Yii ClinkPager doesn't work on Ajax Request - ajax

Firstly, when the page gets loaded, ClinkPager works properly with all the paging correctly displayed.
But when Ajax Request is sent, the results get populated correctly with all the paging.
But clicking on the next or another page in the Paging, the previous data gets loaded and also paging shows different sequence.
/*Controller action to fetch the records and apply the pagination*/
//---------------------------------------------------------------
public function actionGetUser($user_id=null)
{
$user_domain= (isset($_POST['user_domain'])?$_POST['user_domain']: null);
$model=new UserSearch();
$criteria=new CDbCriteria();
//If Category/Title are also specified for search, then its an Ajax request.
if((isset($_POST['ajax_search'])) && ($_POST['ajax_search']==1))
{
//Change the search criteria accordingly
$criteria->select="*";
if($user_domain!= null)
{
//Adding criteria to search for ideas of specific domain
$criteria->addCondition("user_domain=".$usr_domain);
}
}
//Retrieve the users.
$searchData = $model->search();
//Count the no. of results retrieved.
$count=UserSearch::model()->count($criteria);
//Enable pagination
$pages=new CPagination($count);
$searchData->setPagination($pages);
$pages->applyLimit($criteria);
//Search for ideas satisfying that criteria
$models=userSearch::model()->findAll($criteria);
if((isset($_POST['ajax_search'])) && ($_POST['ajax_search']==1))
{
//Rendering the respective page
$this->renderPartial('renderOnAjax', array(
'user' => $models,
'pages' => $pages,
'user_count'=>$count
));
}
else
{
//Rendering the respective page
$this->render('render', array(
'user' => $models,
'pages' => $pages,
'user_count'=>$count
));
}
}
//------------------------------------------------------------
/*render page*/
//------------------------------------------------------------
<div>
<div class="userInfo" id="user_search_result">
<?php $this->renderPartial("renderOnAjax",array('user'=>$user, 'pages'=>$pages));?>
</div>
</div>
//------------------------------------------------------------
/*renderOnAjax Page*/
//------------------------------------------------------------
<?php
$i=0;
$count=count($user);?>
<?php while($i!=$count) {?>
<?php $row=$count[$i];?>
<div class="Box">
/*Some contain to display...*/
</div>
<?php $i++;?>
<?php } ?>
<div class="row">
<?php $this->widget('CLinkPager', array(
'pages' => $pages
));
?>
</div>
//---------------------------------------------------------

try
<?php $this->renderPartial("renderOnAjax",array('user'=>$user, 'pages'=>$pages),false,true);?>
Here is official documentioan for renderPartial
public string renderPartial(string $view, array $data=NULL, boolean $return=false, boolean $processOutput=false)
$view=string name of the view to be rendered. See getViewFile for details about how the view script is resolved.
$data=array data to be extracted into PHP variables and made available to the view script
$return=boolean whether the rendering result should be returned instead of being displayed to end users
$processOutput=boolean whether the rendering result should be postprocessed using processOutput.
{return} string the rendering result. Null if the rendering result is not required.
EDIT:
The above scheme works for ajax call renderPArtials. You should try this where you are rendering ajax request in controller action like
$this->renderPartial('renderOnAjax', array(
'user' => $models,
'pages' => $pages,
'user_count'=>$count
),false,true);

Related

yii2 not rendering to view just refreshing the page

view.php code part:
View Picture
viewgood.php
<?php
echo 'hello';
GoodsController.php
public function viewgood($id = null) {
}
After clicking on button View Picture my page just refreshing instead of going to viewgood.php
What am I doing incorrectly?
I am a begginer in Yii2
Try use
View Picture
in a anchor tag html your need use the complete route, for use shortcut you try use
<?= Html::a('View Picture', ['/goods/viewgood/', 'id' => $good['GoodGallery'][0]['id']], ['class' => 'btn btn-primary']) ?>
view.php
You can use Html:a(), or in your example use Url helper to() function to generate the proper route for your anchor tag.
View Picture
GoodsController.php
public function actionViewgood($id=null){
//fetch the data e.g.
$model = Good::findOne(id);
//Do some extra code checking when no record is found like throw an exception or set a flash error message, etc.
//render the viewgood and pass the data (if needed)
return $this->render('viewgood', [
'model' => $model
]);
}
viewgood.php
<?php
//do what you want with the data passed by the controller. E.g. print the name of the good (if applicable)
echo $model->name;
//your other code ...
?>

