Regular Expression(Ruby): match non-word, but exclude spaces - ruby

Question

^(?=(.*\d){4,})(?=(.*[A-Z]){3})(?!\s)(?=.*\W{2,})(?=(.*[a-z]){2,}).{12,14}$
The RegExp above is trying to:
match at least 4 digits - (?=(.*\d){4,})
match exactly 3 upper case letters - (?=(.*[A-Z]){3})
don't match spaces - (?!\s)
match at least 2 non-word characters - (?=.*\W{2,})
match at least 2 lower - (?=(.*[a-z]){2,})
string must be between 12 and 14 in length - .{12,14}
But I am having a challenge getting this to avoid matching spaces. It seems like because \W also includes spaces, my preceding negative look-ahead on spaces is being ignored.
For example:
b4A#Ac33*8Pd -- should match
b4A#Ac3 3*8Pd -- should not match
rubular link
Edited to provide further clarification:
Basically, I am trying to avoid having to spell out all the characters in the POSIX [:punct:] class ie !"#$%&'()*+,./:;<=>?#\^_\{|}~-` .. that is why I had a need to use \W .. But I would also want to exclude spaces
I can use a second pair of eyes, and more experienced suggestions here ..
Edited again, to correct mix-ups in counts specified in sub-patterns, as pointed out in the accepted answer below.

Answer 1

Instead of using dot ., use non spaces \S:
^(?=(.*\d){3,})(?=(.*[A-Z]){2})(?=.*\W{1,})(?=(.*[a-z]){1,})\S{12,14}$
// here ___^^
And is this a typo match at least 4 digits - (?=(.*\d){3,}),
it should be:
match at least 3 digits - (?=(.*\d){3,})
or
match at least 4 digits - (?=(.*\d){4,})
Same for other counts.