I have a file with very simple syntax:
cat /tmp/test
ARCH=""prtconf -b | awk '/^name:/ {print $2}'
I tried to grep it:
cat /tmp/test | grep "prtconf -b | awk '/^name:/ {print $2"
ARCH=""prtconf -b | awk '/^name:/ {print $2}'
Let's make grep string a little longer, add } to the end:
cat /tmp/test | grep "prtconf -b | awk '/^name:/ {print $2"}
Nothing found
Why when I add } to the end of the line grep stop working?
OS is Solaris 10U11
$2 refers to command-line parameter so here it will substitute blank character in a patter. So you'l need to escape $ by slash like \$
cat /tmp/test | grep "prtconf -b | awk '/^name:/ {print \$2}"
Without adding } in your patter it was working because it was matching actual pattern as prtconf -b | awk '/^name:/ {print for your input. But if you add } in your patter then it will try to match prtconf -b | awk '/^name:/ {print } (which isn't there in your file so it won't show output.)
Related
> root# ps -ef | grep [j]ava | awk '{print $2,$9}'
> 45134 -Dapex=APEC
> 45135 -Dapex=JAAA
> 45136 -Dapex=APEC
I need to put the first APEC of first as First PID, third line of APEC and Second PID and last one as Third PID.
I've tried awk but no expected result.
> First_PID =ps -ef | grep [j]ava | awk '{print $2,$9}'|awk '{if ($0 == "[^0-9]" || $1 == "APEC:") {print $0; exit;}}'
Expected result should look like this.
> First_PID=45134
> Second_PID=45136
> Third_PID=45135
With your shown samples and attempts please try following awk code. Written and tested in GNU awk.
ps -ef | grep [j]ava |
awk '
{
val=$2 OFS $9
match(val,/([0-9]+) -Dapex=APEC ([0-9]+) -Dapex=JAAA\s([0-9]+)/,arr)
print "First_PID="arr[1],"Second_PID=",arr[3],"Third_PID=",arr[2]
}
'
How about this:
$ input=("1 APEC" "2 JAAA" "3 APEC")
$ printf '%s\n' "${input[#]}" | grep APEC | sed -n '2p'
3 APEC
Explanation:
input=(...) - input data in an array, for testing
printf '%s\n' "${input[#]}" - print input array, one element per line
grep APEC - keep lines containing APEC only
sed -n - run sed without automatic print
sed -n '2p' - print only the second line
If you just want the APECs first...
ps -ef |
awk '/java[ ].* -Dapex=APEC/{print $2" "$9; next; }
/java[ ]/{non[NR]=$2" "$9}
END{ for (rec in non) print non[rec] }'
If possible, use an array instead of those ordinally named vars.
mapfile -t pids < <( ps -ef | awk '/java[ ].* -Dapex=APEC/{print $2; next; }
/java[ ]/{non[NR]=$2} END{ for (rec in non) print non[rec] }' )
After read from everyone idea,I end up with the very simple solution.
FIRST_PID=$(ps -ef | grep APEC | grep -v grep | awk '{print $2}'| sed -n '1p')
SECOND_PID=$(ps -ef | grep APEC | grep -v grep | awk '{print $2}'| sed -n '2p')
JAWS_PID=$(ps -ef | grep JAAA | grep -v grep | awk '{print $2}')
i have "handler: xyz.lambda_handler" text in one file and i want "xyz.lambda_handler" i.e text present next to "handler:" as output using shell script, how can i do this.
I have tried
awk -F '${handler}' '{print $1}' filename | awk '{print $2}
grep handler filename
command but not getting correct output
as mentioned in qtn.
I combined two commands and i got my answer
grep Handler: filename | awk -F '${handler}' '{print $1}' | awk '{print $2}'
grep givepattern givefilename | awk -F '${givepattern}' '{print $1}' | awk '{print $2}'
It's grep, not greap. To print only the matched parts of a matching line, use option -o.
grep -o xyz.lambda_handler filename
I have this where it could be one \ or multiple
C:\folder\file.log
C:\folder\folder\file.log
C:\folder\folder\folder\file.log
I want to get this
file.log
This works but its static with print $.
cat C:\folder\file.log | awk -F "\\" "{print $3}"
cat C:\folder\folder\file.log | awk -F "\\" "{print $4}
cat C:\folder\folder\folder\file.log | awk -F "\\" "{print $5}
How can i awk and always grab the data after the last \
You need the $NF special variable, which gives you the number of fields in your input.
echo C:\folder\file.log | awk -F "\\" "{print $NF}"
with grep:
grep -o '[^\\]*$' file
If you have awk, do you also have "basename"?
and as pointed out above, windows has similar capabilities built in.
I am trying to open some files as awk's output; the command is:
grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}'
and it (seems to) work correctly.
If I try to open that output as vim's tabs, like this:
vim -p ${ grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}' }
then I get:
-bash: ${ grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}' }: bad substitution
Any help? Thanks.
The way to execute a command is $(), whereas you are using ${}.
Hence, this should work:
vim -p $(grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}')
I want to create an alias for an long command. But I'm not able to escape it correct, I guess it's a problem with the pipes.
My original command
ps aux | grep gimp | awk '{ print $2 '\011' $11 }' | grep -v 'grep'
My attempt for an alias
alias psa="ps aux | grep $1 | awk '{ print \$2 \"\011\" \$11 }' | grep -v 'grep'"
But I get an error that grep can not open file foo (when I do psa foo)
When I remove the last part | grep -v 'grep' then awkthrows the same error.
I prefer an alias before an shell script.
You need to use a function if you want to to insert arguments:
psa() {
ps aux | grep "$1" | awk '{print $2 "\t" $11 }' | grep -v grep
}
You can avoid all the escaping by using a function for this:
myps() {
ps aux | grep gimp | awk '{ print $2 "\011" $11 }' | grep -v 'grep'
}