Normally when I do cat number.txt | sort -n | uniq -c , I get numbers like this:
3 43
4 66
2 96
1 97
But what I need is the number shows of occurrences at the back, like this:
43 3
66 4
96 2
97 1
Please give advice on how to change this. Thanks.
Use awk to change the order of columns:
cat number.txt | sort -n | uniq -c | awk '{ print $2, $1 }'
Perl version:
perl -lne '$occ{0+$_}++; END {print "$_ $occ{$_}" for sort {$a <=> $b} keys %occ}' < numbers.txt
Through GNU sed,
cat number.txt | sort -n | uniq -c | sed -r 's/^([0-9]+) ([0-9]+)$/\2 \1/g'
Related
We have to find the difference(d) Between last 2 nos and display rows with the highest value of d in ascending order
INPUT
1 | Latha | Third | Vikas | 90 | 91
2 | Neethu | Second | Meridian | 92 | 94
3 | Sethu | First | DAV | 86 | 98
4 | Theekshana | Second | DAV | 97 | 100
5 | Teju | First | Sangamithra | 89 | 100
6 | Theekshitha | Second | Sangamithra | 99 |100
Required OUTPUT
4$Theekshana$Second$DAV$97$100$3
5$Teju$First$Sangamithra$89$100$11
3$Sethu$First$DAV$86$98$12
awk 'BEGIN{FS="|";OFS="$";}{
avg=sqrt(($5-$6)^2)
print $1,$2,$3,$4,$5,$6,avg
}'|sort -nk7 -t "$"| tail -3
Output:
4 $ Theekshana $ Second $ DAV $ 97 $ 100$3
5 $ Teju $ First $ Sangamithra $ 89 $ 100$11
3 $ Sethu $ First $ DAV $ 86 $ 98$12
As you can see there is space before and after $ sign but for the last column (avg) there is no space, please explain why its happening
2)
awk 'BEGIN{FS=" | ";OFS="$";}{
avg=sqrt(($5-$6)^2)
print $1,$2,$3,$4,$5,$6,avg
}'|sort -nk7 -t "$"| tail -3
OUTPUT
4$|$Theekshana$|$Second$|$0
5$|$Teju$|$First$|$0
6$|$Theekshitha$|$Second$|$0
I have not mentiond | as the output field separator but still it appears, why is this happening and the difference is zero too
I am just 6 days old in unix,please answer even if its easy
your field separator is only the pipe symbol, so surrounding whitespace is part of the field definitions and that's what you see in the output. In combined uses pipe has the regex special meaning and need to be escaped. In your second case it means space or space is the field separator.
$ awk 'BEGIN {FS=" *\\| *"; OFS="$"}
{d=sqrt(($NF-$(NF-1))^2); $1=$1;
print d "\t" $0,d}' file | sort -n | tail -3 | cut -f2-
4$Theekshana$Second$DAV$97$100$3
5$Teju$First$Sangamithra$89$100$11
3$Sethu$First$DAV$86$98$12
a slight rewrite will eliminate the number of fields dependency and fixes the format.
file
ID First_Name Last_Name(s) Average_Winter_Grade
323 Popa Arianna 10
317 Tabarcea Andreea 5.24
326 Balan Ionut 9.935
327 Balan Tudor-Emanuel 8.4
329 Lungu Iulian-Gabriel 7.78
365 Brailean Mircea 7.615
365 Popescu Anca-Maria 7.38
398 Acatrinei Andrei 8
How do I sort it by last column, except for the header ?
