How to create channel interceptor programmatically in spring - spring

Question

I want to create programmatically the following XML config on demand:
<int-mqtt:message-driven-channel-adapter id="inboundAdapter"
client-id="${mqtt.client.id}"
url="${mqtt.broker.url}"
topics="${mqtt.subscribed.topics}"
client-factory="clientFactory"
channel="input-channel-1" converter="customConverter" />
<int:channel id="input-channel-1">
<int:queue/>
<int:interceptors>
<int:wire-tap channel="logger"/>
<int:ref bean="messageListener"/>
</int:interceptors>
</int:channel>
<int:channel id="logger" />
<int:logging-channel-adapter channel="logger"
auto-startup="true" level="INFO" id="loggerAdapter" log-full-message="true" />
What i can do is the following
CustomMqttPahoMessageDrivenChannelAdapter adapter = new CustomMqttPahoMessageDrivenChannelAdapter(url, clientId, topic);
adapter.setOutputChannel(outputChannel);
adapter.setConverter(ctx.getBean("customConverter", MyPahoMessageConverter.class));
Now I need to add interceptor bean through which each client will get notified when message arrives according to their subscribed topics respectively.
What I am trying to achieve is:
1) Create mqtt adapter when a client connects to server.(each client will subscribe to different topics as per configuration)
2) Dispose mqtt adapter when client disconnects.
Can anyone help me on this?

Answer 1

It's not clear what you are trying to do; what do you have downstream of the input-channel-1 in the XML configuration.
What does messageListener do?
It is an anti-pattern to put business logic in a channel; unless it's something really lightweight, consider invoking it using a <service-activator/> instead - possibly by making input-channel-1 a pub-sub channel.
To answer your simple question, to add the interceptor, you can use outputChannel.addInterceptor(ctx.getBean("messageListener", ChannelInterceptor.class));.