Drupal 7 - Ajax and Bootstrap - Rerender Main Menu on Login

How can I rerender the main menu in Drupal after an Ajax Login?
I already tried the following (generating the return value in my PHP Ajax Controller):
$tree = menu_tree_all_data('main-menu');
$returnValue = drupal_render(menu_tree_output($tree));
However this will not include the Bootstrap specific class names. It basically just returns a minimalistic menu structure without anything added by the theme.
In the Bootstrap theme, the menu is rendered like this:
<?php if (!empty($primary_nav)): ?>
<?php print render($primary_nav); ?>
<?php endif; ?>
<?php if (!empty($secondary_nav)): ?>
<?php print render($secondary_nav); ?>
<?php endif; ?>
How can I enforce this type of rendering from my module?
Since I am working on an ajax one pager site, I need to update the menu based on a user's role after login. A page reload would destroy the desired look and feel, and is therefore no option.
Currently I am using the following code to process the login:
function wr_pages_form_alter(&$form, $form_state, $form_id) {
if ($form_id == 'user_login_block' || $form_id == 'user_login') {
$form['actions']['submit']['#ajax'] = array(
'callback' => 'wr_login_form_callback',
'wrapper' => 'user-login',
'method' => 'replace',
'effect' => 'fade',
'event' => 'click'
);
}
}
function wr_login_form_callback($form, $form_state) {
if (!form_get_errors()) {
return "<script>adjustViewsAndMenu();</script>";
}
else {
return $form;
}
}
adjustViewsAndMenu() makes changes to the menu, and adds extra parts to the one pager, depending on a user's role, however this function does not use any Drupal rendering, which is most likely not the best way to deal with this problem. Still haven't found out how to rerender a menu with AJAX while using the theme's rendering.

CodeIgniter update page - Simple CRUD website assistance required

After looking through the forums and starting to try to create a basic CRUD website I am currently struggling to have a page that updates the articles as follows. If someone could kindly tell me where I am going wrong, I will be most greatful. I am getting a 404 error at 'news/input'
model (at news_model.php)
public function update($id, $data)
{
$this->db->where('id', $id);
$this->db->update('news', $data);
}
controller (news.php)
public function update($id){
$data = array(
'title' => $this->input->post('title'),
'slug' => $this->input->post('slug'),
'text' => $this->input->post('text'));
if($this->news_model->exists($id)) {
$this->news_model->update($id, $data);
}
else {
$this->news_model->insert($data);
}
}
html (views/news/input.php)
<h2>Update a news item</h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/update') ?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="slug">Slug</label>
<input type="input" name="slug" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Update an item" />
You get a 404 because your news controller seems to have no method 'input'. Try adding something like this:
public function input(){
// load the form
$this->load->view('/news/input');
}
Note that for updating data you will need to fetch and pass it into the view first, then render the (filled out) form using set_val() and other CI functions.
Currently you're "hardcoding" the HTML form which makes populating and maintaining state (when validation fails) difficult. I suggest you play through the forms tutorial on the CI website.
Edit:
To create a update/insert (upsert) controller change as follows:
Controller:
function upsert($id = false){
$data['id'] = $id; // create a data array so that you can pass the ID into the view.
// you need to differntiate the bevaviour depending on 1st load (insert) or re-load (update):
if(isset($_POST('title'))){ // or any other means by which you can determine if data's been posted. I generally look for the value of my submit buttons
if($id){
$this->news_model->update($id, $this->input->post()); // there's post data AND an id -> it's an update
} else {
$this->news_model->insert($id, $this->input->post()); // there's post data but NO id -> it's an insert
}
} else { // nothing's been posted -> it's an initial load. If the id is set, it's an update, so we need data to populate the form, if not it's an insert and we can pass an empty array (or an array of default values)
if($id){
$data['news'] = $this->news_model->getOne($id); // this should return an array of the news item. You need to iterate through this array in the view and create the appropriate, populated HTML input fields.
} else {
$data['news'] = $this->news_model->getDefaults(); // ( or just array();) no id -> it's an insert
}
}
$this->load->view('/news/input',$data);
}
And amend the $id to the action-url in your view:
<?php echo form_open('news/upsert/'.$id) ?>

