I'm struggling to get some ajax pagination with cakephp working. I've read the instructions here and various other pages on the internet eg: SO link
However I get an error in the console:
Uncaught type error undefined is not a function
Which occurs on the $(document).ready() function generated by $this->Js->writeBuffer().
Any ideas on what I'm doing wrong?
In my view index.ctp I set the paginator's options:
$this->Paginator->options(array(
'update' => '#content',
'evalScripts' => true)
);
Then carry on with the remainder of the view, in particular I render the table. The controller has fetched data to be displayed.
I output my pagination controls:
echo $this->Paginator->prev();
echo $this->Paginator->numbers();
echo $this->Paginator->next();
At the end of my view I do:
echo $this->Js->writeBuffer();
I have added the relevant helpers and components to my controller:
public $helpers = array('Js' => array('jquery'));
public $components = array(
'Paginator',
'RequestHandler'
);
In default.ctp I have included jquery by adding this to the end of the HTML (just before </body>:
<script src="https://code.jquery.com/jquery.js"></script>
It looks it works in that it generated the relevant javascript and provides the id's for the links but clicking the links just works like normal.
Functions need to exist before they are called
In default.ctp I have included jquery by adding this to the end of the HTML (just before </body>
Jquery needs to be loaded before it is used. Ensure that script tags appear in the rendered html in this order:
<script src="//code.jquery.com/jquery.js"></script>
... anything or nothing ...
<script>
$(document).ready(
...
Related
I have a js file located in assets folder (not View). can i pass a varible from a controller?
In view file:
The Js is called like this
<canvas id="chart1" class="chart-canvas"></canvas>
</div>
It is not possible (in my point of view) to put a variable to external JS file. You can use data-... attributes and get values from html elements.
For example you can pass your PHP variable as a json encoded string variable in your controller.
$data['chart_info'] = json_encode($chart_info);
return view('your_view', $data);
Then put it in data-info like this.
<canvas id="chart1" class="chart-canvas" data-info="{{ $chart_info }}"></canvas>
And finally in JS, you can get the variable and decode (parse) it as following.
let canvas = document.getElementById('chart1');
let info = JSON.parse(canvas.dataset.id);
console.log(info);
You can put that part of the Javascript in the view and send the variable to the same view. For example, add a section in view:
#section('footer')
<script type="text/javascript">
</script>
#endsection
Do not forget that you should add #yield('footer') to the end of your layout view.
I don't like to mix javascript and PHP/Blade, it might be hard to read the code in the future... You could use a different approach, loading the chart with a async ajax request.
You will have to create a end-point that returns the data you need for your chart:
Your router:
Route::get('/chart/get-data', [ ControllerName::class, 'getChartData' ]);
Your controller method:
public function getChartData() {
$chartData = [];
// Your logic goes here
return $chardData;
}
In your javascript (using jquery) file there will be something like that:
function loadChartData() {
$.ajax({
'url': '/chart/get-data',
'method': 'GET'
})
.done((data) => {
// Load your chart here!!!
})
.fail(() => {
console.log("Could not load chart data");
});
}
Hope I helped ;)
i want to load a list of items on my view via ajax here is my code on lst.cpt
<div id='benpane' class='clearfix'>
<script type="text/javascript">
<?php echo $ajax->remoteFunction(array(
'url'=>array('controller'=>'benefits', 'action'=>'display'),
'update'=>'benpane',
'indicator'=>'benIndicator'
)); ?>
</script>
</div>
here is the lst function in my controller
function lst() {
$this->paginate = array('order' => array('ben_name' => 'ASC'),'conditions' => array($this->Benefit->parseCriteria($this->passedArgs)));
$benefit = $this->paginate('Benefit');
$this->set('bens', $benefit);
}
when i try to open the view i get the error
Error: Call to a member function remoteFunction() on a non-object
File: /var/www/hassportal/app/View/Benefits/lst.ctp
Line: 14
what could i be doing wrong?
