I have multiple web applications deployed in Tomcat and service jar shared in TOMCAT_HOME/lib/ext. All of the application are using Spring, and in the service jar I have beans, annotated with Spring 3.1 Caching annotations . I am using Ehcache provider. And I want to have one single CacheManager used by all the web applications. If I define spring cache configurations at web application level, caching works, but separate cacheManager is created for every app/context. 'Shared' Cache Manager is causing problems, because if one the those applications gets undeployed, this shared cacheManager is shut down. So I want a single CacheManager , configured in my service jar, and used for all the calls to methods made from beans from the web apps. My current try is to define following confuguration in service.jar's applicationContext.xml:
<context:annotation-config/>
<context:component-scan base-package="com.mycompany.app" />
<context:component-scan base-package="com.mycompany.portal.service" />
<bean id="cacheManager" class="org.springframework.cache.ehcache.EhCacheCacheManager" p:cacheManager-ref="ehCacheManager"/>
<bean id="ehCacheManager" class="org.springframework.cache.ehcache.EhCacheManagerFactoryBean" p:configLocation="ehcache.xml" ></bean>
<cache:annotation-driven cache-manager="cacheManager"/>
I have defined parent application context via beanRefContext.xml:
<bean id="service.parent.context" class="org.springframework.context.support.ClassPathXmlApplicationContext">
<constructor-arg>
<list>
<value>applicationContext.xml</value>
</list>
</constructor-arg>
</bean>
And I am using this context as a parent context for all of my web apps with following contextParam in web app's web.xml:
<context-param>
<param-name>parentContextKey</param-name>
<param-value>service.parent.context</param-value>
</context-param>
The result is that this parentContext is loaded, but caching doesn't work at all
How can I solve this? Am I on the right way with the defining of the parentContext in the service.jar?
I don't think so. It looks like you are trying to have a single cache for multiple applications by "hacking" the root classloader.
If you need to share your cache across several applications, use a cache manager that supports that use case (i.e. that provides you a service you can reach from each application).
Related
i have hazelcast instance defined using the hazelcast name space and a map in it. also using spring cache abstraction to define cacheManager.
<bean name="siteAdminPropertyPlaceHolderConfigurer"
class="org.sample.SiteAdminPropertyPlaceHolderConfigurer">
<property name="order" value="1000"/>
<!-- last one-->
</bean>
<!-- hazelcast cache manager -->
<hz:hazelcast id="instance" lazy-init="true">
<hz:config>
<hz:group name="${HAZEL_GROUP_NAME}" password="${HAZEL_GROUP_PASSWORD}"/>
<hz:network port="${HAZEL_NETWORK_PORT}" port-auto-increment="true">
<hz:join>
<hz:multicast enabled="${HAZEL_MULTICAST_ENABLED}"
multicast-group="224.2.2.3"
multicast-port="54327"/>
<hz:tcp-ip enabled="${HAZEL_TCP_ENABLED}">
<hz:members>${HAZEL_TCP_MEMBERS}</hz:members>
</hz:tcp-ip>
</hz:join>
</hz:network>
<hz:map name="oauthClientDetailsCache"
backup-count="1"
max-size="0"
eviction-percentage="30"
read-backup-data="true"
eviction-policy="NONE"
merge-policy="com.hazelcast.map.merge.PassThroughMergePolicy"/>
</hz:config>
</hz:hazelcast>
<bean id="hazelcastCacheManager" class="com.hazelcast.spring.cache.HazelcastCacheManager" lazy-init="true"
depends-on="instance">
<constructor-arg ref="instance"/>
</bean>
The problem is that ,this spring context is also used for other tools we have besides the server and that hazelcast starts listening on the port and the tool actually never exit.
i tried to disable all network join (enabled=false) and i though to enable them programatically only when the server starts. but it does not work hazelcast still starts.
i don't want to give up the spring name space as its very convenient for developers to define new maps(spring caches). also i want as little hazelcast code in there.
any idea how to achieve this ?
thanks
Shlomi
I didn't find a way to do this except telling hazecast to shutdown at the end of each tool run.
i also moved the definition above to separated XML context file so it would not be loaded by the tools (at least not all of them)
Hazelcase.shutdownAll();
I'm using spring integration to create multiple services (each running in their own JVM) with JMS endpoints.
