I am looking for the way to refresh a template inside a view rendered from another controller than the template's controller, I mean:
I got two controllers AdminController & UserController. And two gsps /admin/listUsers & /user/_searchResult.
Then a want to render view listUsers who have inside the template _searchResult and all right.
Now, i want to refresh the template _searchResult, but cant find how. I tryed calling render(view:"/admin/listUsers", template:"/user/_searchResult", model:[searchResult:result])
AdminController.groovy
#Secured(['ROLE_ADMIN'])
def listUsers(){
//...
}
UserController.groovy
#Secured(['ROLE_ADMIN'])
def search(){
//search users for the givven params and send result by chain if there's an action or update a template if it's needed
//in my case this method need to update the template _searchResult
}
#Secured(['ROLE_ADMIN'])
def searchResult(){
//...
[searchResult:result]
}
listUsers.gsp
//...
<formRemote name="searchForm" url="[action:"search", controller:"user"]">
//Some fields for the search
//I need to place here some hidden inputs to send which
//template i want to update or action to redirect
</formRemote>
<g:render template="/user/_searchResult"/>
//...
_searchResult.gsp
//Just itterate and print the search result in a table
I hope I have explained the problem correctly, thanks!
I don't think I entirely understand your question, but I think the source of your confusion is that the way you are naming things doesn't follow regular conventions and you're not using the right tools for the job. Let me explain...
The methods on Controllers are called Actions. They send some data (the Model) to a View to be rendered into HTML. Views can be composed from smaller, reusable fragments called Templates. (sorry if I sound like I'm being condescending here, but I'm just trying to make sure we're all on the same page).
Now, what you've called templateA is actually a View, not a Template. You're correct that templateA (your View) can call templateB to render some markup, but then having the templateB try to call a method on another Controller doesn't make sense. That's not how things flow.
If you have some logic that needs to be executed after you've sent your Model to the View, you want to use a Tag Library (http://grails.org/doc/latest/guide/theWebLayer.html#taglibs).
To summarise, here's a quick recap.
A request should only call one Action, which sends the model to only one view.
If you need to reuse logic between Controllers, move that code to a Service.
If you need to reuse markup between Views, move that markup to a Template.
If you have logic that you want to have executed after you've sent the Model to the View, use a Tag Library.
Hopefully this will point you in the right direction.
--- UPDATE ---
OK, with the real code I can see better what you're trying to achieve. Firstly, as you're using the <g:formRemote> tag, you should have a good read of the docs at http://grails.org/doc/latest/ref/Tags/formRemote.html to understand what it does.
What you will have here is 2 separate requests. The first will be a regular page load by your browser, which is handled by the listUsers() action. Once the page is then finished loading, the user will enter a search term and hit the submit button. This will fire off a second ajax request, which will be handled by the search() action. This action could use the _searchResult.gsp template to render a HTML table to display the search results. When the browser get this, it will insert it into the DOM where you've told it to put it using the "update" attribute of the <g:formRemote> tag.
The important thing here is that from the server's perspective, these are 2 separate requests that are completely independent. They both first call an action, then send a model (a Map containing some data) to a view, which renders/merges the data with HTML and sends it back to the browser.
The difference between the 2 is that the first is a complete page load by the browser, whereas for the second request, the browser only loads a small chunk of HTML (the search results table) and updates the page content without reloading it.
So your code would look more like this...
AdminController.groovy
#Secured(['ROLE_ADMIN'])
def listUsers() {
render(view:"/admin/listUsers")
}
listUsers.gsp
<g:formRemote name="searchForm" update="insertSearchResultsHere"
url="[controller: 'user', action:'search']">
<input name="searchTerm" type="text" />
</g:formRemote>
<div id="insertSearchResultsHere"></div>
UserController.groovy
#Secured(['ROLE_ADMIN'])
def search() {
// use the search term to get a List<User>
render(template: "/user/searchResult", model: [users: users])
}
_searchResult.gsp
<table>
<g:each var="user" in="${users}">
%{-- Iterate through your search results --}%
</g:each>
</table>
I solved it by placing the attribute update and rendering the template alone:
gsp:
<formRemote name="searchForm" url="[action:"search", controller:"user"]" update="divToUpdate">
//Some fields for the search
</formRemote>
<div id="divToUpdate">
<g:render template="/user/_searchResult"/>
</div>
Controller:
def search(){
render(template:"/user/_searchResult", model:[searchResult:result])
}
When i asked this question, i was new on Grails community and i was confused with the use of remoteFunction and tags that use it like remoteForm. But i had this confusion because of i had not read the documentation. So in my case, the solution was search for documentation about how to use remote tags and render. Thanks to #AndrewW for show me the way.
