Hello I am trying to setup spring JTA in myEclipse for Spring.Below are my configuration files:
applicationContent.xml where i have added two imports(note it do include schema locations)
<import resource="infrastructure.xml"/>
<import resource="classpath:**/persistence.xml"/>
infrastrutre.xml(unable to add schema due to input validations)
<bean
class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" />
<bean id="emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="jtaDataSource" ref="masterDataSource" />
<property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
</bean>
<!-- <bean id="masterDataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="java:/test_JTA"></property>
</bean> -->
<jee:jndi-lookup id="masterDataSource" jndi-name="java:/Test_JTA" />
<bean id="jpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<!-- <property name="databasePlatform"
value="org.hibernate.dialect.MySQL5InnoDBDialect" /> -->
<property name="database" value="MYSQL" />
<property name="showSql" value="true" />
<property name="generateDdl" value="true" />
</bean>
<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager" />
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence">
<persistence-unit name="mainPU" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.abc.PaymentCard</class>
<jar-file>mysql-connector-java-5.1.23-bin.jar</jar-file>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/>
<property name="hibernate.transaction.jta.platform" value="org.hibernate.service.jta.platform.internal.JBossAppServerJtaPlatform"/>
<property key="hibernate.transaction.factory_class">org.hibernate.transaction.CMTTransactionFactory</property>
<property key="hibernate.transaction.manager_lookup_class">org.hibernate.transaction.JBossTransactionManagerLookup</property>
</properties>
</persistence-unit>
</persistence>
I am getting error
JBAS010402: Unable to instantiate driver class "com.mysql.jdbc.Driver": org.jboss.msc.service.DuplicateServiceException: Service jboss.jdbc-driver.JTA_Test_war is already registered
I goggled this error but still haven't got any satisfactory answers.Kindly help
I am not sure about JBoss but for Glassfish there is an Ext directory for the Jars you want in the Classpath. So try to figure out how to deploy mysql-connector-java*.jar to your domain.
i know its late but, i believe i fixed this error by using a different factory class.
<property name="hibernate.transaction.factory_class" value="org.hibernate.ejb.transaction.JoinableCMTTransactionFactory"/>
hope it helps :)
Related
I'm developing an application using Spring which directs the DB using entity manager with #PersistenceContext injection. the application is executed in multiple threads, each in its own #Transactional scope.
As part of the thread process it should go and call :
entityManager.createQuery("some statement").getResultList()
This should return if an object exists on the DB and if not it will persist it. because i am using multiple threads i have put the call in a syncronized block on a shared object like this:
synchronized (getLock())
{
List<SomeObject> listOfObjects = entityManager.createQuery("some statement").getResultList();
if(listOfObjects == null || listOfObjects.size() < 1)
{
createObject();
}
}
The problem is that when I'm running this the process get stuck on the call to the getResultList and never released. Moreover, when i run the code and creating only one thread I get the same behavior.
if i change the flushMode to COMMIT the process is released but the results are not reflected well because the different threads could end at different times and the one creating the object will not necessarily be the one to end first.
my persistence xml is:
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0">
<persistence-unit name="syncAdapterUnit"
transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.max_fetch_depth" value="3"/>
<property name="hibernate.connection.pool_size" value="10"/>
<property name="format_sql" value="false"/>
<property name="hibernate.jdbc.batch_size" value="50" />
<property name="hibernate.cache.use_query_cache" value="false" />
<property name="hibernate.cache.use_second_level_cache" value="false" />
</properties>
</persistence-unit>
</persistence>
The spring bean xml:
<beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/beans"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="managerFactoryBean" class="com.amdocs.dim.ManagerFactory" />
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" destroy-method="destroy">
<property name="dataSource" ref="myDataSource"/>
<property name="jpaVendorAdapter" ref="hibernateVendorAdapter"/>
<property name="persistenceUnitName" value="syncAdapterUnit"/>
</bean>
<bean id="hibernateVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="false"/>
<property name="databasePlatform" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="database" value="ORACLE"/>
</bean>
<bean id="cifDBProperties" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="ignoreUnresolvablePlaceholders" value="true" />
<property name="location" value="classpath:APP-INF/conf/database.properties"/>
<property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_FALLBACK"/>
</bean>
<bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" scope="singleton">
<property name="driverClassName" value="${jdbc.driverClassName}"/>
<property name="url" value="${jdbc.url}"/>
<property name="username" value="${jdbc.username}"/>
<property name="password" value="${jdbc.password}"/>
</bean>
</beans>
I believe that the flush process is the one which blocks the app but didn't manage to understand why.