Besides the fact that the Ajax Helper has been deprecated (and/or perhaps you are not using cakephp 2.x), you seem to be calling the wrong action:
'action'=>'display'
should be:
'action'=>'lst'
Also, I would move the code outside of the DIV that is supposed to be updated with the data coming from that action.
Use this
$this->Ajax->remoteFunction
insited of
$ajax->remoteFunction
Ex:-
<?php echo $this->Ajax->remoteFunction(array(
'url'=>array('controller'=>'benefits', 'action'=>'display'),
'update'=>'benpane',
'indicator'=>'benIndicator'
)); ?>
I followed tutorial from cakephp site but pagination with ajax works only once - the content is updated and its ok. But for the second time I click some page-link the whole page is reloaded - I think that click() event handlers are not binded again when content is refreshed by ajax - I don't know why... I am using this:
$this->Paginator->options(array(
'update' => '#content',
'evalScripts' => true
));
When I load page in the source code there is:
« Previous
$(document).ready(function (){
$("#link-925538478").bind("click", function (event) {
$.ajax({dataType:"html", success:function (data, textStatus){
$("#content").html(data);}, url:"\/final\/books\/index\/page:10\/sort:id\/direction:desc"});
return false;});
...
When I click for example next page (for the first time), everything is refreshed (the link hrefs also so it works) but the scripts are not reloaded so no click events are binded I think and clicking next page again just uses the link.
This is strange because I added this just after the pagination links:
<script>
$(document).ready(function (){
alert('yes');
});
</script>
And the alert is shown after first ajax refresh...
And I set up this thing ofc. <?php echo $this->Js->writeBuffer(); ?> at the end...
-------------------edit
I recognised that its not the paginator - for the following 2 links:
<?php echo $this->Js->link('link1', array('author' => 'abc'), array('update' => '#content')); ?>
<?php echo $this->Js->link('link2', array('author' => '123'), array('update' => '#content')); ?>
Its the same - when I click link1 its ajax, then when I click link2 there is normal reload - so it's somthing with script evaluation after ajax refresh... What that might be?
I am setting up JSHelper like this:
var $helpers = array('Js' => array('Jquery'));
I figured it out!!!
It's because ajax request sets the layout to app/View/Layouts/ajax.ctp and ajax.ctp is:
<?php echo $this->fetch('content'); ?>
I had to add this line
<?php echo $this->Js->writeBuffer(); ?>
To ajax.ctp to write java scripts (so the ajax links work after ajax request).
And now pagination works perfect!!!
Cake php Ajax Paginator not seems to be working fine. I had similar issues also.
I would recommend you to use the cakephp plugin Cakephp-DataTable
This plugin has implemented the pagination and it has most of the features by default. They have also provided documentation and if you find any difficulty in implementing please go throught the issues section
Also the developer is very responsive and can get clarifications for that plugin if you have any.
I'm trying to display an image but is dependent on a dropdown list in Yii. I can get the image from the database and display it, but how to do it dynamically depending on the choice from the dropdown?
Here is the reference: http://www.yiiframework.com/wiki/24/creating-a-dependent-dropdown#hh0 but, let me show you how to do it.
First all all, we need a div where the image will be displayed; I'll create one whose id will be 'img'. Then, the ajax request is specified inside the dropdownlist() as follows:
<?php echo $form->labelEx($model,'attribue'); ?>
<?php echo $form->dropDownList($model,'attribute',
array(/*The options in the DropDownList*/),
array(
'ajax'=>array(
'type'=>'POST',
'url'=>CController::createUrl('YourController/actionWhichEchoesTheImage'),
'update'=>'#img',
)));
?>
<div id="img"> // <---- the result of the ajax call will be displayed here
</div>
In the 'url' attribute we specify the function which will be called when the ajax request triggers. In the 'update' attribute we specified the div where will be displayed the result of calling that function (the image).
