I have searched for hours on this one subject and still have not been able to solve my problem. I have a string value that I need converted into a label. In my code I save the NSString and then make sure I am getting a value with the NSLog (which I DO). Then is where I am having problems. I try to set the label value equal to the nesting but when I run its NSLog I get (null). So my question is how may I make my label equal the value of my string? Thank you so much!
NSString *linkString = self.product[#"link"];
NSLog(#"%#", linkString);
linkLabel.text = linkString;
NSLog(#"%#", linkLabel);
Your NSString will never be equal to your UILabel.
on the other hand, your UILabel's text property which is an NSString will be
try to change the code to this
NSString *linkString = self.product[#"link"];
NSLog(#"%#", linkString);
linkLabel.text = linkString;
NSLog(#"%#", linkLabel.text);
All I changed was linkLabel in your NSLog to linkLabel.text
Assuming like you said that linkString has a value, the second log should output the same as the first log.
EDIT: I saw your comment above, there is no need for a duplicate definition of the label as an #property and above that in the h file.
Are you sure that
NSString *linkString = self.product[#"link"];
works? Try this:
NSString *linkString = #"Test";
and use this for logging:
NSLog(#"%#", linkLabel.text);
Did you forget to hook up the linkLabel in your XIB? Is the value of linkLabel not nil?
What does NSLog(#"%#", linkLabel); print out?
Related
Im making an iOS app to do with currency. My app receives the value of maybe: $4. This value the app receives is put into an NSNumber. The trouble is the value actualy has a $ in it. How do I trim out the $ in the NSNumber? Or would I be better of putting it into an NSString?
Use NSNumberFormatter:
// set up your number formatter
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterCurrencyStyle];
// get a string that you'll be converting to a NSNumber
NSString *myNumberString = [NSString stringWithFormat:#"$4"]
// convert then print to the console
NSNumber *myNumber = [numberFormatter numberFromString:myNumberString];
NSLog(#"myNumber: %#", myNumber);
This should accomplish what you're looking to do. myNumberString will need to be altered to contain whatever string you're receiving.
NSNumberFormatter Documentation: https://developer.apple.com/library/ios/#documentation/Cocoa/Reference/Foundation/Classes/NSNumberFormatter_Class/Reference/Reference.html
I have an NSTextField which holds numeric (integer) values. There is a number formatter attached to the field. I want to display an empty field when the value of the field is set to 0 (zero). I think I tried every combination with the formatter, without luck so far. Can this be done?
I don't think you can do that with NSNumberFormatter. But you could make a subclass and implement stringFromNumber: something like this:
-(NSString *)stringFromNumber:(NSNumber *)number {
NSNumber *zero = [NSNumber numberWithInt:0];
if ([number isEqualToNumber:zero])
return #"";
else
return [super stringFromNumber:number];
}
EDIT:
I was wrong. You can do that with NSNumberFormatter:
[formatter setZeroSymbol:#""];
I have a GUI built on IB (Xcode 4).
It has a Static Text field connected to an NSTextField. After reading the information from an XML file it's supposed to change the text to whatever it is coming from the XML
the .h is as follow:
IBOutlet NSTextField * DataBaseLocation;
the .m
NSMutableArray* DBLoc = [[NSMutableArray alloc] initWithCapacity:1];
NSXMLElement* root = [doc rootElement];
NSArray* DBarray = [root nodesForXPath:#"//DataBaseLocation" error:nil];
for(NSXMLElement* xmlElement in DBarray)
[DBLoc addObject:[xmlElement stringValue]];
NSString * DBLocationString = [DBLoc objectAtIndex:0];
[DataBaseLocation setStringValue:DBLocationString];
NSLog(#"DBLoc: %#", DBLoc);
The NSLog shows that DBLoc has the correct string, yet the Text Field is empty and never gets set.
yes, I checked the connections in IB.
Any ideas? thanks!
Found the answer.
I needed to initialize the NSXMLDocument with NSXMLDocumentTidyXML like:
NSXMLDocument* doc = [[NSXMLDocument alloc] initWithContentsOfURL: [NSURL fileURLWithPath:input] options:NSXMLDocumentTidyXML error:NULL];
You should print out DBLocationString instead of DBLoc to make sure it's not empty or in some corrupted format that can't be passed as a string value and go from there.
I have an NSMutableArray i am trying to convert into a string.
Declaring my NSMutableArray...
NSMutableArray *listData;
And later inside a method...
