Remove the bottom level from a path - bash

I am writing a script where I want to check if a folder relative to the script's working directory is in the shell's path.
For example, if the project structure is:
top/
bin/
tests/
test1/
foo.sh
test2/
foo.sh
I want to check if top/bin is in PATH from either foo.sh. I know the following will work:
cd ../../bin
if echo $PATH|grep `pwd`; then
echo "Success"
else
echo "Failure"
fi
But then I have to keep track of what directory I started in so I can cd back there. Can I do something like chopping off the last two directories after pwd and then appending bin to that? Is there some other intelligent way to handle this?
As a bonus, I'd like to make this script robust against additional directory levels inside tests, but that's not strictly necessary if it complicates things.

# Exits with code 0 if the first argument is on the user's path.
is_on_path() {
CANONICAL_NAME=$(readlink -f "$1")
while read -r -d: COMPONENT; do
if [[ "$CANONICAL_NAME" = "$COMPONENT" ]]; then
return 0
fi
done <<< "$PATH"
return 1
}
readlink -f will evaluate path components like ../.. as needed.
read -r -d: COMPONENT will read a colon-separated list of arguments from its input, into the COMPONENT variable.
<<< "$PATH" will pass in the system path into while's stdin.
Now you can call that like this:
if is_on_path "../../bin"; then
echo "Success!"
else
echo "Failure!"
fi
Bonus: From here it's pretty easy to recursively apply this to all parent directories:
find_matching_ancestor() {
current_dir=$(pwd)
while [[ "$current_dir" != "/" ]]; do
if is_on_path "$current_dir/bin"; then
echo "$current_dir"
return 0
fi
current_dir=$(dirname "$current_dir")
done
return 1
}

This seems to work
echo $PATH | xargs -d: -n1 | grep ^$(readlink -f ../../bin)$ | wc -l

Perhaps the most reliable sulution would be to put a file with executable bit set to that directory and to use "which".
For example, is /bin on my PATH?
which ls
/bin/ls

Related

bash check for subdirectories under directory

This is my first day scripting, I use linux but needed a script that I have been racking my brain until i finally ask for help. I need to check a directory that has directories already present to see if any new directories are added that are not expected.
Ok I think i have got this as simple as possible. The below works but displays all files in the directory as well. I will keep working at it unless someone can tell me how not to list the files too | I tried ls -d but it is doing the echo "nothing new". I feel like an idiot and should have got this sooner.
#!/bin/bash
workingdirs=`ls ~/ | grep -viE "temp1|temp2|temp3"`
if [ -d "$workingdirs" ]
then
echo "nothing new"
else
echo "The following Direcetories are now present"
echo ""
echo "$workingdirs"
fi
If you want to take some action when a new directory is created, used inotifywait. If you just want to check to see that the directories that exist are the ones you expect, you could do something like:
trap 'rm -f $TMPDIR/manifest' 0
# Create the expected values. Really, you should hand edit
# the manifest, but this is just for demonstration.
find "$Workingdir" -maxdepth 1 -type d > $TMPDIR/manifest
while true; do
sleep 60 # Check every 60 seconds. Modify period as needed, or
# (recommended) use inotifywait
if ! find "$Workingdir" -maxdepth 1 -type d | cmp - $TMPDIR/manifest; then
: Unexpected directories exist or have been removed
fi
done
Below shell script will show directory present or not.
#!/bin/bash
Workingdir=/root/working/
knowndir1=/root/working/temp1
knowndir2=/root/working/temp2
knowndir3=/root/working/temp3
my=/home/learning/perl
arr=($Workingdir $knowndir1 $knowndir2 $knowndir3 $my) #creating an array
for i in ${arr[#]} #checking for each element in array
do
if [ -d $i ]
then
echo "directory $i present"
else
echo "directory $i not present"
fi
done
output:
directory /root/working/ not present
directory /root/working/temp1 not present
directory /root/working/temp2 not present
directory /root/working/temp3 not present
**directory /home/learning/perl present**
This will save the available directories in a list to a file. When you run the script a second time, it will report directories that have been deleted or added.
#!/bin/sh
dirlist="$HOME/dirlist" # dir list file for saving state between runs
topdir='/some/path' # the directory you want to keep track of
tmpfile=$(mktemp)
find "$topdir" -type d -print | sort -o "$tmpfile"
if [ -f "$dirlist" ] && ! cmp -s "$dirlist" "$tmpfile"; then
echo 'Directories added:'
comm -1 -3 "$dirlist" "$tmpfile"
echo 'Directories removed:'
comm -2 -3 "$dirlist" "$tmpfile"
else
echo 'No changes'
fi
mv "$tmpfile" "$dirlist"
The script will have problems with directories that have very exotic names (containing newlines).

