_END_DATE]": {isEmpty: "Value is required"}
}
}
or something similar, so I can find the element the validation message is for.
Any ideas?
For subforms use Zend_Form_Subform class:
class My_Form extends Zend_Form
{
public function init()
{
$subForm = new Zend_Form_SubForm();
$elem = $this->createElement('text', 'PROJECT_NAME', array(
'required' => true
));
$subForm->addElement($elem);
$elem = $this->createElement('text', 'PLANNED_END_DATE', array(
'required' => true
));
$subForm->addElement($elem);
$this->addSubForm($subForm, 'project');
}
}
Response:
{
"project":{
"PROJECT_NAME":{"isEmpty":"Value is required and can't be empty"},
"PLANNED_END_DATE":{"isEmpty":"Value is required and can't be empty"}
}
}
For form config it is recommended to use init() method.
For json response you can use build-in action helper:
$this->_helper->json($form->getMessages());

cakephp validation response returning data to controller

Hi i have made a custom validation in the model. How can i access the result($visitor) from this in the controller?
model:
<?php
class Visitors extends AppModel
{
var $name = 'Visitors';
var $validate = array(
'xxx' => array(
'rule' => array('checkxxx'),
'message' => 'yyy.'
)
);
function checkIxxx($check){
$visitor = $this->find('first', array('conditions' => $check));
return $visitor;
}
}
?>
in my controller i want this:
function start() {
$this->Visitors->set($this->data);
if($this->Visitors->validates())
{
if($this->Visitors->xxx->type == 'value') //this is a value from the $visitor array in the model**
{
//do something
}
}
is this possible?
Updated to be a relevant answer, apologies.
//Model
var myField = 'invalid';
function myValidation($var){
if($var === true){
// Passed your validation test
$this->myField = 'valid';
}else{
$this->myField = 'invalid';
}
}
// Controller
$this->Model->set($this->data);
$this->Model->validates($this->data);
if($this->Model->myfield == 'valid'){
// Field has passed validation
}
You will want to use
$this->Model->invalidFields()
PS: You dont follow cake conventions
the model should be "Visitor" (singular)

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