NSString *foo = [listData componentsJoinedByString:#"|"];
NSLog(#"%#",foo);
It seems no matter what i try i keep getting EXC_BAD_ACCESS.
To make sure each element in my array was an NSString i also tried this...
NSMutableArray *mArray = [[NSMutableArray alloc] init];
for (id ln in listData) {
NSString *boo = [NSString stringWithFormat: #"%#",ln];
[mArray addObject:boo];
}
NSString *foo = [mArray componentsJoinedByString:#"|"];
NSLog(#"%#",foo);
I can manipulate my NSMutableArray by adding/deleting objects in the same method or other methods inside my class. But when i try "componentsJoinedByString" the error pops up. Does anyone have any advice or another way i can combine this array into a single NSString?
In the code you've given, there will never be an NSMutableArray for listData. At some point in your code, you'll need to create one, and presumably populate it.
Edit
Okay, so you may get into memory management problems here, so let's be a bit clearer:
You're synthesizing getters and setters for the instance variable, so it's good practice to use those to access it, they'll take care of retain and releasing appropriately.
To set listData you can simply use
self.listData = [listManage getList:[[NSUserDefaults standardUserDefaults] stringForKey:#"list_name"] list:#"LIST"];
or
[self setListData:[listManage getList:[[NSUserDefaults standardUserDefaults] stringForKey:#"list_name"] list:#"LIST"]];
if you prefer.
I can't seem to find an easy way to do it. The exact thing I need is:
[NSString stringWithFormat:#"%d doodads", n];
Where n is an int. So for 1234 I'd want this string (under my locale):
#"1,234 doodads"
Thanks.
For 10.6 this works:
NSNumberFormatter* numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setFormatterBehavior: NSNumberFormatterBehavior10_4];
[numberFormatter setNumberStyle: NSNumberFormatterDecimalStyle];
NSString *numberString = [numberFormatter stringFromNumber: [NSNumber numberWithInteger: i]];
And it properly handles localization.
I have recently discovered this one-liner:
[#1234567 descriptionWithLocale:[NSLocale currentLocale]]; // 1,234,567
Or in Swift 2:
1234567.descriptionWithLocale(NSLocale.currentLocale()) // 1,234,567
Swift 3/4:
(1234567 as NSNumber).description(withLocale: Locale.current)
Formatted per the question:
[#(n) descriptionWithLocale:[NSLocale currentLocale]];
Formatted without Objective-C literals:
[[NSNumber numberWithInt:n] descriptionWithLocale:[NSLocale currentLocale]];
This is the solution I was looking for when I asked the question. Available since iOS 2.0 and OS X 10.0, documented to return a string version of the number formatted as per the locale provided. stringValue is even documented to use this method but passing nil.
Seeing as it is my question and this fits my answer best, I am tempted to change the tick, but it seems cruel. Update I changed the tick, this answer is the answer.
The below doesn't address the locale, but it is a better way (in my opinion) of setting the thousand separator on the number formatter.
NSNumberFormatter *numberFormat = [[[NSNumberFormatter alloc] init] autorelease];
numberFormat.usesGroupingSeparator = YES;
numberFormat.groupingSeparator = #",";
numberFormat.groupingSize = 3;
Todd Ransom answered this perfectly.
I would just like to add (in a separate comment, so I can show some nicely formatted code), that if you plan to do this regularly, it's worth creating an NSString helper class.
So, create yourself an NSStringHelper.h containing this:
#import <Foundation/Foundation.h>
#interface NSString (NSStringHelper)
+(NSString*)formatWithThousandSeparator:(NSInteger)number;
#end
..and an NSStringHelper.m file containing this:
#import "NSStringHelper.h"
#implementation NSString (NSStringHelper)
+(NSString*)formatWithThousandSeparator:(NSInteger)number
{
// Format a number with thousand seperators, eg: "12,345"
NSNumberFormatter* numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setFormatterBehavior: NSNumberFormatterBehavior10_4];
[numberFormatter setNumberStyle: NSNumberFormatterDecimalStyle];
NSString *result = [numberFormatter stringFromNumber:[NSNumber numberWithInteger:number]];
return result;
}
#end
This gives you the perfect way to reuse this code in future projects.
#import "NSStringHelper.h"
NSInteger numOfUsers = 12345;
NSString* strNumberOfUsers = [NSString formatWithThousandSeparator:numOfUsers];
Cool, hey ?
Again, apologies for reposting Todd's answer (which was exactly what I was looking for !), but this is a great way to solve the problem, and have it ready to be used in your future XCode projects.
Use an NSNumberFormatter.