I have gone through almost all the posts here regarding Spring JPA configuration. Basically I want to implement JPA Pagination in my project and for that I need spring JPA support. But when I include the spring-data-jpa.jar in my project I get the following exception.
Caused by: java.lang.IllegalArgumentException: JBAS011470: Persistence unitName was not specified and there are 2 persistence unit definitions in application deployment deployment "CPCardApp.ear". Either change the application deployment to have only one persistence unit definition or specify the unitName for each reference to a persistence unit.
at org.jboss.as.jpa.container.PersistenceUnitSearch.ambiguousPUError(PersistenceUnitSearch.java:172)
at org.jboss.as.jpa.container.PersistenceUnitSearch.findWithinDeployment(PersistenceUnitSearch.java:152)
at org.jboss.as.jpa.container.PersistenceUnitSearch.findWithinApplication(PersistenceUnitSearch.java:86)
at org.jboss.as.jpa.container.PersistenceUnitSearch.findPersistenceUnitSupplier(PersistenceUnitSearch.java:76)
at org.jboss.as.jpa.container.PersistenceUnitSearch.resolvePersistenceUnitSupplier(PersistenceUnitSearch.java:63)
at org.jboss.as.jpa.processor.JPAAnnotationParseProcessor.getPersistenceUnit(JPAAnnotationParseProcessor.java:357)
at org.jboss.as.jpa.processor.JPAAnnotationParseProcessor.getBindingSource(JPAAnnotationParseProcessor.java:288)
at org.jboss.as.jpa.processor.JPAAnnotationParseProcessor.processMethod(JPAAnnotationParseProcessor.java:201)
at org.jboss.as.jpa.processor.JPAAnnotationParseProcessor.processPersistenceAnnotations(JPAAnnotationParseProcessor.java:138)
at org.jboss.as.jpa.processor.JPAAnnotationParseProcessor.deploy(JPAAnnotationParseProcessor.java:95)
at org.jboss.as.server.deployment.DeploymentUnitPhaseService.start(DeploymentUnitPhaseService.java:116) [jboss-as-server-7.1.3.Final-redhat-4.jar:7.1.3.Final-redhat-4]
... 5 more
persistence.xml (Note: I have 2 persistence units in my xml and Spring doesn't support that)
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="data01">
<jta-data-source>java:/MySqlDataDS</jta-data-source>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.cache.use_second_level_cache"
value="false" />
<property name="hibernate.id.new_generator_mappings" value="false" />
</properties>
</persistence-unit>
<persistence-unit name="cpaudit">
<jta-data-source>java:/MySqlAuditDS</jta-data-source>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.cache.use_second_level_cache"
value="false" />
<property name="hibernate.id.new_generator_mappings" value="false" />
</properties>
</persistence-unit>
</persistence>
You can have 2 persistence units. There are problems with your config (combo of using JBoss + Spring + JPA (Hibernate) + JTA). The proper configuration will depend on your version of JBoss and Spring.
No matter what you will need to have an xml file to define your JPA config with two entity managers.
Try something like this in a application-jpa-config.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:context="http://www.springframework.org/schema/context"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:transaction="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/beans"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.3.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.3.xsd">
<beans>
<bean id="entityManagerFactorData01" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="jpaProperties">
<map>
<entry key="hibernate.cache.use_second_level_cache" value="false"/>
<entry key="hibernate.id.new_generator_mappings" value="false"/>
<entry key="hibernate.transaction.jta.platform" value-ref="jtaPlatform"/>
</map>
</property>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<property name="jtaDataSource">
<bean class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${database.driver}"/>
<property name="password" value="${database.data01.password}"/>
<property name="url" value="${database.data01.url}"/>
<property name="username" value="${database.data01.user}"/>
</bean>
</property>
<property name="packagesToScan" value="com.app.entites.data01"/>
</bean>
<bean id="entityManagerFactoryCpaudit"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="jpaProperties">
<map>
<entry key="hibernate.cache.use_second_level_cache" value="false"/>
<entry key="hibernate.id.new_generator_mappings" value="false"/>
<entry key="hibernate.transaction.jta.platform" value-ref="jtaPlatform"/>
</map>
</property>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<property name="jtaDataSource">
<bean class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${database.driver}"/>
<property name="password" value="${database.cpaudit.password}"/>
<property name="url" value="${database.cpaudit.url}"/>
<property name="username" value="${database.cpaudit.user}"/>
</bean>
</property>
<property name="packagesToScan" value="com.app.entites.cpaudit"/>
</bean>
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" id="jpaVendorAdapter">
<property name="databasePlatform" value="org.hibernate.dialect.MySQLDialect"/>
</bean>
<context:annotation-config/>
<jpa:repositories base-package="com.app.repo.data01" entity-manager-factory-ref="entityManagerFactorData01"/>
<jpa:repositories base-package="com.app.repo.cpaudit" entity-manager-factory-ref="entityManagerFactoryCpaudit"/>
<!-- ************ JpaTransactionManager *********** -->
<!--
This will depend on your JBoss and Spring version and your application.
