Gradle executes all tasks? - gradle

I have a very simple build script like so
task hello{
println("hello World")
}
task bye {
println("bye")
}
On the command line I run
gradle hello and I get the following output:
hello World
bye
:hello UP-TO-DATE
Why is it executing the task "bye" (I'm assuming it gets executed since "bye" gets printed)? Thanks.

It's a common pitfall:
task hello {
println("Any code in here is about *configuring* the\
task. By default, all tasks always get configured.")
doLast {
println("Any code in here is about *executing* the task.\
This code only gets run if and when Gradle decides to execute the task.")
}
}
The distinction between configuration phase and execution phase is probably the single most important concept to understand in Gradle. It can be confusing at first, and may go away in the future. A kind of analogue in the Ant/Maven world is that these tools first parse XML build scripts and build an object model (perhaps resolving some properties along the way), and only then execute the build.

Adding to Peter answer, If you want to execute all task , you can specify the defaultTasks list.
defaultTasks 'clean', 'run'
task clean {
doLast {
println 'Default Cleaning!'
}
}
task run {
doLast {
println 'Default Running!'
}
}
task other {
doLast {
println "I'm not a default task!"
}
}
Output
Output of gradle -q
> gradle -q
Default Cleaning!
Default Running!
More details can be found here
https://docs.gradle.org/current/userguide/tutorial_using_tasks.html

Related

Gradle: need help to understand

Have in build.gradle
task hello {
doLast {
println 'Hello World!'
}
}
task count {
println "one"
doLast{
4.times {print "$it "}
}
println "two"
doFirst{
2.times {println "$it - 1 "}
}
3.times {println( "$it -3")}
}
task intro(dependsOn: hello){
doLast{
println("I'm Gradle!")
}
}
run in shell
gradle intro
and get
one
two
0 -3
1 -3
2 -3
:hello
Hello World!
:intro
I'm Gradle!
BUILD SUCCESSFUL
but it's not correct!!!
the correct output is
:hello
Hello World!
:intro
I'm Gradle!
BUILD SUCCESSFUL
What did I do wrong?
ps
adding details to because there is too much code here :(
adding details to because there is too much code here :(
adding details to because there is too much code here :(
adding details to because there is too much code here :(
Why do you think it's wrong? Probably it is absolutely correct. This is all due to configuration of the build. Read about it in the official user guide.
There are a number of phases take place during the build. One of them is configuration phase. All the output you don't expect to see - is the configuration's output. When you do something in task's closure, it's executed at the configuration of your build, untill you place it into the doLast or doFirst closure to run at the execution phase (or task's closure is declared with << that's the same as doLast).
Note that configuration is executed for all tasks, no matter if they will be executed or not. That is the reason of your unexpected output - it's just done as a part of your build configuration, though they are declared within some task.

What is the meaning of << in gradle task definition

What is the difference between these two tasks. Only task with << in its definition is shown in the output of ./gradlew tasks.
task greet(type: GreetingToFileTask) {
destination = { project.greetingFile }
}
task sayGreeting(dependsOn: greet) << {
println file(greetingFile).text
}
The lines above are from gradle documentation Here
The << is a shortcut to the toLast configuration item of a task definition. I.e. the following two declarations are equivalent:
task hello << {
println 'Hello world!'
}
and:
task hello {
doLast {
println 'Hello world!'
}
}
(example taken from Gradle documentation here).
Now, in the first code snippet you just define a task and configuring its destination property. However, the task will only be executed if needed.
In the second code snippet, however, you are actually defining an action that will always be executed during the configuration phase, regardless of the tasks targeted for execution (cite from here):
A task has both configuration and actions. When using the <<, you are
simply using a shortcut to define an action. Code defined in the
configuration section of your task will get executed during the
configuration phase of the build regardless of what task was targeted.

Code block in gradle.processResources conditional on whether another task was requested

We have an optional gradle task docker that depends on task war, which if executed, needs a war file generated with an extra file in it. This extra file can be added to the resources within the processResources task (or potentially directly in the war task). However, the corresponding code block must not run if task docker has not been requested and will not be run.
We need a correct condition in the following block checking if task docker is in the pipeline:
processResources {
if (/* CONDITION HERE: task docker is requested */) {
from ("${projectDir}/docker") {
include "app.properties"
}
}
}
task docker(type: Dockerfile) {
dependsOn build
...
Clarification: processResources is a standard dependency of the war task and the latter is a standard dependency of the build task. processResources is always executed on build, with or without the docker task to collect resources for assembling the war and may not be fully disabled in this case. One could move the code in question to a separate task dependent on docker and working on the output directory of processResources, yet before war is run, however, such a construct will result in much less clarity for such a simple thing.
You can simply add additional dependency to your docker task, to make it relying not only on build task, but also on processResources. In that case, your processResources task will be called only if docker should be executed.
Another solution is to use TaskExecutionGraph. This let you initialize some variable, which could tell you, whether or not some task will be executed. But you have to understand, that graph is prepared only after all the configuration is done and you can rely on it only during the execution phase. Here is a short example, how it could be used:
//some flag, whether or not some task will be executed
def variable = false
//task with some logic executed during the execution phase
task test1 << {
if (variable) {
println 'task2 will be executed'
} else {
println 'task2 will not be executed'
}
}
//according to whether or not this task will run or not,
//will differs test1 task behavior
task test2(dependsOn: test1) {
}
//add some logic according to task execution graph
gradle.taskGraph.whenReady {
taskGraph ->
//check the flag and execute only if it's true
if (taskGraph.hasTask(test2)) {
variable = true
println 'task test2 will be executed'
}
}
Furthermore, you can try to configure your custom task to make it disabled by setting is enabled property to false, if docker task is not in the execution graph. In that case you don't have to provide some flags and logic in execution phase. Like:
task test1 {
//some logic for execution
doLast {
println "execute some logic"
}
}
task test2(dependsOn: test1) {
}
gradle.taskGraph.whenReady {
taskGraph ->
if (!taskGraph.hasTask(test2)) {
//Disable test1 task if test2 will not run
test1.enabled = false
}
}
But it'll be impossible to run this custom task separately without some additional configuration.