Related
I am newbie to MVC and Web App.
Recently I have went through the article
http://www.c-sharpcorner.com/UploadFile/pmfawas/Asp-Net-mvc-how-to-post-a-collection/
It uses the Ajax Form, to do the partial update towards a particular region alone..
But I have a doubt in that example...
I have seen the partial Page inside the Div with Id "AllTweets"....
<div id="AllTweets">
#Html.Partial("_AllTweets", Model) ***** (XXX)
</div>
And also in the controller action,
try
{
viewModel.Tweets.Add(viewModel.Tweet);
return PartialView("_AllTweets", viewModel); **** (YYYYY)
}
Now my question is,
They are returning the partial view along with the data from the action in the controller.
Whatever the data returned from the controller, the engine will place that data, inside the target div with id "AllTweets"...
But still, why I have to have the statement, #Html.Partial("_AllTweets", Model) inside the Div, since already I am returning the data from the controller...
And also in some of the examples, i have seen the same kind of the code..
But, even if I have removed the code "#Html.Partial("_AllTweets", Model)" inside the div, the code still works fine, and without any problem and i can able to post the data to the action in the controller.
I got totally stuck at this point.
May I kindly know, what is the reason behind it and why so.... So I can understand it more better.
Thanks in advance...
But, even if I have removed the code #Html.Partial("_AllTweets",
Model) inside the div, the code still works fine, and without any
problem and i can able to post the data to the action in the
controller.
Yes it will work fine. The Html.Partial("_AllTweets",Model) renders the partial with the specified model on every page load. After page is loaded, then ajax is used to fill the div with id AllTweets.
Html.Partial("_AllTweets",Model) is usefull when you want to display, for example, already saved tweets from your database to user when the page first loads. And then ajax takes care of later updates.
The page that I'm working with has a couple tabs and the content of each tab is loaded in via ajax by requesting a partial view from the controller. The problem is that the partial view uses knockoutjs, so it is bound to a view model. In this particular scenario, the page is loaded up in its entirety first time through, so all of the bindings work fine. When you switch tabs, it requests a partial view and replaces the tab content area with the new page. When you switch back to the first tab, it'll successfully loads the partial, except it would appear that all of the knockout bindings have been lost so there is a lot of missing data.
I can't place the viewmodel declaration and model bind in the partial because jquery hasn't been loaded by that point. Or so it would seem ($ is not defined).
The view model is declared and bound on the main page that calls the partial view(s), not the partial view itself, so I thought the model would still be available and bind successfully, but it does not. I know I'm doing this wrong, and partial view are super wonky when it comes to javscript so I'm hoping to steal a bit of insight from you guys.
Here's the basic setup:
If you are able to bind to specific non-overlapping areas of the page, then you could choose to call ko.applyBindings(someViewModel, someDomElement) like in this answer: Can you call ko.applyBindings to bind a partial view?
However, if you have an overall view model bound to the page and then "islands" of content that are loaded via a partial that you want to bind later, then one option would be to go for something like this: http://www.knockmeout.net/2012/05/quick-tip-skip-binding.html. So, you would set up a binding on the container of where your partial goes that tells Knockout to keep its hands off of that area. Then when you load the partial, you can safely call ko.applyBindings(someViewModel, innerContainer).