You will need to work this out.
Getting your transactionManager correct could be difficult.
See the following project for more ideas:
https://github.com/manish-in-java/spring-data-jta/blob/master/src/main/resources/springContext.xml
-->
<transaction:annotation-driven/>
<bean class="java.lang.String" id="jtaPlatform">
<constructor-arg value="org.hibernate.engine.transaction.jta.platform.internal.JBossStandAloneJtaPlatform"/>
</bean>
<bean class="org.springframework.transaction.jta.JtaTransactionManager" id="transactionManager">
<property name="transactionManager">
<bean class="com.arjuna.ats.internal.jta.transaction.arjunacore.TransactionManagerImple"/>
</property>
<property name="userTransaction">
<bean class="com.arjuna.ats.jta.UserTransaction" factory-method="userTransaction"/>
</property>
</bean>
<!-- ************ JpaTransactionManager *********** -->
</beans>
</beans>
Trying to implement Mule module JPA with Hibernate in Mule and unable to persist data using . When I check in db, no values are inserted. I referred this link, but am unable to implement the solution given in this link, Mule JPA persist is not inserting or updating.
Could someone please elaborate or provide alternate suggestions on this? Thanks.
<code>
<spring:beans>
<spring:import resource="classpath:Spring/applicationContext.xml" />
</spring:beans>
<spring:beans>
<spring:bean id="myBean" class="org.Location">
</spring:bean>
<spring:bean class="org.springframework.orm.jpa.JpaTransactionManager"
id="transactionManager">
<spring:property name="entityManagerFactory" ref="entityManagerFactory"/>
</spring:bean>
</spring:beans>
<jpa:config name="JPA" entityManagerFactory-ref="entityManagerFactory" doc:name="JPA"/>
<flow name="FlowParseJson">
<http:listener config-ref="HTTP_Listener_Configuration" path="/parseJSON" doc:name="HTTP"/>
<parse-template location="/jsonjpacheck" doc:name="Parse Template"/>
<json:json-to-object-transformer returnClass="org.Location" doc:name="JSON to Object"/>
<logger message="#[message.payload]" level="INFO" doc:name="In Transaction"/>
<transactional action="ALWAYS_BEGIN" doc:name="Transactional">
<jpa:persist entity-ref="#[payload]" config-ref="JPA" doc:name="Java Persistence API"/>
</transactional>
<logger message="#[message.payload]" level="INFO" doc:name="After Transaction"/>
</flow>
</code>
And Persistence.xml
<code>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="default" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>org.Location</class>
<properties>
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/xxxx" />
<property name="hibernate.connection.username" value="xxx" />
<property name="hibernate.connection.password" value="xxxx" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.hbm2ddl.auto" value="create" />
</properties>
</persistence-unit>
</persistence>
</code>
And applicationcontext.xml,
<code>
<context:spring-configured/>
<context:annotation-config />
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean>
<property name="persistenceUnitName" value="default" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="true"/>
</bean>
</property>
</bean>
<bean class="org.springframework.orm.jpa.JpaTransactionManager"
id="transactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
<bean id="sessionFactory" factory-bean="entityManagerFactory" factory-method="getSessionFactory"/>
<tx:annotation-driven mode="aspectj" transaction-manager="transactionManager"/>
</code>
Here is another alternative example mule_spring_hibernate . After long battles to get get the correct libraries working together I decided I needed to create a demo project and share
Please take note of the loader.override=org.hibernate entry in the mule-deploy.properties file.
