I try to loop over the file I findin a relative path to build a list of relative path/soure file name=source file name
SHARED_LIB_PACK=""
for LIB in $(find ../level1/leve2/ -name "*.so*")
do
$SHARED_LIB_PACK=$SHARED_LIB_PACK" "$LIB"="${LIB##*/}
done
but as I run it, it complain :
line 6: = ../level1/level2/file.so.1.0=file.so.1.0: No such file or directory
Any help will be welcome
Firstly, variable assignment is done via:
FOO="bar"
and not
$FOO="bar"
The former will not work.
Secondly, your quotes seem to be in strange places:
SHARED_LIB_PACK=$SHARED_LIB_PACK" "$LIB"="${LIB##*/}
should probably be
LIB="${LIB##*/}"
SHARED_LIB_PACK="$SHARED_LIB_PACK $LIB"
or
SHARED_LIB_PACK="$SHARED_LIB_PACK ${LIB##*/}"
Related
I want to schedule my Perl code to be run every day at a specific time. so I put the below code in bash file:
Automate.sh
#!/bin/sh
perl /tmp/Taps/perl.pl
The schedule has been specified in below path:
10 17 * * * sh /tmp/Taps/Automate.sh > /tmp/Taps/result.log
When the time arrived to 17:10 the .sh file hasn't been running. however, when I run ./Automate.sh (manually) it is running and I see the result. I don't know what is the problem.
Perl Code
#!/usr/bin/perl -w
use strict;
use warnings;
use Data::Dumper;
use XML::Dumper;
use TAP3::Tap3edit;
$Data::Dumper::Indent=1;
$Data::Dumper::Useqq=1;
my $dump = new XML::Dumper;
use File::Basename;
my $perl='';
my $xml='';
my $tap3 = TAP3::Tap3edit->new();
foreach my $file(glob '/tmp/Taps/X*')
{
$files= basename($file);
$tap3->decode($files) || die $tap3->error;
}
my $filename=$files.".xml\n";
$perl = $tap3->structure;
$dump->pl2xml($perl, $filename);
print "Done \n";
error:
No such file or directory for file X94 at /tmp/Taps/perl.pl line 22.
X94.xml
foreach my $file(glob 'Taps/X*') -- when you're running from cron, your current directory is /. You'll want to provide the full path to that Taps directory. Also specify the output directory for Out.xml
Cron uses a minimal environment and a short $PATH, which may not necessarily include the expected path to perl. Try specifying this path fully. Or source your shell settings before running the script.
There are a lot of things that can go wrong here. The most obvious and certain one is that if you use a glob to find the file in directory "Taps", then remove the directory from the file name by using basename, then Perl cannot find the file. Not quite sure what you are trying to achieve there. The file names from the glob will be for example Taps/Xfoo, a relative path to the working directory. If you try to access Xfoo from the working directory, that file will not be found (or the wrong file will be found).
This should also (probably) lead to a fatal error, which should be reported in your error log. (Assuming that the decode function returns a false value upon error, which is not certain.) If no errors are reported in your error log, that is a sign the program does not run at all. Or it could be that decode does not return false on missing file, and the file is considered to be empty.
I assume that when you test the program, you cd to /tmp and run it, or your "Taps" directory is in your home directory. So you are making assumptions about where your program looks for the files. You should be certain where it looks for files, probably by using only absolute paths.
Another simple error might be that crontab does not have permission to execute the file, or no read access to "Taps".
Edit:
Other complications in your code:
You include Data::Dumper, but never actually use that module.
$xml variable is not used.
$files variable not declared (this code would never run with use strict)
Your $files variable is outside your foreach loop, which means it will only run once. Since you use glob I assumed you were reading more than one file, in which case this solution will probably not do what you want. It is also possible that you are using a glob because the file name can change, e.g. X93, X94, etc. In that case you will read the last file name returned by the glob. But this looks like a weak link in your logic.
You add a newline \n to a file name, which is strange.
I am trying to iterate over files in a folder, renaming them as foldername1, foldername2, etc. However, I'm getting an error which says that the mv isn't being used correctly.
So far my code looks like this:
FILES='(Full Path)/Macbeth/audio/'
for file in "$FILES"*
do
mv $file 'Macbeth'$i''
done
The final code should iterate through the files and rename them as, in this case Macbeth1.mp3, but I'm not sure how the Bash syntax works.
As suggested by Cyrus, the solution was to use the full path
Im trying to move multiple files from one directory to another directory.
File name is with sequence and will be varying.
