I want to create an entity X with atributes.
Everything is right except the attribute "permissions" :
public class X implements Serializable{
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private Long idNotateur;
#NotEmpty
private String nomNotateur;
#NotEmpty
private String prenomNotateur;
#NotEmpty
private String fonctionNotateur;
#NotEmpty
private String userNotateur;
#NotEmpty
private String passNotateur;
#ManyToOne
#JoinColumn(name="id_poste")
private Poste poste;
#ManyToOne
#JoinColumn(name="id_dir")
private Direction direction;
#OneToMany(mappedBy="notateur")
private Collection<Employe> Employes;
private Collection<Long> permissions;
getters & setters ...
public Collection<Long> getPermissions() {
return permissions;
}
public void setPermissions(Collection<Long> permissions) {
this.permissions = permissions;
}
}
Then I came across the following error: Caused by: org.hibernate.MappingException: Could not determine type for: java.util.Collection, at table: X, for columns: [org.hibernate.mapping.Column(permissions)]
So how to solve it?
I'm using Spring MVC Hibenate
Related
My entities are as follows
Office
#Entity
public class Office {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
private int latitude;
private int longitude;
private String buildingName;
// getters and setters omitted for brevity
}
Point - which is an EmbeddedId
#Embeddable
public class Point implements Serializable {
private int latitude;
private int longitude;
// getters and setters omitted for brevity
}
Location
#Entity
public class Location {
#EmbeddedId
private Point point;
private String country;
#OneToOne // How to add a OneToOne Mapping
private Office office;
// getters and setters omitted for brevity
}
Question:
I want to add a one-to-one mapping between the Office and the Location entity.
What I've tried:
I added the following annotations along with #OneToOne mapping in the Location entity
#JoinColumn(name = "latitude", referencedColumnName = "latitude")
#JoinColumn(name = "longitude", referencedColumnName = "longitude")
but I got the following error
Provided id of the wrong type for class com.example.demo.entity.employee.o2m_cpk.Office. Expected: class java.lang.Integer, got class com.example.demo.entity.employee.o2m_cpk.Point
Use the following mappings:
#Entity
public class Office {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
#OneToOne(mappedBy = "office")
private Location location;
private String buildingName;
}
#Embeddable
public class Point implements Serializable {
private int latitude;
private int longitude;
}
#Entity
public class Location {
#EmbeddedId
private Point point;
private String country;
#OneToOne
private Office office;
}
I'm using Hibernate in my spring project. But It doesn't work for One-To-One relationships. It gives me the below error.
Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: com.example.TransfertNational.model.Client, at table: ComptePaiement, for columns: [org.hibernate.mapping.Column(client)]
I have ran some searches in the internet, but it doesn't work for me.
the Client Entity :
#Data #Entity
#AllArgsConstructor #NoArgsConstructor #ToString
public class Client {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private String typeTransfert;
private String typePiece;
private String cin;
private String sexe;
private String prenom;
private String typePieceIdentite;
private String paysEmission;
private String numPI;
private String validitePI;
private String dateNaissance;
private String profession;
private String nationalite;
private String paysAdresse;
private String adresseLegale;
private String ville;
private String gsm;
private String email;
#OneToMany(fetch = FetchType.LAZY,
cascade = CascadeType.ALL)
private Set<Beneficiaire> beneficiares;
#OneToOne(fetch = FetchType.LAZY,
cascade = CascadeType.ALL)
private ComptePaiement comptePaiement;
}
the ComptePaiement Entity :
#Data
#Entity
#AllArgsConstructor
#NoArgsConstructor
#ToString
public class ComptePaiement {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int id;
private String solde;
private String rip;
private Client client;
}
Answer from comments:
You are probably missing #JoinColumn on Client or ComptePaiement and mappedBy in #OneToOne annotation, depending which will hold reference id in database.