Only run task if another isn't UP-TO-DATE in gradle

I want to automatically add a serverRun task when doing functional tests in Gradle, so I add a dependency :
funcTestTask.dependsOn(serverRun)
Which results in the task running whether or not the funcTestTask even runs
:compile
:serverRun
:funcTestTask (and associate compile tasks... etc)
:serverStop
OR
:compile UP-TO-DATE
:serverRun <-- unnecessary
:funcTestTask UP-TO-DATE
:serverStop
The cost of starting the server is pretty high and I only want it to start if the functionalTest isn't UP-TO-DATE, I'd like to do or something :
if(!funcTestTask.isUpToDate) {
funcTestTask.dependsOn(serverRun)
}
So I know I can't know the up-to-date status of funcTestTask until all it's inputs/outputs are decided BUT can I inherit it's uptoDate checker?
serverRun.outputs.upToDateWhen(funcTestTask.upToDate)
The alternative is to "doFirst" the ServerRun in the FuncTest, which I believe is generally frowned upon?
funcTestTask.doFirst { serverRun.execute() }
Is there a way to conditionally run a task before another?
UPDATE 1
Tried settings inputs/outputs the same
serverRun.inputs.files(funcTestTask.inputs.files)
serverRun.outputs.files(funcTestTask.outputs.files)
and this seems to rerun the server on recompiles (good), skips reruns after successful unchanged functional tests (also good), but wont rerun tests after a failed test like the following
:compile
:serverRun
:funcTestTask FAILED
then
:compile UP-TO-DATE
:serverRun UP-TO-DATE <-- wrong!
:funcTestTask FAILED
Having faced the same problem I found a very clean solution. In my case I want an eclipse project setup to be generated when the build is run, but only at the times when a new jar is generated. No project setup should be executed when the jar is up to date. Here is how one can accomplish that:
tasks.eclipse {
onlyIf {
!jar.state.upToDate
}
}
build {
dependsOn tasks.eclipse
}
Since the task is a dependent tasks of the one you are trying to control then you can try:
tasks {
onlyIf {
dependsOnTaskDidWork()
}
}
I ended up writing to a 'failure file' and making that an input on the serverRun task:
File serverTrigger = project.file("${buildDir}/trigger")
project.gradle.taskGraph.whenReady { TaskExecutionGraph taskGraph ->
// make the serverRun task have the same inputs/outputs + extra trigger
serverRun.inputs.files(funcTestTask.inputs.files, serverTrigger)
serverRun.outputs.files(funcTestTask.outputs.files)
}
project.gradle.taskGraph.afterTask { Task task, TaskState state ->
if (task.name == "funcTestTask" && state.failure) {
serverRun.trigger << new Date()
}
}
With information from an answer to my question on the Gradle forums :
http://forums.gradle.org/gradle/topics/how-can-i-start-a-server-conditionally-before-a-functionaltestrun
I had the same problem but the solution I came up is much simpler.
This starts up the server only if testing is necessary
test {
doFirst {
exec {
executable = 'docker/_ci/run.sh'
args = ['--start']
}
}
doLast {
exec {
executable = 'docker/_ci/run.sh'
args = ['--stop']
}
}
}
Assuming you have task1 and task2 which depends on task1 and you need to run task2 only if task1 is not up-to-date, the following example may be used:
task task1 {
// task1 definition
}
task task2(dependsOn: task1) {
onlyIf { task1.didWork }
}
In this case task2 will run only when task1 is not up-to-date. It's important to use didWork only for tasks which are defined in dependsOn, in order to ensure that didWork is evaluated after that task (task1 in our example) had chance to run.

gradle task build already exists issue

I am getting the error
Cannot add task ':webserver:build' as a task with that name already exists.
The weird thing is my hello task is fine but my build task is not AND YES, I am trying to override the Java plugin's build task.
Master build.gradle file:
allprojects {
apply plugin: 'java'
apply plugin: 'eclipse'
task hello << { task -> println "I'm $task.project.name" }
task build << { task -> println "I'm building now" }
}
subprojects {
hello << {println "- I depend on stserver"}
build << { println "source sets=$sourceSets.main.java.srcDirs" }
}
My child webserver build.gradle file:
sourceSets.main{
java.srcDirs = ['app']
}
build << { println "source sets=$sourceSets.main.java.srcDirs" }
hello << {println "- Do something specific xxxx"}
What is the deal here, is overriding build special or something? Overriding my own hello task worked fine and I thought overriding build would be just as simple?
You aren't overriding the hello task, you are just adding more task actions. You can override a task with task foo(overwrite: true). I haven't come across a good reason to override the build task; there are probably better ways to achieve what you want.
What is the deal here, overriding build is special or something. Overriding my own hello task worked fine and I thought overriding build would be just as simple?
The reason the behaviour seems different is because build task already exists and hello does not (and not because build is special).
In gradle you cannot do this:
task hello << { print "hello" }
task hello << { print "hello again" }
This will fail with the familiar error: "Cannot add task ':hello' as a task with that name already exists.".
Since build task already exists, it's illegal to have a second task build << { ... }. However, it will work for hello task, because it does not exist, and therefore task hello << { ... } is legal, as it's the first declaration of hello task.
If you replace your task build << { ... } with build << { ... }, which just adds more behaviour to an existing task, it will "compile" fine.

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