The binding might look like:
ko.bindingHandlers.stopBinding = {
init: function() {
return { controlsDescendantBindings: true };
}
};
and you would use it like:
<div id="outerContainer" data-bind="stopBinding: true">
<div id="innerContainer">
...load your partial here
</div>
</div>
Then, ko.applyBindings(someViewModel, document.getElementById("innerContainer"));
Using ASP.NET MVC 3 and Razor, I have a strongly typed view against MyViewModel class. Within the view I have an AJAX form that consists of a group of radio buttons. Below it, I have a normal HTML form that collects data for MyViewModel. Depending on which radio button is selected in the AJAX form, I want to update the HTML form with one set of default values or another. In the AJAX form, I'm trying to post two pieces of data: 1) a value that represents the option chosen (basedon the radio button value parameter), and 2) the Model from the view. I want the controller action to update the model based on the option received, and then return a partial view with the updated model object as parameter. How do I do this? Here's the code for the AJAX form for my attempt:
#using (Ajax.BeginForm("MyAction", "MyController",
new AjaxOptions {
HttpMethod = "POST",
InsertionMode = InsertionMode.Replace,
UpdateTargetId = "createForm"
}))
{
<div id="formOptions">
#foreach (Option op in Model.GetOptions()) {
<div class="editor-field">
#Html.RadioButton("option", op.OptionType, false, new { #id = op.ID, #name = op.ID, #title = #op.Description, #onfocus = "javascript:$(this).closest('form').find(':submit').first().click()" })
<label for="#op.ID">#op.Name</label>
</div>
}
</div>
#Html.Hidden("model", Model)
<input type="submit" value="Select" style="display:none;" />
}
My problem is that the model parameter in the HttPost action method is null. However, the option parameter seems to get passed correctly. I'm not sure if I'm using the Html.Hidden input in a way it's not supposed to be used or what the problem is. I can post more code if needed.
This is my first attempt at doing something like this, so after reading a lot of (seemingly) similar questions I still cannot decipher the solution for what I want to do. I see a lot of different things, like JSON encoding, using JQuery, etc., but I'm not sure if I need those things, or if I can accomplish this using MVC features (I'd rather not recode things that are already built into MVC 3). If anyone can point me in the right direction or possibly give a little code example, it would be appreciated. And, given what my end goal is, if there's a better way to asynchronously update a form based on option controls, I'd be very interested to hear about it. Thanks!
EDIT:
I also noticed that the request using HttpPost does not make it to the controller, but a HttpGet does. Anyone out there? This is driving me nuts!
ADDED CONTROLLER METHOD:
public PartialViewResult CreateForm(OptionType opType, MyViewModel model) {
model.ApplyOptionValues(opType);
return PartialView("_CreateForm", model);
}
I would not post the entire model back to the controller which you are attempting to do with #Html.Hidden("model", Model) simply place the specific items you need in the form with names/types that match your controller. You can use the selected radio button's value as well as a hidden input's values to pass identifying information to the controller and perform whatever logic you need there.
That being said, I think the best solution going forward would be to use some javascript framework like JQuery to handle all AJAX requests. Asp.net MVC makes it really easy to do simple operations with the built in pieces, but once you need to perform more complicated operations, it definitely falls short. You end up putting in more effort to work within the limitations than if you just used the correct tool (JQuery).
Make sure that you annotate your POST action methods with [HttpPost] to differentiate from GET methods.
Also use a detailed web debugger to examine exactly what is being sent to your application. I like Fiddler, which is extremely popular.
http://www.fiddler2.com/fiddler2/
I would agree with Mattbo: posting the whole model round in a circle is unnecessary overhead. You don't say why you are but I suspect it's so you can compare 'old' and 'new' values. Given the model originates in the controller, you could include a unique identifier for the model (e.g. GUID) in the ViewModel, put that in a hidden field to include in your POST data, then on the return POST your 'new' data will be auto mapped to the strongly typed ViewModel. You can then re-get the original model and do whatever you need to with them both.
Dealing with the AJAX form is a separate issue/form then: you have your radio buttons which fill out default values in the (view model) form (including a hidden field to record which radio was selected), the user fills out the other data and the whole of the (non ajax) form gets posted to the MyController.MyAction method and the default binders will automatically map the form values to the MyViewModel, if they follow the right naming convention. So the AJAX has nothing to do with the form that is actually posted. Alternatively you could do the whole thing with AJAX as Mattbo also suggests.
