Am using Windows XP 32-Bit Operating System with Intel Xeon processor. My current RAM memory is 4GB and 320GB of hard disk. And I feel that my computer is very slow. So if I upgrade the RAM memory to 8GB, will my computer handle the upgrade?
I probably do not think so. 32 bit OS can only support 4 GB of memory.
Calculation example:
2 ^ 32 bytes = 4 GB.
If you want more than 4 gb to use, then use a 64 bit OS
No,friend your computer will not use 8GB ram. At first you will have to know what is ram,
ram is a device that store information for temporarily, and share that data with very speedy and less consuming time.In 32 bit OS ram can hold data of 2 ^ 32 bytes = 4 GB if u have 8 gb ram, you 32 bit system can not use it,
Think about a car garage which is constructed for 4 cars, if you have 10 car you can't put all of your in the garage, so your 32 bit OS can not hold information more than 4gb ram, like car garage.Hope it will help you to get your answer
Theoretically it could: http://en.wikipedia.org/wiki/Physical_Address_Extension, but in XP there is no support for this.
Upgrade your os to 64 bit to use 8gb ram.
Just wondering, why did you put windows xp 32 bit on your computer? it could be x64 edition. Intel xeon processors are 64 BIT, not 32 bit.
Related
I am currently looking for a laptop to use for university next year. I will be studying Computer Sciences and I am still debating which laptop I should get.
These where the laptops I had in mind:
Dell XPS 15 9570 (€ 1.829,00)
i7-8750H processor (4,1 GHz; 6-cores)
16 GB DDR4, 2.666 MHz
512 GB M.2 2280 PCIe
NVIDIA® GeForce® GTX 1050Ti 4 GB GDDR5
1920 x 1080 15'' display.
Up to 11h of battery life (97-Wh)
Asus ZenBook Pro UX550VD (€1.599)
i7-7700HQ processor (3,8 GHz; 4-cores)
16 GB SO-DIMM DDR4
512 GB M.2 PCIe
NVIDIA® GeForce® GTX 1050 4 GB GDDR5
1920 x 1080 15'' display.
Up to 8h of battery life
The XPS has better battery life and has a better screen.
The ZenBook is cheaper, has more ports but has an older processor and CPU.
Maby their is another PC that is better. I would love to see different suggestions. Please note that since I am living in Belgium not every laptop is available here.
I hope I can post this type of question on this website. I don't really know where else to post. If you are not allowed to post this on here, I am terribly sorry in advance!
Thank you for helping!
If you want to use for studies only then you could go for Asus. It is good anyway. If you want to have laptop for your job then go with Dell
My cpuinfo file says that my processor has address sizes as 39 bits physical, and 48 bits virtual. This has got me into some confusion.
Mine is a 64 bit machine. From what I understand, this is the word size of my machine. That is, it will fetch data from memory in chunks of 8 bytes. Also, a 64 bit machine means that the CPU can address 2^64 byte addressable locations, which is a lot. So, manufacturers cut-down some of these lines.
Here are the questions:
If the CPU only generates logical addresses, then what is the need for having 39 bits physical address size.
When we say that the CPU can access 2^64 bytes, do we mean Physical memory or the virtual memory?
I read somewhere that a 64 bit machine has size of its registers as 64 bits, and a 32 bit machine has 32 bit registers. Is this the case?
I think I have confused myself terribly, and need some help. Any other information on this would be appreciated. Thanks!
I can see why people are puzzled considering the number of academic questions posed on this board that suggest there is some mathematical relationship among address sizes.
The processor word size, physical address size, logical address size, and bus size are all independent to some degrees.
If the CPU only generates logical addresses, then what is the need for having 39 bits physical address size.
The CPU translates logical addresses to physical addresses.
When we say that the CPU can access 2^64 bytes, do we mean Physical memory or the virtual memory?
I could be either.
I read somewhere that a 64 bit machine has size of its registers as 64 bits, and a 32 bit machine has 32 bit registers. Is this the case?
Generally this is true for general registers but special purpose registers may be a different size (e.g., floating point, control registers)
There have been many occasions when a processor does not use all available bits for the generation of addresses.
In ancient times, the old MC68000 had 32 bit registers but only a 24 bit address bus.
For the i5 consider that a 64 bit address would control a mind boggling memory space of 17,179,869,184 gigabytes. A stupendously huge number even compared to the storage at Google or the NSA or the planet Earth.
