I'm trying to calculate confidence interval from several files: ones contains lines with means, and others contains lines with values (one per line). I'm trying to read one line from the file that contains the means, and all the lines from another file (because I have to do some computations). Here is what I've done (of course it's not working):
parameters="some value to move from a file to another one"
while read avg; do
for row in mypath/*_${parameters}*.dat; do
for value in $( awk '{ print $2; }' ${row}); do
read all the lines in first_file.dat (I need only the second column)
read the first line in avg.dat
combine data and calculate the confidence interval
done
done
done < avg.dat
** file avg.dat (not necessarily 100 lines) **
.99
2.34
5.41
...
...
2.88
** firstfile.dat in mypath (100 lines) **
0 13.77
1 2
2 63.123
3 21.109
...
...
99 1.05
** secondfile.dat in mypath (100 lines) **
0 8.56
1 91.663
2 19
3 0
...
...
99 4.34
The first line of avg.dat refers to the firstfile.dat in mypath, the second line of avg.dat refers to the secondfile.dat in mypath, etc... So, in the example above, I have to do some computation using .99 (from avg.dat) with all the numbers in the second column of firstfile.dat. Same with 2.34 and secondfile.dat.
I can't reach my objective because I can't find a way to switch to the next line in the avg.dat when I've finished to read a file in mypath. Instead I read the first line in avg.dat and all the files in mypath, then the second line in avg.dat and, again, all the files in mypath, etc... Can you help me to find a solution? Thank you all!
In bash I would do this:
exec 3<avg.dat
shopt -s extglob
for file in !(avg).dat; do
read -u 3 avg
while read value; do
# do stuff with $value and $avg
done < <(cut -f 2 -d " " "$file")
done
exec 3<&- # close the file descriptor
Related
My AWK script processes each log file from the folder "${results}, from which it looks for a pattern (a number occurred on the first line of ranking table) and then print it in one line together with the filename of the log:
awk '$1=="1"{sub(/.*\//,"",FILENAME); sub(/\.log/,"",FILENAME); printf("%s: %s\n", FILENAME, $2)}' "${results}"/*_rep"${i}".log
Here is the format of each log file, from which the number
-9.14
should be taken
AutoDock Vina v1.2.3
#################################################################
# If you used AutoDock Vina in your work, please cite: #
# #
# J. Eberhardt, D. Santos-Martins, A. F. Tillack, and S. Forli #
# AutoDock Vina 1.2.0: New Docking Methods, Expanded Force #
# Field, and Python Bindings, J. Chem. Inf. Model. (2021) #
# DOI 10.1021/acs.jcim.1c00203 #
# #
# O. Trott, A. J. Olson, #
# AutoDock Vina: improving the speed and accuracy of docking #
# with a new scoring function, efficient optimization and #
# multithreading, J. Comp. Chem. (2010) #
# DOI 10.1002/jcc.21334 #
# #
# Please see https://github.com/ccsb-scripps/AutoDock-Vina for #
# more information. #
#################################################################
Scoring function : vina
Rigid receptor: /home/gleb/Desktop/dolce_vita/temp/nsp5holoHIE.pdbqt
Ligand: /home/gleb/Desktop/dolce_vita/temp/active2322.pdbqt
Grid center: X 11.106 Y 0.659 Z 18.363
Grid size : X 18 Y 18 Z 18
Grid space : 0.375
Exhaustiveness: 48
CPU: 48
Verbosity: 1
Computing Vina grid ... done.
Performing docking (random seed: -1717804037) ...
0% 10 20 30 40 50 60 70 80 90 100%
|----|----|----|----|----|----|----|----|----|----|
***************************************************
mode | affinity | dist from best mode
| (kcal/mol) | rmsd l.b.| rmsd u.b.