As an alternative, consider persisting data via Hibernate from a Mule component. Working example of this in Mule 3.6.1 may be found here.
I am getting confused on how to get the entity Manager Factory in spring spring-datasource.xml using
I did the following :
spring-datasource.xml file:
<tx:jta-transaction-manager id="transactionManager" />
<tx:annotation-driven mode="proxy"
transaction-manager="transactionManager" />
<jee:jndi-lookup id="entityManagerFactory" jndi-name="jdbc/mysqldatasource" />
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="ebankingUnit"
transaction-type="JTA">
<jta-data-source>jdbc/mysqldatasource</jta-data-source>
<class>com.datamodel.Product</class>
<properties>
<property name="eclipselink.logging.level" value="INFO" />
<property name="eclipselink.query-results-cache.expiry"
value="5000" />
<property name="eclipselink.ddl-generation" value="create-tables" />
<property name="hibernate.hbm2ddl.auto" value="none" />
</properties>
</persistence-unit>
but I am getting thid
which version of Spring are you using? You don't even need persistence.xml in the latest versions.
Here is the configuration using Spring 3.x, for oracle.
<tx:annotation-driven/>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<!-- FactoryBean that creates the EntityManagerFactory -->
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="ORACLE" />
<property name="showSql" value="false" />
</bean>
</property>
<property name="packagesToScan" value="blah.com..domain" />
<property name="jpaProperties">
<props>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.format_sql">true</prop>
</props>
</property>
<property name="dataSource" ref="dataSource" />
</bean>
<bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
<property name="jndiName" value="java:comp/env/myoracledb}" />
</bean>
Now define myoracledb jndi resource in your web.xml
<Resource name="myoracledb" auth="Container"
type="javax.sql.DataSource"
driverClassName="oracle.jdbc.OracleDriver"
maxActive="50"
url="your db url"
username="dbuser" password="dbpwd" />
Regards
There is a spring no-web application Apache James (Java Mail server).
It uses openjpa. It has a persistence unit and datasource and entitymanager factory definition.
I must manipulate it to use one more persistence unit, for an external DB.
I added one more unit into persistence.xml
<persistence-unit name="James" transaction-type="RESOURCE_LOCAL">
<!-- Mailbox stuff-->
<class>org.apache.james.mailbox.jpa.mail.model.JPAMailbox</class>
<class>org.apache.james.mailbox.jpa.mail.model.JPAUserFlag</class>
<class>org.apache.james.mailbox.jpa.mail.model.openjpa.AbstractJPAMessage</class>
<class>org.apache.james.mailbox.jpa.mail.model.openjpa.JPAMessage</class>
<class>org.apache.james.mailbox.jpa.mail.model.openjpa.JPAMessage</class>
<class>org.apache.james.mailbox.jpa.mail.model.JPAProperty</class>
<class>org.apache.james.mailbox.jpa.user.model.JPASubscription</class>
<class>org.apache.james.domainlist.jpa.model.JPADomain</class>
<class>org.apache.james.user.jpa.model.JPAUser</class>
<class>org.apache.james.rrt.jpa.model.JPARecipientRewrite</class>
<properties>
<property name="openjpa.jdbc.SynchronizeMappings" value="buildSchema(ForeignKeys=true)"/>
<property name="openjpa.jdbc.MappingDefaults" value="ForeignKeyDeleteAction=cascade, JoinForeignKeyDeleteAction=cascade"/>
<property name="openjpa.jdbc.SchemaFactory" value="native(ForeignKeys=true)"/>
<property name="openjpa.jdbc.QuerySQLCache" value="false"/>
</properties>
</persistence-unit>
<persistence-unit name="myPU" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>package.EmailAddress</class>
<class>package.Message</class>
<properties>
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="root" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/kepsDb" />
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="hibernate.hbm2ddl.auto" value="none" />
<property name="hibernate.show_sql" value="false" />
<property name="hibernate.dialect" value=" org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.max_fetch_depth" value="0" />
<property name="hibernate.cache.use_second_level_cache" value="true" />
<property name="hibernate.cache.use_query_cache" value="false" />
<property name="hibernate.cache.region.factory_class" value="org.hibernate.cache.ehcache.EhCacheRegionFactory" />
<property name="hibernate.ejb.naming_strategy" value="web.app.persistence.util.AppImprovedNamingStrategy"/>
</properties>
</persistence-unit>
I do not define a second entity manager factory in spring-server.xml, instead, i generate my own entitymanager factory inline with:
EntityManagerFactory emf=Persistence.createEntityManagerFactory("myPU");
EntityManager entityManager=emf.createEntityManager();
entityManager.getTransaction().begin();
But i am getting exception:
Caused by: org.springframework.beans.FatalBeanException: Unable to execute lifecycle method on beanmailetcontext; nested exception is <openjpa-2.1.0-r422266:1071316 nonfatal user error> org.apache.openjpa.persistence.InvalidStateException: This operation cannot be performed while a Transaction is active.
