I am trying to write Query using JPA Criteria API. I have the following classes:
Class Booking {
#ForeignKey(name = "BVisit_ID_FK")
private List<BVisit> BVisits = new LinkedList<>();
//other properties
...
}
Class Visit{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID")
private Long id;
}
Class VisitSpecial extends Visit{
#Column(name = "ARRIVAL_TIME", nullable = false)
private Date arrivalTime;
#Column(name = "DEPARTURE_TIME", nullable = false)
private Date departureTime;
//other properties...
}`
How can I write query using JPA Criteria Api (and metamodels) that will find all bookings that have
visits with date value(parameter) that is between min arrival time, an max departure time for its booking visits.
I use org.springframework.data.jpa.domain.Specification
The query should look like something like this:
SELECT Booking
from Booking B, Visit V, VisitSpecial VS
where Visit.bookingId = Booking.id and Visit.id = VisitSpecial.id
and VisitSpecial.arrivalTime = (SELECT MIN(VisitSpecial.arrivalTime) from VisitSpecial VS1 WHERE V.id = VS1.id)
and VisitSpecial.arrivalTime <= :date
and VisitSpecial.departureTime = (SELECT MAX(VisitSpecial.departureTime) from VisitSpecial VS1 Where V.id = VS1.id)
and VisitSpecial.departureTime >= :date
See my answer here for dealing with InheritanceType.JOINED and other inheritance strategies through JPA Criteria Subquery.
Downcasting with treat may work, but I do not recommend it for complex queries as it may produce inefficient queries (redundant joins) or not work at all based on your JPA provider (Hibernate, Eclipselink, etc.).
Related
Consider the entities below -
#Entity
public class Employee {
#Id
#GeneratedValue
private long id;
private String name;
#OneToMany(mappedBy = "employee", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private List<Phone> phones; //contains both "active" & "inactive" phones
}
#Entity
public class Phone {
#Id
#GeneratedValue
private long id;
private boolean active;
private String number;
#ManyToOne(fetch = FetchType.LAZY)
private Employee employee;
}
I need to pull all the employees and sort them depending on the count of "active" phones they have.
Please note that the employee can have active as well as inactive phones. So the query I am trying to achieve is
ORDER BY (SELECT
COUNT(phone4_.employee_id)
FROM
phone phone4_
WHERE
employee4_.id = phone4_.employee_id
AND phone4_.active = true
) DESC
I am stuck with specification here because of some reason and below is the code I have used -
List<Order> orders = new ArrayList<>();
orders.add(cb.desc(cb.size(employee.get("phones"))));
cq.orderBy(orders);
When I run the code the query that's get generated is
ORDER BY (SELECT
COUNT(phone4_.employee_id)
FROM
phone phone4_
WHERE
employee4_.id = phone4_.employee_id) DESC
I am unable to add an extra AND condition to the logic. Please suggest
As specified in the Persistence API specification:
4.6.16 Subqueries
Subqueries may be used in the WHERE or HAVING clause.
JPA doesn't support subqueries in the order by clause, nor in the select clause.
Hibernate ORM, though, supports them in the SELECT and WHERE clauses.
So you cannot write that query and being JPA compliant.
This HQL should work though and it's covered by Hibernate ORM:
SELECT e1, (SELECT count(p)
FROM Phone p
WHERE p.active = true AND p.employee = e1) as activeCount
FROM Employee e1
ORDER BY activeCount DESC
Surprisingly, writing this query with criteria doesn't work:
CriteriaBuilder builder = ormSession.getCriteriaBuilder();
CriteriaQuery<Object> criteria = builder.createQuery();
Root<Employee> root = criteria.from( Employee.class );
Subquery<Long> activePhonesQuery = criteria.subquery( Long.class );
Root<Phone> phoneRoot = activePhonesQuery.from( Phone.class );
Subquery<Long> phonesCount = activePhonesQuery
.select( builder.count( phoneRoot ) )
.where( builder.and( builder.isTrue( phoneRoot.get( "active" ) ), builder.equal( phoneRoot.get( "employee" ), root ) ) );
criteria.multiselect( root, phonesCount )
.orderBy( builder.desc( phonesCount ) );
The reason is that, Hibernate ORM tries to expand the subquery in the order by clause instead to refer to an alias. And as I mentioned before, this is not supported.
I think the HQL is the easiest option if you don't want to use native queries.
i'm using Spring Boot 2.4.2 and Data module for JPA implementation.
Now, i'm using an Oracle View, mapped by this JPA Entity:
#Entity
#Immutable
#Table(name = "ORDER_EXPORT_V")
#ToString
#Data
#NoArgsConstructor
#EqualsAndHashCode(onlyExplicitlyIncluded = true)
public class OrderExportView implements Serializable {
private static final long serialVersionUID = -4417678438840201704L;
#Id
#Column(name = "ID", nullable = false)
#EqualsAndHashCode.Include
private Long id;
....
The view uses an UNION which allows me to obtain two different attributes of the same parent entity, so for one same parent entity (A) with this UNION I get the attribute B in row 1 and attribute C in row 2: this means that the rows will be different from each other.
If I run the query with an Oracle client, I get the result set I expect: same parent entity with 2 different rows containing the different attributes.
Now the issue: when I run the query with Spring Data (JPA), I get the wrong result set: two lines but duplicate.