This is what file should look like after the changes:
ID First_Name Last_Name(s) Average_Winter_Grade
323 Popa Arianna 10
326 Balan Ionut 9.935
327 Balan Tudor-Emanuel 8.4
398 Acatrinei Andrei 8
329 Lungu Iulian-Gabriel 7.78
365 Brailean Mircea 7.615
365 Popescu Anca-Maria 7.38
317 Tabarcea Andreea 5.24
If it's always 4th column:
head -n 1 file; tail -n +2 file | sort -n -r -k 4,4
If all you know is that it's the last column:
head -n 1 file; tail -n +2 file | awk '{print $NF,$0}' | sort -n -r | cut -f2- -d' '
You'd like to just sort by the last column, but sort doesn't allow you to do that easily. So rewrite the data with the column to be sorted at the beginning of each line:
Ignoring the header for the moment (although this will often work by itself):
awk '{print $NF, $0 | "sort -nr" }' input | cut -d ' ' -f 2-
If you do need to trim the order (eg, it's getting mixed in the sort), you can do things like:
< input awk 'NR==1; NR>1 {print $NF, $0 | "sh -c \"sort -nr | cut -d \\\ -f 2-\"" }'
or
awk 'NR==1{ print " ", $0} NR>1 {print $NF, $0 | "sort -nr" }' OFS=\; input | cut -d \; -f 2-
I'm trying, as an exercise, to output how many words exist in the dictionary for each possible length.
Here is my code:
$ awk '{print length}' dico.txt | sort -nr | uniq -c
Here is the output:
...
1799 5
427 4
81 3
1 2
My problem is that awk length count one more letter for each word in my file. The right output should have been:
1799 4
427 3
81 2
1 1
I checked my file and it does not contain any space after the word:
ABAISSA
ABAISSABLE
ABAISSABLES
ABAISSAI
...
So I guess awk is counting the newline as a character, despite the fact it is not supposed to.
Is there any solution? Or something I'm doing wrong?
I'm gonna venture a guess. Isn't your awk expecting "U*X" style newlines (LF), but your dico.txt has Windows style (CR+LF). That easily give you the +1 on all lengths.
I took your four words:
$ cat dico.txt
ABAISSA
ABAISSABLE
ABAISSABLES
ABAISSAI
And ran your line:
$ awk '{print length}' dico.txt | sort -nr | uniq -c
1 11
1 10
1 8
1 7
So far so good. Now the same, but dico.txt with windows newlines:
$ cat dico.txt | todos > dico_win.txt
$ awk '{print length}' dico_win.txt | sort -nr | uniq -c
1 12
1 11
1 9
1 8
In a bash shell script, I want to go through a list of numbers and then print out the number that occurs most often. If there are several different numbers appearing an equal amount of times, I want to print the highest number. For example, in a file like this:
10
10
10
15
15
20
20
20
20
I want to print the value 20.
How can I achieve this?
If the numbers are in a file, one per line:
sort < myfile | uniq -c | sort -r | head -1
without the count:
A=$(sort < myfile | uniq -c | sort -r | head -1)
set $A
echo $2
You can use this command -
echo 10 10 10 15 15 20 20 20 20 | sed 's/ /\n/g' | sort | uniq -c | sort -V | tail -n 1 | awk '{print $2}'
It will print the number you want.
Suppose I have a file similar to as follows:
Abigail 85
Kaylee 25
Kaylee 25
kaylee
Brooklyn
Kaylee 25
kaylee 25
I would like to find the most repeated line, the output must be just the line.
I've tried
sort list | uniq -c
but I need clean output, just the most repeated line (in this example Kaylee 25).
Kaizen ~
$ sort zlist | uniq -c | sort -r | head -1| xargs | cut -d" " -f2-
Kaylee 25
does this help ?
IMHO, none of these answers will sort the results correctly. The reason is that sort, without the -n, option will sort like this "1 10 11 2 3 4", etc., instead of "1 2 3 4 10 11 12". So, add -n like so:
sort zlist | uniq -c | sort -n -r | head -1
You can then, of course, pipe that to either xargs or sed as described earlier.
awk -
awk '{a[$0]++; if(m<a[$0]){ m=a[$0];s[m]=$0}} END{print s[m]}' t.lis
$ uniq -c list | sort -r | head -1 | awk '{$1=""}1'
Kaylee 25
Is this what you're looking for?