Change directory for saving a file and return to old directory

I wrote a very little and basic script which compares two files and writes all matching lines into a file.
I now want to secure, that no matter from which directory/working directory you run the bash script, the file is stored in the directory where the script is located.
#! /bin/bash
typeset -i count=1
typeset -i useable_counter=1
file="Fundstellen.txt"
curDir=`pwd`
wantedDir="/Users/Stephan/Documents/Schule/SYT/Skripting/bin/Uebungen"
echo `pushd ${wantedDir}`
if [ -e $file ]; then
echo `chmod 777 ${file}`
echo `rm ${file}`
fi
echo `touch ${file}`
while read pass; do
pass_nr=`echo $pass | cut -d ":" -f 3`
while read groups; do
group_nr=`echo $groups | cut -d ":" -f 3`
if [ "$pass_nr" = "$group_nr" ]; then
if [ $count -gt 15 ]; then
echo "#$useable_counter: $pass in $groups" >> $file
useable_counter=$useable_counter+1
fi
count=$count+1
fi
done < /etc/group
done < /etc/passwd
echo `chmod 444 $file`
echo `popd`
echo "Writing done!"
That's my script with the pushd command to get to the directory in which the script is located and popd should return.
But still, the output file is created in the directory/working directory, from where the script is launched.
What do I have to change so it'll work? I already tried to use normal cd to change the directory, that's why the variable curDir stores the starting directory.
By putting pushd into backticks, you're running it in a subshell. No subshell can change the current working directory of its parent shell.
Just call
pushd "$wantedDir"
directly, and same with popd.
Your script is a hopeless mess. All you need to produce output in the named file is
command >/Users/Stephan/Documents/Schule/SYT/Skripting/bin/Uebungen/Fundstellen.txt
Generally, very few scripts need to explicitly cd and fewer still would need to pushd and popd -- these commands are almost exclusively for interactive use.
The loop where you read all of the group file for every entry in the passwd file is extremely inefficient, especially when the purpose of the inner loop seems to be to find only a small subset of the records in the file. Very often, when you see while read, you want Awk instead. Here is a simple framework for doing that.
awk -F : 'NR==FNR { ++p[$3]; next }
FNR > 15 && $3 in p { print "#" ++i ": " $3 " in " $0 }' /etc/passdwd /etc/group
It's not clear what the 15 is supposed to accomplish. Is it a bug in your script, or is the intent to only skip the first 15 lines on the first iteration?