In debug, I check the query that perform Spring Data and it's correct; if I run the same query, the result set is correct, but from Java/Spring Data not. Why??
Thanks for your support!
I got it! I was wrong in the ID field.
The two rows have the same parent id, which is not good for JPA, which instead expects a unique value for each line.
So, now I introduced a UUID field into the view:
sys_guid() AS uuid
and in JPA Entity:
#Id
#Column(name = "UUID", nullable = false)
#EqualsAndHashCode.Include
private UUID uuid;
#Column(name = "ID")
private Long id;
and now everything works fine, as the new field has a unique value for each row.
I have two entities(Invoice and InvoiceItems) without adding any relationship.
Invoice
public class Invoice {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long invoiceID;
#Column(name="code")
private String code;
//other columns
}
Invoice Items
public class InvoiceItems {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long invItemID;
#Column(name="invoice_id")
private Integer invoiceId;
//other columns
}
Can I join these entities and get data without adding relationship using JPA?
If it isn't possible how to join 2 entities using JPQL or Native query?
If your data is valid then using native query you can do that
#Query(nativeQuery = true, "select * from Invoice i join InvoiceItems im on i.id = im.invoice_id")
public List<Invoice> findData();
But that is not a good way join without relation using JPA.
Yes, you can join these entities and get data without adding relationship using JPA, but it's a little bit losing the purpose of using JPA.
You need to create a java class first, which will be the returning data object from the DB. After that you can use entityManager's createNamedQuery method to get the result.
createNamedQuery(String sqlString, ResultClass.Class)
sqlString may be something like:
SELECT INV.INVOICE_ID
INV.CODE
INV_ITEMS.INV_ITEM_ID
FROM INVOICE INV
JOIN INVOICE_ITEMS INV_ITEMS
ON INV.INVOICE_ID = INV_ITEMS.INVOICE_ID;
And the corresponding ResultClass:
public class ResultClass {
private Long invoiceID;
private String code;
private Long invItemID;
// other columns
}
Or you can even use RowMapper to map the object all by yourself for more flexibility by using JdbcTemplate with query() method.
I have problem to select all value from one table and few other columns using Spring Data JPA. I am using PostgreSql database and when I send query through PgAdmin I get values I want, but if I use it in Spring Boot Rest returns only one table values (subquery not working). What I am doing wrong?
#Query(value = "SELECT item.*, MIN(myBid.bid) AS myBid, (SELECT MIN(lowestBid.bid) AS lowestbid FROM bids lowestBid WHERE lowestBid.item_id = item.item_id GROUP BY lowestBid.item_id) FROM item JOIN bids myBid ON item.item_id = myBid.item_id WHERE myBid.user_id = :user_id GROUP BY item.item_id", nativeQuery = true)
public List<Item> findAllWithDescriptionQuery(#Param("user_id") UUID userId);
Added Item class
#Data
#Entity(name = "item")
public class Item {
#Id
#GeneratedValue
private UUID itemId;
#NotNull
#Column(name = "title")
#Size(max = 255)
private String title;
#NotNull
#Column(name = "description")
private String description;
#NotNull
#Column(name = "created_user_id")
private UUID createdUserId;
}
The result from your native query cannot simply be mapped to entities due to the in-database aggregation performed to calculate the MIN of own bids, and the MIN of other bids. In particular, your Item entity doesn't carry any attributes to hold myBid or lowestbid.
What you want to return from the query method is therefore a Projection. A projection is a mere interface with getter methods matching exactly the fields returned by your query:
public interface BidSummary {
UUID getItem_id();
String getTitle();
String getDescription();
double getMyBid();
double getLowestbid();
}
Notice how the query method returns the BidSummary projection:
#Query(value = "SELECT item.*, MIN(myBid.bid) AS myBid, (SELECT MIN(lowestBid.bid) AS lowestbid FROM bids lowestBid WHERE lowestBid.item_id = item.item_id GROUP BY lowestBid.item_id) FROM item JOIN bids myBid ON item.item_id = myBid.item_id WHERE myBid.user_id = :user_id GROUP BY item.item_id", nativeQuery = true)
public List<BidSummary> findOwnBids(#Param("user_id") UUID userId);
Return type is List of Item objects and the query specified is having columns which are not part of return object. I recommend using appropriate Entity which full-fills your response type.
I am having below classes
#Entity
#Table(name = "USR_E_GROUPS")
public class GroupEntity {
#Id
#Column(name = "UIDUSERGROUP")
#GenericGenerator(name = "generator", strategy = "uuid2")
#GeneratedValue(generator = "generator")
private String id;
.........
#OneToMany(mappedBy = "group", cascade = CascadeType.PERSIST)
private List<UserGroupEntity> users;
same is for UserGroupEntity
now if I use groupRepoository.findAll()
It's is firing select query for every Group and inside different select query for UserGroupEntity. so it's taking too much time.
I want to make it to fire select with join so it will be a single query.
This is probably an n + 1 issue.
From the docs
By default, Hibernate3 uses lazy select fetching for collections and
lazy proxy fetching for single-valued associations. These defaults
make sense for most associations in the majority of applications.
By default the children are fetched lazily. Use JOIN FETCH to get the result in a single query.
In your GroupRepoository
#Query("SELECT g FROM GroupEntity g JOIN FETCH g.users gu")
List<GroupEntity> findAllEager();