I want to generate a random string with the pattern:
number-number-letter-SPACE-letter-number-number
for example "81b t15", "12a x13". How can I generate something like this? I tried generating each char and joining them into one string, but it does not look efficient.
Nums = (0..9).to_a
Ltrs = ("A".."Z").to_a + ("a".."z").to_a
def rand_num; Nums.sample end
def rand_ltr; Ltrs.sample end
"#{rand_num}#{rand_num}#{rand_ltr} #{rand_ltr}#{rand_num}#{rand_num}"
# => "71P v33"
Have you looked at randexp gem
It works like this:
> /\d\d\w \w\d\d/.gen
=> "64M c82"
Ok here's another entry for the competition :D
module RandomString
LETTERS = (("A".."Z").to_a + ("a".."z").to_a)
LETTERS_SIZE = LETTERS.size
SPACE = " "
FORMAT = [:number, :letter, :number, :space, :letter, :number, :number]
class << self
def generate
chars.join
end
def generate2
"#{number}#{letter}#{number} #{letter}#{number}#{number}"
end
private
def chars
FORMAT.collect{|char_class| send char_class}
end
def letter
LETTERS[rand(LETTERS_SIZE)]
end
def number
rand 10
end
def space
SPACE
end
end
end
And you use it like:
50.times { puts RandomString.generate }
Out of curiosity, I made a benchmark of all the solutions presented here. Here are the results:
JRuby:
user system total real
kimmmo 1.490000 0.000000 1.490000 ( 0.990000)
kimmmo2 0.600000 0.010000 0.610000 ( 0.479000)
sawa 0.960000 0.040000 1.000000 ( 0.533000)
hp4k 2.050000 0.230000 2.280000 ( 1.234000)
brian 17.700000 0.170000 17.870000 ( 14.867000)
MRI 2.0
user system total real
kimmmo 0.900000 0.000000 0.900000 ( 0.908601)
kimmmo2 0.410000 0.000000 0.410000 ( 0.406443)
sawa 0.570000 0.000000 0.570000 ( 0.568935)
hp4k 4.940000 0.000000 4.940000 ( 4.945404)
brian 25.860000 0.010000 25.870000 ( 25.870011)
You can do it this way
(0..9).to_a.sample(2).join + ('a'..'z').to_a.sample + " " + ('a'..'z').to_a.sample + (0..9).to_a.sample(2).join
How would I count the total number of characters in an array of strings in Ruby? Assume I have the following:
array = ['peter' , 'romeo' , 'bananas', 'pijamas']
I'm trying:
array.each do |counting|
puts counting.count "array[]"
end
but, I'm not getting the desired result. It appears I am counting something other than the characters.
I searched for the count property but I haven't had any luck or found a good source of info. Basically, I'd like to get an output of the total of characters inside the array.,
Wing's Answer will work, but just for fun here are a few alternatives
['peter' , 'romeo' , 'bananas', 'pijamas'].inject(0) {|c, w| c += w.length }
or
['peter' , 'romeo' , 'bananas', 'pijamas'].join.length
The real issue is that string.count is not the method you're looking for. (Docs)
Or...
a.map(&:size).reduce(:+) # from Andrew: reduce(0, :+)
Another alternative:
['peter' , 'romeo' , 'bananas', 'pijamas'].join('').size
An interesting result :)
>> array = []
>> 1_000_000.times { array << 'foo' }
>> Benchmark.bmbm do |x|
>> x.report('mapreduce') { array.map(&:size).reduce(:+) }
>> x.report('mapsum') { array.map(&:size).sum }
>> x.report('inject') { array.inject(0) { |c, w| c += w.length } }
>> x.report('joinsize') { array.join('').size }
>> x.report('joinsize2') { array.join.size }
>> end
Rehearsal ---------------------------------------------
mapreduce 0.220000 0.000000 0.220000 ( 0.222946)
mapsum 0.210000 0.000000 0.210000 ( 0.210070)
inject 0.150000 0.000000 0.150000 ( 0.158709)
joinsize 0.120000 0.000000 0.120000 ( 0.116889)
joinsize2 0.070000 0.000000 0.070000 ( 0.071718)
------------------------------------ total: 0.770000sec
user system total real
mapreduce 0.220000 0.000000 0.220000 ( 0.228385)
mapsum 0.210000 0.000000 0.210000 ( 0.207359)
inject 0.160000 0.000000 0.160000 ( 0.156711)
joinsize 0.120000 0.000000 0.120000 ( 0.116652)
joinsize2 0.080000 0.000000 0.080000 ( 0.069612)
so it looks like array.join.size has the lowest runtime
a = ['peter' , 'romeo' , 'bananas', 'pijamas']
count = 0
a.each {|s| count += s.length}
puts count
Example:
[12,23,987,43
What is the fastest, most efficient way to remove the "[",
using maybe a chop() but for the first character?