Once retry, exception handling, etc is added, the configuration is no longer trivial. I have moved the spring integration into its own context file and import it in all services to have a consistent setup.
eg
<import resource="classpath:/spring/jmsEndpoint.xml"/>
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="properties">
<props>
<prop key="queueName">myServiceQueue</prop>
</props>
</property>
</bean>
<alias name="myBusinessLogic" alias="abstractJmsEndpoint"/>
<bean id="myBusinessLogic" class="..."/>
This configuration allows me to keep each individual service configuration simple, only requiring an override of an abstract bean and setting a few properties.
The problem is I now want multiple jms endpoints in the same service (jvm). As I can't import jmsEndpoint.xml multiple times, what is the best way to reuse the configuration?
See the dynamic-ftp sample - it uses a technique of creating instances of a parameterized application contexts, passing different properries into each. It's README also has links to forum discussions about how to make these contexts children of the main context, in cases where the child needs access to shared resources.
I have developed a small webapp using and SpringMVC(3.1.3.RELEASE) and Hibernate 4.2.0.Final.
I'm trying to convert it to be a multi-tenant application.
Similar topics have been covered in other threads, but I couldn't find a definitive solution to my problem.
What I am trying to achieve is to design a web app which is able to:
Read a datasource configuration at startup (an XML file containing multiple datasource definitions, which is placed outside the WAR file and it's not the application-context or hibernate configuration file)
Create a session factory for each one of them (considering that each datasource is a database with a different schema).
How can i set my session factory scope as session? ( OR Can i reuse the same session factory ?) .
Example:
Url for client a - URL: http://project.com/a/login.html
Url for client b - URL: http://project.com/b/login.html
If client "a" make request,read the datasource configuration file and Create a session factory using that XML file for the client "a".
This same process will be repeating if the client "b" will send a request.
What I am looking, how to implement datasource creation upon customer subscription without editing the Spring configuration file. It needs to be automated.
Here is my code ,that i have done so far.
Please anyone tell me,What modifications i need to be made?
Please give an answer with some example code..I am quite new in spring and hibernate world.
Spring.xml
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close" p:driverClassName="${jdbc.driverClassName}"
p:url="${jdbc.databaseurl}"
p:username="${jdbc.username}" p:password="${jdbc.password}" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${jdbc.dialect}</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
JDBC.properties File
jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.dialect=org.hibernate.dialect.MySQLDialect
jdbc.databaseurl=jdbc:mysql://localhost:3306/Logistics
jdbc.username=root
jdbc.password=rot#pspl#12
hibernate.cfg.xml File
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<mapping class="pepper.logis.organizations.model.Organizaions" />
<mapping class="pepper.logis.assets.model.Assets" />
</session-factory>
</hibernate-configuration>
Thanks,
First create a table for Tenant with tenant_id and associate it with all users.Now, you can fetch this details while the user logs in and set it in session.
We are using AbstractRoutingDataSource to switch DataSource for every request on Spring Boot. I think it is Hot Swapable targets/datasource mentioned by #bhantol above.
It solves our problems but I don't think it is sound solution. I guess JNDI could be a better one than AbstractRoutingDataSource.
Wondering what you ended up with.
Here are some ideas for you.
Option 1) Single Application Instance.
It is somewhat ambitious to to this using what you are actually trying to achieve.
The gist is to simply deploy the same exact application with different context root on the same JVM. You can still tune the JVM as a whole like you would have if you had a truely multi-tenant application. But this comes at the expense of duplication of classes, contexts, local caching, start up times etc.
But as of today the Spring Framework 4.0 does not provide much of an multi-tenancy support (other than Hot Swapable targets/datasource) etc. I am looking for a good framework but it may be a wash to move away from Spring at this time for me.
Option 2) Multiple deployments of same application (more practical as of today)
Just have your same exact application deploy to the same application server JVM instance or even different.
If you use the same instance you may now need to bootstrap your app to pickup a DataSource based on what the instance should serve e.g. client=a property would be enough to pickup a **a**DataSource" or **b**DataSource I myself ended up going this approach.
If you have a different application server instance you could just configure a different JNDI path and treat things generically. No need for client="a" property because you have liberty to define your datasource differently with the same name.
No joy in the Liferay forum on this issue and the clock is ticking on this project. This may be caused by my lack of knowledge of Spring.
