golang - Elem Vs Indirect in the reflect package - go

From the docs
func (v Value) Elem() Value
Elem returns the value that the interface v contains or that the pointer v points to. It panics if v's Kind is not Interface or Ptr. It returns the zero Value if v is nil.
func Indirect(v Value) Value
Indirect returns the value that v points to. If v is a nil pointer, Indirect returns a zero Value. If v is not a pointer, Indirect returns v.
So can I safely assume the following?
reflect.Indirect(reflect.ValueOf(someX)) === reflect.ValueOf(someX).Elem().
Is Indirect method just a convenience method for the right hand side of the above?

If a reflect.Value is a pointer, then v.Elem() is equivalent to reflect.Indirect(v). If it is not a pointer, then they are not equivalent:
If the value is an interface then reflect.Indirect(v) will return the same value, while v.Elem() will return the contained dynamic value.
If the value is something else, then v.Elem() will panic.
The reflect.Indirect helper is intended for cases where you want to accept either a particular type, or a pointer to that type. One example is the database/sql conversion routines: by using reflect.Indirect, it can use the same code paths to handle the various types and pointers to those types.

Related

Wrap a reflect.Value with pointer which points to the same element

Here I found the following code -
// ptr wraps the given value with pointer: V => *V, *V => **V, etc.
func ptr(v reflect.Value) reflect.Value {
pt := reflect.PtrTo(v.Type()) // create a *T type.
pv := reflect.New(pt.Elem()) // create a reflect.Value of type *T.
pv.Elem().Set(v) // sets pv to point to underlying value of v.
return pv
}
As stated, calling this function on variable V of type reflect.Value, which describes an element of type T that holds data d, returns variable VP of type reflect.Value, which describes an element of type *T that points to data d.
When modifying VP by setting it's data to something other then d, V doesn't change (ie by calling VP.Set(..)).
I need a function that returns VP as described above, but so that modifying the data in VP modifies it in V.
The reason I need this function is that I want to extend this stack overflow answer to initialize strings and ints with default values. I wanted to use this stack overflow answer to do it, but for that I need to have a value of a pointer of a struct, not a value of a struct, when running SetString and SetInt.
Thanks,

Get inteface's dynamic value when there is a pointer to integer as dinamic type

I'm struggling trying to figure out how to "extract" an integer value from a interface that holds a value whose dynamic type is pointer to integer.
You may follow this ready-to-run example in order to fully get the picture of what is problem and my intention.
TD;DR:
For some reason the reflection on a first call to reflect.ValueOf(value) over an interface whose dynamic type is pointer to integer, it returns a value whose Kind() results in reflect.Ptr, when i extract again the "inner" value using reflect.ValueOf(value).Elem() i get another value whose Kind() results in reflect.Struct. I don't even code any struct, but they appears by their own "magically". So golang may not panic but i don't understand what is happening, probably i lack of some information. I would be very thankful with anyone that explaint me what is going on.
This may work for this case, but it doesn't enlight me. I would expect to have an integer value "behind" the pointer. I don't need to access for modification, i only need to get it.
It's struct because when you call ToCompliantValue inside the function, you're not passing it the value itself, you're passing a reflect.Value value, and reflect.Value is a struct. You have to handle it directly instead of trying to use recursion:
v := reflect.ValueOf(value)
fmt.Printf("Value is %+v\n", v)
if v.Kind() == reflect.Ptr {
v = v.Elem()
}
switch v.Kind() {
// ...
Working example: https://play.golang.org/p/ndRjXJfj5xV

When a receiver method T cannot take *T?

The official Go site writes as follows:
As the Go specification says, the method set of a type T consists of
all methods with receiver type T, while that of the corresponding
pointer type *T consists of all methods with receiver *T or T. That
means the method set of *T includes that of T, but not the reverse.
This distinction arises because if an interface value contains a
pointer *T, a method call can obtain a value by dereferencing the
pointer, but if an interface value contains a value T, there is no
safe way for a method call to obtain a pointer. (Doing so would allow
a method to modify the contents of the value inside the interface,
which is not permitted by the language specification.)
Even in cases where the compiler could take the address of a value to
pass to the method, if the method modifies the value the changes will
be lost in the caller.
My question is, when can't the compiler take a value to a pointer receiver value?
Addressable is defined in the https://golang.org/ref/spec#Address_operators:
For an operand x of type T, the address operation &x generates a pointer of type *T to x. The operand must be addressable, that is, either a variable, pointer indirection, or slice indexing operation; or a field selector of an addressable struct operand; or an array indexing operation of an addressable array. As an exception to the addressability requirement, x may also be a (possibly parenthesized) composite literal.
A counter examples include map values and functions:
func f() {}
func main() {
var m map[string]string
p1 := &m["foo"] // cannot take the address of m["foo"]
p2 := &f // cannot take the address of f
}

What is the difference between reflect.ValueOf() and Value.Elem() in go?

