To upload image i'am using this code:
[HttpPost]
public ActionResult Index(FotoModel model)
{
if (ModelState.IsValid)
{
if (model != null && model.File != null)
{
var fileName = Path.GetFileName(model.File.FileName);
var path = Path.Combine(Server.MapPath("~/Content/Images"), fileName);
model.File.SaveAs(path);
return View();
}
}
return View();
}
Works fine, but is there option to change file name ?. I was trying do something like this:
fileName = FileMode(fileName, "user");
But there an exception: "System.IO.FileMode is a type but is used like a variable"
Doesn't Path.Combine() allow for combining strings into a filename? So couldn't you simply do:
var fileName = "user";
var path = Path.Combine(Server.MapPath("~/Content/Images"), fileName);
In which case use the following to strip the extension then re-add it to the new filename:
string newName = "user";
fileName = newName + fileName.Substring(fileName.LastIndexOf("."));
Related
Everything is setup well (call method, .xsd file, rdlc file, when i do debugging I can see data in my model, I can download the excel file, but it is still remining empty?! Wher did I'm wrong in my code? Any clue?
My ActionResult in Controller:
[HttpGet]
public ActionResult Export_StudentStatus()
{
List<pr_ReportDataGenerate_AllGeneralOverview_Result> model = Context.pr_ReportDataGenerate_AllGeneralOverview().Where(p => p.rdTypeID == 2).ToList();
ReportViewer viewer = new ReportViewer();
try
{
Warning[] warnings;
string[] streamIds;
string mimeType = string.Empty, encoding = string.Empty, extension = string.Empty;
viewer.ProcessingMode = ProcessingMode.Local;
//viewer.LocalReport.EnableExternalImages = true;
viewer.LocalReport.ReportPath = Server.MapPath("~/RDLC/GeneralOverviewStudentStatus.rdlc");
viewer.LocalReport.DataSources.Add(new ReportDataSource("dsGeneralOverviewAnnualAwards", model));//ova e DS vo reportot
viewer.LocalReport.EnableHyperlinks = true;
byte[] bytes = viewer.LocalReport.Render("Excel", null, out mimeType, out encoding, out extension, out streamIds, out warnings);
Response.Clear();
Response.ContentType = mimeType;
Response.AddHeader("content-disposition", "attachment; filename=GeneralOverviewStudentStatus.xls");
Response.BinaryWrite(bytes);
Response.End();
return null;
}
finally
{
if (viewer != null)
{
viewer.Dispose();
viewer = null;
}
}
}
I am attempting to upload an image using MVC 6; however, I am not able to find the class HttpPostedFileBase. I have checked the GitHub and did not have any luck. Does anyone know the correct way to upload a file in MVC6?
MVC 6 used another mechanism to upload files. You can get more examples on GitHub or other sources. Just use IFormFile as a parameter of your action or a collection of files or IFormFileCollection if you want upload few files in the same time:
public async Task<IActionResult> UploadSingle(IFormFile file)
{
FileDetails fileDetails;
using (var reader = new StreamReader(file.OpenReadStream()))
{
var fileContent = reader.ReadToEnd();
var parsedContentDisposition = ContentDispositionHeaderValue.Parse(file.ContentDisposition);
var fileName = parsedContentDisposition.FileName;
}
...
}
[HttpPost]
public async Task<IActionResult> UploadMultiple(ICollection<IFormFile> files)
{
var uploads = Path.Combine(_environment.WebRootPath,"uploads");
foreach(var file in files)
{
if(file.Length > 0)
{
var fileName = ContentDispositionHeaderValue.Parse(file.ContentDisposition).FileName.Trim('"');
await file.SaveAsAsync(Path.Combine(uploads,fileName));
}
...
}
}
You can see current contract of IFormFile in asp.net sources. See also ContentDispositionHeaderValue for additional file info.
There is no HttpPostedFileBase in MVC6. You can use IFormFile instead.
