Stock date in a string then split it for tests - bash

Question

I have some operations to do on files last modified on a specific date. I would like to get the date, stock it in a string, then split it to test if the day corresponds to what I want.
So far, I've been trying things like that:
#!/bin/bash
for i in {45..236}; do
nom=M$i
chem=/Users/nfs/helene/soft/metAMOS-1.5rc3/$nom.fastq/Assemble/out
if [ -e $chem ]; then
IN= $(date -r $chem)
arr=(${IN//\ / })
if [[ ${arr[1]} == 'juin' && ${arr[2]} == '10' ]]; then
echo $nom
#cp $chem/proba.faa /Users/nfs/helene/metagenomes/DB/$nom.faa
fi
fi
done
exit 0
But it seems like the date isn't well stocked in $IN, and I'm not sure about the space-spliting either..

Answer 1

Perhaps the simple mistake is that you didn't place your assignment adjacent to =. It must be:
IN=$(date -r $chem)
And here's a simplified suggestion:
#!/bin/bash
for i in {45..236}; do
nom="M${i}"
chem="/Users/nfs/helene/soft/metAMOS-1.5rc3/${nom}.fastq/Assemble/out"
if [[ -e $chem ]]; then
read month day < <(exec date -r "$chem" '+%b %d')
if [[ $month == 'Jun' && $day == 10 ]]; then
echo "$nom"
# cp "$chem/proba.faa" "/Users/nfs/helene/metagenomes/DB/$nom.faa"
fi
fi
done
exit 0
* See date --help for a list of formats.
* <() is a form of Process Substitution. Check Bash's manual for it.
* Always place your arguments around double quotes when they have variables to avoid word splitting.