I started learning golang a couple of days ago and found reflect.Valueof() and Value.Elem() quite confusing. What is the difference between this two function/methods and how to use them correctly?
Both function/methods return a Value, and according to the go doc
ValueOf returns a new Value initialized to the concrete value stored in the interface i. ValueOf(nil) returns the zero Value.
Elem returns the value that the interface v contains or that the pointer v points to. It panics if v's Kind is not Interface or Ptr. It returns the zero Value if v is nil.
I found this code from a post on stackoverflow but still don't understand when to use .Elem()
func SetField(obj interface{}, name string, value interface{}) error {
// won't work if I remove .Elem()
structValue := reflect.ValueOf(obj).Elem()
structFieldValue := structValue.FieldByName(name)
if !structFieldValue.IsValid() {
return fmt.Errorf("No such field: %s in obj", name)
}
if !structFieldValue.CanSet() {
return fmt.Errorf("Cannot set %s field value", name)
}
structFieldType := structFieldValue.Type()
// won't work either if I add .Elem() to the end
val := reflect.ValueOf(value)
if structFieldType != val.Type() {
return fmt.Errorf("Provided value %v type %v didn't match obj field type %v",val,val.Type(),structFieldType)
}
structFieldValue.Set(val)
return nil
}
reflect.ValueOf() is a function, think of it as the entry point to reflection. When you have a "non-reflection" value, such as a string or int, you can use reflect.ValueOf() to get a reflect.Value descriptor of it.
Value.Elem() is a method of reflect.Value. So you can only use this if you already have a reflect.Value. You may use Value.Elem() to get the value (reflect.Value) pointed by the value wrapped by the original reflect.Value. Note that you may also use reflect.Indirect() for this. There's another "use case" for Value.Elem(), but it's more "advanced", we return to it at the end of the answer.
To "leave" reflection, you may use the general Value.Interface() method, which returns you the wrapped value as an interface{}.
For example:
var i int = 3
var p *int = &i
fmt.Println(p, i)
v := reflect.ValueOf(p)
fmt.Println(v.Interface()) // This is the p pointer
v2 := v.Elem()
fmt.Println(v2.Interface()) // This is i's value: 3
This will output (try it on the Go Playground):
0x414020 3
0x414020
3
For a great introduction to Go's reflection, read The Go Blog: The Laws of Reflection. Although if you're just starting with Go, I'd focus on other things and leave reflection for a later adventure.
Another use case for Value.Elem()
This is kind of an advanced topic, so don't freak out if you don't understand it. You don't need to.
We saw how Value.Elem() can be used to "navigate" when a pointer is wrapped in the reflect.Value. Doc of Value.Elem() says:
Elem returns the value that the interface v contains or that the pointer v points to.
So if reflect.Value wraps an interface value, Value.Elem() may also be used to get the concrete value wrapped in that interface value.
Interfaces in Go is its own topic, for the internals, you may read Go Data Structures: Interfaces by Russ Cox. Again, not necessarily a topic for Go starters.
Basically whatever value you pass to reflect.ValueOf(), if it's not already an interface value, it will be wrapped in an interface{} implicitly. If the passed value is already an interface value, then the concrete value stored in it will be passed as a interface{}. This second "use case" surfaces if you pass a pointer to interface (which is otherwise very rare in Go!).
So if you pass a pointer to interface, this pointer will be wrapped in an interface{} value. You may use Value.Elem() to get the pointed value, which will be an interface value (not a concrete value), and using Value.Elem() again on this will give you the concrete value.
This example illustrates it:
var r io.Reader = os.Stdin // os.Stdin is of type *os.File which implements io.Reader
v := reflect.ValueOf(r) // r is interface wrapping *os.File value
fmt.Println(v.Type()) // *os.File
v2 := reflect.ValueOf(&r) // pointer passed, will be wrapped in interface{}
fmt.Println(v2.Type()) // *io.Reader
fmt.Println(v2.Elem().Type()) // navigate to pointed: io.Reader (interface type)
fmt.Println(v2.Elem().Elem().Type()) // 2nd Elem(): get concrete value in interface: *os.File
Try it on the Go Playground.

Why the pointer is losing its value in this Go program

I don't understand why the pointer s is nil even after the input() method initialised it. Any idea?
package main
import "fmt"
type ps string
func(s *ps)input(){
x := ps("a")
s = &x
}
func(s *ps)output(){
}
func main() {
var v *ps
v.input()
if v == nil{
fmt.Println("v shouldn't be nil")
}
}
Playground http://play.golang.org/p/jU2hoMP7TS
You need two things--main needs to allocate space for a ps that input can write into, which you can do by replacing var v *ps with v := new(ps). The string will be "", but it doesn't matter what it is, just that there's space set aside in memory for a string header that input can write to. As Momer said, otherwise the pointer's nil and your program panics trying to dereference it.
And in order to assign through a pointer, input needs to use *s = x. Since *s is, informally, "get what s points to", you can read that as "change what s points to to x". Usually the automatic ref/deref behavior around the dot operator and method calls saves you from that, but when you assign through a pointer type or do other operations (arithmetic, indexing, etc.) the dereference needs to be there in the code.
v value (0) is passed into v.input. Passed value is stored in a local variable s. s value is modified. No one is saving new s value back into v.
If you want something modified in your function, you must pass pointer to the value. (or reference for slices, maps and so on).
If you want to change pointer value, you should pass pointer to your pointer.
Alex

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