Form validation error not outputted in PyroCMS

Using PyroCMS 1.3.1 I've built a model that's pretty much a copy-paste version of the included contact model, but with a few tweaks. When all fields are inputted correctly everything works as expected. If a field is left out or incorrectly filled in, the form does not submit - just as expected.
However, I can't seem to get the form validation message to be outputted and this is driving me crazy. I'm sure I've just missed something very basic so if anyone could point it out I'd be grateful.
View file (form.php) contains this
<?php if (validation_errors()): ?>
<div class="error-box">
<?php echo validation_errors(); ?>
</div>
<?php elseif (isset($messages['error'])): ?>
<div class="error-box">
<p><?php echo $messages['error']; ?></p>
</div>
<?php endif; ?>
Controller (plugin.php) looks like this
class Plugin_mycustommodule extends Plugin {
private $rules = array(
array(
'field' => 'firstname',
'label' => 'lang:mycustommodule_firstname_label',
'rules' => 'required|trim|max_length[80]'
),
/* ... snip ... */
array(
'field' => 'license',
'label' => 'lang:mycustommodule_license_label',
'rules' => 'required'
)
);
public function __construct()
{
$this->lang->load('mycustommodule');
}
function form()
{
$this->load->library('form_validation');
$this->load->helper('form');
$this->form_validation->set_rules($this->rules);
// If the user has provided valid information
if ($this->form_validation->run())
{
/* ... Custom processing here ... */
// The try to send the email
if ($this->_send_email())
{
$message = $this->attribute('confirmation', lang('mycustommodule_sent_text'));
// Store this session to limit useage
$this->session->set_flashdata('success', $message);
redirect(current_url());
}
else
{
$message = $this->attribute('error', lang('mycustommodule_error_message'));
$data['messages']['error'] = $message;
}
}
// Set the values for the form inputs
foreach ($this->rules as $rule)
{
$form_values->{$rule['field']} = set_value($rule['field']);
}
$data['form_values'] = $form_values;
return $this->module_view('mycustommodule', 'form', $data, TRUE);
}
So it turns out that while I was working on customizing the CodeIgniters language files I must have messed up the upload of form_validation_lang.php because all entries was empty i.e. $lang['required'] = '';
So basically the validator looked for the error message, found an empty string, which was trimmed from being outputted. As suspected something silly, just not in the place I expected.
Let's hope this post will save someone else the trouble.

Action not running with CakePHP Js->submit()

