response=$(curl -sL -w \\n%{http_code} "http://<ip_addr>/api/1/app" -X DELETE)
echo response
if [ "$response" -eq 200 ]
then
echo "Got 200 OK"
else
echo "not getting the result"
fi
What i'm trying to do is to get the http response code.
I'm positive that the response should be 200 OK
When I run the script I'm getting
{
"result":true
}
200
tst.sh: line 302: [: {
200: integer expression expected
I even don't want to display
{
"result":true
}
I just want to print 200 and compare 200.
Just with curl command:
curl -sL -w '%{http_code}' "http://<ip_addr>/api/1/app" -X DELETE -o /dev/null
Get the last line of the output.
response=$(curl -sL -w \\n%{http_code} "http://<ip_addr>/api/1/app" -X DELETE | tail -1)
Besides tail -n you can also use:
awk 'END { print }'
sed -n '$p'
Another way if you're using bash is to remove everything before the last line:
shopt -s extglob
response=${response##*[[:space:]]}
In your above, you are missing a $ in your first echo, but no matter. You can strip the {"result":true} from the $response string
before the if statement:
response=${response#*\}\ }
Related
Imagine I have the following code in a bash script:
curl -s https://cat-fact.herokuapp.com/facts/random?animal=cat | jq .
Notice that I wish to display the payload of the response by passing it to jq.
Now suppose sometimes those curls sometimes return a 404, in such cases my script currently still succeeds so what I need to do is check the return code and exit 1 as appropriate (e.g. for a 404 or 503). I've googled around and found https://superuser.com/a/442395/722402 which suggests --write-out "%{http_code}" might be useful however that simply prints the http_code after printing the payload:
curl -s --write-out "%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat | jq .
$ curl -s --write-out "%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat | jq .
{
"_id": "591f98783b90f7150a19c1ab",
"__v": 0,
"text": "Cats and kittens should be acquired in pairs whenever possible as cat families interact best in pairs.",
"updatedAt": "2018-12-05T05:56:30.384Z",
"createdAt": "2018-01-04T01:10:54.673Z",
"deleted": false,
"type": "cat",
"source": "api",
"used": false
}
200
What I actually want to is still output the payload, but still be able to check the http status code and fail accordingly. I'm a bash noob so am having trouble figuring this out. Help please?
I'm using a Mac by the way, not sure if that matters or not (I'm vaguely aware that some commands work differently on Mac)
Update, I've pieced this together which sorta works. I think. Its not very elegant though, I'm looking for something better.
func() {
echo "${#:1:$#-1}";
}
response=$(curl -s --write-out "%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat | jq .)
http_code=$(echo $response | awk '{print $NF}')
func $response | jq .
if [ $http_code == "503" ]; then
echo "Exiting with error due to 503"
exit 1
elif [ $http_code == "404" ]; then
echo "Exiting with error due to 404"
exit 1
fi
What about this. It uses a temporary file. Seems me a bit complicated but it separates your content.
# copy/paste doesn't work with the following
curl -s --write-out \
"%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat | \
tee test.txt | \ # split output to file and stdout
sed -e 's-.*\}--' | \ # remove everything before last '}'
grep 200 && \ # try to find string 200, only in success next step is done
echo && \ # a new-line to juice-up the output
cat test.txt | \ #
sed 's-}.*$-}-' | \ # removes the last line with status
jq # formmat json
Here a copy/paste version
curl -s --write-out "%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat | tee test.txt | sed -e 's-.*\}--' | grep 200 && echo && cat test.txt | sed 's-}.*$-}-' | jq
This is my attempt. Hope it works for you too.
#!/bin/bash
result=$( curl -i -s 'https://cat-fact.herokuapp.com/facts/random?animal=cat' )
status=$( echo "$result" | grep -E '^HTTPS?/[1-9][.][1-9] [1-9][0-9][0-9]' | grep -o ' [1-9][0-9][0-9] ')
payload=$( echo "$result" | sed -n '/^\s*$/,//{/^\s*$/ !p}' )
echo "STATUS : $status"
echo "PAYLOAD : $payload"
Output
STATUS : 200
PAYLOAD : {"_id":"591f98803b90f7150a19c23f","__v":0,"text":"Cats can't taste sweets.","updatedAt":"2018-12-05T05:56:30.384Z","createdAt":"2018-01-04T01:10:54.673Z","deleted":false,"type":"cat","source":"api","used":false}
AWK version
payload=$( echo "$result" | awk '{ if( $0 ~ /^\s*$/ ){ c_p = 1 ; next; } if (c_p) { print $0} }' )
Regards!
EDIT : I have simplified this even more by using the -i flag
EDIT II : Removed empty line from payload
EDIT III : Included an awk method to extract the payload in case sed is problematic
Borrowing from here you can do:
#!/bin/bash
result=$(curl -s --write-out "%{http_code}" https://cat-fact.herokuapp.com/facts/random?animal=cat)
http_code="${result: -3}"
response="${result:0:${#result}-3}"
echo "Response code: " $http_code
echo "Response: "
echo $response | jq
Where
${result: -3} is the 3rd index starting from the right of the string till the end. This ${result: -3:3} also would work: Index -3 with length 3
${#result} gives us the length of the string
${result:0:${#result}-3} from the beginning of result to the end minus 3 from the http_status code
The site cat-fact.herokuapp.com isn't working now so I had to test it with another site
I'm using the at command to schedule a job in the future.