I have a JNDI global resource defined in server.xml and a resource link in context.xml in my Tomcat 7 /conf folder. I KNOW the JNDI resource is being loaded because I see the validation query being run as the server starts up. So far so good.
I have a portlet that just provides services to other portlets. In that portlet I have a hibernate.cfg.xml which has a session-factory that also points to the JDBC resource (don't know if this is needed or not). I also have an ext-spring.xml file in the services portlet that has the following:
<bean id="liferayHibernateSessionFactory" class="com.liferay.portal.spring.hibernate.PortletHibernateConfiguration" >
<property name="dataSource" ref="MyJDBCResource" />
</bean>
<bean id="MyJDBCResource" class="org.springframework.jndi.JndiObjectFactoryBean" >
<property name="jndiName" value="java:comp/env/jdbc/MyJDBCResource" />
</bean>
Adding the above in ext-spring.xml fixed an issue with a bean error on that services portlet upon deployment. In that service builder built portlet, a services jar was created and I put that service jar in the Tomcat_Home/lib/ext folder so that I could use the services provided by the portlet in my portlet. So far so good. But, when I invoke the portlet method which calls the services provided by the other portlet with the JNDI references, I get a "user lacks privilege or object not found" error. It is definitely object not found. When the query is run I see absolutely NO activity on the JDBC connection specified by the JNDI resource entry and in drilling down on the connection properties I only see the HSQLDB driver in use. It should be using the MSSQL driver specified in my global resource JNDI entry as far as I understand it.
SO WHAT AM I DOING WRONG? Do I need to add some configuration entries in the portlet that invokes the services?
This seems so simple. In reading the many posts that give instructions on using JNDI/JDBC resources I seem to have followed them correctly. Is there some trick to using JNDI/JDBC resources in LR 6.1.1 and Tomcat 7 that I have missed?
Thanks (and really hoping for some answers!).
First, you could try rewrite JNDI resource reference like this:
<bean id="MyJDBCResource" class="org.springframework.jndi.JndiObjectFactoryBean" >
<property name="jndiName" value="jdbc/MyJDBCResource" />
</bean>
also, you could try different approach on JNDI resource lookup in Spring:
<jee:jndi-lookup id="MyJDBCResource" jndi-name="jdbc/MyJDBCResource" expected-type="javax.sql.DataSource" />
Not sure about first approch, but second will definitively fail early in case no JNDI resource could be found.
Hope this helps.
I would like to deploy multiple independent copies of a particular web-app on the same tomcat server under different context paths. Each web-app will need different configuration settings (database name, password, etc), but I would like to keep the wars exactly identical.
My plan was to have the app figure out its context path on startup, then read a specific .properties file outside of tomcat identified by the context path. For example, if a war was deployed to {tomcat path}/webapps/pineapple, then I would want to read /config/pineapple.properties
I've been trying to find a way to inject an instance of ServletContext via spring (3), but all the advice I've seen so far use the deprecated ServletContextFactoryBean.
Is there a better way to get the context path injected or better way to load external files based on the context path?
With the help of ServletContextAttributeFactoryBean and Spring EL, you can reference ServletContext init parameters (<context-param> in web.xml) like that:
#{contextAttributes.myKey}
This allows you to use PropertyPlaceHolderConfigurer and load property files from arbitrary, user-defined locations:
<bean
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location" value="#{contextParameters.APP_HOME}/conf/app.properties"/>
</bean>
The corresponding definition of the ServletContext init parameter in Tomcat's context.xml:
<Parameter name="APP_HOME" value="file:/test" override="false"/>
Or in your app's web.xml:
<context-param>
<param-name>APP_HOME</param-name>
<param-value>file:/test</param-value>
</context-param>
This should be the solution.
<bean name="envConfig" class="EnvironmentConfiguration">
<property name="locations">
<list>
<value>file:///#{servletContext.contextPath}.properties</value>
</list>
</property>
<property name="ignoreUnresolvablePlaceholders" value="true" />
</bean>
Extend Propertyplaceholderconfigurer to use DB to pick up the values. Example here
Load the actual values of the settings (database name, password etc) to the db as part of seed data
When your web-app's app ctx is being initialized, the properties are resolved from the DB
This is the approach we have been following and works great. If you can switch to Spring 3.1 then it has support for Environment Profiles which may be useful for you.