bash - recursive script can't see files in sub directory

I got a recursive script which iterates a list of names, some of which are files and some are directories.
If it's a (non-empty) directory, I should call the script again with all of the files in the directory and check if they are legal.
The part of the code making the recursive call:
if [[ -d $var ]] ; then
if [ "$(ls -A $var)" ]; then
./validate `ls $var`
fi
fi
The part of code checking if the files are legal:
if [[ -f $var ]]; then
some code
fi
But, after making the recursive calls, I can no longer check any of the files inside that directory, because they are not in the same directory as the main script, the -f $var if cannot see them.
Any suggestion how can I still see them and use them?
Why not use find? Simple and easy solution to the problem.
Always quote variables, you never known when you will find a file or directory name with spaces
shopt -s nullglob
if [[ -d "$path" ]] ; then
contents=( "$path"/* )
if (( ${#contents[#]} > 0 )); then
"$0" "${contents[#]}"
fi
fi
you're re-inventing find
of course, var is a lousy variable name
if you're recursively calling the script, you don't need to hard-code the script name.
you should consider putting the logic into a function in the script, and the function can recursively call itself, instead of having to spawn an new process to invoke the shell script each time. If you do this, use $FUNCNAME instead of "$0"
A few people have mentioned how find might solve this problem, I just wanted to show how that might be done:
find /yourdirectory -type f -exec ./validate {} +;
This will find all regular files in yourdirectory and recursively in all its sub-directories, and return their paths as arguments to ./validate. The {} is expanded to the paths of the files that find locates within yourdirectory. The + at the end means that each call to validate will be on a large number of files, instead of calling it individually on each file (wherein the + is replaced with a \), this provides a huge speedup sometimes.
One option is to change directory (carefully) into the sub-directory:
if [[ -d "$var" ]] ; then
if [ "$(ls -A $var)" ]; then
(cd "$var"; exec ./validate $(ls))
fi
fi
The outer parentheses start a new shell so the cd command does not affect the main shell. The exec replaces the original shell with (a new copy of) the validate script. Using $(...) instead of back-ticks is sensible. In general, it is sensible to enclose variable names in double quotes when they refer to file names that might contain spaces (but see below). The $(ls) will list the files in the directory.
Heaven help you with the ls commands if any file names or directory names contain spaces; you should probably be using * glob expansion instead. Note that a directory containing a single file with a name such as -n would trigger a syntax error in your script.
Corrigendum
As Jens noted in a comment, the location of the shell script (validate) has to be adjusted as you descend the directory hierarchy. The simplest mechanism is to have the script on your PATH, so you can write exec validate or even exec $0 instead of exec ./validate. Failing that, you need to adjust the value of $0 — assuming your shell leaves $0 as a relative path and doesn't mess around with converting it to an absolute path. So, a revised version of the code fragment might be:
# For validate on PATH or absolute name in $0
if [[ -d "$var" ]] ; then
if [ "$(ls -A $var)" ]; then
(cd "$var"; exec $0 $(ls))
fi
fi
or:
# For validate not on PATH and relative name in $0
if [[ -d "$var" ]] ; then
if [ "$(ls -A $var)" ]; then
(cd "$var"; exec ../$0 $(ls))
fi
fi

bash save last user input value permanently in the script itself

Is it possible to save last entered value of a variable by the user in the bash script itself so that I reuse value the next time while executing again?.
Eg:
#!/bin/bash
if [ -d "/opt/test" ]; then
echo "Enter path:"
read path
p=$path
else
.....
........
fi
The above script is just a sample example I wanted to give(which may be wrong), is it possible if I want to save the value of p permanently in the script itself to so that I use it somewhere later in the script even when the script is re-executed?.
EDIT:
I am already using sed to overwrite the lines in the script while executing, this method works but this is not at all good practice as said. Replacing the lines in the same file as said in the below answer is much better than what I am using like the one below:
...
....
PATH=""; #This is line no 7
DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )";
name="$(basename "$(test -L "$0" && readlink "$0" || echo "$0")")";
...
if [ condition ]
fi
path=$path
sed -i '7s|.*|PATH='$path';|' $DIR/$name;
Someting like this should do the asked stuff :
#!/bin/bash
ENTERED_PATH=""
if [ "$ENTERED_PATH" = "" ]; then
echo "Enter path"
read path
ENTERED_PATH=$path
sed -i 's/ENTERED_PATH=""/ENTERED_PATH='$path'/g' $0
fi
This script will ask user a path only if not previously ENTERED_PATH were defined, and store it directly into the current file with the sed line.
Maybe a safer way to do this, would be to write a config file somewhere with the data you want to save and source it . data.saved at the begining of your script.
In the script itself? Yes with sed but it's not advisable.
#!/bin/bash
test='0'
echo "test currently is: $test";
test=`expr $test + 1`
echo "changing test to: $test"
sed -i "s/test='[0-9]*'/test='$test'/" $0
Preferable method:
Try saving the value in a seperate file you can easily do a
myvar=`cat varfile.txt`
And whatever was in the file is not in your variable.
I would suggest using the /tmp/ dir to store the file in.
Another option would be to save the value as an extended attribute attached to the script file. This has many of the same problems as editing the script's contents (permissions issues, weird for multiple users, etc) plus a few of its own (not supported on all filesystems...), but IMHO it's not quite as ugly as rewriting the script itself (a config file really is a better option).
I don't use Linux, but I think the relevant commands would be something like this:
path="$(getfattr --only-values -n "user.saved_path" "${BASH_SOURCE[0]}")"
if [[ -z "$path" ]]; then
read -p "Enter path:" path
setfattr -n "user.saved_path" -v "$path" "${BASH_SOURCE[0]}"
fi

