I'm using easeljs to build a certain structure.
Inside that structure, there are many containers and shapes.
I ran across a problem where I needed to change the color of a certain element when the user hovered it with his mouse. I managed to do it However there is a considerable delay until the color is drawn and return to its original color because the stage redraws itself.
I saw that I could use the cache for this purpose so I follow the example in the docs like this:
myShape.cache(150, 150, 100, 100, 1); however nothings happens and I don't see the shape.
I have to say that the shape resides inside a container which is added to the stage.
Here's the relevant code:
enter code here
var g = curShape.graphics.clone().clear();
g.beginFill("#2aa4eb");
g.drawRoundRect(0, 0, curShape.width, curShape.height, 1.5);
//g.drawRect(0, 0, curShape.width + 2, curShape.height + 2);
g.endFill();
g.endStroke();
var newShape= new createjs.Shape(g);
newShape.cache(150, 150, 100, 100, 2);
Any help would be appreciated
You are caching at x:150 and y:150, but you are drawing your shapes at 0,0. If your shape is smaller than 150x150, then it will be caching nothing. Change your cache to 0,0, and it should be fine.
Additionally, you are not providing the 5th parameter (corner radius) to the drawRoundRect call, which will make it fail. Here is a quick sample with a modified version of your code.
http://jsfiddle.net/LNXVg/
var stage = new createjs.Stage("canvas");
var g = new createjs.Graphics();
g.beginFill("#2aa4eb");
g.drawRoundRect(0, 0, 300, 200, 5);
var newShape = new createjs.Shape(g);
//newShape.cache(150, 150, 100, 100, 2);
newShape.cache(0, 0, 100, 100, 2);
stage.addChild(newShape);
stage.update();
Related
I want to implement an animation.
The animation should be a line move to another line. There will be some deformation in the process of the line moving
There is a correspondence between the points of the two lines.
How to implements it with three.js?
I try to use the tween.js.It works.
const material = new THREE.LineBasicMaterial({ color: 0x0000ff })
const geometry = new THREE.BufferGeometry().setAttribute('position',
new THREE.Float32BufferAttribute([-2, 0, 0, -0.5, 0, -0.5, 0, 0, -2], 3))
const line = new THREE.Line(geometry, material)
var position2 = new Float32Array([5, 0, 0, 1, 1, 1, 0, 0, 5])
setupObjectPositionTween(line, geometry.attributes.position.array, position2,
10000, 0, TWEEN.Easing.Linear.None) // duration, delay, easing
scene.add(line)
function setupObjectPositionTween(object, source, target, duration, delay, easing) {
new TWEEN.Tween(source)
.to(target, duration)
.delay(delay)
.easing(easing)
.onUpdate(function () {
// console.log(object,source,target)
object.geometry.attributes.position.array = source
object.geometry.attributes.position.needsUpdate=true
})
.start()
}
and in the render function
TWEEN.update()
I suggest you implement the animation of the green line with morph targets. Meaning the green line represents your default geometry whereas the blue line represents a morph target (also known as blend shape). You can then animate the transformation from green to blue by modulating the morphTargetInfluences parameter from 0 to 1.
Morph targets are part of the geometry data and defined in the BufferGeometry.morphAttributes property. Since multiple meshes can share the same geometry, the morphTargetInfluences property belongs to 3D objects like a mesh.
I suggest you study how the official example webgl_morphtargets is implemented. You can apply the same principles on lines.
I have a view that I want to overlay with a transparent black layer whose edges match the view exactly. The view does not clip its bounds, so subviews may be hanging off.
The obvious solution is the mask property of CALayer, but the docs say that the mask layer "must not have a superlayer" or the behavior is undefined.
I was hoping that using the presentationLayer of that view would be an effective workaround, but I don't think I fully understand what presentation layers are, as that property returns nil.
Does anyone have tips on how I could mask my transparent black layer to match the shape of the view over which it will be drawn? Thanks.