I'm using CakePHP 1.3, and trying to make a simple message posting board with ajax. I'm trying to use the Js helper to submit a form on the index page, then refresh the message board's div to include the new message. This is all on a single page.
I have previously posted on this, but I wanted to rephrase the question and include some updates. The previous question can be seen here How to use Js->submit() in CakePHP?
When I came back to this project after a couple days, I immediately tested and the form worked (sort of). Submitting the form added a message to the database (it didn't display the message, but I haven't attacked that part yet). It worked 2 times, adding 2 messages. Then I opened the controller file and commented out some debug code, and it stopped working. It appears the action is not being called.
Here is my messages_controller.php:
<?php
class MessagesController extends AppController {
function index() {
$messages = $this->Message->find('all');
$this->set('messages',$messages);
}
function add() {
$this->autoRender = false;
$this->Session->setFlash('Add action called');
if($this->RequestHandler->isAjax()) {
$this->Session->setFlash('Ajax request made');
$this->layout = 'ajax';
if(!empty($this->data)) {
if($this->Message->save($this->data)) {
$this->Session->setFlash('Your Message has been posted');
}
}
}
}
}
?>
Here is the index.ctp for my Message class
<div id="guestbook" class="section_box">
<h3 id="toggle_guestbook"><div class="toggle_arrow"></div>Sign our Guestbook</h3>
<?php
echo $this->Form->create('Message');
echo $this->Form->input('name', array('label' => 'From:'));
echo $this->Form->input('text', array('label' => 'Message:'));
echo $this->Js->submit('Post Your Message', array(
'url' => array(
'controller' => 'messages',
'action' => 'add'
),
'update' => '#message_board'
));
echo $this->Form->end();
echo $this->Js->writeBuffer(array('inline' => 'true'));
?>
<div id="message_board">
<?php foreach($messages as $message) { ?>
<div class="message">
<p class="message_txt">
<?php echo $message['Message']['text']; ?>
</p>
<div>
<div class="message_name">
<?php echo $message['Message']['name']; ?>
</div>
<div class="message_date">
<small>
<?php echo $message['Message']['date']; ?>
</small>
</div>
</div>
</div>
<?php } ?>
</div>
</div>
When the submit button is clicked, I can see in the console that a POST is made to http://localhost/messages/add with the correct data. But there doesn't appear to be a response. The flash message "Add action called" is NOT set from the controller (or any of the flash messages, for that matter) and the contents of #message_board are emptied.
If I refresh the page at this point, the SECOND flash message appears ("Ajax request made"), and the contents of the #message_board are restored. However the new message was not saved, its the same 2 messages from before.
I'm stumped. I have a feeling maybe there are bigger issues causing my problem, but I can't see it. Any help would be appreciated.
But there doesn't appear to be a
response ... and the
contents of #message_board are
emptied.
That is because you haven't set what action/view to render. You have to do this manually since you have $this->autoRender set to false. You could use render() to do this. More info can be found at its respective cookbook page.
If you have $this->autoRender set to true, then it'll replace the contents of #message_board with the contents of add.ctp
The flash message "Add action called"
is NOT set from the controller (or any
of the flash messages, for that matter)
I think you have to refresh the page or the part which contains the $this->Session->flash() bit for flash messages to appear.
The fact that the flash message appeared when you refreshed the page means that it did call and run the action.
AFAIK, you can only put/print one message from the flash key in the Messages array. The flash key is where the flash messages are stored by default. Each call to setFlash() will overwrite the flash message set by older calls.
Since only the second flash message was displayed, we could say that it failed at passing at least one of the conditions following the second call to setFlash() in the controller. You might want to put debug($this->data) statements near the conditions related to $this->data to help yourself in debugging your problem.
You could also use debug() to know if your application went through a certain action or path since it will almost always be displayed.
So you could do the following to check if it passed this condition:
if(!empty($this->data)) {
debug('Passed!');
If 'Passed!' will be printed after submitting the form, we would know that it passed that condition.
However the new message was not saved
It might be because $data is empty or it failed at validation. If your $data is not empty, it might have failed at validation and since your form doesn't display the validation errors; you might never have noticed them. One way to know if it passed validation is to do the following:
$this->Message->set($this->data);
if ($this->Message->validates()) {
debug('it validated logic');
} else {
debug('didn't validate logic');
}
Ramon's solutions worked for me. Here's the updated code.
Controller add function
function add() {
$this->autoRender = false;
if($this->RequestHandler->isAjax()) {
$this->layout = 'ajax';
if(!empty($this->data)) {
if ($this->Message->validates()) {
if($this->Message->save($this->data)) {
$this->render('/elements/message_board');
} else {
debug('didn\'t validate logic');
}
}
}
}
}
Heres the add form view:
<?php
echo $this->Form->create('Message');
echo $this->Form->input('name', array('label' => 'From:'));
echo $this->Form->input('text', array('label' => 'Message:'));
echo $this->Js->submit('Post Your Message', array(
'url' => array(
'controller' => 'messages',
'action' => 'add'
),
'update' => '#message_board'
));
echo $this->Form->end();
echo $this->Js->writeBuffer(array('inline' => 'true'));
?>
<?php pr($this->validationErrors); ?>
<div id="message_board">
<?php echo $this->element('message_board'); ?>
</div>
I tried to use the same solution as you used but it's not working. Ajax is ok when I access it directly in the URL, and I have the impression that the click is doing nothing. When I use
<fieldset><legend><?php __(' Run 1');?></legend>
<div id="formUpdateID"><div id="#error-message"></div>
<?php
$orders=array_merge($emptyarray,$orders['r1']['Order']);
echo $this->Form->create('Order');
echo $this->Form->input('id', array('value'=>$orders['id'],'type' =>'hidden'));
echo $this->Form->input('race_id', array('value'=> $orders['race_id'],'type' =>'hidden'));
echo $this->Form->input('driver_id', array('value'=>$session->read('Auth.User.driver_id'),'type' =>'hidden'));
echo $this->Form->input('run', array('value'=>$run,'type' =>'hidden'));
echo $this->Form->input('pm', array('value'=>$orders['pm'],'error'=>$err[$run]));
echo $this->Form->input('pr', array('value'=>$orders['pr'],'error'=>$err[$run]));
echo $this->Form->input('fuel', array('value'=>$orders['fuel'],'error'=>$err[$run]));
echo $this->Form->input('pit', array('value'=>$orders['pit'],'label' => __('Pit on lap '),'error'=>$err[$run]));
echo $this->Form->input('tyre_type', array('value'=>$orders['tyre_type'],'error'=>$err[$run]));
echo $this->Js->submit('Modify', array(
'url' => array(
'controller' => 'orders',
'action' => 'ajax_edit'
),
'update' => '#error_message'
));
echo $this->Form->end();
?>
<?php pr($this->validationErrors); ?>
</div></fieldset>
in view and in controller "orders":
function ajax_edit($id=null){
$this->autoRender = false;
if($this->RequestHandler->isAjax()) {
die(debug('In Ajax'));
$this->layout = 'ajax';
debug('didn\'t validate logic');
}
echo 'hi';
}
None of the messages are displayed.
I have some hard coded JS/ajax before which is not targeting this code part.
I did copy ajax layout in th webroot/view folder.
I can see the AJAX code displayed in formatted source code
<div class="submit"><input id="submit-1697561504" type="submit" value="Modify" /></div> </form><script type="text/javascript">
//<![CDATA[
$(document).ready(function () {$("#submit-1697561504").bind("click", function (event) {$.ajax({data:$("#submit-1697561504").closest("form").serialize(), dataType:"html", success:function (data, textStatus) {$("#error_message").html(data);}, type:"post", url:"\/Webmastering\/form1C\/frame\/orders\/ajax_edit\/1"});
return false;});});
//]]>
</script>
BTW, I start getting bored of the lack of doc in cakephp and its non efficacity to realize task more complicated than just posting a post in a blog. So thank you for your help before I start destroying my computer ;)
I know it's an old topic, but I stumbled acros the same problem in my application, so now I think what Thrax was doing wrong, namely he didn't put echo $this->Js->writeBuffer(array('inline' => 'true')); in the view (or in the layout) file, like Logic Artist did, so the scripts for handling the submit button's click weren't generated.

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