How to manage Long Paths in Bash?

I have a problem to manage long paths. How can I get quickly to paths like
/Users/User/.../.../.../.../.../Dev/C/card.c
I tried an alias
alias cd C='cd /Users/User/.../.../.../.../.../Dev/C'
but I am unable to do aliases for two separate words. I have long lists of Bash aliases and paths in CDPATH, so I am hesitating to make them more. How can manage long paths?
[Ideas for Replies]
The user litb's reply revealed some of my problems in the management. Things, such as "CTRL+R", "!-3:1:2:4:x" and "incremental search", are hard for me. They probably help in navigating long directories and, in the sense, management.
Using symlinks is probably the best idea; but you can do it even easier than dumping them all into your home directory.
As you mentioned, BASH has a feature called CDPATH which comes in really handy here.
Just make a hidden folder in your homedir (so it doesn't clutter your homedir too much):
$ mkdir ~/.paths
$ cd ~/.paths
$ ln -s /my/very/long/path/name/to/my/project project
$ ln -s /some/other/very/long/path/to/my/backups backups
$ echo 'CDPATH=~/.paths' >> ~/.bashrc
$ source ~/.bashrc
This creates a directory in your homedir called ".paths" which contains symlinks to all your long directory locations which you regularly use, then sets the CDPATH bash variable to that directory (in your .bashrc) and re-reads the .bashrc file.
Now, you can go to any of those paths from anywhere:
$ cd project
$ cd backups
Leaving you with a short CDPATH, no cluttering aliasses, and more importantly: A really easy way to navigate to those long paths from other applications, such as UI applications, by just going into ~/.paths or adding that directory into your UI application's sidebar or so.
Probably the easiest all-round solution you can have.
Consider using symbolic links. I have a ~/work/ directory where I place symlinks to all my current projects.
You may also use shell variables:
c='/Users/User/.../.../.../.../.../Dev/C'
Then:
cd "$c"
Create symlinks in your home directory (or somewhere else of your choosing)
ln -s longDirectoryPath ~/MySymLinkName
See man ln for more details.
Probably the easiest solution is to use:
alias cdc='cd /Users/User/.../.../.../.../.../Dev/C'
alias cdbin='cd /Users/User/.../.../.../.../.../Dev/bin'
alias cdtst='cd /Users/User/.../.../.../.../.../Dev/tst'
if you're only really working on one project at a time. If you work on multiple projects, you could have another alias which changed the directories within those aliases above.
So, you'd use something like:
proj game17
cdc
make
proj roman_numerals
cdbin
rm -f *
proj game17 ; cdc
Since this is a useful thing to have, I decided to put together a series of scripts that can be used. They're all based aroung a configuration file that you place in your home directory, along with aliases to source scripts. The file "~/.cdx_data" is of the form:
scrabble:top=~/dev/scrabble
scrabble:src=~/dev/scrabble/src
scrabble:bin=~/dev/scrabble/bin
sudoku:top=~/dev/scrabble
sudoku:src=~/dev/scrabble/src
sudoku:bin=~/dev/scrabble/bin
sudoku:data=~/dev/scrabble/data
and lists all the relevant projects (scrabble and sodoku in this case) and their directories (which may be different for each project, but have top, bin, src and data in this example).
The first action is to initialize stuff, so put:
. ~/.cdx_init
at the end of your .bash_profile and create the "~/.cdx_init" file as:
alias cdxl='. ~/.cdx_list'
alias projl='. ~/.cdx_projlist'
alias cdx='. ~/.cdx_goto'
alias proj='. ~/.cdx_proj'
This sets up the four aliases to source the files which I'll include below. Usage is:
cdxl - List all directories in current project.
projl - List all projects.
proj - Show current project.
proj <p> - Set current project to <p> (if allowed).
cdx - Show current project/directory and expected/actual real
directory, since they can get out of sync if you mix cd and cdx.
cdx . - Set actual real directory to expected directory (in other words,
get them back into sync).
cdx <d> - Set directory to <d> (if allowed).
The actual script follow. First, ".cdx_list" which just lists the allowed directories in the current project (pipelines are broken into multiple lines for readability but they should all be on one line).
echo "Possible directories are:"
cat ~/.cdx_data
| grep "^${CDX_PROJ}:"
| sed -e 's/^.*://' -e 's/=.*$//'
| sort -u
| sed 's/^/ /'
Similarly, ".cdx_projlist" shows all the possible projects:
echo "Possible projects are:"
cat ~/.cdx_data
| grep ':'
| sed 's/:.*$//'
| sort -u
| sed 's/^/ /'
In the meaty scripts, ".cdx_proj" sets and/or shows the current project:
if [[ "$1" != "" ]] ; then
grep "^$1:" ~/.cdx_data >/dev/null 2>&1
if [[ $? != 0 ]] ; then
echo "No project name '$1'."
projl
else
export CDX_PROJ="$1"
fi
fi
echo "Current project is: [${CDX_PROJ}]"
and ".cdx_goto" is the same for directories within the project:
if [[ "$1" == "." ]] ; then
CDX_TMP="${CDX_DIR}"
else
CDX_TMP="$1"
fi
if [[ "${CDX_TMP}" != "" ]] ; then
grep "^${CDX_PROJ}:${CDX_TMP}=" ~/.cdx_data >/dev/null 2>&1
if [[ $? != 0 ]] ; then
echo "No directory name '${CDX_TMP}' for project '${CDX_PROJ}'."
cdxl
else
export CDX_DIR="${CDX_TMP}"
cd $(grep "^${CDX_PROJ}:${CDX_DIR}=" ~/.cdx_data
| sed 's/^.*=//'
| head -1
| sed "s:^~:$HOME:")
fi
fi
CDX_TMP=$(grep "^${CDX_PROJ}:${CDX_DIR}=" ~/.cdx_data
| sed 's/^.*=//'
| head -1
| sed "s:^~:$HOME:")
echo "Current project is: [${CDX_PROJ}]"
echo "Current directory is: [${CDX_DIR}]"
echo " [${CDX_TMP}]"
echo "Actual directory is: [${PWD}]"
unset CDX_TMP
It uses three environment variables which are reserved for its own use: "CDX_PROJ", "CDX_DIR" and "CDX_TMP". Other than those and the afore-mentioned files and aliases, there are no other resources used. It's the simplest, yet most adaptable solution I could come up with. Best of luck.
Revisiting. Today I received this link from a social bookmarking site, then I immediately remembered this question:
Navigation with bm
We keep a simple, plain text bookmarks
file and use a tool called bm to do
the look-ups. The tool can also be
used to edit the bookmark index
dynamically as shown below where we
add the directories from the previous
example to the index.
Once i cd'ed into such a long directory, i have that in the history. Then i just type Ctrl-R for the "(reverse-i-search)" prompt and type in a few characters, like Dev/C that appear somewhere in the path, and it shows me the command what i issued back then and i can easily jump to it again.
That works pretty well in practice. Because it won't find an entry if you haven't typed that path for quite some time, which would mean doing work to make things easier probably wouldn't be worth the time. But it definitely will find it if you used it recently. Which is exactly what i need.
In some way, it's a self-organizing cache for long commands & path-names :)
You might want to consider using a script like this in your .bashrc. I've used it on a daily basis ever since I read that post. Pretty bloody useful.
The user jhs suggested Pushd and Popd-commands. I share here some of my Bash-scripts that I found in Unix Power Tools -book. They are very cool when your directories get a way too long :)
#Moving fast between directories
alias pd=pushd