-----+------------+----------+----------
1 -9.14 0 0
2 -9.109 2.002 2.79
3 -9.006 1.772 2.315
4 -8.925 2 2.744
5 -8.882 3.592 8.189
6 -8.803 1.564 2.092
7 -8.507 4.014 7.308
8 -8.36 2.489 8.193
9 -8.356 2.529 8.104
10 -8.33 1.408 3.841
It works OK for a moderate number of input log files (tested for up to 50k logs), but does not work for the case of big number of the input logs (e.g. with 130k logs), producing the following error:
./dolche_finito.sh: line 124: /usr/bin/awk: Argument list too long
How could I adapt the AWK script to be able processing any number of input logs?
If you get a /usr/bin/awk: Argument list too long then you'll have to control the number of "files" that you supply to awk; the standard way to do that efficiently is:
results=. # ???
i=00001 # ???
output= # ???
find "$results" -type f -name "*_rep$i.log" -exec awk '
FNR == 1 {
filename = FILENAME
sub(/.*\//,"",filename)
sub(/\.[^.]*$/,"",filename)
}
$1 == 1 { printf "%s: %s\n", filename, $2 }
' {} + |
LC_ALL=C sort -t':' -k2,2g > "$results"/ranking_"$output"_rep"$i".csv
edit: appended the rest of the chain as asked in comment
note: you might need to specify other predicates to the find command if you don't want it to search the sub-folders of $results recursively
Note that your error message:
./dolche_finito.sh: line 124: /usr/bin/awk: Argument list too long
is from your shell interpreting line 124 in your shell script, not from awk - you just happen to be calling awk at that line but it could be any other tool and you'd get the same error. Google ARG_MAX for more information on it.
Assuming printf is a builtin on your system:
printf '%s\0' "${results}"/*_rep"${i}".log |
xargs -0 awk '...'
or if you need awk to process all input files in one call for some reason and your file names don't contain newlines:
printf '%s' "${results}"/*_rep"${i}".log |
awk '
NR==FNR {
ARGV[ARGC++] = $0
next
}
...
'
If you're using GNU awk or some other awk that can process NUL characters as the RS and your input file names might contain newlines then you could do:
printf '%s\0' "${results}"/*_rep"${i}".log |
awk '
NR==FNR {
ARGV[ARGC++] = $0
next
}
...
' RS='\0' - RS='\n'
When using GNU AWK you might alter ARGC and ARGV to command GNU AWK to read additional files, consider following simple example, let filelist.txt content be
file1.txt
file2.txt
file3.txt
and content of these files to be respectively uno, dos, tres then
awk 'FNR==NR{ARGV[NR+1]=$0;ARGC+=1;next}{print FILENAME,$0}' filelist.txt
gives output
file1.txt uno
file2.txt dos
file3.txt tres
Explanation: when reading first file i.e. where number of row in file (FNR) is equal number of row globally (NR) I add to ARGV line as value under key being number of row plus one, as ARGV[1] is already filelist.txt and I increase ARGC by 1, I instruct GNU AWK to then go to next line so no other action is undertaken. For other files I print filename followed by whole line.
(tested in GNU Awk 5.0.1)
I have two files. In one file I have a random date per line and in the other file I have a number per line, this means:
File1:
2018/06/24 14:17:19
2018/06/15 17:24:50
2018/07/15 10:25:29
File2:
5938
1234
4567
So, I want to reading the two files and add the number (in seconds) to the dates, one time per line.
My code:
#!/bin/sh
IFS=$'\n'
for i in `cat fechas_prueba.txt`
do
for j in `cat duraciones.txt`
do
echo "$i - $j"
newDate=$(date -d "$i $j seconds" "+%Y/%m/%d %H:%M:%S")
echo $newDate >> sum_dates.txt
done
done
I want that the first line of file1 sum with the first line of file2, the second line with the second line... This means:
2018/06/24 15:56:17
2018/06/15 17:45:24
2018/07/15 11:41:36
However, I get the following:
2018/06/24 15:56:17
2018/06/24 14:37:53
2018/06/24 15:33:26
2018/06/15 19:03:48
2018/06/15 17:45:24
2018/06/15 18:40:57
2018/07/15 12:04:27
2018/07/15 10:46:03
2018/07/15 11:41:36
So, How I can to only sum line1 with line1, line2 with line2, etc.