Similar to Pablo's answer above, but a shade cleaner :
str[1..-1]
Will return the array from 1 to the last character.
'Hello World'[1..-1]
=> "ello World"
I kind of favor using something like:
asdf = "[12,23,987,43"
asdf[0] = ''
p asdf
# >> "12,23,987,43"
I'm always looking for the fastest and most readable way of doing things:
require 'benchmark'
N = 1_000_000
puts RUBY_VERSION
STR = "[12,23,987,43"
Benchmark.bm(7) do |b|
b.report('[0]') { N.times { "[12,23,987,43"[0] = '' } }
b.report('sub') { N.times { "[12,23,987,43".sub(/^\[+/, "") } }
b.report('gsub') { N.times { "[12,23,987,43".gsub(/^\[/, "") } }
b.report('[1..-1]') { N.times { "[12,23,987,43"[1..-1] } }
b.report('slice') { N.times { "[12,23,987,43".slice!(0) } }
b.report('length') { N.times { "[12,23,987,43"[1..STR.length] } }
end
Running on my Mac Pro:
1.9.3
user system total real
[0] 0.840000 0.000000 0.840000 ( 0.847496)
sub 1.960000 0.010000 1.970000 ( 1.962767)
gsub 4.350000 0.020000 4.370000 ( 4.372801)
[1..-1] 0.710000 0.000000 0.710000 ( 0.713366)
slice 1.020000 0.000000 1.020000 ( 1.020336)
length 1.160000 0.000000 1.160000 ( 1.157882)
Updating to incorporate one more suggested answer:
require 'benchmark'
N = 1_000_000
class String
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
def first(how_many = 1)
self[0...how_many]
end
def shift(how_many = 1)
shifted = first(how_many)
self.replace self[how_many..-1]
shifted
end
alias_method :shift!, :shift
end
class Array
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
end
puts RUBY_VERSION
STR = "[12,23,987,43"
Benchmark.bm(7) do |b|
b.report('[0]') { N.times { "[12,23,987,43"[0] = '' } }
b.report('sub') { N.times { "[12,23,987,43".sub(/^\[+/, "") } }
b.report('gsub') { N.times { "[12,23,987,43".gsub(/^\[/, "") } }
b.report('[1..-1]') { N.times { "[12,23,987,43"[1..-1] } }
b.report('slice') { N.times { "[12,23,987,43".slice!(0) } }
b.report('length') { N.times { "[12,23,987,43"[1..STR.length] } }
b.report('eat!') { N.times { "[12,23,987,43".eat! } }
b.report('reverse') { N.times { "[12,23,987,43".reverse.chop.reverse } }
end
Which results in:
2.1.2
user system total real
[0] 0.300000 0.000000 0.300000 ( 0.295054)
sub 0.630000 0.000000 0.630000 ( 0.631870)
gsub 2.090000 0.000000 2.090000 ( 2.094368)
[1..-1] 0.230000 0.010000 0.240000 ( 0.232846)
slice 0.320000 0.000000 0.320000 ( 0.320714)
length 0.340000 0.000000 0.340000 ( 0.341918)
eat! 0.460000 0.000000 0.460000 ( 0.452724)
reverse 0.400000 0.000000 0.400000 ( 0.399465)
And another using /^./ to find the first character:
require 'benchmark'
N = 1_000_000
class String
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
def first(how_many = 1)
self[0...how_many]
end
def shift(how_many = 1)
shifted = first(how_many)
self.replace self[how_many..-1]
shifted
end
alias_method :shift!, :shift
end
class Array
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
end
puts RUBY_VERSION
STR = "[12,23,987,43"
Benchmark.bm(7) do |b|
b.report('[0]') { N.times { "[12,23,987,43"[0] = '' } }
b.report('[/^./]') { N.times { "[12,23,987,43"[/^./] = '' } }
b.report('[/^\[/]') { N.times { "[12,23,987,43"[/^\[/] = '' } }
b.report('sub+') { N.times { "[12,23,987,43".sub(/^\[+/, "") } }