Example:
/global/userhome/usrsats/---------directory which has file names as below:
fl_cl_filename1
fl_cl_filename2
fl_cl_filename3
...
...
Now when moved to another directory, i need to get only the file name and delimit the fl_cl part.
Please help
Assuming you're using bash, I would do this with the remove the matching prefix pattern facility like this (with DEST_DIR set to the destination directory):
cd /global/userhome/usrsats
for f in *; do mv $f ${DEST_DIR}/${f#fl_cl_}; done
I have 312 directories labeled,
Ion_0001- Ion_0312.
In each directory I have a file light.out. I'd like to change the file names in each directory to, for example:
Ion_0001.out
I believe I also need to substitute the / so that my output DOESNT look this this:
Ion_0001/.out
Can any one help me out with a simple script??
This is what I've tried:
#!/bin/bash
for dir in */
do
cd $dir
for filename in *.out; do
mv $filename ${filename//$dir.out}
done
cd ..
done
Thanks!
Not a free coding service, but it's simple enough to not make it worth arguing about...
Assuming this file structure:
Ion_0001/
Ion_0001/light.out
Ion_0002/
Ion_0002/light.out
...
Run this code in a script or just at the command line:
for i in Ion_0*
do
mv "${i}/light.out" "${i}/${i}.out"
done
Resulting in this structure:
Ion_0001/
Ion_0001/Ion_0001.out
Ion_0002/
Ion_0002/Ion_0002.out
...
Is that what you were looking for?
for dir in Ion*/; do
mv "${dir}light.out" "${dir}${dir%/}.out"
done
The trailing slash in the Ion*/ pattern limits the results to directories only, but the slash will be present in the variable's value.
I'm not very good in shell scripting and would like to ask you some question about looping of files big dataset: in my example I have alot of files with the common .pdb extension in the work dir. I need to loop all of them and i) to print name (w.o pdb extension) of each looped file and make some operation after this. E.g I need to make new dir for EACH file outside of the workdir with the name of each file and copy this file to that dir. Below you can see example of my code which are not worked- it's didn't show me the name of the file and didn't create folder for each of them. Please correct it and show me where I was wrong
#!/bin/bash
# set the work dir
receptors=./Receptors
for pdb in $receptors
do
filename=$(basename "$pdb")
echo "Processing of $filename file"
cd ..
mkdir ./docking_$filename
done
Many thanks for help,
Gleb
If all your files are contained within the .Repectors folder, you can loop each of them like so:
#!/bin/bash
for pdb in ./Receptors/*.pdb ; do
filename=$(basename "$pdb")
filenamenoextention=${filename/.pdb/}
mkdir "../docking_${filenamenoextention}"
done
Btw:
filenamenoextention=${filename/.pdb/}
Does a search replace in the variable $pdb. The syntax is ${myvariable/FOO/BAR}, and replaces all "FOO" substrings in $myvariable with "BAR". In your case it replaces ".pdb" with nothing, effectively removing it.
Alternatively, and safer (in case $filename contains multiple ".pdb"-substrings) is to remove the last four characters, like so: filenamenoextention=${filename:0:-4}
The syntax here is ${myvariable:s:e} where s and e correspond to numbers for the start and end index (not inclusive). It also let's you use negative numbers, which are offsets from the end. In other words: ${filename:0:-4} says: extract the substring from $filename starting from index 0, until you reach fourth-to-the-last character.
A few problems you have had with your script:
for pdb in ./Receptors loops only "./Receptors", and not each of the files within the folder.
When you change to parent directory (cd ..), you do so for the current shell session. This means that you keep going to the parent directory each time. Instead, you can specify the parent directory in the mkdir call. E.g mkdir ../thedir
You're looping over a one-item list, I think what you wanted to get is the list of the content of ./Receptors:
...
for pdb in $receptors/*
...
to list only file with .pdb extension use $receptors/*.pdb
So instead of just giving the path in for loop, give this:
for pdb in $receptors/*.pdb
To remove the extension :
set the variable ext to the extension you want to remove and using shell expansion operator "%" remove the extension from your filename eg:
ext=.pdb
filename=${filename%${ext}}
You can create the new directory without changing your current directory:
So to create a directory outside your current directory use the following command
mkdir ../docking_$filename
And to copy the file in the new directory use cp command
After correction
Your script should look like:
receptors=./Receptors
ext=.pdb
for pdb in $receptors/*.pdb
do
filename=$(basename "$pdb")
filename=${filename%${ext}}
echo "Processing of $filename file"
mkdir ../docking_$filename
cp $pdb ../docking_$filename
done