Thanks!
Could use something like that, providing your date are in date.txt, the second to add to those dates are in second.txt and that you want the final result to be in finaldate.txt.
#!/bin/ksh
# Opening finaldate.txt for writing on file descriptor 3
exec 3>./finaldate.txt
# Read simultaneously the OriginalDate from file descriptor 4 and
# SecondToAdd from file descriptor 5
while read -u 4 OriginalDate && read -u 5 SecondToAdd; do
FinalDateInSecond=$(($(date -d "$OriginalDate" +"%s")+$SecondToAdd))
FinalDate=$(date -d #"$FinalDateInSecond" +"%Y/%m/%d %H:%M:%S")
# Printing the result on file descriptor 3
print -u 3 $FinalDate
# Having date.txt being read on file descriptor 4 while second.txt being
# read on file descriptor 5
done 4<date.txt 5<second.txt
Hope it can help
I am stuck on that. So I have this while-read loop within my code that is taking so long and I would like to run it in many processors. But, I'd like to split the input file and run 14 loops (because I have 14 threads), one for each splited file, in parallel. Thing is that I don't know how to tell the while loop which file to get and work with.
For example, in a regular while-read loop I would code:
while read line
do
<some code>
done < input file or variable...
But in this case I would like to split the above input file in 14 files and run 14 while loops in parallel, one for each splited file.
I tried :
split -n 14 input_file
find . -name "xa*" | \
parallel -j 14 | \
while read line
do
<lot of stuff>
done
also tried
split -n 14 input_file
function loop {
while read line
do
<lot of stuff>
done
}
export -f loop
parallel -j 14 ::: loop
But neither I was able to tell which file would be the input to the loop so parallel would understand "take each of those xa* files and place into individual loops in parallel"
An example of the input file (a list of strings)
AEYS01000010.10484.12283
CVJT01000011.50.2173
KF625180.1.1799
KT949922.1.1791
LOBZ01000025.54942.57580
EDIT
This is the code.
The output is a table (741100 lines) with some statistics regarding DNA sequences alignments already made.
The loop takes an input_file (no broken lines, varies from 500 to ~45000 lines, 800Kb) with DNA sequence acessions, reads it line-by-line and look for each correspondent full taxonomy for those acessions in a databank (~45000 lines). Then, it does a few sums/divisions. Output is a .tsv and looks like this (an example for sequence "KF625180.1.1799"):
Rate of taxonomies for this sequence in %: KF625180.1.1799 D_6__Bacillus_atrophaeus
Taxonomy %aligned number_ocurrences_in_the_alignment num_ocurrences_in_databank %alingment/databank
D_6__Bacillus_atrophaeus 50% 1 20 5%
D_6__Bacillus_amyloliquefaciens 50% 1 154 0.649351%
$ head input file
AEYS01000010.10484.12283
CVJT01000011.50.217
KF625180.1.1799
KT949922.1.1791
LOBZ01000025.54942.57580
Two additional files are also used inside the loop. They are not the loop input.
1) a file called alnout_file that only serves for finding how many hits (or alignments) a given sequence had against the databank. It was also previously made outside this loop. It can vary in the number of lines from hundreads to thousands. Only columns 1 and 2 matters here. Column1 is the name of the sequence and col2 is the name of all sequences it matched in the databnk. It looks like that:
$ head alnout_file
KF625180.1.1799 KF625180.1.1799 100.0 431 0 0 1 431 1 431 -1 0
KF625180.1.1799 KP143082.1.1457 99.3 431 1 2 1 431 1 429 -1 0
KP143082.1.1457 KF625180.1.1799 99.3 431 1 2 1 429 1 431 -1 0
2) a databank .tsv file containing ~45000 taxonomies correspondent to the DNA sequences. Each taxonomy is in one line:
$ head taxonomy.file.tsv
KP143082.1.1457 D_0__Bacteria;D_1__Firmicutes;D_2__Bacilli;D_3__Bacillales;D_4__Bacillaceae;D_5__Bacillus;D_6__Bacillus_amyloliquefaciens
KF625180.1.1799 D_0__Bacteria;D_1__Firmicutes;D_2__Bacilli;D_3__Bacillales;D_4__Bacillaceae;D_5__Bacillus;D_6__Bacillus_atrophaeus
So, given sequence KF625180.1.1799. I previously aligned it against a databank containing ~45000 other DNA sequences and got an output whis has all the accessions to sequences that it matched. What the loop does is that it finds the taxonomies for all those sequences and calculates the "statistics" I mentionded previously. Code does it for all the DNA-sequences-accesions I have.
