I was trying to select a particular record, which satisfies the condition if column1 = column2 + column3
SELECT gtt_id ,
column1,
SUM(NVL(column2, 0) + NVL(column3, 0)) AS total
FROM my_table where column1 = total
GROUP BY gtt_id,
column1;
I am getting the following error:
ORA-00904: "TOTAL": invalid identifier
You are not supposed to use total in the same query ,for that you need to wrap the query and use that in outer loop.
SELECT gtt_id,column1,total
FROM
(
SELECT gtt_id ,
column1,
SUM(NVL(column2, 0) + NVL(column3, 0)) total
FROM my_table
--where column1 = total
GROUP BY gtt_id,
column1
)
where column1 = total;
Related
I run a query that returns 2 rows
SELECT a FROM TABLE-A WHERE condition=something;
row1 Value1
row2 Value2
Now, I want to put it in a new table in 2 columns of a single row
SELECT column1, column2 FROM TABLE-B WHERE condition=something;
row1 column1 column2
value1 value2
Can you please help me with this?
It is unclear how you want to pick which row goes into which column - here are a couple of options:
SELECT MIN( a ) AS minimum_value,
MAX( a ) AS maximum_value
FROM table_a
WHERE 1=1;
or
SELECT MAX( a ) KEEP ( DENSE_RANK FIRST ORDER BY ROWNUM ) AS first_value,
MAX( a ) KEEP ( DENSE_RANK LAST ORDER BY ROWNUM ) AS last_value
FROM table_a
WHERE 1=1;
or
SELECT *
FROM ( SELECT a, ROWNUM AS rn FROM table_a WHERE 1=1 )
PIVOT ( MAX(a) FOR rn IN ( 1 AS first_value, 2 AS second_value ) );
I have a table with three columns.
I query that table with IN clause.
select column1 from table1 where column1 in (1,2,3) order by column2, column3
The table1 contains only values 1 and 2 in column1. I want to return the not available value also in my result, and that should be sorted in the bottom.
example data
column1 column 2 column 3
1 100 11
2 101 50
output, the not available values should be in the last.
column1 column 2 column 3
1 100 11
2 101 50
3 null null
I tried with subquery with NVL, like select nvl((select.. in(1,2,3)),null) from dual, due to IN Clause, I am getting single row subquery returns more than one row issue, which is expected.
Also tried with the union but nothing works. Great if any help. Thanks
I think you can do it with a union all:
select column1 from table1 where column1 in (1,2,3) order by column2, column3
union all
select null from table1 where column1 not in (1,2,3) order by column2, column3
If you can't take 1,2,3 values from another table you can try with:
with t1 as (
select col1,col2,col3
from tab1
where cod_flusso in ('1','2','3')),
t2 as (
select '1' as col1,null,null
from dual
union
select '2',null,null
from dual
union
select '3',null,null
from dual)
select t2.col1,col2,col3
from t2
left outer join t1
on t1.col1= t2.col1
It's better if you can store 1,2,3 values in a second table, then use left outer join.
I want to return data from duplicative rows
SELECT column1, column2 FROM table1
COLUMN1 COLUMN2
------- -------
CA 1
CB 2
CB 3
CC 4
CD 5
CE 6
CE 7
CE 8
CF 9
I want to return rows for 'CB' and CE. Here CB and CE has more than 1 row.
I'd code this as follows:
SELECT column1, column2 FROM table1 where column1 in ("CB", "CE")
Try this out - this query first finds out those items in column1 who appear multiple time and then extract their information.
select * from table1
where column1 in (
select column1
from table1
group by column1
having count(*) > 1
)
If you are only interested in knowing the values in column1, you could just run:
select column1
from table1
group by column1
having count(*) > 1
You Can try out this code. Basically the Query is in MySQL but you can use the same logic in Oracle Database. Here the inner subquery will find out the columns which is grouped by column1 and will return a column having a count greater than 1. The Outer query will display the rows of the column fetched by the inner query.Here I have created a table with the table name as name
SQL fiddle Added for your reference SQLCODE
select * from name where column1 in(select column1 from name
group by column1
having count(*)>1);
I have a table table1 below is how the data looks like.
Column1 is my foreign key of another table.
Column1 Column2 Column3
1 A 06/MAY/14
1 A 05/MAY/14
1 B 06/MAY/14
1 B 01/JAN/00
1 A 01/JAN/00
Now i want to find distinct column1 values where it meets the following condition.
1.atleast one record where column2 should be A and column3 should be (sysdate - 1)
AND
2.atleast one record where column2 should be B and column3 should be (sysdate - 1)
Meaning alteast one A and B should have their column 3 populated with (sysdate - 1)
I have written the below query, please tell if i'm doing anything wrong.
I also want to know if i'm doing the right way of joining. The table contains around 50K records and performance should be fine i guess.
SELECT DISTINCT COLUMN1 FROM
TABLE1 A
JOIN
TABLE1 B ON (A.COLUMN1 = B.COLUMN1)
WHERE
((TRUNC(A.COLUMN3) - TRUNC(A.COLUMN3) = 0)
AND TRUNC(A.COLUMN3) = TRUNC(SYSDATE - 1)
AND TRUNC(B.COLUMN3) = TRUNC(SYSDATE - 1)
AND A.COLUMN2 = 'A'
AND B.COLUMN2 = 'B'
AND TO_CHAR(A.COLUMN3, 'DD-MON-YY') != '01-JAN-00'
AND TO_CHAR(B.COLUMN3, 'DD-MON-YY') != '01-JAN-00'
);
For performance-comparison one with subselects and group:
SELECT COLUMN1 FROM (
SELECT
COLUMN1,
COUNT(COLUMN2) CNT
FROM (
SELECT DISTINCT
COLUMN1,
COLUMN2
FROM TABLE1
WHERE TRUNCATE(COLUMN3) = SYSDATE - 1 AND
(COLUMN2 = 'A' OR COLUMN2 = 'B'))
GOUP BY COLUMN1)
WHERE CNT = 2
This should work
SELECT DISTINCT A.column1 -- Obtain distinct from A
FROM table1 A -- TableA
join table1 B -- TableB
ON A.column1 = B.column1 -- Joining them on Column1
WHERE A.column3 = SYSDATE - 1 -- Yesterdays data on Table A
AND A.column2 = 'A' -- A values
AND B.column2 = 'B'; -- B Values
Note: No distinctness in your test case. So try with a unique key.
I have these codes:
select case
when exists (select 1
from table1
where id=608071)
then column1
else 0
end as abc
from table1 where id=608071;
and
select decode(count(column1), 0, column1) abc
from (select column1
from table1
where id=608071) group by column1;
and none of them returns me no column1, no 0, no error. It gives me null, i.e. nothing. No rows return. I need to get 0 when particular id does not exist. What is wrong in here?
try this!!
select case when exists (select 1 from table1 where id= '608071') then (select column1 from table1) else '0' end as abc from dual
Assuming this is your requirement: "I need to get 0 when particular id does not exist"
select
nvl(T.COLUMN1, 0) COLUMN1_OR_ZERO
from
DUAL D left join(
select
*
from
TABLE1
where
id = '608071') T on (1=1)
With this query, you only scan the table once.