Hibernate CompositeUserType mapping has wrong number of columns - spring

Question

I am new to Hibernate. Writing a CompositeUserType. When I run the code I am getting error.
property
mapping has wrong number of columns:
Please help me what am I missing?
My CompositeUserType goes as follows
public class EncryptedAsStringType implements CompositeUserType {
#Override
public String[] getPropertyNames() {
return new String[] { "stockId", "stockCode", "stockName","stockDescription" };
}
#Override
public Type[] getPropertyTypes() {
//stockId, stockCode,stockName,modifiedDate
return new Type[] {
Hibernate.INTEGER, Hibernate.STRING, Hibernate.STRING,Hibernate.STRING
};
}
#Override
public Object getPropertyValue(final Object component, final int property)
throws HibernateException {
Object returnValue = null;
final Stock auditData = (Stock) component;
if (0 == property) {
returnValue = auditData.getStockId();
} else if (1 == property) {
returnValue = auditData.getStockCode();
} else if (2 == property) {
returnValue = auditData.getStockName();
} return returnValue;
}
#Override
public void setPropertyValue(final Object component, final int property,
final Object setValue) throws HibernateException {
final Stock auditData = (Stock) component;
}
#Override
public Object nullSafeGet(final ResultSet resultSet,
final String[] names,
final SessionImplementor paramSessionImplementor, final Object paramObject)
throws HibernateException, SQLException {
//owner here is of type TestUser or the actual owning Object
Stock auditData = null;
final Integer createdBy = resultSet.getInt(names[0]);
//Deferred check after first read
if (!resultSet.wasNull()) {
auditData = new Stock();
System.out.println(">>>>>>>>>>>>"+resultSet.getInt(names[1]));
System.out.println(">>>>>>>>>>>>"+resultSet.getString(names[2]));
System.out.println(">>>>>>>>>>>>"+resultSet.getString(names[3]));
System.out.println(">>>>>>>>>>>>"+resultSet.getString(names[4]));
}
return auditData;
}
#Override
public void nullSafeSet(final PreparedStatement preparedStatement,
final Object value, final int property,
final SessionImplementor sessionImplementor)
throws HibernateException, SQLException {
if (null == value) {
} else {
final Stock auditData = (Stock) value;
System.out.println("::::::::::::::::::::::::::::::::"+auditData.getStockCode());
System.out.println("::::::::::::::::::::::::::::::::"+auditData.getStockDescription());
System.out.println("::::::::::::::::::::::::::::::::"+auditData.getStockId());
System.out.println("::::::::::::::::::::::::::::::::"+auditData.getStatus());
}
}
My Domain class Stock has five attributes. (stockId,stockCode,StockName,Status , Stock
Description)
I need to declare the field Stock description as Composite field Type.
private Integer stockId;
private String stockCode;
private String stockName;
private String status;
private String stockDescription;
//Constructors
#Column(name = "STOCK_CC", unique = true, nullable = false, length = 20)
#Type(type="com.mycheck.EncryptedAsStringType")
#Columns(columns = { #Column(name="STOCK_ID"),
#Column(name="STOCK_CODE"),
#Column(name="STOCK_NAME")
})
public String getStockDescription() {
return stockDescription;
}
}
When I try to execute a insert for Stock. I am getting the error Error creating bean with name
'sessionFactory' defined in class path resource [spring/config/../database/Hibernate.xml]:
Invocation of init method failed. nested exception is org.hibernate.MappingException:
property mapping has wrong number of columns: com.stock.model.Stock.stockDescription type:
com.mycheck.EncryptedAsStringType
Where am I going wrong ?

Answer 1

One can extract the answer from the code samples and the comments to the original question, but to save everyone some reading, I've compiled a quick summary.
If you declare a CompositeUserType that maps a type to n columns, you have to declare n columns in #Columns besides the #Type annotation. Example:
public class EncryptedAsStringType implements CompositeUserType {
#Override
public String[] getPropertyNames() {
return new String[] { "stockId", "stockCode", "stockName","stockDescription" };
}
// ...
}
This CompositeUserType maps to 4 separate columns, therefore 4 separate #Column annotations have to be declared:
#Type(type="com.mycheck.EncryptedAsStringType")
#Columns(columns = {
#Column(name="STOCK_ID"),
#Column(name="STOCK_CODE"),
#Column(name="STOCK_NAME"),
#Column(name="STOCK_DESCRIPTION")
})
public String getStockDescription() {
return stockDescription;
}
That's it and Hibernate is happy.