TAXONOMY=path/taxonomy.file.tsv
while read line
do
#find hits
hits=$(grep $line alnout_file | cut -f 2)
completename=$(grep $line $TAXONOMY | sed 's/D_0.*D_4/D_4/g')
printf "\nRate of taxonomies for this sequence in %%:\t$completename\n"
printf "Taxonomy\t%aligned\tnumber_ocurrences_in_the_alignment\tnum_ocurrences_in_databank\t%alingment/databank\n"
#find hits and calculate the frequence (%) of the taxonomy in the alignment output
# ex.: Bacillus_subtilis 33
freqHits=$(grep "${hits[#]}" $TAXONOMY | \
cut -f 2 | \
awk '{a[$0]++} END {for (i in a) {print i, "\t", a[i]/NR*100, "\t", a[i]}}' | \
sed -e 's/D_0.*D_5/D_5/g' -e 's#\s\t\s#\t#g' | \
sort -k2 -hr)
# print frequence of each taxonomy in the databank
freqBank=$(while read line; do grep -c "$line" $TAXONOMY; done < <(echo "$freqHits" | cut -f 1))
#print cols with taxonomy and calculations
paste <(printf %s "$freqHits") <(printf %s "$freqBank") | awk '{print $1,"\t",$2"%","\t",$3,"\t",$4,"\t",$3/$4*100"%"}'
done < input_file
It is a lot of greps and parsing so it takes about ~12h running in one processor for doing it to all the 45000 DNA sequence accessions. The, I would like to split input_file and do it in all the processors I have (14) because it would the time spend in that.
Thank you all for being so patient with me =)
You are looking for --pipe. In this case you can even use the optimized --pipepart (version >20160621):
export TAXONOMY=path/taxonomy.file.tsv
doit() {
while read line
do
#find hits
hits=$(grep $line alnout_file | cut -f 2)
completename=$(grep $line $TAXONOMY | sed 's/D_0.*D_4/D_4/g')
printf "\nRate of taxonomies for this sequence in %%:\t$completename\n"
printf "Taxonomy\t%aligned\tnumber_ocurrences_in_the_alignment\tnum_ocurrences_in_databank\t%alingment/databank\n"
#find hits and calculate the frequence (%) of the taxonomy in the alignment output
# ex.: Bacillus_subtilis 33
freqHits=$(grep "${hits[#]}" $TAXONOMY | \
cut -f 2 | \
awk '{a[$0]++} END {for (i in a) {print i, "\t", a[i]/NR*100, "\t", a[i]}}' | \
sed -e 's/D_0.*D_5/D_5/g' -e 's#\s\t\s#\t#g' | \
sort -k2 -hr)
# print frequence of each taxonomy in the databank
freqBank=$(while read line; do grep -c "$line" $TAXONOMY; done < <(echo "$freqHits" | cut -f 1))
#print cols with taxonomy and calculations
paste <(printf %s "$freqHits") <(printf %s "$freqBank") | awk '{print $1,"\t",$2"%","\t",$3,"\t",$4,"\t",$3/$4*100"%"}'
done
}
export -f doit
parallel -a input_file --pipepart doit
This will chop input_file into 10*ncpu blocks (where ncpu is the number of CPU threads), pass each block to doit, run ncpu jobs in parallel.