myPU is configured to use JTA transaction. Calling entityManager.getTransaction() when using JTA will cause exception as this method is supposed to use with RESOURCE_LOCAL transaction type .
I don't know if your posted exception messages is due to this , but you can try to change the <persistence-unit> of myPU to :
<persistence-unit name="myPU" transaction-type="RESOURCE_LOCAL">
Please note that if you have to access both databases in the same transaction , you must use JTA .
Following code explains how to configure multiple persistence units with JPA + spring:
First of all, we define two persistence units in the persistence.xml, lets call them unit1 and unit2 respectively:
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0">
<persistence-unit name="Unit1" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.archive.autodetection" value="class" />
<property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver" />
<property name="hibernate.connection.url" value="jdbc:oracle:thin:#my.company.com:1522:D1" />
<property name="hibernate.connection.password" value="my_user" />
<property name="hibernate.connection.username" value="my_password" />
</properties>
</persistence-unit>
<persistence-unit name="Unit2" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.archive.autodetection" value="class" />
<property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver" />
<property name="hibernate.connection.url" value="jdbc:oracle:thin:#my.company.com:1522:D2" />
<property name="hibernate.connection.password" value="my_user" />
<property name="hibernate.connection.username" value="my_password" />
</properties>
</persistence-unit>
</persistence>
Since we dealt with a stand-alone Java applicatie, we defined our data sources in the Spring application context, but for web applicaties one typically defines JNDI references to these datasources in the persistence.xml file itself.
From within the application-context.xml these persisetence units are referred to like so:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd">
<context:annotation-config />
<tx:annotation-driven />
<bean id="dataSource1" class="com.mchange.v2.c3p0.ComboPooledDataSource">
<property name="driverClass" value="oracle.jdbc.driver.OracleDriver" />
<property name="jdbcUrl" value="jdbc:oracle:thin:#my.company.com:1521:D1" />
<property name="user" value="my_user" />
<property name="password" value="my_password" />
</bean>
<bean id="dataSource2" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
<property name="url" value="jdbc:oracle:thin:#my.company.com:1521:D2" />
<property name="username" value="my_user" />
<property name="password" value="my_password" />
</bean>
<!-- DEFINITION OF BOTH ENTITY MANAGER FACTORIES -->
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource1" />
<property name="persistenceUnitName" value="Unit1" />
<property name="persistenceUnitManager" ref="persistenceUnitManager" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform"
value="org.hibernate.dialect.Oracle10gDialect" />
</bean>
</property>
</bean>
<bean id="entityManagerFactory2"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource2" />
<property name="persistenceUnitName" value="Unit2" />
<property name="persistenceUnitManager" ref="persistenceUnitManager" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform"
value="org.hibernate.dialect.Oracle10gDialect" />
</bean>
</property>
</bean>
<!-- PERSISTENCE UNIT MANAGER and TRANSACTION MANAGERS -->
<bean id="persistenceUnitManager"
class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
<property name="dataSources">
<map>
<entry key="d1" value-ref="dataSource1" />
<entry key="d2" value-ref="dataSource2" />
</map>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.jpa.JpaTransactionManager"
p:entity-manager-factory-ref="entityManagerFactory" />
<bean id="abwTransactionManager"
class="org.springframework.orm.jpa.JpaTransactionManager"
p:entity-manager-factory-ref="entityManagerFactory2" />
</beans>
Now all that is left to do is denote the #PersistenceContext in your DAOs like so:
#Required
#PersistenceContext(unitName = "Unit1")
public void setEntityManager(final EntityManager entityManager) {
this.entityManager = entityManager;
}