Example: https://github.com/aspnet/Mvc/blob/dev/test/WebSites/ModelBindingWebSite/Controllers/FileUploadController.cs
Snippet from the above link:
public FileDetails UploadSingle(IFormFile file)
{
FileDetails fileDetails;
using (var reader = new StreamReader(file.OpenReadStream()))
{
var fileContent = reader.ReadToEnd();
var parsedContentDisposition = ContentDispositionHeaderValue.Parse(file.ContentDisposition);
fileDetails = new FileDetails
{
Filename = parsedContentDisposition.FileName,
Content = fileContent
};
}
return fileDetails;
}
I was searching around for quite a while trying to piece this together in .net core and ended up with the below. The Base64 conversion will be next to be done so that the retrieval and display is a little easier. I have used IFormFileCollection to be able to do multiple files.
[HttpPost]
public async Task<IActionResult> Create(IFormFileCollection files)
{
Models.File fileIn = new Models.File();
if(model != null && files != null)
{
foreach (var file in files)
{
if (file.Length > 0)
{
var fileName = ContentDispositionHeaderValue.Parse(file.ContentDisposition).FileName.Trim('"');
byte[] fileBytes = null;
using (var fileStream = file.OpenReadStream())
using (var ms = new MemoryStream())
{
fileStream.CopyTo(ms);
fileBytes = ms.ToArray();
//string s = Convert.ToBase64String(fileBytes);
// act on the Base64 data
}
fileIn.Filename = fileName;
fileIn.FileLength = Convert.ToInt32(file.Length);
fileIn.FileType = file.ContentType;
fileIn.FileTypeId = model.FileTypeId;
fileIn.FileData = fileBytes;
_context.Add(fileIn);
await _context.SaveChangesAsync();
}
}
}
return View();
}
EDIT
And below is return of files to a list and then download.
public JsonResult GetAllFiles()
{
var files = _context.File
.Include(a => a.FileCategory)
.Select(a => new
{
id = a.Id.ToString(),
fileName = a.Filename,
fileData = a.FileData,
fileType = a.FileType,
friendlyName = a.FriendlyName,
fileCategory = a.FileCategory.Name.ToLower()
}).ToList();
return Json(files);
}
public FileStreamResult DownloadFileById(int id)
{
// Fetching file encoded code from database.
var file = _context.File.SingleOrDefault(f => f.Id == id);
var fileData = file.FileData;
var fileName = file.Filename;
// Converting to code to byte array
byte[] bytes = Convert.FromBase64String(fileData);
// Converting byte array to memory stream.
MemoryStream stream = new MemoryStream(bytes);
// Create final file stream result.
FileStreamResult fileStream = new FileStreamResult(stream, "*/*");
// File name with file extension.
fileStream.FileDownloadName = fileName;
return fileStream;
}
I have a fileupload function where users can upload files. I want to restrict the users from upload certain file types. The types allowed are: .doc,.xlsx,.txt,.jpeg.
How I can do this?
This is my actual file upload code:
public ActionResult UploadFile(string AttachmentName, BugModel model)
{
BugModel bug = null;
if (Session["CaptureData"] == null)
{
bug = model;
}
else
{
bug = (BugModel)Session["CaptureData"];
}
foreach (string inputTagName in Request.Files)
{
HttpPostedFileBase file1 = Request.Files[inputTagName];
if (file1.ContentLength > 0)
{
string path = "/Content/UploadedFiles/" + Path.GetFileName(file1.FileName);
string savedFileName = Path.Combine(Server.MapPath("~" + path));
file1.SaveAs(savedFileName);
BugAttachment attachment = new BugAttachment();
attachment.FileName = "~" + path.ToString();
attachment.AttachmentName = AttachmentName;
attachment.AttachmentUrl = attachment.FileName;
bug.ListFile.Add(attachment);
model = bug;
Session["CaptureData"] = model;
}
}
ModelState.Clear();
return View("LoadBug", bug);
}
The first thing to verify is whether the file extension contained in file1.FileName matches one of the allowed extensions. Then if you really want to ensure that the user hasn't renamed some other file type to an allowed extension you will need to look into the contents of the file to recognize whether it is one of the allowed types.