That said I think your real problem is spawning too many programs: If you rewrite doit in Perl or Python I will expect you will see a major speedup.
As an alternative I threw together a quick test.
#! /bin/env bash
mkfifo PIPELINE # create a single queue
cat "$1" > PIPELINE & # supply it with records
{ declare -i cnt=0 max=14
while (( ++cnt <= max )) # spawn loop creates worker jobs
do printf -v fn "%02d" $cnt
while read -r line # each work loop reads common stdin...
do echo "$fn:[$line]"
sleep 1
done >$fn.log 2>&1 & # these run in background in parallel
done # this one exits
} < PIPELINE # *all* read from the same queue
wait
cat [0-9][0-9].log
Doesn't need split, but does need a mkfifo.
Obviously, change the code inside the internal loop.
This answers what you asked, namely how to process in parallel the 14 files you get from running split. However, I don't think it is the best way of doing whatever it is that you are trying to do - but we would need some answers from you for that.
So, let's make a million line file and split it into 14 parts:
seq 1000000 > 1M
split -n 14 1M part-
That gives me 14 files called part-aa through part-an. Now your question is how to process those 14 parts in parallel - (read the last line first):
#!/bin/bash
# This function will be called for each of the 14 files
DoOne(){
# Pick up parameters
job=$1
file=$2
# Count lines in specified file
lines=$(wc -l < "$file")
echo "Job No: $job, file: $file, lines: $lines"
}
# Make the function above known to processes spawned by GNU Parallel
export -f DoOne
# Run 14 parallel instances of "DoOne" passing job number and filename to each
parallel -k -j 14 DoOne {#} {} ::: part-??
Sample Output
Job No: 1, file: part-aa, lines: 83861
Job No: 2, file: part-ab, lines: 72600
Job No: 3, file: part-ac, lines: 70295
Job No: 4, file: part-ad, lines: 70295
Job No: 5, file: part-ae, lines: 70294
Job No: 6, file: part-af, lines: 70295
Job No: 7, file: part-ag, lines: 70295
Job No: 8, file: part-ah, lines: 70294
Job No: 9, file: part-ai, lines: 70295
Job No: 10, file: part-aj, lines: 70295
Job No: 11, file: part-ak, lines: 70295
Job No: 12, file: part-al, lines: 70294
Job No: 13, file: part-am, lines: 70295
Job No: 14, file: part-an, lines: 70297
You would omit the -k argument to GNU Parallel normally - I only added it so the output comes in order.
I think that using a bunch of grep and awk commands is the wrong approach here - you would be miles better off using Perl, or awk. As you have not provided any sample files I generated some using this code:
#!/bin/bash
for a in {A..Z} {0..9} ; do
for b in {A..Z} {0..9} ; do
for c in {A..Z} {0..9} ; do
echo "${a}${b}${c}"
done
done
done > a
# Now make file "b" which has the same stuff but shuffled into a different order
gshuf < a > b
Note that there are 26 letters in the alphabet, so if I add the digits 0..9 to the letters of the alphabet, I get 36 alphanumeric digits and if I nest 3 loops of that I get 36^3 or 46,656 lines which matches your file sizes roughly. File a now looks like this:
AAA
AAB
AAC
AAD
AAE
AAF
File b looks like this:
UKM
L50
AOC
79U
K6S
6PO
12I
XEV
WJN
Now I want to loop through a finding the corresponding line in b. First, I use your approach:
time while read thing ; do grep $thing b > /dev/null ; done < a
That takes 9 mins 35 seconds.
If I now exit grep on the first match, on average I will find it in the middle, which means the time will be halved since I won't continue to needlessly read b after I find what I want.
time while read thing ; do grep -m1 $thing b > /dev/null ; done < a
That improves the time down to 4 mins 30 seconds.
If I now use awk to read the contents of b into an associative array (a.k.a. hash) and then read the elements of a and find them in b like this:
time awk 'FNR==NR{a[$1]=$1; next} {print a[$1]}' b a > /dev/null
That now runs in 0.07 seconds. Hopefully you get the idea of what I am driving at. I expect Perl would do this in the same time and also provide more expressive facilities for the maths in the middle of your loop too.