The i5 designers, trim this insane number down to a more manageable 512 gigabytes of physical address space and 262,144 gigabytes of virtual address space.
I am trying to understand memory management by the OS .
What I understand till now is that in a 32 bit system ,each process is allocated a space of 4gb [2gb user + 2gb kernel] ,in the virtual address space.
What confuses me is that is this 4gb space unique for every process . if I have say 3 processes p1 ,p2 ,p3 running would I need 12 gb of space on the hard disk ?
Also if say I have 2gb ram on a 32 bit system ,how will it manage to handle a process which needs 4gb ?[through the paging file ] ?
[2gb user + 2gb kernel]
That is a constraint by the OS. On an x86 32-bit system without PAE enabled, the virtual address space is 4 GiB (note that GB usually denotes 1000 MB while GiB stands for 1024 MiB).
What confuses me is that is this 4gb space unique for every process .
Yes, every process has its own 4 GiB virtual address space.
if I have say 3 processes p1 ,p2 ,p3 running would I need 12 gb of
space on the hard disk ?
No. With three processes, they can occupy a maximum of 12 GiB of storage. Whether that's primary or secondary storage is left to the kernel (primary is preferred, of course). So, you'd need your primary memory size + some secondary storage space to be at least 12 GiB to contain all three processes if all those processes really occupied the full range of 4 GiB, which is pretty unlikely to happen.
Also if say I have 2gb ram on a 32 bit system ,how will it manage to
handle a process which needs 4gb ?[through the paging file ] ?
Yes, in a way. You mean the right thing, but the "paging file" is just an implementation detail. It is used by Windows, but Linux, for example, uses a seperate swap partition instead. So, to be technically correct, "secondary storage (a HDD, for example) is needed to store the remaining 2 GiB of the process" would be right.
I've been reading Windows via C/C++ by Jeffrey Richter and came across the following snippet in the chapter about Windows' memory architecture related to porting 32 bit applications to a 64 bit environment.
If the system could somehow guarantee that no memory allocations would every be made above 0x00000000'7FFFFFFF, the application would work fine. Truncating a 64 bit address to a 32 bit address when the high 33 bits are 0 causes no problem whatsoever.
I'm having some trouble understanding why the system needs to guarantee that no memory allocations are made above 0x00000000'7FFFFFFF and not 0x00000000'FFFFFFFF. Shouldn't it be okay to truncate the address so long as the high 32 bits are 0? I'm probably missing something and would really appreciate it if someone with more knowledge about windows than me could explain why this is the case.
Not all 32bit systems/languages use unsigned values for memory addresses, so the 32th bit might have different meaning in some contexts. By limiting the address space to 31 bits, you don't run into that problem. And also, Windows limits a 32bit app from accessing addresses higher than 2 GB without the use of special extensions to extend that, so most apps would not need the 32th bit anyway.
If I have thousands of string like
Toshiba - Satellite C855D-S5100 Laptop, AMD E-Series Processor (1.3 GHZ), 4GB DDR3, 320GB HDD, 15.6" Display, AMD Radeon HD 6310, Double-layer DVD±RW/CD-RW, 802.11 b/g/n, Windows 8 » for $279.99 at Best Buy
and have a Laptop object with different properties like:
Processor
RAM
Hard Drive
Operating System
etc
I want to create a laptop object for every string and set the attributes with the formatted data from the string.
I am wondering if there is an easy way to go about doing this rather than splitting the string into an array by doing s.split(","), looping through it and comparing it to keywords:
i.e. If the string contains "DDR3", set that string as the RAM property
Can you tell if for the thousands of strings you have some semblance of regularity, structure. The difficulty of what you ask is dependant of the variability between 2 different entries.
Toshiba - Satellite C855D-S5100 Laptop, AMD E-Series Processor (1.3
GHZ), 4GB DDR3, 320GB HDD, 15.6" Display, AMD Radeon HD 6310,
Double-layer DVD±RW/CD-RW, 802.11 b/g/n, Windows 8 » for $279.99 at
Best Buy
Is pretty disimilar from
Apple MacBook Pro - Core i5 2.5 GHz - 500 GB HDD / 5400 rpm - 13.3″
1280 x 800 - 4 GB RAM - English
In one you have RAM in the other DDR3. In one you have 4GB with no space and in the other there is a space. But it's not hopeless if your list contains strings which are all very similar in structure. Then I'd say figure out a regex for what you want to extract.