b.report('sub') { N.times { "[12,23,987,43".sub(/^\[/, "") } }
b.report('gsub') { N.times { "[12,23,987,43".gsub(/^\[/, "") } }
b.report('[1..-1]') { N.times { "[12,23,987,43"[1..-1] } }
b.report('slice') { N.times { "[12,23,987,43".slice!(0) } }
b.report('length') { N.times { "[12,23,987,43"[1..STR.length] } }
b.report('eat!') { N.times { "[12,23,987,43".eat! } }
b.report('reverse') { N.times { "[12,23,987,43".reverse.chop.reverse } }
end
Which results in:
# >> 2.1.5
# >> user system total real
# >> [0] 0.270000 0.000000 0.270000 ( 0.270165)
# >> [/^./] 0.430000 0.000000 0.430000 ( 0.432417)
# >> [/^\[/] 0.460000 0.000000 0.460000 ( 0.458221)
# >> sub+ 0.590000 0.000000 0.590000 ( 0.590284)
# >> sub 0.590000 0.000000 0.590000 ( 0.596366)
# >> gsub 1.880000 0.010000 1.890000 ( 1.885892)
# >> [1..-1] 0.230000 0.000000 0.230000 ( 0.223045)
# >> slice 0.300000 0.000000 0.300000 ( 0.299175)
# >> length 0.320000 0.000000 0.320000 ( 0.325841)
# >> eat! 0.410000 0.000000 0.410000 ( 0.409306)
# >> reverse 0.390000 0.000000 0.390000 ( 0.393044)
Here's another update on faster hardware and a newer version of Ruby:
2.3.1
user system total real
[0] 0.200000 0.000000 0.200000 ( 0.204307)
[/^./] 0.390000 0.000000 0.390000 ( 0.387527)
[/^\[/] 0.360000 0.000000 0.360000 ( 0.360400)
sub+ 0.490000 0.000000 0.490000 ( 0.492083)
sub 0.480000 0.000000 0.480000 ( 0.487862)
gsub 1.990000 0.000000 1.990000 ( 1.988716)
[1..-1] 0.180000 0.000000 0.180000 ( 0.181673)
slice 0.260000 0.000000 0.260000 ( 0.266371)
length 0.270000 0.000000 0.270000 ( 0.267651)
eat! 0.400000 0.010000 0.410000 ( 0.398093)
reverse 0.340000 0.000000 0.340000 ( 0.344077)
Why is gsub so slow?
After doing a search/replace, gsub has to check for possible additional matches before it can tell if it's finished. sub only does one and finishes. Consider gsub like it's a minimum of two sub calls.
Also, it's important to remember that gsub, and sub can also be handicapped by poorly written regex which match much more slowly than a sub-string search. If possible anchor the regex to get the most speed from it. There are answers here on Stack Overflow demonstrating that so search around if you want more information.
We can use slice to do this:
val = "abc"
=> "abc"
val.slice!(0)
=> "a"
val
=> "bc"
Using slice! we can delete any character by specifying its index.
Ruby 2.5+
As of Ruby 2.5 you can use delete_prefix or delete_prefix! to achieve this in a readable manner.
In this case "[12,23,987,43".delete_prefix("[").
More info here:
Official docs
https://blog.jetbrains.com/ruby/2017/10/10-new-features-in-ruby-2-5/
https://bugs.ruby-lang.org/issues/12694
'invisible'.delete_prefix('in') #=> "visible"
'pink'.delete_prefix('in') #=> "pink"
N.B. you can also use this to remove items from the end of a string with delete_suffix and delete_suffix!
'worked'.delete_suffix('ed') #=> "work"
'medical'.delete_suffix('ed') #=> "medical"
Docs
https://bugs.ruby-lang.org/issues/13665
Edit:
Using the Tin Man's benchmark setup, it looks pretty quick too (under the last two entries delete_p and delete_p!). Doesn't quite pip the previous faves for speed, though is very readable.