Here's an example how to check whether the file extension belongs to a list of predefined extensions:
var allowedExtensions = new[] { ".doc", ".xlsx", ".txt", ".jpeg" };
var extension = Path.GetExtension(file1.FileName);
if (!allowedExtensions.Contains(extension))
{
// Not allowed
}
[AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
public class AllowedFileExtensionAttribute : ValidationAttribute
{
public string[] AllowedFileExtensions { get; private set; }
public AllowedFileExtensionAttribute(params string[] allowedFileExtensions)
{
AllowedFileExtensions = allowedFileExtensions;
}
protected override ValidationResult IsValid(object value, ValidationContext validationContext)
{
var file = value as HttpPostedFileBase;
if (file != null)
{
if (!AllowedFileExtensions.Any(item => file.FileName.EndsWith(item, StringComparison.OrdinalIgnoreCase)))
{
return new ValidationResult(string.Format("{1} için izin verilen dosya uzantıları : {0} : {2}", string.Join(", ", AllowedFileExtensions), validationContext.DisplayName, this.ErrorMessage));
}
}
return null;
}
}
Usage In Model
[AllowedFileExtension(".jpg", ".png", ".gif", ".jpeg")]
public HttpPostedFileBase KategoriResmi { get; set; }
You can use the ContentType property of the HttpPostedFileBase for a basic check of the file type (mime type): See MSDN's page on the Content-Type property here
Here is one way to do it:
private static bool IsValidContentType(string contentType)
{
string ct = contentType.ToLower();
return ((ct == "application/msword") || (ct == "application/pdf") || (ct == "application/vnd.openxmlformats-officedocument.wordprocessingml.document"));
}
etc..
However, for a deeper inspection, you will have to inspect the file content. It's easy to change a file extension..
I have a javascript function from which I need to call a controller action to return the filestream to the UI .
I am not getting the open,save and save as dialog box.
In the cshtml file I have following function:DownloadFile
var selectUrl = '#Url.Action("Download", "Controller")' + "/" + filedetails;
$.post(selectUrl);
and in the controller I have the following code:
public ActionResult Download(string id)
return File(downloadStream, "application/octet-stream",fileName);
Please let me know is this the correct way of calling.
try this way :ActionResult
public ActionResult Download(string id)
{
var cd = new System.Net.Mime.ContentDisposition
{
FileName = "imagefilename",
Inline = false,
};
Response.AppendHeader("Content-Disposition", cd.ToString());
string contentType = "application/octet-stream";
// you are downloadStream
return File(downloadStream, contentType);
}
link here
This code is supposed to download a file using mvc3 controller
public FilePathResult GetFileFromDisk(String file)
{
String path = AppDomain.CurrentDomain.BaseDirectory + "AppData/";
String contentType = "text/plain";
return File(path+file, contentType, file);
}
View part :
#Html.ActionLink("Download", "GetFileFromDisk","Upload", new { file = "textfile" },null);
But when i click the link I am getting this error
Could not find a part of the path 'D:\Project\FileUploadDownload\FileUploadDownload\AppData\textfile'.
[DirectoryNotFoundException: Could not find a part of the path 'D:\Project\FileUploadDownload\FileUploadDownload\AppData\textfile'.]
Why the foldername is repeating in the file path? Please offer a solution...
Try like this:
public ActionResult GetFileFromDisk(string file)
{
var appData = Server.MapPath("~/App_Data");
var path = Path.Combine(appData, file);
path = Path.GetFullPath(path);
if (!path.StartsWith(appData))
{
// Ensure that we are serving file only inside the App_Data folder
// and block requests outside like "../web.config"
throw new HttpException(403, "Forbidden");
}
if (!System.IO.File.Exists(path))
{
return HttpNotFound();
}
var contentType = "text/plain";
return File(path, contentType, Path.GetFileName(path));
}