Finally, we have to declare the action actionWhichEchoesTheImage(). Let's declare it in the current controller. It would look something like this:
public function actionWhichEchoesTheImage()
{
if(isset($_POST['ModelName']['attribute']))
/*Here goes your code to load the image*/
echo CHtml::image(//Check the reference to see how to set this function);
}
Check CHtml::image() here: http://www.yiiframework.com/doc/api/1.1/CHtml/#image-detail
I'm trying to set up a basic web page, and it has a small music player on it (niftyPlayer). The people I'm doing this for want the player in the footer, and to continue playing through a song when the user navigates to a different part of the site.
Is there anyway I can do this without using frames? There are some tutorials around on changing part of a page using ajax and innerHTML, but I'm having trouble wrapping my head aroung getting everything BUT the music player to reload.
Thank you in advance,
--Adam
Wrap the content in a div, and wrap the player in a separate div. Load the content into the content div.
You'd have something like this:
<div id='content'>
</div>
<div id='player'>
</div>
If you're using a framework, this is easy: $('#content').html(newContent).
EDIT:
This syntax works with jQuery and ender.js. I prefer ender, but to each his own. I think MooTools is similar, but it's been a while since I used it.
Code for the ajax:
$.ajax({
'method': 'get',
'url': '/newContentUrl',
'success': function (data) {
// do something with the data here
}
});
You might need to declare what type of data you're expecting. I usually send json and then create the DOM elements in the browser.
EDIT:
You didn't mention your webserver/server-side scripting language, so I can't give any code examples for the server-side stuff. It's pretty simple most of time. You just need to decide on a format (again, I highly recommend JSON, as it's native to JS).
I suppose what you could do is have to div's.. one for your footer with the player in it and one with everything else; lets call it the 'container', both of course within your body. Then upon navigating in the site, just have the click reload the page's content within the container with a ajax call:
$('a').click(function(){
var page = $(this).attr('page');
// Using the href attribute will make the page reload, so just make a custom one named 'page'
$('#container').load(page);
});
HTML
<a page="page.php">Test</a>
The problem you then face though, is that you wouldnt really be reloading a page, so the URL also doesnt get update; but you can also fix this with some javascript, and use hashtags to load specific content in the container.
Use jQuery like this:
<script>
$("#generate").click(function(){
$("#content").load("script.php");
});
</script>
<div id="content">Content</div>
<input type="submit" id="generate" value="Generate!">
<div id="player">...player code...</div>
What you're looking for is called the 'single page interface' pattern. It's pretty common among sites like Facebook, where things like chat are required to be persistent across various pages. To be honest, it's kind of hard to program something like this yourself - so I would recommend standing on top of an existing framework that does some of the leg work for you. I've had success using backbone.js with this pattern:
http://andyet.net/blog/2010/oct/29/building-a-single-page-app-with-backbonejs-undersc/
You can reload desired DIVs via jQuery.ajax() and JSON:
For example:
index.php
<script type="text/javascript" src="jquery-1.4.2.js"></script>
<script type="text/javascript" src="ajax.js"></script>
<a href='one.php' class='ajax'>Page 1</a>
<a href='two.php' class='ajax'>Page 2</a>
<div id='player'>Player Code</div>
<div id='workspace'>workspace</div>
one.php
<?php
$arr = array ( "workspace" => "This is Page 1" );
echo json_encode($arr);
?>
two.php
<?php
$arr = array( 'workspace' => "This is Page 2" );
echo json_encode($arr);
?>
ajax.js
jQuery(document).ready(function(){
jQuery('.ajax').click(function(event) {
event.preventDefault();
// load the href attribute of the link that was clicked
jQuery.getJSON(this.href, function(snippets) {
for(var id in snippets) {
// updated to deal with any type of HTML
jQuery('#' + id).html(snippets[id]);
}
});
});
});