Maven Packing Type Based on Profile - maven

Question

I am using a found example on stackoverflow that dynamically changes the packaging type based on profile
Changing packaging based on active profile in pom
This is a snippet of my pom.xml
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.scene7.is.qa</groupId>
<artifactId>jorogumo</artifactId>
<packaging>${packaging.type}</packaging>
...
<profile>
<id>JorogumoReportingWebApp</id>
<properties>
<packaging.type>war</packaging.type>
<final.name>jorogumo</final.name>
</properties>
...
Based on the upvotes from the answer link above I am assuming this should work, but I receive an error when cleaning
$ mvn clean
[INFO] Scanning for projects...
[ERROR] The build could not read 1 project -> [Help 1]
[ERROR]
[ERROR] The project com.scene7.is.qa:jorogumo:0.0.1-SNAPSHOT (/Users/xyz/working/_workspaces/Scene7/java/jorogumo/pom.xml) has 1 error
[ERROR] Unknown packaging: ${packaging.type} # line 10, column 13
Am I missing something? Or is this the wrong approach?
My end goal is to share common java classes between the web app and the command line jar.

Answer 1

I ended up creating a default packing.type property with a value:
<modelVersion>4.0.0</modelVersion>
<groupId>com.scene7.is.qa</groupId>
<artifactId>jorogumo</artifactId>
<packaging>${packaging.type}</packaging>
...
<properties>
<packaging.type>war</packaging.type>
</properties>
<profiles>
<profile>
<id>JorogumoReportingWebApp</id>
<properties>
<packaging.type>war</packaging.type>
<final.name>jorogumo</final.name>
</properties>
...