DoCurlAt () {
if [ -n "${AuthToken:-}" ] ; then
$4 << 'EOF'
curl -s -H "${AuthHeader:-}" -H "$1" --data-urlencode "$2" "$3"
EOF
Exitcode=$?
fi
WriteLog Output Info "AT Output: $AtOutput Exitcode: $Exitcode"
}
How can I capture the result of the at in a variable called $AtOutput?
I tried with
AtOutput=$(bash $4 << EOF
curl -s -H "${AuthHeader:-}" -H "$1" --data-urlencode "$2" "$3"
EOF
)
But that does't really give any result.
Also tried with:
AtOutput=$(curl -s -H "${AuthHeader:-}" -H "$1" --data-urlencode "$2" "$3" | at "$4")
But I would prefer to use the HERE-doc.
The function is called with
DoCurlAt "$AcceptJson" "argString=$ArgString" "$ApiUrl/$ApiVersion/job/$JobUid/run" "$OneTime"
$OneTime ($4) could be for example "at 15:19 today" The output is mostly something like this:
job 7 at 2016-08-16 15:30
at writes to standard error, not standard output. Use the 2>&1 redirection to copy standard error to standard output first.
$ at_output=$( echo "cmd" | at "$when" 2>&1 )
This code ouputs a http status of 000 - which seems to indicate something didn't connect properly but when I do this curl outside of the bash script it works fine and produces a 200 so something with this code is off... any guidance?
#!/bin/bash
URLs=$(< test.txt | grep Url | awk -F\ ' { print $2 } ')
# printf "Preparing to check $URLs \n"
for line in $URLs
do curl -L -s -w "%{http_code} %{url_effective}\\n" $line
done
http://beerpla.net/2010/06/10/how-to-display-just-the-http-response-code-in-cli-curl/
your script works on my vt.
I added in a couple of debugging lines, this may help you to see where any metacharacters are getting in, as I would have to agree with the posted coments.
I've output lines in the for to a file which is then printed out with od.
I have amended the curl line to grab the last line, just to get the response code.
#!/bin/bash
echo -n > $HOME/Desktop/urltstfile # truncate urltstfile
URLs=$(cat testurl.txt | grep Url | awk -F\ ' { print $2 } ')
# printf "Preparing to check $URLs \n"
for line in $URLs
do echo $line >> $HOME/Desktop/urltstfile;
echo line:$line:
curl -IL -s -w "%{http_code}\n" $line | tail -1
done
od -c $HOME/Desktop/urltstfile
#do curl -L -s -w "%{http_code} %{url_effective}\\n" "$line\n"
I am trying to write a script to test if my firewall is blocking multiple pages. When I try to read one or multiple lines from command line I get a -ne: unitary operator expected error.
This is my attempt:
sh test www.3232.com.pe
www.3232.com.pe
test: line 7: [: -ne: unary operator expected
$ cat test
#!/bin/sh
for var in "$#"
do
echo $var
res=`curl -s -I $var | grep HTTP/1.1 | awk {'print $2'}`
if [ $res -ne 200 ]
then
echo "Error on $var"
fi
done
Consider what happens if curl does not successfully connect:
res=`curl -s -I $var | grep HTTP/1.1 | awk {'print $2'}`
if [ $res -ne 200 ]
If curl does not get any headers, or does not get a HTTP/1.1 header, then the pipline in the first command outputs nothing and res is assigned to nothing. In that case, the test in the second line will fail with an unexpected operator error.
You need to first test that res is nonempty. And, if it is empty, take an appropriate action.
I am writing a shell script to monitor website live or not and send an email alert below is my code
#!/bin/bash
if [[ curl -s --head --request GET http://opx.com/opx/version | grep "200 OK" > /dev/null] && [ curl -s --head --request GET http://oss.com/version | grep "200 OK" > /dev/null ]]
then echo "The HTTP server on opx.com and oss.com is up!" #> /dev/null
else
msg="The HTTP server opx.com Or oss.com is down "
email="opx-noc#opx.com"
curl --data "body=$msg &to=$email &subject=$msg" https://opx.com/email/send
fi;
if i run this code i got
./Monitoring_Opx_Oss: line 2: conditional binary operator expected
./Monitoring_Opx_Oss: line 2: syntax error near `-s'
./Monitoring_Opx_Oss: line 2: `if [[ curl -s --head --request GET http://opx.com/opx/version | grep "200 OK" > /dev/null] && [ curl -s --head --request GET http://oss.com/version | grep "200 OK" > /dev/null ]] '
Please correct me...
Change it do this:
if [ $(curl -s --head --request GET http://opx.opera.com/opx/version | grep "200 OK" > /dev/null) ] && [ $(curl -s --head --request GET http://oss.opera.com/version | grep "200 OK" > /dev/null) ]
To check the status of a command inside an if, you have to do it like
if [ $(command) ]
while you were using
if [ command]
note also the need of spaces around [ ]: if [_space_ command _space_ ]
Update
Based on Ansgar Wiechers's comment, you can also use the following:
if curl -s --head --request GET http://opx.com/opx/version | grep "200 OK" > /dev/null && curl -s --head --request GET http://oss.com/version | grep "200 OK" > /dev/null;
That is,
if command && command