alias pd2='pushd +2'
alias pd3='pushd +3'
alias pd4='pushd +4'
The command 'pushd +n' "rotates" the stack. The reverse command 'popd +n' deletes the n entry of the stack. If your stack gets too long, use 'repeat n popd'. For examle, your stack is 12 directories long:
repeat 11 popd
When you want to see your stack, write 'pushd'. For further reading, I recommend the book on pages 625-626.
In your .bashrc find PS1='${debian_chroot:+($debian_chroot)}[\033[01;32m]\u#\h[\033[00m]:[\033[01;34m]
\W[\033[00m]\$ '
and replace the \w with \W.I already have it changed here. This will only give you the main directory where you are working. You can get the full directory by typing pwd
There are fundamental well-known ideas, like creating aliases:
alias cdfoo="cd /long/path/to/foo"
and also "dropping pebbles"
export foo=/long/path/to/foo
and also making the above "project-based". I use 'ticket based' directories.
topdir=ticket_12345
alias cdfoo="cd home/me/sandbox/$topdir/long/path/to/foo"
export foo="/home/me/sandbox/$topdir/long/path/to/foo"
but beyond all this, sometimes it's just handy to jump back and forth to where you've been recently, using command-line menus. (pushd and popd are cumbersome, IMHO).
I use acd_func.sh (listed below). Once defined, you can do
cd --
to see a list of recent directories, with a numerical menu
cd -2
to go to the second-most recent directory.
Very easy to use, very handy.
Here's the code:
# Insert into .profile, .bash_profile or wherever
# acd_func 1.0.5, 10-nov-2004
# petar marinov, http:/geocities.com/h2428, this is public domain
cd_func ()
{
local x2 the_new_dir adir index
local -i cnt
if [[ $1 == "--" ]]; then
dirs -v
return 0
fi
the_new_dir=$1
[[ -z $1 ]] && the_new_dir=$HOME
if [[ ${the_new_dir:0:1} == '-' ]]; then
#
# Extract dir N from dirs
index=${the_new_dir:1}
[[ -z $index ]] && index=1
adir=$(dirs +$index)
[[ -z $adir ]] && return 1
the_new_dir=$adir
fi
#
# '~' has to be substituted by ${HOME}
[[ ${the_new_dir:0:1} == '~' ]] && the_new_dir="${HOME}${the_new_dir:1}"
#
# Now change to the new dir and add to the top of the stack
pushd "${the_new_dir}" > /dev/null
[[ $? -ne 0 ]] && return 1
the_new_dir=$(pwd)
#
# Trim down everything beyond 11th entry
popd -n +11 2>/dev/null 1>/dev/null
#
# Remove any other occurence of this dir, skipping the top of the stack
for ((cnt=1; cnt <= 10; cnt++)); do
x2=$(dirs +${cnt} 2>/dev/null)
[[ $? -ne 0 ]] && return 0
[[ ${x2:0:1} == '~' ]] && x2="${HOME}${x2:1}"
if [[ "${x2}" == "${the_new_dir}" ]]; then
popd -n +$cnt 2>/dev/null 1>/dev/null
cnt=cnt-1
fi
done
return 0
}
alias cd=cd_func
if [[ $BASH_VERSION > "2.05a" ]]; then
# ctrl+w shows the menu
bind -x "\"\C-w\":cd_func -- ;"
fi
This might also be a useful function to put in your .bashrc; it moves up either a number of directories, or to a named directory, i.e. if you're in /a/b/c/d/ you can do up 3 or up a to end up in a.
I have no idea where I found this; if you know, please comment or add the attribution.
function up()
{
dir=""
if [ -z "$1" ]; then
dir=..
elif [[ $1 =~ ^[0-9]+$ ]]; then
x=0
while [ $x -lt ${1:-1} ]; do
dir=${dir}../
x=$(($x+1))
done
else
dir=${PWD%/$1/*}/$1
fi
cd "$dir";
}
If you want to switch to zsh, this is very easy-- just use "alias -g" (global alias, i.e. an alias that works anywhere in the command, not just the first word).
# alias -g c=/my/super/long/dir/name
# cd c
# pwd
/my/super/long/dir/name
In bash, I think the closest thing you'll get to 'aliasing' style is to write a function:
function ccd {
case "$1" in
c) cd /blah/blah/blah/long/path/number/one ;;
foo) cd /blah/blah/totally/different path ;;