[Aside] Forgive me if you already know but you can use the razor Html helpers to create your fields like:
#Html.EditorForModel()
#Html.EditorFor(model => model.[field name])
In the Controller you would create the actions like:
public ActionResult MyAction()
{
MyViewModel
}
[HttpPost]
public ActionResult MyAction(MyViewModel myModel)
What is the best way to address an AJAX script that sends data to POST in codeigniter? Right now I am loading a view with the AJAX through $this->load->view('AJAX', $data); however there is no UI or user actions in the view. It's simply running through the script and returning POST data a little after the script loads. I receive the POST data in my model where I input the values into the DB and output some other values based on the data.
I need to open a real view, set metatags and re-direct the user to another website afterwards.
How do I address this?
The problem I'm facing is that I cannot open up another view because the AJAX view is the one that's in focus but I need this AJAX view to be temporary that basically does it's thing and sends to POST.
Is there any convention that I can lookup/research to what I'm describing? Let me know what kind of clarification is needed if any.
Some people like to write "ajax" controllers and post to them exclusively, but you don't need to do that. You can handle the request in the same controller that handles the non-ajax request. Personally, I exclusively return json, but you can return chunks of HTML if that works better for you.
Your exact problem is vague (actual code would help clarify), but I think you are on the wrong track. Don't use a view for processing anything ever. Use your Controller layer, this is for handling input and requests.
Example of controller method responding to either ajax or non-ajax request:
function edit_user()
{
$data['status'] = $this->user_model->save();
if ($this->input->is_ajax_request())
{
// return json string with our update status
// Something like: {"status":true}
echo json_encode($data);
exit;
}
// Load the non ajax view with the same data
$this->load->view('users/edit', $data)
}
$this->input->is_ajax_request() is a function of the Input class that reads $_SERVER['HTTP_X_REQUESTED_WITH'] and checks if it's value is XMLHttpRequest. This should only be true if it's an "ajax" request.
You can make life easier by wrapping this in a class or function. No matter what you decide to do, don't use the view layer for processing data.
I think my problem is, how do I address javascript without a view? how do I call the script and/or where do I put the JS code in the controller? I felt it was the wrong direction to address the code in a view but I didn't see how else to do it.
Whenever possible, you should put javascript code in a .js file and use a <script> tag to load it, in an HTML document. The only other exception is putting it in a "view" file (a file that's only purpose is to construct your final HTML output). In other words, follow the same rules of HTML as to where to put javascript, and follow the usual conventions of MVC of where HTML belongs (in the view). Javascript code does not belong in your controller. Javascript is not processing your data, it is sending the data to the server.
I need to open a real view, set metatags and re-direct the user to another website afterwards.
If you want to load a view, then redirect (after a certain amount of time I assume), you can do it with javascript or a <meta> tag (but don't use a meta tag, use js).
I've been using Codeigniter in order to get accustomed to the Model-View-Controller architecture, and to try and speed up the process of making and implementing sites.
I keep seeing references to "Partial Views" but can't find a definition for the term.
Can anyone tell me what a partial view is, and where it is used?
A partial view is just a sub-view that you can include in a parent view. Let's take a look at a common example:
// Controller:
$data['myvar'] = array('element1', 'element2', 'element3');
$this->load->view('myview', $data);
// Myview:
<ul>
foreach ($myvar as $var) {
$this->load->view('partialview', array('var', $var));
}
</ul>
// Partialview:
<li><?= $var ?></li>
This is useful to repeat content according to a list.
Note that nothing differs between a view and a partialview, it's just the way you include it that defines the term.
The best way to describe a "partial view" is to think of it as a template, it displays a chunk of html with Model data passed to it.
Good examples of where to use one would be where you plan on displaying the same html over and over, like a menu or a page header or even better yet use them to display content requested using ajax.
Basically you call an action on the controller that returns the partial view from lets say jQuery and then put the returned markup into a select or div tag. Here is an example of doing that from my blog easy ajax with aspnet mvc and jquery, yes I know it asp.net mvc not php and codeigniter, but the principal is the same.