2.5.0
user system total real
[0] 0.174766 0.000489 0.175255 ( 0.180207)
[/^./] 0.318038 0.000510 0.318548 ( 0.323679)
[/^\[/] 0.372645 0.001134 0.373779 ( 0.379029)
sub+ 0.460295 0.001510 0.461805 ( 0.467279)
sub 0.498351 0.001534 0.499885 ( 0.505729)
gsub 1.669837 0.005141 1.674978 ( 1.682853)
[1..-1] 0.199840 0.000976 0.200816 ( 0.205889)
slice 0.279661 0.000859 0.280520 ( 0.285661)
length 0.268362 0.000310 0.268672 ( 0.273829)
eat! 0.341715 0.000524 0.342239 ( 0.347097)
reverse 0.335301 0.000588 0.335889 ( 0.340965)
delete_p 0.222297 0.000832 0.223129 ( 0.228455)
delete_p! 0.225798 0.000747 0.226545 ( 0.231745)
I prefer this:
str = "[12,23,987,43"
puts str[1..-1]
>> 12,23,987,43
If you always want to strip leading brackets:
"[12,23,987,43".gsub(/^\[/, "")
If you just want to remove the first character, and you know it won't be in a multibyte character set:
"[12,23,987,43"[1..-1]
or
"[12,23,987,43".slice(1..-1)
Inefficient alternative:
str.reverse.chop.reverse
For example : a = "One Two Three"
1.9.2-p290 > a = "One Two Three"
=> "One Two Three"
1.9.2-p290 > a = a[1..-1]
=> "ne Two Three"
1.9.2-p290 > a = a[1..-1]
=> "e Two Three"
1.9.2-p290 > a = a[1..-1]
=> " Two Three"
1.9.2-p290 > a = a[1..-1]
=> "Two Three"
1.9.2-p290 > a = a[1..-1]
=> "wo Three"
In this way you can remove one by one first character of the string.
Easy way:
str = "[12,23,987,43"
removed = str[1..str.length]
Awesome way:
class String
def reverse_chop()
self[1..self.length]
end
end
"[12,23,987,43".reverse_chop()
(Note: prefer the easy way :) )
Thanks to #the-tin-man for putting together the benchmarks!
Alas, I don't really like any of those solutions. Either they require an extra step to get the result ([0] = '', .strip!) or they aren't very semantic/clear about what's happening ([1..-1]: "Um, a range from 1 to negative 1? Yearg?"), or they are slow or lengthy to write out (.gsub, .length).
What we are attempting is a 'shift' (in Array parlance), but returning the remaining characters, rather than what was shifted off. Let's use our Ruby to make this possible with strings! We can use the speedy bracket operation, but give it a good name, and take an arg to specify how much we want to chomp off the front:
class String
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
end
But there is more we can do with that speedy-but-unwieldy bracket operation. While we are at it, for completeness, let's write a #shift and #first for String (why should Array have all the fun‽‽), taking an arg to specify how many characters we want to remove from the beginning:
class String
def first(how_many = 1)
self[0...how_many]
end
def shift(how_many = 1)
shifted = first(how_many)
self.replace self[how_many..-1]
shifted
end
alias_method :shift!, :shift
end
Ok, now we have a good clear way of pulling characters off the front of a string, with a method that is consistent with Array#first and Array#shift (which really should be a bang method??). And we can easily get the modified string as well with #eat!. Hm, should we share our new eat!ing power with Array? Why not!
class Array
def eat!(how_many = 1)
self.replace self[how_many..-1]
end
end
Now we can:
> str = "[12,23,987,43" #=> "[12,23,987,43"
> str.eat! #=> "12,23,987,43"
> str #=> "12,23,987,43"
> str.eat!(3) #=> "23,987,43"
> str #=> "23,987,43"
> str.first(2) #=> "23"
> str #=> "23,987,43"
> str.shift!(3) #=> "23,"
> str #=> "987,43"
> arr = [1,2,3,4,5] #=> [1, 2, 3, 4, 5]
> arr.eat! #=> [2, 3, 4, 5]
> arr #=> [2, 3, 4, 5]
That's better!
str = "[12,23,987,43"
str[0] = ""
class String
def bye_felicia()
felicia = self.strip[0] #first char, not first space.
self.sub(felicia, '')
end
end
Using regex:
str = 'string'
n = 1 #to remove first n characters
str[/.{#{str.size-n}}\z/] #=> "tring"
I find a nice solution to be str.delete(str[0]) for its readability, though I cannot attest to it's performance.
list = [1,2,3,4]
list.drop(1)
# => [2,3,4]
List drops one or more elements from the start of the array, does not mutate the array, and returns the array itself instead of the dropped element.