"multiword phrase") cd /tmp ;;
esac
}
This means using something other than "cd" as the command when you want a shortcut, but other than that, it's flexible; you can also add an "ls" to the function so that it always reminds you what's in the directory after you cd, etc.
(Note that to use a multiword argument as above, you need to quote it on the command line, like this:
ccd "multiword phrase"
so it's not really all that convenient. But it'll work if you need to.)
Based on Andrew Medico's suggestion, check out J
Look into pushd, which allows you to maintain a stack of directories which you can push onto, pop off of, or rearrange.
Check out autojmp or dirmarks
Management requires both fast creation and removal of directories. Create many directiories:
mkdir -p user/new_dir/new/_dir/.../new_dir
Remove recursively many directories (be very careful when you are in lower directories!):
rm -r dir/.../new_dir/
For further reading, the cheat sheet may help you:
http://www.scribd.com/doc/2082838/Bash-Command-Line-History-Cheat-Sheet
It contains some nuggets, but I find it rather hard to read. I cannot get commands, like Meta+>, working. They probably help you in navigating long directories.
I realize the question is pretty old, but none of the scripts out there satisfied me, so I wrote a new one.
Here's the requirements I had in mind:
1) Use only bash commands -- I intend to use this on many different unices -- Linux, cygwin, HP-UX, AIX, and a couple others, so I couldn't depend on grep being consistent. Luckily I do have bash everywhere I work.
2) Short code -- I wanted to be able to bind this to a key in GNU screen, and just hit that key to paste the script into the current bash shell I'm using, so that I don't have to setup bash profiles on every system I use. Anything super long would be annoying and take too much time to paste.
3) No file usage -- Don't want to be littering shared logons with random files.
4) Act just like "cd" in the normal case. Don't want to have to think about which command to use before I start typing.
5) Provide "up" usage like this answer: How to manage Long Paths in Bash?
6) Keep a list of recently used directories, and switch to the most recent.
Here's the script:
#Jump History - Isaiah Damron
function jfind() {
lp=${JNHIST//==${PWD}==/==}
lp=${lp%%${lp#==*$1*==}}
lp=${lp##${lp%==*$1*==*}}
lp=${lp//==/}
[[ -d "$lp" ]] && echo $lp && return 0
return 1;
}
function jadd() {
[[ -z "$JNHIST" ]] && export JNHIST='=='
[[ 3000 -lt ${#JNHIST} ]] && export JNHIST=${JNHIST:0:3000} && export JNHIST="${JNHIST%==*}=="
export JNHIST="==$PWD${JNHIST//==${PWD}==/==}"
}
function j() {
{ cd $* 2> /dev/null && jadd; } \
|| { cd ${PWD/$1*/}$1 2> /dev/null && jadd; } \
|| { jfind $1 \
&& { cd $( jfind $1 ) 2> /dev/null && jadd; } ; } \
|| cd $*
}
function jh() {
[[ -z "$1" ]] && echo -e ${JNHIST//==/\\n}
[[ -n "$1" ]] && jfind $1 && cd $(jfind $1) && jadd
}
Usage:
jh [parameters]
If called on its own, without any parameters, it outputs the current history list. If it has a parameter, then it searches through the history for the most recently used directory that contains the string $1, and cd's to it.
j {parameters}
Does cd parameters. If that fails, it checks if any of the parent directories of $PWD match $1, and cd's to it. If that fails, then it calls jh $1. If that fails, then it outputs the result of cd parameters
Note: I used '==' as an internal separator. Hopefully you don't have any directories that contain a '==', but if you do you'll have to change around the script. Just :%s/==/whatever/g

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