There’s a less obvious solution to this that should work better than masking: a blend-mode filter, specifically source-atop. If you add your transparent layer as a sibling of the layers it’s supposed to dim, and assign it the appropriate CI compositing filter, it will dim those layers without affecting anything outside of their boundaries. As a bonus, you’ll get correct antialiasing at the edges, unlike the masked-overlay approach.
Here’s an example. For illustrative purposes I made the dimming layer only half the height of the area it covers, but you’d of course want to make it larger.
let container = CALayer()
container.backgroundColor = NSColor.systemBlue.cgColor
container.frame = CGRect(x: 0, y: 0, width: 200, height: 200)
let dimmedRoot = CALayer()
let dimmedLayer1 = CALayer()
dimmedLayer1.frame = CGRect(x: 20, y: 20, width: 100, height: 100)
dimmedLayer1.backgroundColor = NSColor.systemGreen.cgColor
dimmedLayer1.transform = CATransform3DMakeRotation(0.3, 0, 0, 1)
let dimmedLayer2 = CALayer()
dimmedLayer2.frame = CGRect(x: 80, y: 80, width: 100, height: 100)
dimmedLayer2.backgroundColor = NSColor.systemPurple.cgColor
dimmedLayer2.transform = CATransform3DMakeRotation(-0.1, 0, 0, 1)
let dimmingLayer = CALayer()
dimmingLayer.frame = CGRect(x: 0, y: 50, width: 200, height: 100)
dimmingLayer.backgroundColor = NSColor(white: 0, alpha: 0.5).cgColor
dimmingLayer.compositingFilter = CIFilter(name: "CISourceAtopCompositing")
dimmedRoot.sublayers = [ dimmedLayer1, dimmedLayer2, dimmingLayer ]
container.addSublayer(dimmedRoot)
I have a problem with jCanvas which is a framework drawing canvas and jquery.
When I set x = 0 , y = 0 The .drawRect output should be same as the pure javascript result.
I tried the document and google but I did not find anything to solve this.
Screen shoot:
Pure js result
jCanvas result
Please help me.
Many thanks.
// Pure javascript
var canvas = document.getElementsByTagName('canvas')[0];
var ctx = canvas.getContext("2d");
ctx.fillStyle = 'blue';
ctx.fillRect(0, 0, 100, 100);
// jCanvas
$('canvas').drawRect({
fillStyle: '#000',
x: 0, y: 0,
width: 100,
height: 100
});
To run this code, please copy and pass to this sanbox.
https://projects.calebevans.me/jcanvas/sandbox/
From jCanvas documentation:
The [.drawRect's] fromCenter property determines if a rectangle’s x and y properties lie at its center (as opposed to its top-left corner). This property is true by default.
So yeah. Your X and Y with jCanvas, refer to the center of the rectangle, unlike canvas' fillRect X and Y, which refer to the top left corner of the rectangle.
https://jsfiddle.net/sepoto/Ln7qvv7w/2/
I have a base set up to display a cube with different colored faces. What I am trying to do is set up a camera and apply a combined X axis and Y axis rotation so that the cube spins around both axis concurrently. There seems to be some problems with the matrices I set up as I can see the blue face doesn't look quite right. There are some examples of how this is done using older versions of glMatrix however the code in the examples no longer works because of some changes in vec4 of the glMatrix library. Does anyone know how this can be done using the latest version of glMatrix as I have attached a CDN to the fiddle?
