I am new in Laravel 4 framework, I am working on library management project. I get all the data from my DB but I can't add a new book to my database.
I've created a form to add new books to my database. I get the Input::get('element') value from my store() method but the create Methode doesn't work . here's my code to save a new book :
Livre::create(array('titre' => Input::get('titre'),
'resume'=> Input::get('resume') ));
and here's my Model :
class Livre extends Eloquent {
protected $table = 'livre';
}
You need to create a new Model instance by calling:
$livre = new Livre;
Then add your 'fields':
$livre->titre = Input::get('titre');
$livre->resume = Input::get('resume');
Then save your new book by calling the save() or push() method:
$livre->save();
Or if you'd like to save a model with its relationships, use the push() method:
$livre->push();
Seems that when you say that create method doesn't work you mean that the record in your DB is created, but it has empty values. This happens when you dont't specify the fields enabled for massive assignment.
By default , the Eloquent model has the guarded attribute set to a wildcard blocking of mass assignment. To use the code that you showed us, modify your model :
class Livre extends Eloquent {
protected $table = 'livre';
protected $fillable = array(
'titre',
'resume'
);
}
You can read more here : Mass Assignment
Related
In laravel 6 project there is a model with guarded id field:
class Customer extends Model implements Transformable
{
use SoftDeletes, RevisionableTrait, TransformableTrait;
protected $table = 'customers';
protected $guarded = ['id'];
and creating new customer with factory, I see null id field value:
$NewCustomer = factory(Customer::class)->make();
\Log::info( '-99 $NewCustomer->id ::' . print_r( $NewCustomer->id, true
) ); // THIS value is null
How to read id value of $NewCustomer ?
Thanks!
Make only creates an object but does not save it to the database. Therefore you do not get an id.
The primary key will be auto-incremented in the database, so you only know the id after you save the object.
Creating Models
If you want to save automatically you can also directly use the save function:
$NewCustomer = factory(Customer::class)->create();
This work the same as:
$newCustomer = factory(Customer::class)->make();
$newCustomer->save();
Persisting Models
Also guarded is only a security feature for mass-assignment and prevents saving the id row on those.
Mass Assignment
I get via Request a Json Object.
I clearly parse this object in order to check if it may fit the destination model.
Instead of assigning property by property. Is there a quick way to populate the model with the incoming object?
If you have an array of arrays, then you can use the hydrate() method to cast it to a collection of the specified model:
$records = json_decode($apiResult, true);
SomeModel::hydrate($records);
If you just have a single record, then you can just pass that array to the model’s constructor:
$model = new SomeModel($record);
Just pass your object casted to array as Model constructor argument
$model = new Model((array) $object);
Internally this uses fill() method, so you may first need to add incoming attributes to $fillable property or first create model and then use forceFill().
You should convert that object to array and use fill($attributes) method.
As method name says, it will fill object with provided values. Keep in mind that it will not persist to database, You have to fire save() method after that.
Or if You want to fill and persist in one method - there is create($attributes) which runs fill($attributes) and save() under the hood.
You can use Mass Assignment feature of Laravel,
You model would look like this:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
/**
* The attributes that are mass assignable.
*
* #var array
*/
protected $fillable = ['name', 'email', 'phone'];
}
And the process of populating the Model would be like this:
// This would be your received json data converted to array
// use 'json_decode($json, true)' to convert json data to array
$json_arr = [
'name' => 'User Name',
'email' => 'email#example.com',
'phone' => '9999999999'
];
$user = new \App\User($json_arr);
Hope this helps!
Castings may fail due to several reasons. A safe way is to add a static function to the model to generate from both array or object. feels like an extension to the model.
public static function generateFromObject($object)
{
$myModel = new MyModel();
foreach($object as $k => $v)
$myModel->{$k} = $v; //for arrays $myModel[$k] = $v;
return $myModel;
}
and you can use anywhere like,
$myModel = MyModel::generateFromObject($myObjectOrArray)->save();
I'm very new to laravel and PHP MVC frameworks, it's my first use of Eloquent. I'm trying to following a video tutorial.
So after creating a table by making new migration and migrate with artisan.
I created a model.Then I tried to instance it using tinker tool like so :
>>> $task = new App\Task;
I got this error :
=> App\Task {#672}
this my model class :
class Task extends Model
{
protected $table = 'tasks';
}
I did many research before asking this question, some people recommends using homestead, but I want to understand what I'm doing wrong.
This is not an error. It shows that an Object of App\Task Class has been created.
Now you can assign values to this $task Object. Like we have a field 'name' in tasks table then the following part of code can save the $task in database with value of 'name' field.
$task = new App\Task;
$task->name = 'My first task';
$task->save();
I want to create a whole bunch of instances of a model object in Laravel, then pick the optimal instance and save it to the database. I know that I can create an instance with Model::create([]), but that saves to the database. If possible I'd like to create a bunch of models, then only "create" the one that is best.
Is this possible?
I am using Laravel 5.0
You create a new model simply by instantiating it:
$model = new Model;
You can then save it to the database at a later stage:
$model->save();
You can create instances with Model::make(). It works the same way as create but it doesn't save it.
Whether or not this is best practice is another matter entirely.
Yes, it is possible different ways: you can use the mass assignment without saving.
Please remember to set first the $fillable property in your model.
WAY #1: using the method fill
$model = new YourModel;
$model->fill([
'field' => 'value',
'another_field' => 'another_value'
]);
$model->save();
WAY #2: using the constructor
$model = new YourModel([
'field' => 'value',
'another_field' => 'another_value'
]);
$model->save();
In YourModel set the $fillable property with the fileds allowed for mass assignment:
class YourModel extends Model
{
protected $fillable = ['field', 'another_field'];
// ...
}
Laravel documentation: https://laravel.com/docs/9.x/eloquent#mass-assignment
there is also a method you can call it statically to get new instance:
$modelInstance = $modelName::newModelInstance();
it takes array $attributes = [] as a parameter
I am new with Laravel, I was able to query Many-to-Many relationships. Where 'template_dynamic' is the pivot of two tables 'template' and 'dynamic'.
// Template Model
class Template extends Eloquent
{
protected $table = 'template';
protected $guarded = array('template_id');
protected $primaryKey = 'template_id';
public function dynamic()
{
return $this->belongsToMany('dynamic', 'template_dynamic')
->select('*')
->withPivot('template_dynamic_id')
->orderBy('template_dynamic_html_sort', 'ASC');
}
here I was able to retrieve the records
// Template Controller
$dynamic_fields = Template::find($rec->template_id)->dynamic;
what I want to do now is that pivot table has-many properties 'template_dynamic_option'. How will I query the records and combine it with $dynamic_fields variable?
// What I want to do is something like this. But sadly this is an invalid syntax
$dynamic_fields = $dynamic_fields->with('template_dynamic_option');
Any recommendation or enhancements are welcome.
Thank you in advance.
First, I am pretty sure you don't need the select('*') in your relationship query there.
But let's get to your actual problem ;)
To access the pivot table in Eloquent is pretty simple.
$dynamic_fields = Template::find($rec->template_id)->dynamic;
foreach($dynamic_fields as $dynamic){
var_dump($dynamic->pivot)
}
The thing is though, by default only the keys of the pivot table are present in the object.
To change that you have to define them with withPivot(). Actually like you already did but not with the id.
public function dynamic()
{
return $this->belongsToMany('dynamic', 'template_dynamic')
->withPivot('template_dynamic_option')
->orderBy('template_dynamic_html_sort', 'ASC');
}
And if you have multiple additional columns use this syntax:
->withPivot('template_dynamic_option', 'foo', 'bar');