I'm trying to update my user entity and I have an error that comes to mind:
ERROR: A NULL value violates the NOT NULL constraint of the "id" column Detail: The failed row contains (null, 1, 1)
The problem surely stems from my relationship between user and profile which is n-n
public class Utilisateur implements Serializable {
private static final long serialVersionUID = 1L;
#Id
private Integer id;
private Integer fixe;
private Boolean deleted;
private Boolean actif;
private String email;
private Integer mobile;
private String motDePasse;
private String nom;
private String prenom;
#ManyToMany
private List<Profil> profils = new ArrayList<Profil>();
public Utilisateur() {
}
}
public class Profil implements Serializable {
private static final long serialVersionUID = 1L;
#Id
private Integer id;
private String codeProfil;
private String libelleProfil;
#JsonManagedReference
#ManyToMany
private List<MenuAction> menuActions = new ArrayList<MenuAction>();
public Profil() {
}
}
How you generate value for your id?
Seems you need some way to generate value for you ID.
For example, use #GeneratedValue, like:
#GeneratedValue(strategy = IDENTITY)
I'm having trouble understanding how the #RelationshipEntity works. I've tried following examples, but even though I think I'm following the same pattern as the example, I end up witha stackoverflow, because the Relationship Entity grabs the NodeEntity, which has the RelationshipEntity, and on and on...
My model is:
(:Vendor)-[:BELONGS_TO {active: true, sinceDate: date}]->(:Store)
So my two nodes are Vendor and Store:
#NodeEntity
#Data
public class Vendor {
#GraphId
private Long id;
private Long vendorId;
private String name;
private String address;
#Relationship(type = "OWNS")
private Collection<Inventory> inventory;
#Relationship(type = "BELONGS_TO")
private Collection<Store> store;
}
#NodeEntity
#Data
public class Store {
#GraphId
private Long id;
private Long storeId;
private String name;
private String address;
private String email;
#Relationship(type = "BELONGS_TO", direction = Relationship.INCOMING)
private List<StoreParticipant> storeParticipant;
}
And my RelationshipEntity:
#RelationshipEntity(type = "BELONGS_TO")
#Data
public class StoreParticipant {
#GraphId
private Long id;
#StartNode
private Vendor vendor;
#EndNode
private Store store;
private int count;
private double price;
private boolean negotiable;
private boolean active;
}
I based this off of the Movie example which had (:Person)-[:ACTED_IN]->(:MOVIE) and the acted_in relationship was ROLE
This is happening when I call the repository method findByVendorId
#Repository
public interface VendorRepository extends GraphRepository<Vendor> {
List<Vendor> findByVendorId(Long vendorId);
}
If you're referencing this from both ends, you need to reference the relationship entity, not the node entity directly.
Store looks fine but Vendor contains
#Relationship(type = "BELONGS_TO")
private Collection<Store> store;
when it should be
#Relationship(type = "BELONGS_TO")
private Collection<StoreParticipant> store;
im new to Spring and hibernate, i got the error above when trying to persist the transaction data. please try to help this problem
Here's my Entity:
#Entity #NamedQuery(name="Employee.findAll", query="SELECT e FROM Employee e")
public class Employee implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private int id;
private String city;
private String civil;
#Temporal(TemporalType.DATE)
#Column(name="dob", length=11)
private Date dob;
private String email;
private int epf;
private String fname;
private String gender;
private int landtp;
private String lname;
#Temporal(TemporalType.DATE)
#Column(name="salaryincrement", length=11)
//bi-directional many-to-one association to Designation
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name="designation_id", nullable=false)
private Designation designation;
public Employee() { }
#Entity
#NamedQuery(name="Designation.findAll", query="SELECT d FROM Designation d")
public class Designation implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private int id;
private String type;
//bi-directional many-to-one association to Employee
#OneToMany(mappedBy="designation")//, cascade=CascadeType.ALL
private List<Employee> employees;
public Designation() {
}
this is my Entity class,
Entities have a getters ans setters
designation is set nullable = false. However employees variable isn't initialized in Designation. So, you'll have to initialize as
#OneToMany(mappedBy="designation")//, cascade=CascadeType.ALL
private List<Employee> employees = new LinkedList<>();
I'm not sure that you can go with primitive type int as your Id - you should probably use Integer - because int has default zero value and cannot be null, your new record can be rather seen as a detached entity with Id ZERO and not as a transient one.
The same mistake is in Designation class.
See Primitive or wrapper for hibernate primary keys