Thank you!
function drawScene() {
gl.viewport(0,0,gl.viewportWidth, gl.viewportHeight);
gl.clear(gl.COLOR_BUFFER_BIT | gl.DEPTH_BUFFER_BIT);
mat4.ortho( mOrtho, -5, 5, 5, -5, 2, -200);
mat4.identity(mMove);
var rotMatrix = mat4.create();
mat4.identity(rotMatrix);
rotMatrix = mat4.fromYRotation(rotMatrix, yRot,rotMatrix);
rotMatrix = mat4.fromXRotation(rotMatrix, xRot,rotMatrix);
mat4.multiply(mMove, rotMatrix, mMove);
setMatrixUniforms();
gl.bindBuffer(gl.ARRAY_BUFFER, triangleVertexPositionBuffer);
gl.vertexAttribPointer(shaderProgram.vertexPositionAttribute, triangleVertexPositionBuffer.itemSize, gl.FLOAT, false, 0, 0);
gl.bindBuffer(gl.ARRAY_BUFFER, triangleColorBuffer);
gl.vertexAttribPointer(shaderProgram.vertexColorAttribute, triangleColorBuffer.itemSize, gl.FLOAT, false, 0, 0);
gl.drawArrays(gl.TRIANGLES, 0, triangleVertexPositionBuffer.numItems);
yRot += 0.01;
xRot += 0.01;
}
As the name says, fromYRotation() initializes a matrix to a given rotation. Hence, you need two temporary matrices for the partial rotations, which you can then combine:
var rotMatrix = mat4.create();
var rotMatrixX = mat4.create();
var rotMatrixY = mat4.create();
mat4.fromYRotation(rotMatrixY, yRot);
mat4.fromXRotation(rotMatrixX, xRot);
mat4.multiply(rotMatrix, rotMatrixY, rotMatrixX);
And the reason why your blue face was behaving strangely, was the missing depth test. Enable it in your initialization method:
gl.enable(gl.DEPTH_TEST);
You dont need to use three matrices:
// you should do allocations outside of the renderloop
var rotMat = mat4.create();
// no need to set the matrix to identity as
// fromYRotation resets rotMats contents anyway
mat4.fromYRotation(rotMat, yRot);
mat4.rotateX(rotMat,xRot);
Well , the problem is the next :
canvas = GreenCanvas.get(0).getContext('2d');
grad = canvas.createLinearGradient(0,0,255,0);
grad.addColorStop(0, 'rgb('+r+','+0+','+b+')');
grad.addColorStop(1, 'rgb('+r+','+255+','+b+')');
canvas.fillStyle = grad;
canvas.fillRect(0,0,256,34);
256 pixels . from for example rgb(0,0,0) to rgb(0,255,0)
Chrome 6.0.472: gradient (0,0,0) (0,1,0) (0,2,0) (0,3,0) (0,4,0) ... (0,255,0)
Firefox 3.6.6: gradient (0,0,0) (0,0,0) (0,1,0) (0,2,0) ... (0,255,0)
i would like to see who programs that gradient function in firefox . But anyway , i would like to know if its a real problem , or is that in firefox the gradient is done that manner. Or if it exist another manner to do a well done gradient without using too much memory.
It's known that Chrome has problems with the Canvas gradients at the moment.
I submitted a bug to Chromium because of how many of hixie's (the specification writer) tests were failing on Chrome.
In short, you can't make your 'grad' variable. You have to set it directly.
This works:
var context = document.getElementsByTagName('canvas')[0].getContext('2d');
context.fillStyle = context.createLinearGradient(0, 0, 500, 300);
context.fillStyle.addColorStop(0, '#0000ff');
context.fillStyle.addColorStop(1, '#ff00ff');
context.fillRect(0, 0, 500, 300);
This does NOT work, even though they are SUPPOSED to do the same thing:
var context = document.getElementsByTagName('canvas')[0].getContext('2d');
var g = context.createLinearGradient(0, 0, 500, 300);
g.addColorStop(0, '#0000ff');
g.addColorStop(1, '#ff00ff');
context.fillStyle = g;
context.fillRect(0, 0, 500, 300);
For now, just do it the first way.
Here's the filed bug report from early September.
http://code.google.com/p/chromium/issues/detail?id=54070&can=4&colspec=ID%20Stars%20Pri%20Area%20Feature%20Type%20Status%20Summary%20Modified%20Owner%20Mstone%20OS