I hope this small script helps you out:
function process {
while read line; do
echo "$line"
done < $1
}
function loop {
file=$1
chunks=$2
dir=`mktemp -d`
cd $dir
split -n l/$chunks $file
for i in *; do
process "$i" &
done
rm -rf $dir
}
loop /tmp/foo 14
It runs the process loop on the specified file with the specified number of chunks (without splitting lines) in parallel (using & to put each invocation in the background). I hope it gets you started.
This can do the job for You, I am not familiar with parallel instead using native bash spawning processes &:
function loop () {
while IFS= read -r -d $'\n'
do
# YOUR BIG STUFF
done < "${1}"
}
arr_files=(./xa*)
for i in "${arr_files[#]}"
do loop "${i}" &
done
wait
I'm trying to write a Bash script that reads files with several columns of data and multiplies each value in the second column by each value in the third column, adding the results of all those multiplications together.
For example if the file looked like this:
Column 1 Column 2 Column 3 Column 4
genome 1 30 500
genome 2 27 500
genome 3 83 500
...
The script should multiply 1*30 to give 30, then 2*27 to give 54 (and add that to 30), then 3*83 to give 249 (and add that to 84) etc..
I've been trying to use awk to parse the input file but am unsure of how to get the operation to proceed line by line. Right now it stops after the first line is read and the operations on the variables are performed.
Here's what I've written so far:
for file in fileone filetwo
do
set -- $(awk '/genome/ {print $2,$3}' $file.hist)
var1=$1
var2=$2
var3=$((var1*var2))
total=$((total+var3))
echo var1 \= $var1
echo var2 \= $var2
echo var3 \= $var3
echo total \= $total
done
I tried placing a "while read" loop around everything but could not get the variables to update with each line. I think I'm going about this the wrong way!
I'm very new to Linux and Bash scripting so any help would be greatly appreciated!
That's because awk reads the entire file and runs its program on each line. So the output you get from awk '/genome/ {print $2,$3}' $file.hist will look like
1 30
2 27
3 83
and so on, which means in the bash script, the set command makes the following variable assignments:
$1 = 1
$2 = 30
$3 = 2
$4 = 27
$5 = 3
$6 = 83
etc. But you only use $1 and $2 in your script, meaning that the rest of the file's contents - everything after the first line - is discarded.
Honestly, unless you're doing this just to learn how to use bash, I'd say just do it in awk. Since awk automatically runs over every line in the file, it'll be easy to multiply columns 2 and 3 and keep a running total.
awk '{ total += $2 * $3 } ENDFILE { print total; total = 0 }' fileone filetwo
Here ENDFILE is a special address that means "run this next block at the end of each file, not at each line."
If you are doing this for educational purposes, let me say this: the only thing you need to know about doing arithmetic in bash is that you should never do arithmetic in bash :-P Seriously though, when you want to manipulate numbers, bash is one of the least well-adapted tools for that job. But if you really want to know, I can edit this to include some information on how you could do this task primarily in bash.
I agree that awk is in general better suited for this kind of work, but if you are curious what a pure bash implementation would look like:
for f in file1 file2; do
total=0
while read -r _ x y _; do
((total += x * y))
done < "$f"
echo "$total"
done
This question already has answers here:
How can I split a large text file into smaller files with an equal number of lines?
(12 answers)
Closed 5 years ago.
I was wondering if it was possible to split a file into equal parts (edit: = all equal except for the last), without breaking the line? Using the split command in Unix, lines may be broken in half. Is there a way to, say, split up a file in 5 equal parts, but have it still only consist of whole lines (it's no problem if one of the files is a little larger or smaller)? I know I could just calculate the number of lines, but I have to do this for a lot of files in a bash script. Many thanks!
