Unable to Save form Django - ajax

Question

I am trying to save a form to update an existing user, but I am unable to get it to work. The error occurs when I try to save the form. The console shows the error occurs in the view (internal server error).
Form:
class updateFirstName(forms.ModelForm):
class Meta:
model = User
fields = ('first_name',)
def __init__(self, *args, **kwargs):
super(updateInfoForm, self).__init__(*args, **kwargs)
self.helper = FormHelper()
self.helper.form_id = 'id-updateFirst'
self.helper.form_class = 'blueForms'
self.helper.form_method = 'post'
self.helper.form_action = '/login/userInfoChange/'
self.helper.add_input(Submit('submit', 'Submit'))
view:
#json_view
#csrf_exempt
def userInfoChange(request):
context = RequestContext(request)
if request.method == 'POST':
user = User.objects.get(username=request.user.username)
user_form = updateFirstName(request.POST)
print user_form
if user_form.is_valid():
user_form.save()
print "Valid Form"
return {'success': True}
html:
<form id="updateUsername">
<div class="input-group">
<span class="input-group-btn">
<button class="btn btn-success" type="button" id="submit-username">Change</button>
</span>
<input type="text" class="form-control" id="id_firstname" placeholder="First Name: {{user.first_name}}">
<script type="text/javascript">
$('#submit-username').click(function(){
$.ajax({//begin
type: 'POST',
url: '/login/userInfoChange/',
data: $('#updateUsername').serialize(),
success: function(result){
console.log('updateUsername');
}
});
});
</script>
</div><br></form>
Model:
class UserProfile(models.Model):
user = models.OneToOneField(User)
confirmation_code = models.CharField(max_length=128)
reset_code = models.CharField(max_length=128)
address_lineOne = models.CharField(max_length=128)
address_lineTwo = models.CharField(max_length=128)
city = models.CharField(max_length=128)
State = models.CharField(max_length=128)
zipCode = models.CharField(max_length=10)
def __unicode__(self):
return self.user.username
Solution:
first_name = request.POST.get('first_name')
user.first_name = first_name
user.save()
Thanks ejey for resolving my csrf ajax issue.

Answer 1

If you are intending on posting using ajax you ought to use have a view method such as:
def some_ajax_view(request):
data = request.POST.copy()
if request.is_ajax() and request.POST:
...
...
You can get more information on how to process your ajax request without having to compromise on the csrf https://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ajax

Answer 2

Firstly, you didn't answer my question about the error message. This is a vital step in debugging, and it's very little use coming onto SO and asking questions without first finding the actual error and doing what you can to fix it yourself.
That said, you do have a huge obvious bug in your code. If the request is not a POST, and/or the form is not valid, what are you expecting to happen? Currently, your code just stops; so in either of those cases it will return None, which is an error: all views must return an HttpResponse. If you did look at the error message, that is probably what it would say.
You should ensure that your view at least returns an empty HttpResponse in either of those circumstances. More useful, though, would be a response that actually contains the errors from the form validation.