If you mean an equal number of lines, split has an option for this:
split --lines=75
If you need to know what that 75 should really be for N equal parts, its:
lines_per_part = int(total_lines + N - 1) / N
where total lines can be obtained with wc -l.
See the following script for an example:
#!/usr/bin/bash
# Configuration stuff
fspec=qq.c
num_files=6
# Work out lines per file.
total_lines=$(wc -l <${fspec})
((lines_per_file = (total_lines + num_files - 1) / num_files))
# Split the actual file, maintaining lines.
split --lines=${lines_per_file} ${fspec} xyzzy.
# Debug information
echo "Total lines = ${total_lines}"
echo "Lines per file = ${lines_per_file}"
wc -l xyzzy.*
This outputs:
Total lines = 70
Lines per file = 12
12 xyzzy.aa
12 xyzzy.ab
12 xyzzy.ac
12 xyzzy.ad
12 xyzzy.ae
10 xyzzy.af
70 total
More recent versions of split allow you to specify a number of CHUNKS with the -n/--number option. You can therefore use something like:
split --number=l/6 ${fspec} xyzzy.
(that's ell-slash-six, meaning lines, not one-slash-six).
That will give you roughly equal files in terms of size, with no mid-line splits.
I mention that last point because it doesn't give you roughly the same number of lines in each file, more the same number of characters.
So, if you have one 20-character line and 19 1-character lines (twenty lines in total) and split to five files, you most likely won't get four lines in every file.
The script isn't even necessary, split(1) supports the wanted feature out of the box:
split -l 75 auth.log auth.log.
The above command splits the file in chunks of 75 lines a piece, and outputs file on the form: auth.log.aa, auth.log.ab, ...
wc -l on the original file and output gives:
321 auth.log
75 auth.log.aa
75 auth.log.ab
75 auth.log.ac
75 auth.log.ad
21 auth.log.ae
642 total
A simple solution for a simple question:
split -n l/5 your_file.txt
no need for scripting here.
From the man file, CHUNKS may be:
l/N split into N files without splitting lines
Update
Not all unix dist include this flag. For example, it will not work in OSX. To use it, you can consider replacing the Mac OS X utilities with GNU core utilities.
split was updated in coreutils release 8.8 (announced 22 Dec 2010) with the --number option to generate a specific number of files. The option --number=l/n generates n files without splitting lines.
coreutils manual
I made a bash script, that given a number of parts as input, split a file
#!/bin/sh
parts_total="$2";
input="$1";
parts=$((parts_total))
for i in $(seq 0 $((parts_total-2))); do
lines=$(wc -l "$input" | cut -f 1 -d" ")
#n is rounded, 1.3 to 2, 1.6 to 2, 1 to 1
n=$(awk -v lines=$lines -v parts=$parts 'BEGIN {
n = lines/parts;
rounded = sprintf("%.0f", n);
if(n>rounded){
print rounded + 1;
}else{
print rounded;
}
}');
head -$n "$input" > split${i}
tail -$((lines-n)) "$input" > .tmp${i}
input=".tmp${i}"
parts=$((parts-1));
done
mv .tmp$((parts_total-2)) split$((parts_total-1))
rm .tmp*
I used head and tail commands, and store in tmp files, for split the files
#10 means 10 parts
sh mysplitXparts.sh input_file 10
or with awk, where 0.1 is 10% => 10 parts, or 0.334 is 3 parts
awk -v size=$(wc -l < input) -v perc=0.1 '{
nfile = int(NR/(size*perc));
if(nfile >= 1/perc){
nfile--;
}
print > "split_"nfile
}' input
var dict = File.ReadLines("test.txt")
.Where(line => !string.IsNullOrWhitespace(line))
.Select(line => line.Split(new char[] { '=' }, 2, 0))
.ToDictionary(parts => parts[0], parts => parts[1]);
or
enter code here
line="to=xxx#gmail.com=yyy#yahoo.co.in";
string[] tokens = line.Split(new char[] { '=' }, 2, 0);
ans:
tokens[0]=to
token[1]=xxx#gmail.com=yyy#yahoo.co.in"